i need solution for this question please
Select the right answer ​

Answer:

Kinetic Energy

Explanation:

Energy is transferred from one object to another when a reaction occurs. Energy can be transferred from one object to another as heat, light, and motion.

Answer:

it's C

Explanation:

hopefully that helps you

The Breaker bar is not a power wrench, the power wrench are impact, air ratchet, and air hammer option (C) is correct.

To swiftly tighten or loosen nuts, use a power or impact wrench. They are essentially tiny, portable electric or pneumatic motors with high-speed socket wrench rotation.

As we know,

An impact wrench also referred to as an impactor, impact gun, air wrench, air gun, rattle gun, torque gun, or windy gun, is a type of socket wrench power tool that uses a rotating mass to store energy before abruptly releasing it into the output shaft to produce high torque output with little user effort.

Thus, the Breaker bar is not a power wrench, the power wrench are impact, air ratchet, and air hammer option (C) is correct.

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Answer:

yes..?

Explanation:

I mean humans made it? the wave length that microwaves use is not man made, but using that wave length, microwaves were made by man

Answer:

The molecular weight of the gas mixture is 35.38 g/mol.

Explanation:

The molecular weight of the gas can be found using the following equation:

[tex] M = \frac{m}{n} [/tex]

Where:

m: is the mass = 230 g

n: is the number of moles

First, we need to find the number of moles using Ideal Gas Law:

[tex] PV = nRT [/tex]

Where:

P: is the pressure = 135 psi

V: is the volume = 15 L

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 465 °R (K = R*5/9)

[tex]n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles[/tex]                

Finally, the molecular weight of the gas is:

[tex] M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol [/tex]

Therefore, the molecular weight of the gas mixture is 35.38 g/mol.

I hope it helps you!

Answer:

Negative feedback control of the amplifier is achieved by applying a small part of the output voltage signal at Vout back to the inverting ( – ) input terminal via the feedback resistor

Answer:

The system has parts that sense the amount of output

Explanation:

Apex cirtified

Answer:

1) The exergy of destruction is approximately 456.93 kW

2) The reversible power output is approximately 5456.93 kW

Explanation:

1) The given parameters are;

P₁ = 8 MPa

T₁ = 500°C

From which we have;

s₁ = 6.727 kJ/(kg·K)

h₁ = 3399 kJ/kg

P₂ = 2 MPa

T₂ = 350°C

From which we have;

s₂ = 6.958 kJ/(kg·K)

h₂ = 3138 kJ/kg

P₃ = 2 MPa

T₃ = 500°C

From which we have;

s₃ = 7.434 kJ/(kg·K)

h₃ = 3468 kJ/kg

P₄ = 30 KPa

T₄ = 69.09 C (saturation temperature)

From which we have;

h₄ = [tex]h_{f4}[/tex] + x₄×[tex]h_{fg}[/tex] = 289.229 + 0.97*2335.32 = 2554.49 kJ/kg

s₄ =  [tex]s_{f4}[/tex] + x₄×[tex]s_{fg}[/tex] = 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)

The exergy of destruction, [tex]\dot X_{dest}[/tex], is given as follows;

[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot S_{gen}[/tex] = T₀ × [tex]\dot m[/tex] × (s₄ + s₂ - s₁ - s₃)

[tex]\dot X_{dest}[/tex] = T₀ × [tex]\dot W[/tex]×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)

∴ [tex]\dot X_{dest}[/tex] = 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138  - 2554.49) ≈ 456.93 kW

The exergy of destruction ≈ 456.93 kW

2) The reversible power output, [tex]\dot W_{rev}[/tex] = [tex]\dot W_{}[/tex] + [tex]\dot X_{dest}[/tex] ≈ 5000 + 456.93 kW = 5456.93 kW

The reversible power output ≈ 5456.93 kW.

Answer: True is correct

A third-degree burn may look charred and black or dry and white.

Explanation:

Answer: true

Explanation:

A key is a machine element that us used to connect the element of a rotating machine to a shaft. It should be noted that the key hinders the relative rotation that may take place between the two parts.

Key length is designed to provide desired factor of safety. It should also be noted that the factor of safety shouldn't be much and the key length is typically limited to the hub length.

Answer:

knowledge of animal behavior and anatomy

Explanation:

the qualification that will make Milton successful in his research is a knowledge of animal behaviour and also their anatomy. the knowledge of whales behaviour has opened his eyes into their world so he knows to a great deal about them. it is through his knowledge of the behaviour of whales that he's able to get used to their migrating patterns to know where and when to find them. Also, through the body anatomy of whales he knows what their movement is like.

Answer:

knowledge of animal behavior and anatomy

Answer:

Explanation: that’s the answer! 46kg

Answer:

  C.  3325 Ω - 3675 Ω

Explanation:

5% of 3500 Ω is ...

  0.05 × 3500 = 175

The lower limit is this amount less than the nominal value:

  3500 -175 = 3325

The upper limit is the nominal value plus the tolerance:

  3500 +175 = 3675

The lower and upper limits are 3325 Ω and 3675 Ω, respectively.

Answer:

Explanation: 2 is thy answer

Answer:

15

Explanation:

A compass may be used to create circles, arcs, bisect lines, angle bisectors, and locate midpoints. By using a compass, a protector is also drawn.

A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It can also be used as dividers to indicate distances, particularly on maps.

A compass, or more correctly, a pair of compasses, is a tool for technical drawing that may be used to draw arcs or circles. It may also be used as dividers to indicate distances, particularly on maps. Compasses can be used for navigation, mathematics, and other things.

Therefore, a protector is sketched using a compass.

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Answer:

Inventory reduction

Explanation:

Shine is a term that deals with the general cleaning and overall maintenance of the workplace. It is used as a part of an organizational theme involving five steps which are often referred to as 5S and it is basically defined as the mainstay of the visual workplace. They are Sort, Set in order, Shine, Standardize, and Sustain.

Hence, in this situation, considering the option that is not a benefit of Shine the correct answer is "Inventory reduction." This is because Shine is not about reducing the inventory levels. It is Sort and Set-in-Order will help reduce inventory.

The answer choice which is NOT a benefit of Shine is:

According to the given question, we are asked to show the answer choice which is not a direct benefit of Shine and how Shine is used to increase productivity in an office space.

Shine is a term which is used to refer to the general cleanliness of an office space and is a part of organization which is used to improve quality, make the employees happier, and have a less production downtime, etc

As a result of this, we can see that inventory reduction is not a benefit of Shine.

Therefore, the correct answer is option D

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Answer: 199.1 kip

Explanation:

Given that

Outer diameter is Do = 7 in

Inner diameter Di = ( Do - ( 2×0.5)) = 6 in

Length = 5000 ft = 60000 in

Now change in length of the pipe due to temperature difference

SL = L∝ΔT

= 60000 × 6.5×10^-6(140-40)

SL = 39 in

Also

sL = PL/AE

A = cross sectional area of pipe = π/4(Do^2 - Di^2)

so

P = SL×A×E / L

= (39 × π/4(7^2 - 6^2)×30000) / 60000

= 199.1 kip

compressive load applied by the pipeline on a PLET due to its thermal expansion is 199.1 kip

That is an example of a want because you don't need the ball.

Answer:

keep your head out of a fume plume

Explanation:

According to the guidelines and precaution procedures of OSHA, an acronym for Occupational Safety and Health Administration in the United States of America stated that The easiest way for an individual to reduce his or her exposure to dangerous fumes is to ensure that such person keeps his or her head out of a fume plume.

Hence, in this situation, the correct answer is "keep your head out of a fume plume"

Answer:

True

Explanation:

This is true. Welding fumes are a combination of metallic oxides, silicates and also fluorides. the formation of these films are a result of a metal being exposed to heat above its boiling point and a condensation of its vapours into good fine particles. such films are made up of particles from the material that one is welding and also particles from electrode.

Answer:

This one is false

Explanation:

I just took a test on it..

Most hazardous waste can be disposed of in a landfill. Thus, the above statement is true. Thus, option (A) is correct.

A hazardous waste is a waste that has characteristics that make it unsafe or allow it to negatively impact the environment or human health.

Wastes classified as hazardous have characteristics that make them unsafe or potentially damaging to the environment or human health. Liquid, solid, confined gas, and sludge are all examples of hazardous wastes.

Any source that could potentially cause injury, damage, or unfavorable health impacts to someone or something is a hazard.

The majority of hazardous garbage can be dumped in landfills. So, the aforementioned claim is accurate. Therefore, it can be concluded that option (A) is correct.

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Answer:

2k20

Explanation:

4k ✈

Answer:

Explanation:

When solving for the reliability of a complex machine, that is a machine that has more than one component, the reliability of the machine is the products of all individual components.

Given the

reliabilities of 98%,

96%, and

94%

Converting to decimals we have

98/100= 0.98

96/100= 0.96

94/100= 0.94

The product of all reliability is

0.98* 0.96 0.94= 0.88

now converting back to percent we have

0.88*100= 88%

Answer:

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.

From the diagram, equating the component of the upward forces and the downward forces, we have:

[tex]\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}[/tex] --- (1)

Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:

[tex]\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}[/tex]

If:

[tex]F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN[/tex]

Then, from equation (1), we can have the following:

[tex]\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}[/tex]

collecting like terms;

[tex]\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }[/tex]

[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex] --- (3)

From equation (2);

[tex]\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}[/tex]

collecting like terms:

[tex]\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}[/tex]

[tex]\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}[/tex]

Suppose we equate (3) and (4) together using the elimination method;

[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex] --- (3)

[tex]\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}[/tex]

Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);

Then, we have:

[tex]\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}[/tex]

[tex]\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}[/tex]

Adding both previous equations together, we have:

[tex]\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}[/tex]

[tex]\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}[/tex]

[tex]\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}[/tex]

[tex]\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}[/tex]

[tex]\mathbf{( F_g(0.866)) =(13.23)}[/tex]

[tex]\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}[/tex]

[tex]\mathbf{ F_g =15.28 \ N}[/tex]

Replacing the value of [tex]\mathbf{F_g}[/tex] into equation (3), to solve for [tex]\mathbf{F_a}[/tex], we have:

[tex]\mathbf{F_a sin 70 + F_gsin 50 =23.93}[/tex]

[tex]\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\[/tex]

[tex]\mathbf{F_a =13.01 \ N}[/tex]

Therefore, we can conclude that the magnitudes of [tex]\mathbf{F_a}[/tex] and [tex]\mathbf{F_g}[/tex] are 13.0 N and 15.28 N respectively.

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Answer:

ask someone u fool hhhhhhhh

Answer:

The number of holes.

Explanation:

A semiconductor can be defined as a crystalline solid substance that has its conductivity lying between that of a metal and an insulator, due to the effects of temperature or an addition of an impurity. Semiconductors are classified into two main categories;

1. Extrinsic semiconductor.

2. Intrinsic semiconductor.

An intrinsic semiconductor is a crystalline solid substance that is in its purest form and having no impurities added to it. Examples of intrinsic semiconductor are Germanium and Silicon.

In an intrinsic semiconductor, the number of free electrons is equal to  the number of holes. Also, in an intrinsic semiconductor the number of holes and free electrons is directly proportional to the temperature; as the temperature increases, the number of holes and free electrons increases and vice-versa.

In an intrinsic semiconductor, each free electrons (valence electrons) produces a covalent bond.

Answer:

Option C..Farmers saught new technology to help with the workload

hope this helped you

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Answer:

In order to take a portrait, the distance of the mascot from the camera should be approximately 7.33 feet

Explanation:

The size of the film paper = 3 in. × 5 in.

The focal length of the camera = 5.5 in.

The height and width of the guinea pig = 4 ft.

The height of the aperture above the ground = 2 ft.

Therefore, we have;

Magnification = Height of image/(Height of object)

Withe the 3 in. wide film, we have;

Magnification = 3 in./(4 ft.) = 3 in./(48 in.) = 0.0625

Magnification = Length of camera/(Distance of object from pin hole)  

∴ Length of camera/(Distance of object from pin hole) = 0.0625

Length of camera = Focal length of the camera = 5.5 in.

Therefore;

5.5 in./(Distance of object from pin hole) = 0.0625

Distance of object from pin hole = 5.5/0.0625 = 88 inches = 7.33 ft

Therefore, the camera should be approximately 7.33 ft. from the mascot to take a portrait.

In this exercise we have to use the magnification knowledge to calculate the distance that the photograph should be taken, thus we have to:

Distance of the mascot from the camera should be approximately 7.33 feet

To calculate the best distance to take the photo, we have that some information must be taken into account such as:

Therefore, we have that the formula of magnification is:

[tex]Magnification = Height \ of \ image/(Height \ of \ object)[/tex]

With the 3 in wide film, we have;

[tex]Magnification = 3 in/(4 ft) \\= 3 in/(48 in) = 0.0625 in[/tex]

Rewriting the magnification formula as:

[tex]Magnification = Length \ of \ camera/(Distance \ of \ object \ from \ pin \ hole)[/tex]  

Substituting the values ​​already known we have the equation will be matched as:

[tex]Length\ of \ camera/(Distance\ of\ object \ from \ pin \ hole) = 0.0625\\Length \ of \ camera = Focal \ length \ of \ the \ camera = 5.5 in.[/tex]

Therefore;

[tex]5.5 /(Distance \ of \ object\ from \ pin\ hole) = 0.0625 in\\Distance \ of \ object\ from \ pin \ hole = 5.5/0.0625\\ = 88 inches = 7.33 ft[/tex]

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Answer: Application.

Explanation:

The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.