I need help with this, I'm terrible with graphs lol.

Answer:

1/2

Step-by-step explanation:

Because there are 2 numbrs that are greater than 3.

Hope this helped!

Stay Safe!

Answer:

Option 1

Step-by-step explanation:

The shaded area is 2/3 and it is divided into 1/9 pieces. So, 2/3 divided by 1/9 which equals 6 pieces. The only equation that matches this is option 1.

Answer:

1/14

Step-by-step explanation:

There is only 1 common multiple of 4 and 6 between 1 and 14.

So the probability is:

[tex]P = \frac{1}{14}[/tex]

Answer:

5/14

Step-by-step explanation:

the multiples of 6 are 6 and 12. the multiples of 4 are 4,8,12(but its the same as 4 so we don't add that one), and 14. Add 2 and 3 and you get 5.

The total is 14 so it ends up being a 5/14 chance.

Answer:

sub to garce franz

Step-by-step explanation:

257

Answer:

31.5576

Step-by-step explanation:

Answer:

6 passengers got off at New Jersey

Step-by-step explanation:

let the number of passengers who got off be x and let the number of passengers who boarded the bus be y

y=2x

44 - x + y=50

y=50-44+x

y=6+x

subst y=2x

2x=6+x

2x-x=6

x=6

Answer:

4/3

Step-by-step explanation:

7x + 4 = 10x

4 = 3x

x = 4/3

Answer:

hope this helps

Step-by-step explanation:

31 divided by 2 = 15.5 then do 15.5 x 15.5= 240.25 then you do 240.25 x 3.14 = 754.385

Answer:

Step-by-step explanation:

so we know that a triangle degrees have to add up to 180 in the inside right? So we know c is 90 and so you need to find A and B. The left over degrees you have is 90 so the sum of B and A would have to be 90, thats all i can help you with sorry.

Answer:

D. The prism is missing a sixth face, which should be colored white.

The prism is missing a sixth face, which should be colored white.

We have given that,

A net with 5 faces. 3 rectangles are stacked. The top and bottom rectangles are shaded blue.

The middle rectangle is white. An orange rectangle is connected to the left of the top blue rectangle, and another is connected to the right of the bottom blue rectangle.

Juan is drawing the two-dimensional net of a rectangular solid, but he made a mistake.

We have to determine what error did Juan make, and how can he correct it.

A plane figure with four straight sides and four right angles, especially one with unequal adjacent sides, in contrast to a square.

Therefore we get,

The prism is missing a sixth face, which should be colored white.

The correct statement is The prism is missing a sixth face, which should be colored white.

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Answer:

m=  1/2

y=1

Step-by-step explanation:

you go up 2 over 4 but you simplify it to 1/2

you then go to the first point for y intercept, which is 1 (because it follow the patteren)

Answer:

The most efficient method is completing the square because the equation can be written in the form [tex]x^2 - d[/tex]

x ~ 2.24

x ~ -2.24

Step-by-step explanation:

Solve the equation using any method that is efficient. The most efficient method is completing the square, because the equation can be written in the form [tex]x^2 - d[/tex]. Use this method to solve the problem, since the equation is already in the format, [tex]x^2 - d[/tex], all one has to use is inverse operations to solve the equation.

[tex]-5x^2 = -25\\/-5\\\\x^2 = 5\\\sqrt{}\\\\x = +- \sqrt{5}[/tex]

x ~ 2.24

x ~ -2.24

Number of years to make a worth of $45000 with Depreciation rate of 12% and Total worth $45000 is 4 years

Years= 4 year

The term depreciation refers to an accounting method used to allocate the cost of a tangible or physical asset over its useful life. Depreciation represents how much of an asset's value has been used. It allows companies to earn revenue from the assets they own by paying for them over a certain period of time.

Given that:

limousine costs $75000

Depreciation rate = 12% per year= 0.12

Total worth= $45000

By using the formula for year we have

total worth = cost of object [tex](1- Depreciation \;rate)^{year}[/tex]

45000= 75000x [tex](1-0.12)^{year}[/tex]

0.6= [tex](0.88)^{year}[/tex]

Now taking log on both side we have

log 0.6= year x  log0.88

-0.2218 = year x -0.05551

year= 4.049

year≈ 4 year(rounding off nearest year)

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Given:

Initial value = $800 per acre

Growth rate = 3% per year

To find:

How long will it be before the land is worth $1000 per acre.

Solution:

The exponential growth model is:

[tex]y=a(1+r)^t[/tex]

Where, y is the new value, a is the initial value, r is the growth rate in decimal and t is the number of years.

Putting [tex]y=1000, a=800, r=0.03[/tex], we get

[tex]1000=800(1+0.03)^t[/tex]

[tex]\dfrac{1000}{800}=(1.03)^t[/tex]

[tex]1.25=(1.03)^t[/tex]

Taking log both sides, we get

[tex]\log 1.25=\log (1.03)^t[/tex]

[tex]0.09691=t\log (1.03)[/tex]

[tex]0.09691=0.012837t[/tex]

Isolating the variable t, we get

[tex]\dfrac{0.09691}{0.012837}=t[/tex]

[tex]7.54927=t[/tex]

[tex]t\approx 7.55[/tex]

Therefore, the land is worth $1000 per acre after 7.55 years.

Answer:

There is a 1/3 chance it lands on each section

Step-by-step explanation:

Answer:

Hello! answer: 62.8

Step-by-step explanation:

Cirmcumfrence is just diameter × pi so since we are using 3.14 for pi we can just do 3.14 × 20 so...

3.14 × 20 = 62.8 Therefore the circumference is 62.8 Hope that helps!

Answer:

Its A let me know if im wrong!

Answer:

Fourth option is most suitable here.

Answer:

m<BAC = 34

Step-by-step explanation:

It is given that (<BOC) is a central angle with a degree measure of (68). A central angle is an angle whose vertex is the center of the circle. (<BAC) is an inscribed angle, an angle whose vertex is on the circumference (perimeter) of the circle. Arc (BC) connects the ends of both of these angles.

The central angle theorem states that the measure of the central angle is equivalent to its surrounding arc. Using this theorem, one can state the following,

m<BOC = BC = 68

The inscribe angle theorem states that the measure of the arc surrounding the inscribed angle is twice the measure of the inscribed angle. Applying this theorem, one can state the following,

2(m<BAC) = (BC)

2 (m<BAC) = 68

m<BAC = 34

Answer:

c≈5.2

Step-by-step explanation:

c=a2+b2=1.412+52≈5.19501

Answer:

thank you <3 I needed this.

Step-by-step explanation:

who's cutting onions??!?!?

Answer:

put it on the calculator

Answer:

its 136

Step-by-step explanation:

Answer:

Package 2

Step-by-step explanation:

Mr. avola is deciding which of these packages of cheese to buy

For Package 1

Package 1: SLICED cheese 12oz for 3 dollars

12oz = 3 dollars

1 oz = x

Cross Multiply

12 oz × x = 3 × 1 oz

x = 3 × 1 oz/12 oz

x = 0.25 dollars

Hence, Package 1 cost 0.25 dollars per ounce

For Package 2

Package 2: BLOCK of cheese 1.5lbs for 5.52 dollars.

We convert Ibs to oz

1 Ibs = 16 oz

1.5 Ibs = x

x = 1.5Ibs × 16 oz/1 Ibs

x = 24 oz

Hence:

24oz = 5.52 dollars

1 oz = x

Cross Multiply

24 oz × x = 5.52 × 1 oz

x = 5.52 × 1 oz/24oz

x = 0.23 dollars

Package 2 cost 0.23 dollars per ounce

Therefore, the package that cost less per ounce is Package 2

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

I'll do problem 1 to get you started

First sort the values from smallest to largest and you should end up with this set

{1, 6, 7, 11, 13, 16, 18, 21, 22, 23}

The smallest value is 1 and the largest value is 23, so the min and max are 1 and 23 in that order.

We have ten values in this set. The middle-most number is going to be between the 10/2 = 5th slot and the 6th slot. The numbers 13 and 16 are in the fifth and sixth slots respectively. Average those values to get (13+16)/2 = 29/2 = 14.5

The median is 14.5 which is another name for the second quartile (Q2).

Now split the data set into two halves

L = lower half of values smaller than the median

U = upper half of values larger than the median

In this case,

L = {1, 6, 7, 11, 13}

U = {16, 18, 21, 22, 23}

sets L and U have five items each

Find the median of set L and U to get 7 and 21 respectively. These medians of L and U represent the values of Q1 and Q3 in that order.

Q1 = first quartile = 7

Q3 = third quartile = 21

===================================================

Answer:

The five number summary for problem 1 is

Answer:

71

Step-by-step explanation:

ndndnrbrjen3n3nn3b2n2b2b

Answer:

4.2

Step-by-step explanation:

By intersecting chords theorem:

[tex]x \times 10 = 6 \times 7 \\ \\ 10x = 42 \\ \\ x = \frac{42}{10} \\ \\ x = 4.2[/tex]

The answer to the above statement is: $k$ has a perfect square trinomial value of 16.

To determine the value of $k$ such that $9x^2 - 16x + k$ is a perfect square trinomial, we can follow these steps:

Identify the form of a perfect square trinomial. A perfect square trinomial can be written in the form $(ax + b)^2$, where $a$ and $b$ are constants.

Examine the $9x2 - 16x + k$ trinomial in comparison to the perfect square trinomial form.  We need to match the quadratic term and the linear term.

The quadratic term in the perfect square trinomial is $(ax)^2 = a^2x^2$, which corresponds to $9x^2$ in our trinomial.

The linear term in the perfect square trinomial is $2abx$, which corresponds to $-16x$ in our trinomial.

By comparing the terms, we can set up the following equation: $2abx = -16x$. This implies that $2ab = -16$.

Solve for $a$ and $b$ using the equation $2ab = -16$.

Let's consider possible factor pairs of $-16$: $(1, -16)$, $(2, -8)$, and $(4, -4)$.

We need to find a pair $(a, b)$ such that $2ab = -16$. Checking the options, we find that $(a, b) = (2, -4)$ satisfies the condition since $2(2)(-4) = -16$.

To determine the value of $k$, substitute the values of $a$ and $b$ into the perfect square trinomial form.

The perfect square trinomial form is $(ax + b)^2 = (2x - 4)^2 = 4x^2 - 16x + 16$.

We can see that $k = 16$ by comparing the derived form to the supplied trinomial $9x2 - 16x + k$.

As a result, $k$ has a Perfect Square Trinomial value of 16.

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Answer:

12

Step-by-step explanation: