Identify one simple machine used at your home and explain how it makes your work easier​

Answer:

LED;

      The energy of photons emitted by an LED is dictated by the band gap of the semiconductor used – the energy required to make an electron–hole pair. When an electron and hole recombine in a radiative process, a photon carries away the extra energy.

BULB

        In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. ... 1, chemical potential energy is converted to electrical energy, which is immediately converted to light energy and heat energy

       This flow of charge converts chemical potential energy into electrical energy. In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. bulb have a fillament but LED have no filament they produce energy through clod process but bulb have a filament and they produce energy through hot process

Explanation:

This progression of charge changes over substance expected vitality into electrical vitality. In the light, the progression of charge through the fiber warms it up and makes it shine. Along these lines, the light believers electrical vitality to warm vitality and light vitality.

hope soo u can understand my point

Answer:

Magnitude of the acceleration(g) = 9.7 meters/second²

Explanation:

Given:

Height of tower = 56 meter

Time taken = 3.4 second

Final velocity (v) = 33 meters/second

Initial velocity (u) = 0 meters/second

Find:

Magnitude of the acceleration(g)

Computation:

Using first equation of motion:

v = u + at

Magnitude of the acceleration(g)

v = u + gt

33 = 0 + g(3.4)

g = 33 / 3.4

g = 9.7 meters/second²

Magnitude of the acceleration(g) = 9.7 meters/second²

Answer:

The answer to this should be: 5.0 x 10⁸ Hz

Explanation:

The speed, s, of a wave, equals the product of its frequency, ν, times its wavelength, λ:

s = νλ.

As the question states, the speed of an electromagnetic wave is a constant, c, equal to 3.0 × 10⁸ m/s.

Substituting this constant in the equation for the speed of the wave, you get:

c =  νλ.

From that equation, you can solve for the frequency to show the inverse realation of frequency and wavelength:

ν =  c / λ

Now, you just have to substitute values and compute, leaving you with:

5.0 x 10⁸ Hz

Answer:

Explanation:

The resistance of a material is expressed as R = ρL/A

Volume of the original material V = Area * Length = A*L

ρ is the resistivity of the material

R is the resistance

A is the cross sectional area

L is the length of the wire.

If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.

This means V = V₂

A*L = = A₂*L₂

A*L = A₂*(2 L)

A = 2 A₂

A₂ = A/2

The new resistance of the material Rf = ρL₂/A₂

R₂ = ρ(2 L)/(A/2)

Rf =  2ρL * 2/A

Rf = 4(ρL/A)

Since R = ρL/A

R₂ = 4R

Hence, the resistance of the stretched wire will be four times that of the original wire.

If the wire is stretched to twice its original length, the new resistance would be quadrupled.

The resistance (R) of a wire is given by:

[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]

Since the wire is stretched, the new length (L₁) is twice its original length, hence:

L₁ = 2L

An increase in length affects the area, the new area (A₁) is:

initial volume = volume after stretch

AL = A₁L₁

AL = A₁(2L)

A₁ = A/2

The resistance of the stretched wire (R₁) is:

[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]

Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.

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Answer:

Since gravitational potential is generally defined to be zero at infinity

and gravity does work as an object moves from infinity in a gravitational field,  

(the potential becomes more negative)  the farther the satellite is from the attractive force the greater is its gravitational potential. Since point E is most distant from the attractive force it has the most gravitational potential.

The Gravitational potential energy connected to a planet's position within the gravitational field of a central object, such as a star or a larger planet, is referred to as its gravitational energy.

The gravitational potential energy is given by:

PE = -G × (M × m) ÷ r

Here, (G) is the gravitational constant, (M) is the mass of a planet, (m)  is the mass of a planet, and distance (r).

From the given figure, points E and A are the farthest.

Hence, at points E and A satellite have the most gravitational potential energy

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Answer:

The jug drowns because the density of the jug is more than that of the density of water.

Answer:

it gets force upwards .

as there is presence of atmospheric pressure in it which causes upthrust and push upwards.

Answer:

Please INCLUDE a picture.

Explanation:

You did not include a picture, so there is no way to tell how the charges will interact with each other.

Please INCLUDE a picture.

The net force acting on q1 is 3.2 N to the right.

The force on q₁ due to q₂ is:

F1 = k * q₁ * q₂ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₂, which is 0.1 m

Plugging in the values, we get:

F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²

= 6.4 N

The force on q₁ due to q₃ is:

F₂ = k * q₁ * q₃ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₃, which is 0.2 m

Plugging in the values, we get:

F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²

= 16 N

The net force on q₁ is the sum of F₁ and F₂:

Fnet = F₁ + F₂

= 6.4 N + 16 N

= 22 N

The net force on q1 is to the right because both F₁ and F₂ are to the right.

Net electric field

The net electric field acting on q1 is 3.2 N/C to the right.

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Answer:

Zero

Explanation:

The magnetic field due to the first wire on the second wire with current i₁ in the first wire at a distance d from the second wire is B₁ = μ₀i₁/2πd.

The magnetic force due to this field on the second wire of length segment, L and current i₂ is F₁ = Bi₂L = (μ₀i₁/2πd)i₂L = μ₀i₁i₂L/2πd = F

The magnetic field due to the second wire on the first wire with current i₂ in the first wire at a distance d from the second wire is B₂ = μ₀i₂/2πd.

The magnetic force due to this field on the first wire of length segment, L and current i₁ is F₂ = Bi₁L = (μ₀i₂/2πd)i₁L = μ₀i₁i₂L/2πd = F

Since their magnetic fields are in opposite directions, according to the right hand rule, their forces would also be in opposite directions.

So F₁ = F and F₂ = -F

So their vector sum F₁ + F₂ = F +(-F) = F - F = 0

Answer:

A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.

Answer: A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc

Explanation:

Answer:

85.0 please I don't understand

Answer:

A.) H = 58.6 m

B.) T = 6.92 s

C.) 345.12 m

D.) V = 22.13 m/s

E.) Ø = 32.1 degree

Explanation:

Given that the

initial speed U = 60.3 m/s

Angle Ø = 34.2 degree

A.) At maximum height, final velocity V is equal to zero.

Using the third equation of motion under gravity.

V^2 = U sin Ø^2 - 2gH

Substitute for U and g. Where g = 9.8 m/s^2

0 = (60.3 sin 34.2)^2 - 2 × 9.8 × H

1148.78 = 19.6 H

H = 1148.78/19.6

H = 58.6 m

B.) To Determine the total time in the air, let us use the formula

V = UsinØ - gt

At maximum height, V = 0

t = UsinØ/g

Total time T = 2t

Therefore, T = 2UsinØ/g

T = (2 × 60.3 × sin 34.2)/9.8

T = 67.79/9.8

T = 6.92 s

C.) To determine the total horizontal distance covered which is the range, we will use second equation of motion.

S = UcosØT - 1/2gt^2

Where S = range R

g = 0, since the range is not a vertical distance

T = total time

Substitute all the parameters into the formula

R = 60.3 cos 34.2 × 6.92

R = 345.12 m

D.) After 1.2 s firing,

V = UsinØ - gt

Where t = 1.2 s

Substitute into the formula

V = 60.3 × sin34.2 - 9.8 × 1.2

V = 33.89 - 11.76

V = 22.13 m/s

Therefore the speed of the projectile 1.20 s after firing is 22.13 m/s

E.) The direction will be determined by using the formula

t = VsinØ/ g

Cross multiply

VsinØ = gt

Make SinØ the subject of formula

SinØ = gt/V

SinØ = (9.8×1.2)/22.13

Sin Ø = 11.76/22.13

Sin Ø = 0.53

Ø = sin^-1( 0.53 )

Ø = 32.1 degree

Answer:

You will fly forward in the bus until you hit something.

Explanation:

While standing there on the bus, you are traveling at the same speed as the bus. If the bus suddenly stops, you will still be traveling at the same speed you started with. That is until you hit something hard enough or big enough to stop you.

Answer:

You will fall towards the front of the bus i.e towards its front seat

Explanation:

When the bus is moving, you are supposed to be in that motion. Your body is experiencing a forward force as the bus is moving forward So when bus stops suddenly your inertia does not allow you to stay in that standing position it will let you move forrward to maintain your inertia so you will feel a forward push. (If you were sitting on a seat with seatbelt on you that seatbelt will make you come back when car or bus stops.)

Answer:

Explanation:

a. CH₄- Covalent bonding(ligação covalente)

b. SrO- ionic bonding (ligação iônica)

c. HBr- Polar Covalent bonding (ligação covalente polar)

d. NH₃ - covalent bonding(ligação covalente)

e. Cl₂O - Covalent bonding (ligação covalente)

f. Li₂O- ionic bonding (ligação iônica)

g. CO₂ - double covalent bonding (ligação covalente dupla)

h. MgCl₂- ionic bonding(ligação iônica)

Given that,

Eccentricity = 0.0086

Suppose, The length of half of the major axis is [tex]1\times10^{9}\ km[/tex]

We need to calculate the distance from the center to the foci

Using formula of eccentricity

[tex]e=\dfrac{c}{a}[/tex]

[tex]c=e\times a[/tex]

Where, e = eccentricity

a = major axis

c = the distance from the center to the foci

Put the value in to the formula

[tex]c=0.0086\times1\times10^{9}[/tex]

[tex]c=8600000[/tex]

We need to calculate the perihelion distance of Neptune from the sun

Using formula of distance

[tex]d=a-c[/tex]

Put the value into the formula

[tex]d=1\times10^{9}-0.0086\times10^{9}[/tex]

[tex]d=991400000\ km[/tex]

Hence, The perihelion distance of Neptune from the sun is 991400000 km.

Answer:

we have to measure distances and time, possibly with an automated system since the values ​​are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

        I = ∫ F dt = Δp

        F t = m [tex]v_{f}[/tex] - mv₀

In the exercise they indicate that the final speed is zero

         F t = - m v₀

         F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values ​​are very small

Answer:

The 5-number summary is

1. Median = 0.93 W/kg

2. Lower quartile = 0.69 W/kg

3. Upper quartile = 1.16 W/kg

4. Minimum value = 0.54 W/kg

5. Maximum value = 1.42 W/kg

Explanation:

We are given the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones.

1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57

What is 5-number summary?

A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.

These statistical characteristics are:    

1. Median

2. Lower quartile

3. Upper quartile  

4. Minimum value  

5. Maximum value  

1. Median:

Arrange the data in ascending order

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

(n+1)/2 gives the median value of the data set.

(11 + 1)/2 = 6th position

Therefore, 0.93 W/kg is the median of the data set.

2. Lower quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The lower quartile is the median of the lower half of the data set.

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

The median is 6/2 = 3rd position

Therefore, the lower quartile of the data set is 0.69 W/kg

3. Upper quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The upper quartile is the median of the lower half of the data set.

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The median is 6/2 = 3rd position

Therefore, the upper quartile of the data set is 1.16 W/kg

4. Minimum value:

The minimum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the minimum value of the data set is 0.54 W/kg

5. Maximum value  

The maximum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the maximum value of the data set is 1.42 W/kg

The box plot is illustrated in the attached diagram.

Answer:

D. the water's latent heat of vaporization is being pulled from the air.

Explanation:

A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.

In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.

Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.

The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.

The swamp coolers are typically made up of the following essential components, these are;

1. Float.

2. Blower.

3. Pump.

4. Evaporative pad.

5. Water supply valve.

Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.

Answer:

B and D

Explanation:

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

Answer:

Water is non-polar molecule False

Water is polar molecule because the electronegativity of Oxygen is much greater than electronegativity of hydrogen and it has also a bend shape that is why it is polar molecule.

Explanation:

I hope this will help you :)

False. Water is a polar molecule.

Water (H2O) consists of two hydrogen atoms and one oxygen atom. The oxygen atom has a higher electronegativity, meaning it attracts electrons more strongly than hydrogen.

As a result, the shared electrons in the covalent bonds between hydrogen and oxygen are pulled closer to the oxygen atom, creating an uneven distribution of charge.

This leads to a partial negative charge (δ-) on the oxygen atom and partial positive charges (δ+) on the hydrogen atoms, making water a polar molecule.

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Answer:

Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.

Explanation:

The dimension of relative density:-

Relative Density of a Substance (R.D.) = Substance Density / Water Density.

Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.

For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).

Tension:-   Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.

Answer:

people in urban areas strip the soil of nutrition and makes it difficult to grow crops. people of urban areas consume more energy,food,and water. people in urban areas remove minerals and metals from the ground so, urbanization is a contribution to pollution .

Explanation:

it may help you and give me brainliest

Answer:

pollution and loss of trees not to mention how much electricity we use which doesnt benefit the world.

Explanation: because when we urbanize things we get rid of natural resources around us

The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.

Explanation:

The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.

Since the net force acting on the sled is zero, the sled is in some state of equilibrium...

Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.

Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.

From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.

So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.

Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.

Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...

EXTRA

Given is that the sled is moving with a constant speed.

No imagine two situations and try to predict what will happen.... Here we go...

Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.

Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...

Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.

Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.

Answer:

yes

Explanation:

edg 2020

Answer:

most likely just 1

Explanation:

I sucked at sig figs in middle school, in fact it was the lowest test grade i ever received, but it is relatively simple.

because there is only one sig fig involved in each number, there can't be multiple sig figs here. 3000/500=6

500/3000=2(round up from 1.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666) you get the point.

Answer:

First Reaction:

[tex]^{234}U[/tex]  =>  [tex]^{230} Th + ^{4}He[/tex]

Second Reaction:

[tex]^{230} Th[/tex] => [tex]^{226} Ra + ^{4}He[/tex]

Combined Reaction:

[tex]^{234} U[/tex]  => [tex]^{226}Ra + 2( ^{4} He)[/tex]

Answer:

c i took the test

Explanation:

The total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.

The energy present in the wood change into other forms of energy such as heat and radiant energy. We know that during a reaction, matter is transformed into another form with the release of different types of energy.

So we can conclude that he total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.

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Answer:

The overall charge on the wall is zero.

Explanation:

Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.

Answer:

total number of modes is 8

Explanation:

attached here is the calculations

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

Answer:

Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]

Explanation:

Radius of the wire, a = 2.80 mm

Currents carried by each of the wires, i = 5.00 A

Center-to-Center Separation, W = 19.0 cm

The flux in the wires is given by the equation, ∅ = Li

The Net flux of the region between the wires  is given by the equation:

[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]

Divide both sides by l to get the net flux per unit length

[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]