Identify the scenarios in which the statistics are misleading.
A supermarket claims that 65% of its shoppers would like to see home delivery offered. They arrived at the conclusion by polling 50 randomly selected customers on a Tuesday afternoon.
A report by a company that manufactures hair brushes says 56% of people who buy their brushes own only one hair brush. The conclusion comes from a survey of 500 males who bought the company's brush.
A website claims that 47% of its visitors click on at least one advertisement while browsing the site. The information was collected from a database containing all the activity on the website during the past month.
A music store owner claims that about 15% of high school students in his city can play the piano. He concludes this after surveying 80 randomly selected students from the various high schools in his city.
A clothing store claims that 45% of its customers prefer skinny jeans over regular jeans. They concluded this from a survey which asked 120 randomly selected teenage customers which style they prefer.

Answer:

x = 15

Step-by-step explanation:

15 * 15 = 225

Answer:

X = 15

Step-by-step explanation:

This is because if you square 15, you get 225.

Answer:

I believe the correct answer is C

Answer:

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

Step-by-step explanation:

Let [tex]A[/tex] denote a Boolean variable.

The negation of [tex]A[/tex] ([tex]\lnot A[/tex]) is false if when [tex]\!A[/tex] is true, and true when [tex]A\![/tex] is false. In a truth table:

[tex]\begin{array}{c||c} A & \lnot A \\ \cline{1-2} \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c||c} A & \lnot A \\ \hline \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].

Let [tex]B[/tex] denote another Boolean variable. The material implication "[tex]A[/tex] implies [tex]\!B[/tex]" ([tex]A \to B[/tex]) is true unless [tex]B\![/tex] is false when [tex]A\![/tex] is true.  

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex]

The logical or "[tex]A[/tex] or [tex]B[/tex]" is true when either [tex]A\![/tex] or [tex]B\![/tex] is true (and also when both are true.)

[tex]\begin{array}{c|c||c} A & B & A \lor B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm T \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F\end{array}[/tex]

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].

Start by finding the value of [tex]\lnot X[/tex], [tex](X \to Y)[/tex], and [tex](Z \to \lnot X)[/tex] for each of the [tex]2^3 = 8[/tex] possible combinations of [tex]X[/tex], [tex]Y[/tex], and [tex]Z[/tex].

[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \cline{1-6} \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \cline{1-6} \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].

[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].

The value of [tex](X \to Y) \lor (Z \to \lnot X)[/tex] is true whenever either [tex](X \to Y)[/tex] or [tex](Z \to \lnot X)[/tex] is true (or both.) The combination [tex]X = \rm T[/tex], [tex]Y = \rm F[/tex], and [tex]Z = \rm T[/tex] is the only one among the eight where neither [tex](X \to Y)\![/tex] nor [tex](Z \to \lnot X)\![/tex] is true. [tex](X \to Y) \lor (Z \to \lnot X)\![/tex] would evaluate to true for all other combinations.

Hence, the truth table would be:

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

Answer:

Option c.

Step-by-step explanation:

Volume = length * breadth *height

According to the question,

(3/2 * 1/2 * 2)ft^3

= 3/2ft^3

Hope this helped :)

Answer:

Ben is 4 meters below the surface area.

Answer:

D) 20º

Step-by-step explanation:

if one angle is 70º, and the other is 90º, that means that the first two angles equal 160º. since all three interior angles of a triangle have to add up to 180º, the third angle must be 20º.

Answer: p/7 + 8

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

Answer:

Hello good afternoon

Step-by-step explanation:

you have to put this link

Answer:

A=-7

Step-by-step explanation:

7=35+A4

4A=-28

A=-7

Answer:

The height of prism A is 4, the height of prism B is 5, the height of prism C is 4, and the height or prism D is 2. Since 4=4, prisms A and C have the same height.

Hope this helped! If it did, please give me brainliest! It would help a lot! Thanks! :D

Answer:

$60.75×m

Step-by-step explanation:

'5'5"5"5""55

Answer:

11

Step-by-step explanation:

2y + 4y = 6y = 6y + 8 + 3 Add the numbers: 8 + 3 = 11     hope this helps ;)                      ITS A ME LUIGI ON THE XBOX ONE WAAAAAAAAAAAAAAAAAAAAAAAAHHOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO                                                                                              

Answer:

A. make a point on the line to the right 2 units from 0

B. the opposite of 2 isn't located at the same place as point P on the number line because the opposite of 2 is -2 and the point P is the opposite of negative 2 which would be positive 2. So the two points are not in the same place because they have different signs.

Step-by-step explanation:

hope this helps

I know the wording is a bit complicated lol <3

Answer:

The standard form of the ellipse is [tex]\frac{x^{2}}{25} +\frac{y^{2}}{169} = 1[/tex]. Coordinates of the foci are [tex]F_{1} (x,y) = (0,-c)[/tex] and [tex]F_{2}(x,y) = (0,c)[/tex], respectively.

Step-by-step explanation:

The equation of a ellipse centered in the origin in standard form is defined by following formula:

[tex]\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}} = 1[/tex] (1)

Where [tex]a, b[/tex] are the coefficients of the ellipse.

Now we proceed to transform the equation of the ellipse in general form into standard form by algebraic means:

[tex]169\cdot x^{2}+25\cdot y^{2}-4225 = 0[/tex]

[tex]169\cdot x^{2}+25\cdot y^{2} = 4225[/tex]

[tex]\frac{x^{2}}{25} +\frac{y^{2}}{169} = 1[/tex]

Since [tex]b > a[/tex], then major axis of the ellipse is located in y-axis. The distance between center and focus ([tex]c[/tex]) is calculated by following Pythagorean identity:

[tex]c =\sqrt{b^{2}-a^{2}}[/tex] (2)

[tex]c = 12[/tex]

The location of the foci are represented by [tex]F_{1} (x,y) = (0,-c)[/tex] and [tex]F_{2}(x,y) = (0,c)[/tex]. If we know that [tex]c = 12[/tex], then the location of the foci are, respectively:

[tex]F_{1}(x,y) = (0,-12)[/tex], [tex]F_{2}(x,y) = (0,12)[/tex]

Answer:

-6.5 degrees/km  

Step-by-step explanation:

I couldn't rlly find the answer myself, but this quizzis link has it. Question 7 on the quizzis btw https://quizizz.com/admin/quiz/5cbe6de57d6ff2001bf22fc3/2019-algebra-i-staar-review-day-2

Answer:

1,695.6 in. 3

Step-by-step explanation:

Answer:

3. D 4. B

Step-by-step explanation:

3.  e^2 = g^2 + f^2, answer is d

4. Let a = 3, b = 4, c = 5

2c = 10

2b = 8

2a = 6

10^2 = 8^2 + 6^2

answer is b

3. The Pythagorean theorem states the hypotenuse squared is equal to each side squared added to each other.

The answer is D. E^2 = f^2 + g^2

4.

To keep the proportion you could multiply the sides by the same numbers . The answer would be 2A, 2b, 2c

The medians are about the same.

Option C is the correct answer.

It is the middle value of the given set of numbers after arranging the given set of numbers in order.

We have,

Movie theater 1.

From the box plot given,

The median is 995.

Movie theater 2.

From the box plot given,

The median is 995.

Thus,

The median in both the box plot is the same.

Learn more about the median here:

https://brainly.com/question/28060453

#SPJ2

Answer:

The answer is C

Step-by-step explanation:

9 of the 20 drawn were red

9/20* 100 = 45

Answer:

(X-1+I)(x-1-I)

Step-by-step explanation:

Expression (x + 1 - i)(x + 1 + i) is equivalent to  x² + 2x +2.

Option (B) is correct option.

Variables, integers, and a variety of mathematical procedures make up an algebraic expression.

To find the expression equivalent to x² + 2x +2,

Solve with the help of options.

(A)

(x - 1 + i)(x - 1 - i)

Solve by using formula (a + b)(a - b) = a² - b²

(x - 1 + i)(x - 1 - i) = (x -1)² - i² = x² + 1 - 2x +1 = x² - 2x + 2

(B)

(x + 1 - i)(x + 1 - i)

Solve by using formula (a + b)(a - b) = a² - b²

(x + 1 - i)(x + 1 + i) = (x + 1)² - i² = x² + 1 + 2x +1 = x² + 2x + 2

Expression in option (B) is equivalent to x² + 2x + 2.

To know more about Algebraic expression on:

https://brainly.com/question/19245500

#SPJ2

Answer:

Compound interest is that which, once generated, is added to the capital, in order to expand the calculation base on which, in turn, new interests will be generated. Thus, in short, if the interest is, for example, 5 percent, said interest will be added to the initial capital, with which that 5% generated will be increasing, since it will be calculated on an increasingly large basis.

Compound interest is very important for financial investments, as it maximizes the results of said investments, even more so when compared to simple interest, in which the interest generated is not added to the initial capital.

Answer:

700

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

( (23 * 13) / 2 ) - ( (13 * 13) / 2 ) = ( 299 / 2 ) - ( 169 / 2 ) = 149.5 - 84.5 = 65

Numbers are slightly unclear but I think this is right.

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

[tex]P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444[/tex]

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

[tex]P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333[/tex]

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172[/tex]

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Answer:

D

Step-by-step explanation:

Answer:

What is acceleration?

Imagine you are playing golf, and you’ve just set up the golf ball on the tee. You test your grip, take a few practice swings, and peer into the distance at the flag pole marking the first hole for the course. Your wise golf ball guru (who happens to also teach physics) tells you to “Be the ball, young grasshopper.” So you close your eyes and picture the distance the ball must travel. “Yes, young earthworm”, your sensei says, “that distance you see is the displacement you must achieve, displacement is the change in position from one place to another.”

Step-by-step explanation: