Answer:
1. Static Friction
2. Sliding friction
3. Fluid friction
4. is rolling friction
Sorry if i am wrong
Explanation:
9. How is spring potential energy determined from a force versus position graph?
Answer: The potential energy associated with a mass attached to a spring depends on how much the spring is stretched or compressed. ... The gravitational force on the mass is −mg (“−” because the force points down). The force is the negative of the slope on the potential energy versus position graph.
Explanation:
:)
By getting the data from the graph of force versus displacement we can calculate the Potential energy of the spring.
What will be the potential energy?As we know that potential energy is defined as the energy possessed by the body due to its position with respect to other positions.
For an example the potential energy of an object if it is placed at height h will be due to the gravitational acceleration of the earth and is given by [tex]PE=mgh[/tex]
Similarly, for a spring-mass system, the potential energy will be due to the weight of the mass that will be the force exerted by the mass on the spring so there will be an extension in the spring.
So this extension will be found out by the force and displacement graph as the position of the mass attached to the spring goes down so the potential energy can be calculated as the
[tex]PE= F\times X[/tex]
[tex]F=mg[/tex] weight of the mass
X= deflection of the spring
Thus by getting the data from the graph of force versus displacement we can calculate the Potential energy of the spring.
To know more about potential energy follow
https://brainly.com/question/24933254
How do the properties of the planets change as you move away from the sun?
Answer:
as we move away from the sun the velocity of the planet decreases
the shock absorbers in a car act as a big spring with k= 21900 N/m. when a 92.5 kg person gets in, how far does the spring stretch?
Answer: 0.04139m
Explanation:
First, we need to calculate the weight of the man which will be:
Weight = mass × acceleration due to gravity
Weight = mg
Weight = 92.5 × 9.8
Weight = 906.5N
Then, we calculate the force which will be:
F = kx
mg = kx
x = mg/k
x = 906.5/21900
x = 0.04139m.
The spring stretched for 0.04139m.
What type of liquid would never freeze
Answer:
gas
Explanation:
gasoline will never freeze up
Answer:
Alcohol
Explanation: I'm not sure
HELP PLS
In the context of climate change, is “positive feedback” a good thing?
A ball experiences forces of 14 N [N] and 9.2 N [W]. A Free Body diagram is required. What is the acceleration of the ball if its mass is 225 g?
Answer:
First, we can define the North as the positive y-axis, and the East as the positive x-axis.
Here we have two forces:
F₁ = 14N to north
F₂ = 9.2 N to west.
Then the free body diagram will be the one that can be seen below:
Now we want to find the acceleration that the ball experiences if the mass is 225g
Knowing that 1k = 1000g, we can rewrite the mass as:
M = 0.225g
Here we also need to remember the second Newton's law:
F = M*a
Net force equals mass times acceleration.
First, let's find the net force:
F = F₁ + F₂ = 14N*(0, 1) + 9.2N*(-1, 0 )
F = (-9.2N, 14N)
The module of the force is then:
I F I = √( (-9.2N)^2 + (14N)^2) = 16.75 N
Then the acceleration is given by
16.75 N = 0.225kg*a
(16.75 N)/(0.225 kg) = a = 74 m/s^2
Which one of the following properties apply to both waves and particles?
A) Photoelectric Effect
B) Diffraction
C) Refraction
Answer:
b
Explanation:
sorry if im wrong
What is the average kinetic energy (temperature) of
sample A
The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth's surface. Relative to infinitydetermine the potential energy the telescope at this location. Would the formula be Ep=-Gm1m2/r or positive G since it’s relative to infinity
Answer:
[tex]E=8.13\times 10^{12}\ J[/tex]
Explanation:
Given that,
The mass of a Hubble Space Telescope, [tex]m_1=1.16\times 10^4\ kg[/tex]
It orbits the Earth at an altitude of [tex]5.68\times 10^5\ m[/tex]
We need to find the potential energy the telescope at this location. The formula for potential energy is given by :
[tex]E=\dfrac{Gm_1m_e}{r}[/tex]
Where
[tex]m_e[/tex] is the mass of Earth
Put all the values,
[tex]E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J[/tex]
So, the potential energy of the telescope is [tex]8.13\times 10^{12}\ J[/tex].