I will give extra points please help

Answer:

[tex]f^{-1}[/tex](x)=2x+10

Step-by-step explanation:

f(x)=[tex]\frac{x}{2}[/tex]-5

Let y= [tex]\frac{x}{2}[/tex]-5

y= [tex]\frac{y}{2}[/tex]-5

x+5= [tex]\frac{y}{2}[/tex]

Both side multiple 2,

2x+10=y

[tex]f^{-1}[/tex](x)=2x+10

Answer:

78.5

Step-by-step explanation:

Answer:

z > 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

15.6 < 2.7(z - 1) - 0.6

Step 2: Solve for z

Here we see that any value z greater than 7 would work as a solution to the inequality.

Answer:

7x²(3x-7)

Step-by-step explanation:

21x³ - 49x²

7(3x³ - 7x²)

7x²(3x - 7)

Answer:

(22,0)

Step-by-step explanation:

y=mx+b

y=-2/3x+44/3

0=-2x/3+44/3

x=22

(22,0)

Answer:

250

Step-by-step explanation:

Answer:

82.5 is the right answer

Answer:

x = 0.99

x will equal 0.99. Have a good day.

Answer:

The perimeter of the given parallelogram increases to four times the current value

Step-by-step explanation:

The given dimensions of the parallelogram are 8 cm by 10 cm

Therefore, the perimeter of the given parallelogram, 'P₁', is found as follows;

P₁ = 2 × 8 cm + 2 × 10 cm = 16 cm + 20 cm = 36 cm

The perimeter of the given parallelogram, P₁ = 36 cm

When each side of the parallelogram are multiplied by 4, we get;

The new sides of the parallelogram = 4 × 8 cm = 32 cm and 4 × 10 cn = 40 cm

The new perimeter of the parallelogram, P₂ = 2 ×32 cm + 2 × 40 cm = 144 cm

Therefore, the perimeter, P₂ is P₂/P₁ times larger than the perimeter P₁

P₂  = (144 cm)/(36 cm) × P₁

∴  P₂  = 4 × P₁

The change in the perimeter after multiplying each side of the given parallelogram by 4 is that the perimeter of the given parallelogram increases to four times the current value

Answer:

3,825 y³

Step-by-step explanation:

Answer:

What is the length of EF? 28

What is the measure of D? 47 degrees

This question is incomplete, the complete question is;

4. A scale measuring trust inthe media was administered to a random sample of 114 Democrats and 112 Republicans. The researcher finds that Democrats average a score of 8.5 on this scale, while Republicans average a score of 7.8. Together the Democrats and Republicans have a pooled standard error of .32. Is there a statistically significant difference between Democrats and Republicans in their level of trust in the media (at the alpha = .05 level )

Answer:

p-value 0.0297

Hence, p value ( 0.0297 ) is LESS THAN ∝ ( 0.05 )

Therefore, this is sufficient evidence to conclude that there is difference between Democrats and Republicans in their level of trust in the media.

Step-by-step explanation:

Given the data in the question;

H₀ : u₁ = u₂

Hₐ : u₁ ≠ u²

test statistics

t = x - u / s

we substitute

t = ( 8.5 - 7.8 ) / 0.32

t = 0.7 / 0.32

t = 2.1875

∝ = 0.05

degree of freedom = n₁ + n₂ - 2 = 114 + 112 - 2 = 224

so

{t[tex]_{\alpha /2[/tex], [tex]_{df[/tex] } =  {t[tex]_{0.025[/tex], [tex]_{224[/tex] } = 1971

p-value = 0.02974

p-value 0.0297

Hence, p value ( 0.0297 ) is LESS THAN ∝ ( 0.05 )

Therefore, this is sufficient evidence to conclude that there is difference between Democrats and Republicans in their level of trust in the media.

Answer:

4x3x2x1=24

Step-by-step explanation:

Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

[tex]P(A) = \frac{9}{92}[/tex]

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

[tex]P(B) = \frac{10}{91}[/tex]

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

[tex]P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108[/tex]

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Answer:

B. Yes! Jason has printed 73/100 of the posters needed.

Step-by-step explanation:

7/10(1500) = 1050 minimum to print

1500-400 = 1100 printed

1100/1500 = 73/100

He ate 1/2 of the carrot

---

hope it helps

sorry if it doesn't

Answer:

9,2 and 2,9

Step-by-step explanation:

x+y=11

xy=18

Since they are asking for integers you can simply look through and see what integers multiply out to 18 and then check if they add up to 11. The answers for x and y are 9 and 2. but 9 can be for y as well and 2 can be for x.

How to solve it algebraically

18/y=x

x+y=11(insert 18/y for x)

18/y+y=11(factor it)

(y^2+18)/y=11(multiply both sides by y)

y^2+18=11y (subtract both sides by 11y)

y^2-11y+18=0

complete the square

y^2-11y    = -18

(-11/2)^2=121/4 (add in on both sides)

y^2-11y+121/4=49/4

(y-11/2)^2=49/4 (square root both sides)

y-11/2=±7/2

y=11/2±7/2

y=9 or y=2

so

x=9 or x=2

Hope this helps :)

Please give brainliest

The size he should bring more of is small and is denoted as option C.

This is a term which refers to the number of goods sold within a given period of time.

Given that, a vendor is thinking about changing the number of sweatshirts he brings to an event.

To make sure he doesn't run out, he plans to bring more of the size most likely to be sold.

we need to determine that which size should he bring more of,

So, here according to the table,

Small size has the smallest remaining which is 9 when the difference between the number sold and number put up for sale is calculated.

This is therefore why bringing more of small size will ensure he doesn't run out of stock in the next event as more people prefer it.

Hence, the size he should bring more of is small and is denoted as option C.

Read more about Sales here,

brainly.com/question/24951536

#SPJ7

Answer:

Step-by-step explanation:

1.5 rounded to the nearest tenths

Answer:

h(-3) = -27

Step-by-step explanation:

Given that,

[tex]h(x)=-2x^{(2)}+3x[/tex]

We need to find the value of h(-3).

Put x = -3 in the given expression.

[tex]h(-3)=-2(-3)^{(2)}+3(-3)\\\\=-2\times 9-9\\\\=-27[/tex]

So, the value of h(-3) is equal to -27.

Answer:

either 7 and 21 or 1 and 3 I believe I'm terribly sorry if I'm wrong friend

Answer:

Terrence spend more time walking his dog .

Step-by-step explanation:

3/5 = 0.6

1/3 = 0.333

0.6>0.333

Answer:

Number (n)

Cubes (n3)

1-1

2-8

3-27

4-64

5-125

6-216

7-343

8-512

9-729

10-1000

Step-by-step explanation:

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time [tex]t[/tex]

At [tex]t=0, the weight of the bucket is 6+36=42 \mathrm{lb}[/tex]

After [tex]t[/tex] seconds, the weight of the bucket is [tex]42-0.15 t \mathrm{lb}[/tex]

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after [tex]t[/tex] seconds is [tex]x=1.5 t[/tex]

Since the well is 80 ft deep, the time to pull out the bucket is [tex]\frac{80}{2}=40 \mathrm{~s}[/tex]

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

[tex]W=\int_{t=0}^{t=36} F d x[/tex]

Use [tex]x=1.5 t[/tex] and [tex]F=42-0.15 t[/tex]

[tex]W=\int_{0}^{36}(42-0.15 t)(1.5 d t)[/tex]

[tex]=\int_{0}^{36} 63-0.225 t d t[/tex]

[tex]=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}[/tex]

[tex]=\left[63 t-0.2 t^{2}\right]_{0}^{36}[/tex]

[tex]W=3200 \mathrm{ft} \cdot \mathrm{lb}[/tex]

Answer:

46.091 m

Step-by-step explanation:

Given that

Height of the range finder, = 496 feet

Angle of elevation, θ = 0.875 Rad = 50°

Velocity of increment, = 0.225 rad/min

For starters, we try and assume that it all takes place in a triangular shape. Using Pythagoras theorem, we then know that

Tanθ = y / 496

y = 496 tanθ

On differentiating, we have

dy/dt = 496 sec²θ

dy/dt = 496 * 0.413 * de/df

dy/dt = 204.848 * de/df

dy/dt = 204.848 * 0.225

dy/dt = 46.091 m

Answer:

7,4

Step-by-step explanation:

Answer:

[tex]Probability = \frac{243}{1024}[/tex]

Step-by-step explanation:

Given

[tex]Sum = \{7, 11, 12\}[/tex]

[tex]Rolls = 5[/tex]

Required

Probability of not getting audited

If a pair of dice is rolled, the following are the observations of the sum

[tex]Outcomes = 36[/tex]

[tex]Sum\ of\ 7 = 6[/tex]

[tex]Sum\ of\ 11 = 2[/tex]

[tex]Sum\ of\ 12 = 1[/tex]

So, in a single roll; The probability of getting audited is:

[tex]p= \frac{1 + 2 + 6}{36}[/tex]

[tex]p= \frac{9}{36}[/tex]

[tex]p= \frac{1}{4}[/tex]

The probability of not getting audited in a single roll is:

[tex]q = 1 - p[/tex] --- Complement rule

[tex]q = 1 - \frac{1}{4}[/tex]

Take LCM

[tex]q = \frac{4 - 1}{4}[/tex]

[tex]q = \frac{3}{4}[/tex]

The probability of not getting audited in 5 rolls is:

[tex]Probability = q^5[/tex]

[tex]Probability = (\frac{3}{4})^5[/tex]

[tex]Probability = \frac{3^5}{4^5}[/tex]

[tex]Probability = \frac{243}{1024}[/tex]