If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.

Answers

Answer 1

Answer:

The mass of the copper is 3.00kg

Explanation:

If 11,550 J Heat Is Absorbed By A Copper Object When It Is Heated From 20.0C To 30.0C,what Is The Mass

Related Questions

Tions: Encircle the letter that corresponds
you answer
Homest
mga kab
1. The framework of a house provides the house with both support and structure allowing it to
stand. Which system provides those functions in humans?
A. Skeletal System
C. Integumentary System
B. Muscular System
D. Digestive System
2. What 2 systems are MOST DIRECTLY responsible for your ability to stand up for long periods of time, walk,
and sit down?
A. Integumentary and Excretory C. Circulatory and Respiratory
B. Digestive and Reproductive D. Musculoskeletal
3. The soft, fatty tissue that fills the inside of most bones and makes red blood cells and many white blood
cells.
A. Bone marrow B. Fat
C. Heart
D. Skin
4. Skin, hair, and nails make up the
system.
A. muscular system
C. digestive system
HONE
B. integumentary system
D. skeletal system
5.
the body's largest organ, contains melanin, which gives skin color that protects it from
the sun's rays.
A. Skin
B. Tendon
C. Nerves
D. Joint Ignition
6. If the portion of the cerebellum was damaged as a result of trauma, what effect would this person
likely experience?
A. rapid breathing
C. trouble in maintaining balance
B. changes in body temperature D. partial or incomplete memory loss
7. It is involved in the fight or flight response.
A. parasympathetic B. autonomic C. sympathetic D. somatic
8. Which of the following organs is made up the central nervous system?
A. muscles and bones
C. interneurons and motor neurons
B. brain and spinal cord D. sensory neurons and motor neurons
9. The following are parts of neuron, EXCEPT
A. nucleus
B. cell body
C. axon
D. dendrites
10. Which of the following is not controlled by the cerebrum.
A. judging a beauty contest C. thinking of your assignment
B. smelling a bad odor
D. Breathing
11. The main function of musculoskeletal system is to
A. support the body, allowing motion, and protecting vital organs
B. release waste product from the body
C. maintain heat and temperature of the body
D. send and receive different stimuli from the sense organs
12. Muscles in the body work
A. individually
B. in group
C. in pairs D. as needed
13. The bones provide
A. food for the body.
B. proper nourishment.
C. stability of the body.
D. protection against all kinds of diseases.
14. The skeletal portion of the system serves as the main storage of​

Answers

Answer:

1. A Skeletal System

2. D Musculoskeletal System

3. A Bone Marrow ( specifically red bone marrow where red blood cells produce and yellow bone marrow where fats and other tissues produce)

4. B Integumentary System

5. A Skin

6. C (Cerebellum is a part of the brain responsible for making postural adjustments in order to maintain balance).

7. C

8. B

9. A

10. D (Breathing was controlled by Medulla Oblongata)

11. A

12. B

13. B

14. Minerals specifically calcium and phosphorus.

[O.04H]The table below shows the use of some energy production methods over time.


Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500

Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.

Answers

I think The coastal areas were highly polluted

Answer:

i think its greenhouse gases may increase

Explanation:

HELPPP BESTIESSS An astronomer is studying two stars that have about the same size and brightness. From the Earth, one of the stars appears very bright in the night sky. The other star appears very faint and dim.

Why does one star appear to be brighter than the other?
A. The Earth is moving toward the brighter star.
B. The Earth is moving toward the dimmer star.
C. The Earth is farther from the brighter star.
D. The Earth is closer to the brighter star.

Answers

Answer:

If the stars are about the same  size and brightness then the earth must be nearer to the stat that appears brighter, The stars movement, nearer or farther,  would only effect the frequency received (redshift).

Answer:

D- The earth is closer to the bright star

Explanation:

If two stars have SAME brightness and size then that means the only point of difference is distance . Earth should be closer to the brighter star for the star to be bright.

I hope im right!!

In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?

Answers

84.0 was applied by John Stapp

The cheetah is one of the fastest-accelerating animals, because it can go from rest to 27 m/s (about 60 mi/h) in 4.0 s. If its mass is 110 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in

(a) watts

(b) horsepower.

Answers

Answer:

A. 10023.75 Watts

B. 13.44 horse power

Explanation:

A. Determination of the power in Watts.

We'll begin by calculating the energy of the cheetah. This can be obtained as follow

Velocity (v) = 27 m/s

Mass (m) = 110 kg

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 110 × 27²

KE = 55 × 729

KE = 40095 J

Finally, we shall determine the power in Watts. This can be obtained as follow:

Kinetic energy (KE) = 40095 J

Time (t) = 4 s

Power (P) =?

Power = Energy /time

Power = 40095 / 4

Power = 10023.75 Watts

B. Determination of the power in horse power.

Power in Watts = 10023.75 Watts

Power in horse power =?

Recall:

746 Watts = 1 hp

Therefore,

10023.75 Watts = 10023.75 / 746

10023.75 Watts = 13.44 hp

Therefore, the power in horse power is 13.44 hp

write any three utilities of plastics​

Answers

Explanation:

container, bottles, boxes, cups

container plates spoons

Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)

Answers

Answer:

acc to formula= F= G m1m2/rsq

mass of Uranus= F×r sq/G×m

M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21

=3×10^25-8×7614×7614/667×301×10^-2-11+21-2

=173918988×10^11/200767

=866×10^11(approx)

of 72.0 units. If the mass of Object 1 is halved AND the mass of object 2 is tripled, then the new gravitational force will be units.

Answers

Answer:

youtg jugre contact coming call details

a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?​

Answers

Answer:

L = 2 J.s

Explanation:

The angular momentum of an object travelling in a horizontal circle is given by the following formula:

[tex]L = mvr[/tex]

where,

L = Angular momentum = ?

m = mass = 0.8 kg

v = linear speed = rω

r = radius of circular path = length of rope = 0.5 m

ω = Angular Speed = 10 rad/s

therefore,

[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]

L = 2 J.s

​A hose, of radius 0.018 m, is connected to a water faucet. The water pressure at the point where the hose connects to the faucet is 150,000 Pa. The other end of the hose is connected to an outlet of radius 0.011 m, where the water comes out. The total length of the hose and outlet is 15 m.
(a) An experiment shows that the water exists the outlet with a speed 5.2 m/s. What is the flow rate through the hose?
(b) What is the maximum height that the end of the outlet can he held above the faucet, and water still comes out?
(c) Suppose there is a small hole in the hose. How does that affect the speed at which the water comes out? Explain.

Explain each step!

Answers

Answer:

The smaller the hole, the more force.

A voltage is applied to a resistor,
which creates a 1.50 A current. If
you double the resistance, keeping
the voltage the same, what will the
new current be?
(Unit = A)

Answers

Answer:

Explanation:

By Ohms Law, Voltage = Current * Resistance

Keeping the voltage the same and doubling the resistance, the current will be halved.

So the new current = 1.5/2 = 0.75A

By using Ohms law,  the current will be 0.75A.

What is Ohm's law?

Ohm's law states that the current flowing through a resistance is proportional to potential difference across the resistance under constant temperature and pressure conditions. Ohm's law can be expressed as:

V =IR

Here, I = 1.50 AR = R Ωso, V = 1.50 R Now Voltage is same but resistance is doubled so new resistance is

Now, put the values of given data in ohms law formula:

2RI = 1.50 R/ 2R = 0.75A

Hence current is 0.75A

To know more about Ohms law here

https://brainly.com/question/14796314.

#SPJ2

Suppose the equation of the velocity of a car at any given time is Vx= 30m/s+(2.5m/s^3)t^2 Find the change in the velocity of the car during time t1= 4s and t2= 5.5s (a) 70.00 m/s (b) 105.63 m/s (c) 35.63 m/s (d) 175.63 m/s

Answers

Answer:

time=4, answer choice A

time=5.5, answer choice B

Explanation:

This is taken from the kinematic equation, v=vo+(1/2)at^2

Velocity at time 4 = 30+(2.5)(4)^2

Velocity at time 5.5 = 30+(2.5)(5.5)^2

Velocity at time 4 seconds = 70 m/s

Velocity at time 5.5 seconds = 105.63 m/s

Can you help me plzz ?

Answers

We are given:

Mass of the Crate(m) = 71 kg

Applied force(F) = 577 N

Resolving the applied force:

To solve this problem, we will first make a free-body diagram (attached)

The Applied force has been resolved into 2 components denoted by a thinner line and 'g' is the acceleration due to gravity

We found the values by using basic trigonometry

Finding the Normal Force:

Normal force is equal and opposite to the net force applied on the ground. So, we will subtract the vertical component of the applied force from the weight of the crate.

Normal force = mg - F*Sin(27°)

Normal force = [(71)*(9.8)] - [ (577)(0.454) ]                           [g = 9.8 m/s²]

Normal Force = 433.84 N

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