Answer:
Step-by-step explanation:
ASAP!!!!!!!!! PLEASE help me with this question! This is really urgent! No nonsense answers please.
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Explanation:
Let point A be the center of the circle.
Arc DCF is 316 degrees. Arc FG is 20 degrees. Subtracting the arc measures gives 316-20 = 296 which is the measure of arc DCG, and by extension, it is the measure of reflex angle DAG. The acute angle DAG is 360-296 = 64 degrees
Triangle DAG is isosceles with AD = AG, so the base angles are ADG and AGD. Let's call each of these angles x for now. The sum of the three angles add to 180
x+x+64 = 180
2x+64 = 180
2x = 180-64
2x = 116
x = 116/2
x = 58
Therefore angle ADG is 58 degrees. It adds to angle ADB = 90 to get 90+58 = 148, which is the measure of angle BDG.
Note: angle ADB is 90 because tangent BD forms a right angle with the radius AD.
Another note: angle ADG is half that of the arc it cuts off, so in a sense it's similar to an inscribed angle
Which function can be used to find r, the total amount the teacher pays in dollars when
z scissors are ordered?
A teacher is ordering scissors for her classroom.
• the teacher pays a one-time fee of $8.
• the teacher also pays $2 for each pair of scissors ordered.
Identify a transformation of the function f(x) = x by observing the equation of
the function g(x) = VX+3.
Answer:
1st option
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
Here g(x) = [tex]\sqrt{x+3}[/tex]
The base graph f(x) has been shifted left 3 units
Is there any video related to this or can you explain how to do it
Angles ECD and CEF add to 180
40+140 = 180
So that means we have EF parallel to CD (due to the same side interior angle theorem)
--------------
Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.
In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.
--------------
So far we have
AB || CD
CD || EF
Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.
It's like saying "P --> Q and Q --> R, therefore P --> R"
Use the figure below to find the measure of angle x.
Answer:
70 degrees
Step-by-step explanation: this is an equilateral triangle. All of its angles are the same.
Two numbers are in ratio 3 by 2 and their difference is 5 find numbers
Answer:
15,10
Step-by-step explanation:
let the numbers be 3x and 2x
3x-2x=5
x=5
∴ numbers are 3×5,2×5
or 15,10
4x3+ 13x2 + 5x- 4 is divided by x+ 1?
Answer:
The quotient to this equation is 4x² + 13x + 1
Step-by-step explanation:
When we divide exponents, we subtract the exponential numbers.
4x³ + 13x² + 5x - 4 / x + 1
Now, we divide. For this problem, we are only dividing the like terms of x because anything divided by 1 will equal to itself.
4x² + 13x + 5 - 4
Now, we combine like terms.
4x² + 13x + 1
ESSENTIAL QUESTION How do graphs
and equations reveal information about a
relationship between two quantities?
Answer:
When you plot the graph, you may see a line or a curve. This presents the trend of the relationship of the two quantities when the independent variable changes.
Graphs visually depict patterns and trends, while equations provide precise mathematical descriptions, both revealing valuable information about the relationship between two quantities.
Graphs visually represent data and patterns, allowing us to identify the nature of the relationship between two quantities. The slope and intercepts of a graph provide information about the rate of change and the values when one quantity is zero.
Equations, on the other hand, offer precise mathematical descriptions of the relationship. The form of the equation reveals the nature of the relationship, while coefficients and constants provide specific information. Solving equations yields solutions that satisfy the relationship.
Both graphs and equations work together to provide a comprehensive understanding of the relationship between two quantities, with graphs offering visual insights and equations providing precise mathematical information.
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Carolyn was training for cross-country season on an indoor track. During her workout, she ran 24 laps around a track that measured 110 meters. What was the total distance Carolyn ran in kilometers?
Answer:
2.64 km
Step-by-step explanation:
24*110=2640 meters
2640/1000=2.64 km
convert 28km into cm
Answer:
28km to cm = 2,800,000cm
Step-by-step explanation:
In order to convert km to cm you have to times it by 100,000
So... 28 x 100,000 = 2,800,000
Hope this helps
Answer:2,800,000cm
Step-by-step explanation:
To convert a larger unit into a smaller unit, you must first check how much does the smaller unit need to make the larger unit. Then multiply the given larger unit to the amount of smaller unit that is equal to 1 of the larger unit.
Because: 100,000cm = 1km
So = 28km×100,000 =2,800,000cm
Pls answer all questions
5:-c
The 3multiples are 25,50,75
6:-c
[tex]\\ \sf\longmapsto 6\:of\:2+9-5[/tex]
[tex]\\ \sf\longmapsto 6(11-5)[/tex]
[tex]\\ \sf\longmapsto 6(6)[/tex]
[tex]\\ \sf\longmapsto 36[/tex]
7:-a
12,17
8:-c
22=2×1188=2×2×2×11HCF=2×2×11=44
9:-c
LCM of 9 and 5 is 45 hence its true
10:-c
HCF of two consecutive numbers is 1
An insurance firm reported that "the typical water-skiing accident occurs near the dock from which they start." Which of the following statistical measurements are they most likely discussing? A. mode B. range C. mean D. median
Answer:
The correct option is;
B. Range
Step-by-step explanation:
In descriptive statistics which analyses the quantitative summary of the statistical data, the range is the region or area or the statistical interval where the data is obtained from and as such the range (in descriptive statistics) gives a guide to the dispersion of the statistical information.
The range is best suited for the representation of the dispersion when the size of the data set is small.
22.
A map has a scale of 1 inch : 20 miles. If two
cities are 240 miles apart, how far apart are
they on the map?
NEED HELP FAST!!
Answer:
12
Step-by-step explanation:
1 inch = 20 miles
240 miles ÷ 20 miles =
12 inches
Answer:
12 inches
Step-by-step explanation:
Hey there!
Well to solve the given question we need to use fractions,
if 1 inch is 20 milles, we can set up the following.
[tex]\frac{1}{20} = \frac{x}{240}[/tex]
Cross multiply
240 = 20x
Divide both sides by 20
x = 12
So it is 12 inches in the map.
Hope this helps :)
2x + 5 = 22.
how can I write it in a scenario?
Answer:
Alexis sold 22 lemon cups, 5 of the cups she sold were large and the rest were small, how many small cups did she sell?
Simply Square Roots of 45
[tex] \sqrt{45} [/tex]
Answer:
[tex] 3\sqrt{5} [/tex]
Step-by-step explanation:
Find the largest factor of 45 that is a perfect square.
The factors of 45 are 1, 3, 5, 9, 15, 45.
The largest perfect square is 9.
Now breakup 45 into a product which has 9 as a factor.
45 = 9 * 5
[tex] \sqrt{45} = \sqrt{9 \times 5} = \sqrt{9} \times \sqrt{5} = 3\sqrt{5} [/tex]
!!!!HELP PLS!!!!
WHAT IS:
2.039 x 31.5
Answer:
2039/1000×315/10
642285/10000
=64.2285
(y 2 - 3)(y 4 - 6y 2 + 9)
Find the product.
Answer:
y^6 - 9y^4 + 27y² - 27
Step-by-step explanation:
(y² - 3) (y^4 - 6y² + 9)
y^6 - 6y^4 + 9y² - 3y^4 + 18y² - 27
y^6 - 9y^4 + 27y² - 27
In January, the average temperature t hours after midnight in Mumbai, India, is given by:
T(t)=24.5-5.5sin((2pi(t+1))/24)
What is the coldest time of day in Mumbai? give an exact answer
The coldest time of day in Mumbai is 5 hours after midnight.
Since the average temperature t hours after midnight in Mumbai, India, is given by:
T(t)=24.5-5.5sin((2pi(t+1))/24)
We have that
T(t) = 24.5 - 5.5sin((2π(t+1))/24)
The coldest time of day is when T(t) is minimum.
T(t) is minimum when 5.5sin((2π(t+1))/24) is minimum where t is the coldest time of day at minimum temperature, T(t).
Since for a sine function, -1 ≤ sinФ ≤ 1, the minimum value of sinФ = -1.
So, T(t) = 24.5 - 5.5sin((2π(t+1))/24) is minimum when
5.5sin((2π(t+1))/24) is minimum.
Also, -5.5sin((2π(t+1))/24) = 5.5 × -1 at minimum temperature T(t)
So, 5.5 × -1 = 5.5 × -sin((2π(t+1))/24)
So, -sin((2π(t+1))/24) = -1
sin((2π(t+1))/24) = 1
Taking inverse sine of both sides, we have
sin⁻¹sin((2π(t+1))/24) = sin⁻¹(1)
((2π(t+1))/24) = π/2
Multiplying both sides by 24, we have
(2π(t+1))/24 × 24 = π/2 × 24
(2π(t+1)) = 12π
Dividing both sides by 2π, we have
2π(t+1)/2π = 12π/2π
t + 1 = 6
t = 6 - 1
t = 5 hours
So, the coldest time of day in Mumbai is 5 hours after midnight.
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Here is a list of fractions 18/45 14/30 10/25 8/20 16/40 one of these fractions are not equivalent to 2/5 write down this fractions
Answer:
14/30Step-by-step explanation:
How to simplify: • divide both numerator and denominator by their GCF.18/45= 18 ÷ 9 / 45 ÷ 9= 2/514/30= 14 ÷ 2 / 30 ÷ 2= 7/1510/25= 10 ÷ 5 / 25 ÷ 5= 2/58/20= 8 ÷ 4 / 20 ÷ 4= 2/516/40= 16 ÷ 8 / 40 ÷ 8= 2/5[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
[tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex] in the list of fractions [tex]\frac{18}{45}, \frac{14}{30} , \frac{x}{y} \frac{10}{25}, \frac{8}{20}, \frac{16}{40}[/tex].
Equivalent FractionsEquivalent fractions represent the same value even though they look different.
How to determine the Equivalent fractions?We know we can find an equivalent fraction of a given fraction by or dividing both the numerator and denominator of the given fraction with the same number (maybe LCM or HCF of the numerator or denominator).
[tex]\frac{18}{45}=\frac{18/9}{45/9}=\frac{2}{5}[/tex] (since [tex]9[/tex] is HCF of [tex]18, 45[/tex])
[tex]\frac{14}{30}=\frac{14/2}{30/2}=\frac{7}{15}[/tex] (since [tex]2[/tex] is HCF of [tex]7, 15[/tex])
[tex]\frac{10}{25} =\frac{10/5}{25/5} =\frac{2}{5}[/tex] (since [tex]5[/tex] is HCF of [tex]10, 25[/tex])
[tex]\frac{8}{20} =\frac{8/4}{20/4} =\frac{2}{5}[/tex] (since [tex]4[/tex] is HCF of [tex]8, 20[/tex])
[tex]\frac{16}{40} =\frac{16/8}{40/8} =\frac{2}{5}[/tex] (since [tex]8[/tex] is HCF of [tex]16, 40[/tex])
Thus, [tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex].
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Can some one help me answer this
7. √9
√9 is a rational number because √9 = 3 = 3/1.
8. No, there is no integer between -6 and -7.
9. π
π is an irrational number
how many are 5 raised to 3 ???
Answer:
[tex]\boxed{125}[/tex]
Step-by-step explanation:
Hey there!
Well 5 raised to the 3 can be written as,
[tex]5^3[/tex]
This is 5*5*5
= 125
Hope this helps :)
Write the number 3388198 in word form
Three million three hundred eighty-eight thousand one hundred ninety-eight - 3388198
what is (a x b) x c if a = 2, b = 8, and c = 12? PLEASE HELP!!
Answer:
192
Step-by-step explanation:
(a x b) x c
Let a=2 b=8 c=12
(2 * 8) * 12
16 * 12
192
Answer:
192Step-by-step explanation:
[tex]a = 2\\b = 8\\c = 12\\\\(a \times b) \times c\\\\(2 \times 8) \times 12\\\\(16) \times12\\\\= 192[/tex]
What does the lines mean around the x: |x|
Answer:
absolute value
Step-by-step explanation:
Answer:
This shows the absolute value of an integer.
Step-by-step explanation:
When you see the lines | | around a number, it should always give you the answer of that number's positive integer. So lets say I out | -2 | the answer for this equation should be 2.
HELP FAST 100 POINTS - please show how you got it thank you
Which theorem/postulate can be used to prove ∆PQR ≅ ∆STU?
What is the perimeter of ∆PQR?
side angle side (SAS) is the postulate because we can clearly see that two of the sides of the triangles are congruent (9 & 14), as well as the Q and T angle.
the perimeter is 43
6y+5=8y
y= 5/2
9+14+6(5/2)+5= 43
Answer:
Solution given:
In ∆ PQR and ∆ STQ
PQ=ST=9ft given
<Q=<T given
QR=TU = 14ft [given]
S.A.S axiom therom is used to prove
∆PQR ≅ ∆STU
Since ∆PQR ≅ ∆STU
their corresponding side is equal.so
6y+5=8y
5=8y-6y
2y=5
y=5/2
now
perimeter of ∆ PQR=sum of all sides
=9ft +14ft+ 6*5/2+5=43ft
pls help answer, explain it too. I will give brainliest
Pages read by Arnold in 7 minutes = 3 pages
Pages read by Arnold in 1 minutes
= 3/7 pages
= 6/14 pages
Pages read by Brenda in 14 minutes = 8 pages
Pages read by Brenda in 1 minutes = 8/14 pages
(6/14) < (8/14)
So, speed of Arnold < speed of Brenda.
So, Brenda reads faster.
At 11:00 a.m., John started driving along a highway at constant speed of 50 miles per hour. A quarter of an hour later, Jimmy started driving along the same highway in the same direction as John at the constant speed of 65 miles per hour. At what time will Jimmy catch up with John?
Answer:
12:05 pm
Step-by-step explanation:
Let z be the number of hours, from 11:00 am, when Jimmy would catch up with John. The time that Jimmy will have to drive to catch up with John is z - 1/4 as he started a quarter of an hour late. When Jimmy would catch up with John, they would have traveled the same distance. Hence
50 z = 65 (z - 1/4)
Solve for t
50z = 65z - 65/4
z = 65/60 = 1.083 hours = 1 hour and 5 minutes
Jim will catch up with John at
11:00 am + 1 hour 5 minutes = 12:05 pm
Answer From Gauth Math
PLEASE HELP Polynomial Graph Studies Polynomials are great functions to use for modeling real-world scenarios where different intervals of increase and decrease happen. But polynomial equations and graphs can be trickier to work with than other function types. In mathematical modeling, we often create an equation to summarize data and make predictions for information not shown on the original display. In this activity, you’ll create an equation to fit this graph of a polynomial function. Part A Describe the type of function shown in the graph. Part B What are the standard form and the factored form of the function? Part C What are the zeros of the function? Part D Use the zeros to find all of the linear factors of the polynomial function. Part E Write the equation of the graphed function f(x), where a is the leading coefficient. Use the factors found in part D. Express the function as the product of its leading coefficient and the expanded form of the equation in standard form. Part F Use the y-intercept of the graph and your equation from part E to calculate the value of a. Part G Given what you found in all of the previous parts, write the equation for the function shown in the graph.
Answer:
Here's what I get
Step-by-step explanation:
Part A
The graph shows a polynomial of odd degree. It is probably a third-degree polynomial — a cubic equation.
Part B
The standard form of a cubic equation is
y = ax³ + bx² + cx + d
The factored form of a cubic equation is
y = a(x - b₁)(x² + b₂x + b₃)
If you can factor the quadratic, the factored form becomes
y = a(x - c₁)(x - c₂)(x - c₃)
Part C
The zeros of the function are at x = -25, x = - 15, and x = 15.
Part D
The linear factors of the function are x + 25, x + 15, and x - 15.
Part E
y = a(x + 25)(x + 15)(x - 15) = a(x + 25)(x² - 225)
y = a(x³ + 25x² - 225x - 5625)
Part F
When x = 0, y = 1.
1 = a[0³ +25(0)² - 225(0) - 5625] = a(0 + 0 - 0 -5625) = -5625a
a = -1/5625
Part G
[tex]y = -\dfrac{1}{5625}( x^{3} + 25x^{2} - 225x - 5625)\\\\y = \mathbf{ -\dfrac{1}{5625} x^{3} - \dfrac{1}{225}x^{2} + \dfrac{1}{25} x + 1}[/tex]
Answer
Actually, the answer should be -0.0007(x+20)(x+5)(x-15)
Step-by-step explanation:
This is continuing off of the previous answer
PART C
The zeros should be (15,0), (-5,0), and (-20,0)
PART D
x - 15, x + 5, and x + 20
PART E
a(x - 15)(x + 5)(x + 20)
Standard: [tex]a(x^{3} + 10x^{2} -275x-1500)[/tex]
PART F
The y-intercept is at (0,1), so we replace the x's with 0:
1 =[tex][(0)x^{3} +10(0)x^{2} -275(0)-1500][/tex] and this gives us (0+0-0-1500) which also equals -1500
Then we do [tex]\frac{1}{-1500}[/tex] which gives us -0.0006 repeating which rounds to -0.0007
a= -0.0007
PART G
Just place the numbers where they should go and your answer is
y =-0.0007(x + 20)(x + 5)(x - 15)
the placement for (x + 20) (x + 5) and (x - 15) doesn't matter as long as they are behind -0.0007
Consider the equation:
x ^2 −4x+4=2x
1) Rewrite the equation by completing the square.
Your equation should look like (x+a)^2=b or (x-c)^2 =d
Answer:
(x-3)^2 = 5
x = 3 ±sqrt(5)
Step-by-step explanation:
x ^2 −4x+4=2x
Subtract 2x from each side
x ^2 −4x-2x+4=2x-2x
x^2 -6x +4 = 0
Subtract 4 from each side
x^2 -6x+4-4 =0-4
x^2 -6x = -4
Take -6
Divide by 2
-6/2 = -3
Square it
(-3)^2 = 9
Add to each side
x^2 -6x+9 = -4+9
(x-3)^2 = 5
Take the square root
sqrt((x-3)^2) = ±sqrt(5)
x-3 = ±sqrt(5)
Add 3 to each side
x = 3 ±sqrt(5)
Answer:
lusing completing square metjod
x
Step-by-step explanation:
x^2_6x+(_3)^2=_4+9
(x_3)^2=5
x_3=
[tex] \sqrt{5} [/tex]
[tex]x = 3 + or - \sqrt{5} [/tex]
If the area of the rectangle shown below is given by the expression 3x2 + 7x – 6,
and the width is (x + 3), which of the following could represent the length?
Answer:
Step-by-step explanation:
3x² + 7x - 6 = 3x² + 9x - 2x - 2*3
= 3x (x + 3) - 2(x +3)
= (3x - 2)(x + 3)
Area of the rectangle = 3x² + 7x - 6
length * width = 3x² + 7x - 6
length * (x + 3) = (3x -2)(x +3)
length = [tex]\frac{(3x-2)(x+3)}{(x+3)}[/tex]
length = (3x - 2)