I really need help I will mark brainliest​

Answer:

$2.79

Step-by-step explanation:

$11.78

- $8.99

=$2.79

Answer:

5/4

Step-by-step explanation:

Answer:

exact form 5/4

1 1/2 for a mixed number

1.25 as a decimal

Answer:

me gusta las mujeres :)

Step-by-step explanation:

Step-by-step explanation:

Prolly not the correct answer but oh well

Good luck

Answer:

Friday

Step-by-step explanation:

Answer:

x>169/3

Step-by-step explanation:

x- the money that each earned

3x>197-28

3x>169

x>169/3

Answer:

Less

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

slope=3-(-1)/4-(-2)=4/6=2/3

Answer:

x=-17 y=-14 (-17,-14)

Step-by-step explanation:

-2(y-3)+3y=-8

-2y+6+3y=-8

combine like terms

y+6=-8

y=-14

next plug in y to find x

x=-14-3

x=-17

Answer:

3 minutes a sculpture

5 balloons in each sculpture

Step-by-step explanation:

96/32=3

160/32=5

:)

Answer:

they have three solutions  

HOPE IT HELPS

TAHE CARE

Step-by-step explanation:

Answer:

X = 5

Step-by-step explanation:

Answer:

Step-by-step explanation:

22.4(1-3/4)

22.4(1/4)

5.6 patients per day pay cash.

Answer:

it would be 4

Answer:

35.4÷ 0.59=60

Step-by-step explanation:

Answer:

60

Step-by-step explanation:

35.4 ÷0.59= 60

(hope this helps can i plz have brainlist :D hehe)

Answer:

i think its approximately 5 gallons because if you do 4 gallons it would be 15.14 liters and if u do 5 gallons it would be 18.925 liters its the one that is a little more close i think

Answer:

5 liters

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Answer:

Step-by-step explanation:

15.5cm(40mi/2.5cm)=620mi/2.5

248mi

Answer:

37/39

Step-by-step explanation:

We know that formula for n terms of an AP is written as;

(n/2)(2a + (n - 1)d)

Let the sum of the first AP be;

(n/2)(2a + (n - 1)d)

Let the sum of the second AP be (n/2)(2A + (n - 1)D)

We are told that they have a ratio of (2n-1):(2n+1)

Thus;

(2n-1)/(2n+1) = [(n/2)(2a + (n - 1)d)]/[ (n/2)(2A + (n - 1)D)]

On RHS, n/2 will cancel out to give;

(2n-1)/(2n+1) = [(2a + (n - 1)d)]/[(2A + (n - 1)D)]

Rewriting this we have;

(2n - 1)/(2n + 1) = [(a + ½(n - 1)d)]/[A + ½(n - 1)D)]

But we want tod find;

(a + (n - 1)d)/(A + (n - 1)D)

Thus,at n = 10, we have;

(a + 9d)/(A + 9D)

Comparing with [(a + ½(n - 1)d)]/[A + ½(n - 1)D)], we can say that;

½(n - 1) = 9

n = 18 + 1

n = 19

Thus;

(a + 9d)/(A + 9D) = (2n-1)/(2n+1)

Putting n = 19 gives;

(a + 9d)/(A + 9D) = (2(19) - 1)/(2(19) + 1)

(a + 9d)/(A + 9D) = 37/39

Answer:

Step-by-step explanation:

Give the fractions a common denominator

11/13 + 4/7 = 77/91 + 52/91

= 129/91

Answer:

Infant mortality will reduce to 33% in 1.63 years

Step-by-step explanation:

Let the population be X

Population after 1 year

[tex]X - 7.3[/tex] % of [tex]X[/tex]

[tex]X -0.073 X\\0.927X[/tex]

As we know

[tex]P = P_0 * e^{rt}[/tex]

Substituting the given values we get -

[tex]\frac{P_0 - 0.33P_0}{P_0} = e^{-0.33 * t}\\0.67 = e^{-0.33 * t}\\[/tex]

Taking log on both sides we get -

[tex]-0.20273 = -0.33 * t\\t = 1.627[/tex]

You can form a general expression for resultant reduction percentage after t years. Then equate it with 33% to get the value of t

The time that will be taken by the program to reduce the infant mortality rate by 33% is approx 3.35 years.

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

[tex]\dfrac{a}{100} \times b[/tex]

The rate of decrement for infant mortality rate is 7.3% per year.

Let the mortality rate in the start be [tex]r[/tex]

Then after 1 year it becomes

[tex]r - \dfrac{r}{100} \times 7.5 = r(1-\frac{7.5}{100}) = r_1 \text{\: (say)}[/tex]

After 1 more year, we will have:

[tex]r_1 -> r_1(1 - \frac{7.5}{100}) = r(1-\frac{7.5}{100})(1-\frac{7.5}{100}) = r(1-\frac{7.5}{100}) ^2 = r_2 \text{\: (say)}[/tex]

Thus, after t years, we will have:

[tex]r_t = r(1-\frac{7.5}{100})^t[/tex]

Simplifying it, we get:

[tex]r_t = r(1 - 0.075)^t = r(0.925)^t[/tex]

The percent of decrement can be calculated by:

[tex]p = \dfrac{\text{old rate - new rate}}{\text{old rate}} \times 100[/tex]

Thus,

the percent of decrement after t years will be

[tex]p = \dfrac{r - r_t}{r} \times 100 = \dfrac{r(1- (0.925)^t)}{r} \times 100 = 100(1-0.925^t)\\\\p = 100(1-0.925^t)[/tex]

We need the time after which the infant mortality rate would be reduced by 33%, thus, p = 33%

or

[tex]p = 33\\p = 100(1-0.925^t) = 33\\1 -0.925^t = \dfrac{33}{100}\\t = log_{0.925}(1 - \dfrac{33}{100}) \approx 3.3525[/tex]

Thus, after approx 3.35 years, the mortality rate would decrease by 33%

Thus,

The time that will be taken by the program to reduce the infant mortality rate by 33% is approx 3.35 years.

Learn more about percentage here;

https://brainly.com/question/11549320

Answer:

[tex]Suppose,~a~line~segment~has~midpoints~(x_1,y_1)~and~(x_2,y_2). Then,\\Midpoint~of~the~line = (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})\\Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\According~ to~ the ~question,\\(x_1,y_1) = A(2,3)\\(x_2,y_2) = B(5,7)\\Midpoint~of~AB = (\frac{2+5}{2},\frac{3+7}{2}) = (\frac{7}{2},5)\\AB = \sqrt{(5-2)^2+(7-3)^2} = \sqrt{3^2+4^2} = 5units[/tex]

Answer:

[tex]\displaystyle \frac{-4 + i\sqrt{5}}{12}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \frac{-8 + \sqrt{-20}}{24}[/tex]

Step 2: Simplify

Answer:

(d) is correct

Equilibrium quantity is 4.5

Equilibrium price is 5

Step-by-step explanation:

Given

[tex]p = \frac{1}{4}q^2[/tex] -- supply

[tex]p = -\frac{1}{4}q^2 + 10[/tex] -- demand

Required

Find the equilibrium price

Equilibrium price is when:

[tex]Demand = Supply[/tex]

This means that (d) is correct

So, we have:

[tex]p =p[/tex]

[tex]\frac{1}{4}q^2 = -\frac{1}{4}q^2 + 10[/tex]

Collect Like Terms

[tex]\frac{1}{4}q^2 +\frac{1}{4}q^2= + 10[/tex]

[tex]\frac{1}{2}q^2 = 10[/tex]

Multiply both sides by 2

[tex]2*\frac{1}{2}q^2 = 2*10[/tex]

[tex]q^2 = 20[/tex]

Take the square root of both sides

[tex]q = \sqrt{20[/tex]

[tex]q = 4.47[/tex]

[tex]q = 4.5[/tex] -- approximated

The equilibrium price is:

[tex]p = \frac{1}{4}q^2[/tex]

Substitute value for q^2

[tex]p= \frac{1}{4}*20[/tex]

[tex]p = 5[/tex]