Answer:
I believe it it is c
Explanation:
I dont knkw what els e to add so yea
A correct name for the following compound is:_________.a) 4-bromo-3,8-dimethylbicyclo[5.2.2]nonane b) 3,8-dimethyl-4-bromo-bicyclo[5.2.O)nonane c) 4-bromo-3,8-dimethylbicyclo[5.2.1]decane d) 7-bromo-2,6-dimethylbicyclo[5.2.0]nonane e) 4-bromo-3,8-dimethylbicyclo[5.2.0]nonane
Answer:
e) 4-bromo-3,8-dimethylbicyclo[5.2.0]nonane
Explanation:
The missing image of the the compound we are to name is attached below.
Before we can name an organic compound; It is crucial we know the guiding rules in naming them.
1. Select the longest continuous carbon chain as the root hydrocarbon and name according to the number of carbon atoms it contains, adding appropriate suffix to indicate the principal substituent group.
2. Number the carbon atoms in the root hydrocarbon from the end which gives the lowest number to the substituents.
3. If the same substituent is present two or more times in a molecule; the number of this substituent is indicated by the prefix di -(2), tri - (3) , tetra - (4) etc attached to the substituent name.
4. If there is more than one type of substituent in the molecule ; the substituents are named according to the alphabetical order but where there are mixed substituents ; the inorganic are named first.
5. In selecting and numbering the longest continuous chain, the functional groups are given preference over substituents., i.e the functional group is given the smallest possible number.
In the light of the above guiding rules; we were able to name the given compound because the compound contains nine carbons in the ring form which result to root name nonane. The two methyl are on the third and eight carbon; bromine is on the fourth carbon ; there are two cyclic ring present in the compound where we have 5 carbons in one structure, another 2 carbons in the second structure and zero carbon in the bridge structure which eventually result to the correct name:
4-bromo-3,8-dimethylbicyclo[5.2.0]nonane
Elvira Walks 4 miles to the west from school and stops at the store. She then walks 3 miles south.
What is the Distance and the displacement?
Answer:
distance = 7 miles
displacement = 5 miles
Explanation:
Distance is a scalar quantity as it takes account of magnitude traveled but not the direction traveled from starting point.
The distance traveled is the sum total of distances moved
distance = 4 + 3 = 7 miles
Displacement however, is a vector and measure the shortest possible distance traveled in a given direction from the starting point.
The path of Elvis' walking forms a right-angle triangle with the hypotenuse being the displacement and the other two sides being the distance traveled west and south.
Using Pythagoras' theorem; c² = a² + b²
where c = hypotenuse and a and b are the other two sides
c² = 4² + 3²
c² = 16 + 9 = 25
√c² = √25
c = 5
Therefore, displacement = 5 miles
A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to reach the equivalence point, then what is the molarity of the borax solution
Answer:
The concentration of the borax solution is 0.1066 M
Explanation:
Step 1: Dtaa given
Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L
Molarity of H2SO4 = 1.03 M
Volume of the H2SO4 = 2.07 mL = 0.00207 L
Step 2: The balanced equation
Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O
Step 3: Calculate molarity of borax solution
b*Ca*Va = a * Cb*Vb
⇒with B = the coefficient of H2SO4 = 1
⇒with Ca = the concentration of borax = TO BE DETERMINED
⇒with Va = the volume of borax = 0.020 L
⇒with a = the coefficient of borax = 1
⇒with Cb = the concentration of H2SO4 = 1.03 M
⇒with Vb = the volume of H2SO4 = 0.00207 L
Ca*0.020 L = 1.03 M * 0.00207 L
Ca = (1.03 * 0.00207) / 0.020
Ca = 0.1066 M
The concentration of the borax solution is 0.1066 M
A chemistry student weighs out of ascorbic acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with solution. Calculate the volume of solution the student will need to add to reach the final equivalence point. Round your answer to significant digits.
Answer:
14.3 mL
Explanation:
Assume the student used 0.113 g ascorbic acid and 0.0900 mol·L⁻¹ NaOH.
1. Balanced chemical equation.
The formula of ascorbic acid is H₂C₆H₆O₆ (MM = 176.12 g/mol).
However, for the balanced equation, let's write it as H₂A.
[tex]\rm H_{2}A + 2NaOH \longrightarrow Na_{2}A + 2H_{2}O[/tex]
2. Moles of ascorbic acid
[tex]\text{Moles of H$_{2}$A} =\text{0.113 g H$_{2}$A} \times \dfrac{\text{1 mmol H$_{2}$A}}{\text{0.176 12 mg H$_{2}$}A} = \text{0.6416 mmol H$_{2}$A}[/tex]
3. Moles of NaOH
The molar ratio is 2 mmol NaOH:1 mmol H₂A.
[tex]\text{Moles of NaOH}= \text{0.6416 mmol H$_{2}$A} \times \dfrac{\text{2 mmol NaOH}}{\text{1 mmol H$_{2}$A}} =\text{1.283 mmol NaOH}[/tex]
4. Volume of NaOH
[tex]V = \text{1.283 mmol NaOH}\times \dfrac{\text{1 mL NaOH}}{\text{0.0900 mmol NaOH}} = \textbf{14.3 mL NaOH}\\\\\text{The student will need $\large \boxed{\textbf{14.3 mL NaOH}}$}[/tex]
c) What is the pH of the buffer system in part a when 0.030 moles of strong acid are added (without a change in volume)
Answer:
remain the same
Explanation:
The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. What is the final level of the electron?(c=3.00×10^8m/s, h=6.63×10^-34 J·s, RH=2.179×106-18J)a. 5
b. 6
c. 8
d. 9
e. 1
Explanation:
It is given that,
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,
[tex]n_i=8[/tex]
[tex]\lambda=3745\ nm[/tex]
The amount of energy change during the transition is given by :
[tex]\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}][/tex]
And
[tex]\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}][/tex]
Plugging all the values we get :
[tex]\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5[/tex]
So, the final level of the electron is 5.
For the reaction of nitrogen gas and hydrogen gas to make methane, describe FOUR stresses that would shift the equilibrium to the left toward the reactants? N2(g) + 3 H2(g) ⇌ 2 NH3(g) + Energy
Answer:
- Addition of NH₃(g)
- Removal of N₂(g)
- Increase of temperature
- Pressure decrease
Explanation:
According to Le Chatelier's principle, if we apply an stress to a reaction at equilibrium, the system will try to shift the equilibrium in order to decrease the stress. If we add reactants, the equilibrium will shift toward the formation of more products (to the consumption of reactants) and vice versa.
The stresses we can apply to this equilibrium are the following:
- Addition of NH₃(g) : it is a product, thus its addition will result in a shift toward reactants.
- Removal of N₂(g): it is a reactant, thus its removal from the reaction mixture will result in a shift toward reactants.
- Increase of temperature: the reaction is exothermic, so it releases energy. Energy is a product. If we add energy (increase the temperature), we are adding a product, so the equilibrium will shift toward the reactants.
- Pressure decrease: because both reactants and products are in the gas phase. A decrease in pressure shifts an equilibrium to the side of the reaction with greater number of moles of gas. In this case, the reactants side has greater number of moles of gas (1 mol + 3 moles= 4 moles) than the products side (2 moles). Thus, the equilibrum will shift toward reactants.
9. In a certain chemical reaction, 2 hydrogen chloride molecules in aqueous solution react with solid zinc. The reaction produces zinc
chloride in aqueous solution and hydrogen gas. Which of the following reaction equations correctly describes this reaction?
A. 2HCI (g) + 2Zn (s) - 2ZnCl2 (s) + H2 (9)
B. HCI (aq) + 2Zn (s) - 2ZnCl (aq) + H2 (9)
C. 2HCl (aq) + Zn (s) → ZnCl2 (aq) + H2 (g)
D. HCI (aq) + Zn (s) Zn,Cl (aq) + 2H2 (1)
Answer: [tex]2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.
In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.
A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution.
The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Gases are represented by (g) after their chemical formulas.
Thus 2 hydrogen chloride molecules in aqueous solution react with solid zinc. The reaction produces zinc chloride in aqueous solution and hydrogen gas is represented as :
[tex]2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
A volume of 0.800 L of a 2 x 10–4 M Ba(NO3)2 solution is added to 0.200 L of 5 x 10–4 M Li2SO4. Does BaSO4 precipitate? Explain your answer
Answer:
The BaSO₄ precipitates as a solid.
Explanation:
In order to determine the precipitation, we need to look at the reactants, we have: Ba(NO₃)₂ and Li₂SO₄
Salts from nitrate are all soluble and sulfates can make precipitate if they react to elements from group 2. (Solubility rules) So this reaction, has a precipitate but we can predict it, if we look at the reaction and we take acount the Kps:
Ba(NO₃)₂ (aq) + Li₂SO₄ (aq) → 2LiNO₃ (aq) + BaSO₄ (s) ↓
Let's find out the moles of each ion:
Ba(NO₃)₂ (aq) → Ba²⁺ (aq) + 2NO₃⁻ (aq)
0.8 L . 0.0002 M = 1.6×10⁻⁴ moles. These are the moles of Ba²⁺ in 1 L of solution, so [Ba²⁺] = 1.6×10⁻⁴ M
Li₂SO₄ (aq) → 2Li⁺ (aq) + SO₄⁻² (aq)
0.2 L . 0.0005 M = 1×10⁻⁴ M. These are the moles of sulfate, in 1 L of solution so [SO₄⁻²] = 1×10⁻⁴ M
BaSO₄ (s) ⇆ Ba²⁺ (aq) + SO₄⁻² (aq) Kps = 1.08×10⁻¹⁰
We need to compare Kps to [ Ba²⁺] . [SO₄⁻²]
[ Ba²⁺] . [SO₄⁻²] = 1.6 ×10⁻⁸ > Kps → Precipitate.
If [Ba²⁺] . [SO₄⁻²] = Kps → Solution is saturated
If [ Ba²⁺] . [SO₄⁻²] < Kps → There is no precipitate formed, or if it is formed, it will be quickly dissolved to reach saturation.
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr3+(aq) + Pb(s)2Cr2+(aq) + Pb2+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: G° for this reaction would be _________ than zero. Submit AnswerRetry Entire Group
Answer:
3.47 ×10^-10
Explanation:
The equation of the reaction is 2Cr3+(aq) + Pb(s)------->2Cr2+(aq) + Pb2+(aq)
A total of two moles of electrons were transferred in the process. The chromium was reduced while the lead was oxidized. Hence the lead species will constitute the oxidation half equation and the chromium will constitute the reduction half equation.
E°cell = E°cathode - E°anode
E°cathode = -0.41 V
E°anode = -0.13 V
E°cell = -0.41 -(-0.13) = -0.28 V
From
E°cell = 0.0592/n log K
n= 2, K= the unknown
-0.28 = 0.0592/2 log K
log K = -0.28/0.0296
log K = -9.4595
K = Antilog ( -9.4595)
K= 3.47 ×10^-10
Balance the chemical equation
Fe2O3 (s) + CO (g) 2 Fe(s) + CO2 (g)
Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer:
[tex]Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2[/tex]
Explanation:
[tex]Fe_2O_3+CO\Rightarrow \:2Fe+CO_2\\\\Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2[/tex]
Best Regards!
A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate minerals. If it undergoes lots of chemical weathering, which sand grains will be quickly chemically weathered away?
a. Calcite
b. ferromagnesian silicate minerals
c. non-ferromagnesian silicate minerals
The sand that grained will be quickly chemically weathered away should be option b. ferromagnesian silicate minerals.
What are ferromagnesian silicate minerals?It should be considered as the Silicate minerals where cations of iron and the form of magnesium should be important for the chemical components. It is used for covering up the minerals. Also, calcite should be normal weather via the solution process so it required a lot of water that contains a high amount of carbonic acid.
Hence, the correct option is b.
Learn more about mineral here: https://brainly.com/question/20772787
4. The pH of an aqueous solution is determined to be 1.50.
Calculate the hydronium ion concentration.
b. Calculate the hydroxide ion concentration.
-lg[H+]=1.5
which means that [H+]=0.03M
pOH=14-pH=14-1.5=12.5
-lg[H+]=1.5
which means that [H+]=0.03M
pOH=14-pH=14-1.5=12.5
the hydroxide ion concentration. is 12.5.
How do you find hydronium ion concentration when given pH?The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH) Example: What is the hydronium ion concentration in a solution that has a pH of 8.34? On a calculator, calculate 10-8.34, or "inverse" log ( - 8.34).
What is the pH of a solution that has a hydronium ion concentration of 0.025 M?For a 0.025 M HCl solution the concentration of the hydrogen ions, [H+] , is 0.025 moles/liter (i.e. 0.025 M). pH is defined as −log[H+] . Substituting 0.025 into the equation for pH we find that the 0.025 M HCl solution has a pH of -log(0.025) = 1.60.
Learn more about hydronium ion concentration at
https://brainly.com/question/27586088
#SPJ2
Write a net ionic equation to show that benzoic acid, C6H5COOH, behaves as a Brønsted-Lowry acid in water.
Answer:
H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)
Explanation:
According to Brönsted-Lowry acid-base theory, an acid is a substance that donates H⁺. Let's consider the molecular equation showing that benzoic acid is a Brönsted-Lowry acid.
C₆H₅COOH(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)
The complete ionic equation includes all the ions and molecular species.
C₆H₅COO⁻(aq) + H⁺(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)
Why at night, under the mercury or sodium vapor lights in a mall parking lot, do cars seem to be peculiar colors?
Answer:
Here's what I find
Explanation:
Sodium vapour produces mostly yellow light.
Mercury vapour produces mostly blue light.
A white car reflects all colours back to our eyes.
A coloured car, say green, absorbs all the other colours and reflects the green.
Under a sodium light, a white or a yellow car will appear yellow. A red car will be nearly black because there is no red light to reflect.
Under a mercury light, a white or a blue car will appear blue. A yellow car will be quite dark, but there will be a yellowish tinge because there is some yellow in the Hg spectrum for it to reflect.
The picture below shows a red car and a black car under sodium light. Can you tell which is which?
8. A 25.0 mL sample of an H2SO4 solution is titrated with a 0.186 M NaOH solution. The equivalence point is reached with 12.9 mL of base. The concentration of H2SO4 is ________ M. (Hint: write a balanced chemical equation first!)
Answer:
0.0480 M
Explanation:
The reaction is ...
H₂SO₄ + 2NaOH ⇒ Na₂SO₄ +2H₂O
That is, 2 moles of NaOH react with each mole of H₂SO₄. Then the molarity of the H₂SO₄ is ...
moles/liter = (0.186 M/2)(12.9 mL)/(25.0 mL) ≈ 0.0480 M
A chemistry student weighs out of hypochlorous acid into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Round your answer to significant digits.
Answer:
Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.
A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.
Explanation:
1 mole HClO = 74.44g
0.0941g = [tex]\frac{0.0941}{74.44}[/tex] = 0.00126 moles
Concentration = no. of moles/volume in L
Hence, Concentration of HClO = 0.00126/ 0.250L
= 0.005M.
C1V1 =C2V2
0.005 × 250 mL = 0.2 × V2
Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.
which process is used to produce gases from solutions of salts dissolved in water or another liquid?
A.Electrolysis
B.Metallic bonding
C.Ionic bonding
D. Polar covalent bonding
Answer:
A.Electrolysis
Explanation:
A.Electrolysis
For example, electrolysis of solution of NaCl in water gives H2 and O2.
What is the name of CaCl2 7H2o
Answer:
calcium chloride dihydrate
The reduction of iron(III) oxide to iron metal is an endothermic process: Fe2O3(s) + 2 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = +26.3 kJ How many kilojoules of energy are required to produce 1.00 kilogram of iron metal?
Answer: Thus 234 kJ of energy are required to produce 1.00 kilogram of iron metal
Explanation:
To calculate the number of moles , we use the equation:
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
Putting values , we get:
[tex]\text{Moles of iron}=\frac{1000g}{56g/mol}=17.8moles[/tex] (1.00kg=1000g)
The balanced chemical reaction is:
[tex]Fe_2O_3(s)+2CO(g)\rightarrow 2Fe(s)+3CO_2(g)[/tex] [tex]\Delta H=+26.3kJ[/tex]
Given :
Energy released when 2 moles of [tex]Fe[/tex] is produced = 26.3 kJ
Thus Energy released when 17.8 moles of [tex]Fe[/tex] is produced =
= [tex]\frac{26.3kJ}{2}\times 17.8=234kJ[/tex]
Thus 234 kJ of energy are required to produce 1.00 kilogram of iron metal
An atom of element number 33 (As) is in its ground electronic state. Which one of the following sets quantum numbers could not apply to any of its electrons?
A) n=2 l=1 ml= -1 ms= 1/2
B) n=3 l=0 ml=0 ms= -1/2
C) n=3 l=2 ml=-2 ms= -1/2
D) n=4 l=0 ml=0 ms= -1/2
E) n=4 l=2 ml=1 ms= 1/2
Answer:
E) n=4 l=2 ml=1 ms= 1/2
Explanation:
Arsenic is a member of group 15 in the periodic table. Its electronic configuration is;
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3. Its condensed electronic configuration can be written as [Ar]4s2 3d10 4p3. This electronic configuration shown here can now enable us to consider each option given in the question in order to meaningfully arrive at a logical answer.
If we look at option E, the data given for that electron is; n=4 l=2 ml=1 ms= 1/2. This refers to an electron in a 4d orbital. In the ground state configuration of arsenic shown above, there is no 4d orbital, hence option E must be the correct answer.
Is carbon or oxygen more electronegative?
Answer:
Oxygen is more electronegative than carbon.
Explanation:
Electronegativity increases from left to right across the periodic table. Since oxygen is further right than carbon, it is more electronegative. Also, if you look at a chart of electronegativity, oxygen has an electronegativity of 3.44 while carbon has an electronegativity of 2.55.
So oxygen is more electronegative than carbon. Hope this helps.
where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells. Use the rules for determining electron configurations to write the electron configuration for Ca. Express your answer in complete form in order of orbital filling. For example, 1s22s2 should be entered as 1s^22s^2.
Answer: [tex]1s^22s^22p^63s^23p^64s^2[/tex]
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.
The electrons are filled according to Afbau's rule in order of increasing energies where orbital with higher value of (n+l) has higher energy as compared to orbital having lower (n+l) value. Thus the electronic configuration for calcium with atomic number of 20 and hence containing 20 electrons is :
[tex]Ca:20:1s^22s^22p^63s^23p^64s^2[/tex]
For this assignment, the target compound that you should synthesize is 1-methyl-4-nitro-benzene. This is an electrophilic aromatic substitution reaction. Examine the product carefully and determine the substitution pattern. Which group will already be present in the substrate? Keep in mind the mechanism and how that will control the selectivity of the process. Remember, you can easily separate ortho and para isomers.
Answer:
The methyl group will already be present
Explanation:
You want to make 1-methyl-4-nitrobenzene.
The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"
The methyl group is activating and ortho, para directing.
The nitro group is deactivating and meta directing.
You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g) Complete the following table
Answer:
1. 0.421 g (C₄H₁₀), 1.51 g (O₂), 1.28 g (CO₂), 0.653 g (H₂O)
2. 4.92 g (C₄H₁₀), 17.6 g (O₂), 14.9 g (CO₂), 7.63 g (H₂O)
3. 6.63 g (C₄H₁₀), 23.7 g (O₂), 20.12 g (CO₂), 10.3 g (H₂O)
4. 7.12 g (C₄H₁₀), 12.1 g (O₂), 10.2 g (CO₂), 8.84 g (H₂O)
5. 252 mg (C₄H₁₀), 903 mg (O₂), 763 mg (CO₂), 390 mg (H₂O)
6. 65 mg (C₄H₁₀), 234 mg (O₂), 198 mg (CO₂), 101 mg (H₂O)
Explanation:
1. First of all, we determine the moles of each reactant.
For the first case:
1.51 g . 1 mol/32 g = 0.0472 moles
Ratio is 13:2, 13 moles of oxygen needs 2 moles of C₄H₁₀ for the combustion,
Therefore 0.0472 mol will react with (0.0472 . 2)/13 = 7.26×10⁻³ mol.
Now we convert the moles to mass:
7.26×10⁻³ mol . 58 g/ 1mol = 0.421 g
Now we use stoichiometry to find the mass of the products.
Ratio is 13:8:10.
13 moles of oxygen can produce 8 moles of CO₂ and 10 moles of water
Then, 0.0472 mol would produce:
(0.0472 . 8)/13 = 0.0290 mol
We convert the moles to mass → 0.0290 mol . 44g /mol = 1.28 g
(0.0472 . 10)/13 = 0.0363 mol
We convert the moles to mass → 0.0363 mol . 18 g /1mol = 0.653 g
2. 4.92 g / 58 g/mol = 0.0848 moles of C₄H₁₀
2 moles of C₄H₁₀ react with 13 moles of O₂
So, 0.0848 moles will react with (0.0848 . 13) / 2 = 0.551 moles
We convert to mass: 0.551 mol . 32 g /mol = 17.6 g
Now we use stoichiometry to find the mass of the products.
Ratio is 13:8:10.
0.551 moles of O₂ will produce:
(0.551 . 8)/13 = 0.339 mol of CO₂
We convert to mass: 0.339 mol . 44g / mol = 14.9 g
(0.551 . 10)/13 = 0.424 mol of H₂O
0.424 mol . 18 g /mol = 7.63 g
3. In this case, we have the mass of one of the product
20.12 g . 1mol / 44 g = 0.457 moles of CO₂
According to stoichiometry:
8 moles of CO₂ are produced by the reaction of 13 moles of O₂ and 2 moles of C₄H₁₀
Then, 0.457 moles of CO₂ would be produced by:
(0.457 . 13)/ 8 = 0.743 moles of O₂
We convert to mass: 0.743 mol . 32 g/1mol = 23.7 g
(0.457 . 2)/8 = 0.114 moles of C₄H₁₀
We convert to mass: 0.114 mol . 58g/mol = 6.63g
Now we can determine, the mass of produced water:
(0.743 . 10)/13 = 0.571 mol of H₂O . 18g /mol = 10.3 g
4. We convert the moles of water:
8.84 g / 18g/mol = 0.491 moles
According to stoichiometry: 10 moles of water are produced by 13 moles of O₂ and 2 moles of C₄H₁₀
Then 0.491 moles will be produced by:
(0.491 . 10)/ 13 = 0.378 moles of O₂
We convert to mass: 0.378 mol . 32 g/1mol = 12.1 g
(0.491 . 2)/8 = 0.123 moles of C₄H₁₀
We convert to mass: 0.123 mol . 58g/mol = 7.12g
Now we can determine, the mass of produced carbon dioxide:
(0.378 . 8)/13 = 0.232 mol of CO₂ . 44g /mol = 10.2 g
5. Mass of mg, must be converted to grams
252 mg . 1 g/1000 mg = 0.252 g
It is the same as 2.
0.252 g of C₄H₁₀ . 1mol/58 g = 4.34×10⁻³ mol
2 mol of C₄H₁₀ react to 13 moles of O₂ then,
4.34×10⁻³ mol will react with (4.34×10⁻³ mol . 13) / 2 = 0.0282 mol
We convert the grams → 0.0282 mol . 32 g/mol = 0.903 g (903 mg)
0.0282 mol of oxygen will produced:
(0.0282 . 8)/13 = 0.0173 mol of CO₂
We convert to mass: 0.0173 mol . 44g / mol = 0.763 g (763 mg)
(0.0282 . 10)/13 = 0.0217 mol of H₂O
0.0217 mol . 18 g /mol = 0.390 g (390 mg)
6. We define the mass of CO₂ → 198 mg . 1g/1000 mg = 0.198 g
0.198 g / 44g/mol = 4.5×10⁻³ moles of CO₂
According to stoichiometry:
8 moles of CO₂ are produced by the reaction of 13 moles of O₂ and 2 moles of C₄H₁₀
Then, 4.5×10⁻³ moles of CO₂ would be produced by:
(4.5×10⁻³ . 13)/ 8 = 7.31×10⁻³ moles of O₂
We convert to mass: 7.31×10⁻³ . 32 g/1mol = 0.234 g (234 mg)
(4.5×10⁻³ . 2)/8 = 1.125×10⁻³ moles of C₄H₁₀
We convert to mass: 1.125×10⁻³ mol . 58g/mol = 0.065 g (65 mg)
Now we can determine, the mass of produced water:
(7.31×10⁻³ . 10)/13 = 5.62×10⁻³ mol of H₂O . 18g /mol = 0.101 g (101 mg)
Which best describes the relationship between heat internal energy, and thermal energy?
O Internal energy is heat that flows, and heat is the part of thermal energy that can be transferred.
O Internal energy is thermal energy that flows, and thermal energy is the part of heat that can be transferred.
O Thermal energy is heat that flows, and heat is the part of internal energy that can be transferred.
O Heat is thermal energy that flows, and thermal energy is the part of internal energy that can be transferred.
Answer:
Heat is thermal energy that flows, and thermal energy is the part of internal energy that can be transferred
Explanation:
Aqueous solutions of sodium sulfate and potassium chloride are mixed. What is the precipitate and how many molecules are formed?
Answer:
The two products of this reaction, Sodium Chloride and Potassium Sulfate, are both soluble in water, hence, there's no precipitate formed from this reaction.
Explanation:
Sodium sulfate is Na₂So₄
Potassium Chloride is KCl
When they both react, theres a double displacement where ions and radicals are exchanged
Na₂SO₄ + KCl → NaCl + K₂SO₄
The products are
NaCl - Sodium Chloride
K₂SO₄ - Potassium Sulfate
The two products are soluble in water, hence, there's no precipitate formed from this reaction.
And we would need numerical values of the number of moles of the two reactants mixed to obtain the number of moles of products formed and then the number of molecules from Avogadro's constant.
Hope this Helps!!!
the iupac name of the compound
Answer:
3-Pentyn-1-ol
Explanation:
tripple bond is at 3 postion from alochol
carbon are 5 atoms so pent
yn becauese its alkyne
Why can liquids change shape but solids cannot
Answer:
Explanation:
the forces between the molecules are stronger in solid than in liquids
A student mixed 115 g of sugar, 350 g of water and 5 g of spices. What will be the mass of the solution?
these are the options
470g
465g
350g
120g
Answer:
[tex]m_{solution}=470g[/tex]
Explanation:
Hello,
In this case, a solution is formed when a solute is completely dissolved in a solvent, thus, for this situation, the sugar is the solute and the water the solvent but in addition to them we find spices which are also considered in the total mass of the solution. In such a way, for computing the total mass we must add the mass of three constituents (115 g sugar, 350 g water and 5 g spices) as shown below:
[tex]m_{solution}=115g+350g+5g\\\\m_{solution}=470g[/tex]
Best regards.