Identify the incorrect Algebra forms that multiplication is represented in the expressions 5 times 3x.
A 5(3x)
B (5) x (3x)
C (5)3x
D 5(3)(x)

Answer:

t-10

Step-by-step explanation:

fewer than means it comes after

t-10

Answer:

it's t -10

Step-by-step explanation:

Answer:

1/11 is a repeating decimal

9/100 is a terminated decimal

Step-by-step explanation:

Properties of the fractional part of 100 can be determined as percentages.  Using this, we can see that 9/100 will result in .09 or 9%.

Properties of the fractional part of 11 can be seen to be a non-divisible number resulting in a repeating decimal equivalent.  So, 1/11 will result in .090909 ad infinitum.

Note, that odd divisors that are not multiples of 5, typically will result in a repeating decimal.

Cheers.

Answer:

2,3,5,6,8,9 (i think)

Step-by-step explanation:

Answer:

2,3,5,6,8,9

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

8 hours and 35 minutes can be rewritten as the mixed fraction 8 35/60.

You can reduce this fraction by dividing the numerator and denominator by 5.

35/5 = 7

60/5 = 12

So, 35/60 = 7/12

Now add 8 to your reduced fraction.

8 + 7/12 = 8 7/12

Hope this helped!

Answer:

1< and 2< are equal to 125

Step-by-step explanation:

The angle of a straight line is 180, so it would be 180° minus 55°, and that equals to 125°

Answer:

  x = 7

Step-by-step explanation:

The sum of the interior angles is 90°, so you have ...

  (7x +8) +(5x -2) = 90

  12x = 84 . . . . subtract 6; next, divide by 12

  x = 7

Answer:

87.48

Step-by-step explanation:

First find the area of the square

12^2=144

find area of the 2 circles

9*3.14

but theres 2

18*3.14=56.52

144-56.52=87.48

Hi there! :)

Answer:

[tex]\large\boxed {\frac{1}{4}}[/tex] Common difference

[tex]\large\boxed{\frac{3}{2}, \frac{7}{4}, 2}[/tex] Next three terms

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Find the common difference by subtracting the previous term from a term. We can use the terms 1/4 and 1/2:

Convert 1/2 into a fraction over 4:

1/2 · 2/2 = 2/4

Find the common difference by subtracting the fractions:

2/4 - 1/4 = 1/4. This is the common difference.

Find the next 3 terms by adding 1/4:

5/4 + 1/4 = 6/4 (Reduce fraction) = 3/2

6/4 + 1/4 = 7/4

7/4 + 1/4 = 8/4 (Reduce fraction)

Therefore, the next 3 terms are 3/2, 7/4 and 2.

Answer:−2=x that’s the answer

Answer:

The height of Ara's tree is 50/3 feet while Vartan's tree is 25/3 feet high

Step-by-step explanation:

Represent Ara's tree with A and Vartan's with V

Given

[tex]A = 2V[/tex]

[tex]A + V = 25[/tex]

Required

Determine A and V

[tex]A = 2V[/tex]

[tex]A + V = 25[/tex]

Substitute 2V for A in [tex]A + V = 25[/tex]

[tex]2V + V= 25[/tex]

[tex]3V = 25[/tex]

Divide both sides by 3

[tex]V =\frac{25}{3}\ feet[/tex]

Recall that [tex]A = 2V[/tex]

So:

[tex]A = 2 * \frac{25}{3}\ feet[/tex]

[tex]A = \frac{2 * 25}{3}\ feet[/tex]

[tex]A = \frac{50}{3}\ feet[/tex]

Hence, the height of Ara's tree is 50/3 feet while Vartan's tree is 25/3 feet high

Answer:

The number is 50.

Step-by-step explanation:

We need to understand the problem and convert it into a mathematical equation, or a series of equations. That way, we can solve them with ease.

The first thing we can do is to assign variables to represent the values that we do not know.

Let us assign the first number to be = x and the second number to be = y.

Important!

At this point, we must put their place values into consideration.

Since we are dealing with a two-digit number, we only have tens and units.

We will account for the place values of the variables assigned (x and y) by multiplying them by 10 and 1

x is the tens place value. To occupy this place value, it will become 10x

y is the unit place value. To occupy this place value, it will become 1 X y = y

This means that the original number is of the format x y

To convert this to an equation, it will become 10 (x) + y

Once the number order is reversed we will have 10 (x) + y = 10(y) + x - 45

grouping like terms

10x-x - 10y +y = - 45

9x -9y = - 45

From the second statement, we also have that x + y = 5

hence we have two equations x + y = 5   ---------- equation 1

                                                  9x -9y = - 45 ------------ equation 2

solving simultaneously, we have that the two numbers are 0 and 5

The number therefore, is 50

x = 5 and y = 0

Answer: Jayden walked 8 miles on Tuesday

Step-by-step explanation:

Answer:

(-1, 1)

Step-by-step explanation:

I used a graphing tool to graph the two lines. When graphed, the lines intercept at point (-1,1). Therefore, it is the solution to the system of equations.

Hope this helps.

Answer:

Problem 2:

4x - 20 = 4

4x = 24

x = 6

Step-by-step explanation:

Answer:

1/10x+3

Step-by-step explanation:

1/6(3/5x+18)

Multiply 3/5x and 18 by 1/6

1/10x+3

Answer:

is that all the context that is given?

Answer:

x=7

Step-by-step explanation:

4x-2(x+3)=8

4x-2x-6=8

2x-6+6=8+6

2x=14

x=7

Proof:

4x-2(x+3)=8

4(7)-2(7+3)=8

28-14-6=8

14-6=8

8=8

Hope this helps ;) ❤❤❤

The value of x in the equation 4x - 2(x+3) = 8 is 7.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

We need to find the value of x in the equation 4x - 2(x+3) = 8

4x-2(x+3)=8

4x-2x-6=8

2x-6+6=8+6

2x=14

x=7

Proof: 4x-2(x+3)=8

4(7)-2(7+3)=8

28-14-6=8

14-6=8

8=8

Hence, the value of x in the equation 4x - 2(x+3) = 8 is 7.

Learn more about equations here;

https://brainly.com/question/10413253

#SPJ2

Answer:

-infinity < x < +infinity

Step-by-step explanation:

the domain of a cube root function is the set of all real numbers. unlike a square root function which is limited to non-negative numbers, a cube root can use all real numbers because it is possible for three negatives to equal a negative.

Answer:

A

Step-by-step explanation:

Edge 2021

Answer:

[tex]\bold{cot(t) =\dfrac{12}{5}}[/tex]

Step-by-step explanation:

Given that:

[tex]Cosec (t) = -\frac{13}5[/tex]

for [tex]\pi < t < \frac{3 \pi}2[/tex]

That means, angle [tex]t[/tex] is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

[tex]cosec^2\theta -cot^2\theta =1[/tex]

here, [tex]\theta =t[/tex]

So, [tex]cosec^2t-cot^2t=1[/tex]

[tex]\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}[/tex]

But, angle [tex]t[/tex] is in 3rd quadrant, so value of

[tex]\bold{cot(t) =\dfrac{12}{5}}[/tex]

Answer:

12/5

Step-by-step explanation:

◈ LHS :

[tex]:\implies\tt\:sin60\degree[/tex]

[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]

◈ RHS :

[tex]:\implies\tt\:\dfrac{2tan30\degree}{1+tan^230\degree}[/tex]

[tex]:\implies\tt\:\dfrac{2\times \dfrac{1}{\sqrt{3}}}{1+{\large(}\dfrac{1}{{\sqrt{3}}}{\large)}^2}[/tex]

[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{3+1}[/tex]

[tex]:\implies\tt\:\dfrac{2}{\sqrt{3}}\times \dfrac{3}{4}[/tex]

[tex]:\implies\bf\:\dfrac{\sqrt{3}}{2}[/tex]

Hence Proved !!

Answer:

(4 * (1 + 2 * 3))^5

Step-by-step explanation:

Try many possibilites and see which one is greater.

The '5' should be an exponent, as it will make the result very large.

Multiplication is usually an operation that makes numbers very big.

Answer:

[tex]\Large \boxed{f(3)=11}[/tex]

Step-by-step explanation:

[tex]f(x)=2x+5[/tex]

For f(3), the input for the function f(x) is 3.

Let x (input) = 3.

[tex]f(3)=2(3)+5 \\\\ f(3)=6+5 \\\\ f(3)=11[/tex]

Answer:

11

Step-by-step explanation:

f(x)=2x+5

Let x = 3

f(3) = 2*3+5

     = 6+5

    = 11

Answer:

a. The given equation is d = -75·t + 275 is a function

b. f(t) = -75·t + 275

c.  275 km

d. The situation does not makes sense for t > 11/2 hours.

Step-by-step explanation:

a. Given that a relation is a functional relation if for each input of a member in the relation, there is only one output for the other member, therefore;

The given equation is d = -75·t + 275 is a function

As when t = 1, d = 200 km

b. The equation written in functional notation, f(t) is f(t) = -75·t + 275

c. At the start of the journey, t = 0

Therefore;

f(0) = -75×0 + 275 = 275 km

d. The values of t that do no make sense in the function are given as follows

0 = -75×t + 275

t = 275/75 = 11/3 = 3.67 hours

For times above 3.67, the distance becomes negative

Therefore, the situation does not makes sense for t > 11/2 hours.

Answer:

91 +3409/12500

Step-by-step explanation:

Did you mean simplify as a fraction?

Answer:

Step-by-step explanation:

[tex] \frac{3y - z}{y + 5z} [/tex]

To find the value of the expression when

y = 6 and when z = 2 , substitute the values into the above formula and solve.

That's

[tex] \frac{3(6) - 2}{6 + 5(2)} \\ = \frac{18 - 2}{6 + 10} \\ \frac{16}{16} [/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]\Huge \boxed{1}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{3y-z}{y+5z}[/tex]

Let y = 6 and z = 2.

[tex]\Rightarrow \displaystyle \frac{3(6)-2}{6+5(2)}[/tex]

Evaluate the expression.

[tex]\Rightarrow \displaystyle \frac{18-2}{6+10}[/tex]

[tex]\Rightarrow \displaystyle \frac{16}{16}[/tex]

[tex]\Rightarrow 1[/tex]

The value of the expression when y = 6 and z = 2 is 1.

I gave steps in the picture how to solve it was much easier to write it out then type it. hope this helps!

Greetings from Brasil...

Solving this equation

Answer:

Step-by-step explanation:

f(-7)= -3(-7)^2 - 20

f(-7) = -3(49) - 20

       = -147 - 20 = -167

Answer:

c.

Step-by-step explanation: