Answer:
240.625
Step-by-step explanation:
Circumference = 55 m. = 2pi*r
Radius of enclosure, r = 55/(2pi)
Area of enclosure
= pi (r^2)
= pi (55/2pi)^2
= 55^2/(4pi)
=3025/4pi
substitute pi = 22/7
= 1925/8
= 240.625
What is the area of the regular hexagon shown below?
Answer in complete sentences and include all relevant calculations.
Answer:
6381.4 cm²
Step-by-step explanation:
Applying,
A = n/2(a×h)................ Equation 1
Where A = Area of the regular polygon, n = number of sides of the polygon, a = length of one side of the polygon, h = length of the apothem
But,
a = 2htan∅.............. Equation 2
Where ∅ = angle substands at the center by the regular polygon.
∅ = 360/n.................... Equation 3
Substitute equation 3 into equation 2
a = 2htan(360/n)........... Equation 4
Substitute equation 4 into equation 1
A = n/2[2htan(360/n)×h).............. Equation 5
From the question,
Given: n = 6 side, h = 24.78 cm
Substitute these values into equation 5
A = 6/2[24.78×24.78×2×tan(360/6)]
A = 3[24.78×(24.78×2×tan60°)]
A = 6381.4 cm²
Find X. Round your answer to the nearest TENTH of a degree. (GIVING BRAINLEST)
Answer:
36.8 i think
Step-by-step explanation:
If f(x) = x + 1, and g(x) = 2x,
then
f(g(x)) = [ ? ]x + [ ]
Answer:
2x+1
Step-by-step explanation:
f(g(x))= (2x)+1
(2)x+1
A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal places.) (a) What is the half-life of the substance
Answer:
23 years
Step-by-step explanation:
Step 1: Calculate the rate constant (k) for the radioactive decay
A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.
ln [A]/[A]₀ = - k.t
k = ln [A]/[A]₀ / -t
k = ln 0.97 [A]₀/[A]₀ / -1 year
k = 0.03 year⁻¹
Step 2: Calculate the half-life of the substance
We will use the following expression.
[tex]t_{1/2}[/tex] = ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years
There are 97 students in a nutrition class. The instructor must choose two students at random. Students in a Nutrition Class Academic Year Nutrition majors in-Nutrition majors Freshman 13 20 Sophomores 3.19 Juniors 9 18 Seniors 4 11 What is the probability that a junior Nutrition major and then a freshman non-Nutrition major are chosen at random
Full question attached(original question isn't clear)
Answer:
0.075
Explanation:
Probability is calculated by dividing number of favorable outcomes by total number of outcomes
Now given number of junior Nutrition major and then freshman non-Nutrition major are 8 and 11 respectively
Probability of choosing junior Nutrition major and then freshman non-Nutrition major at random= 8/total of nutrition major × 11/total of non-nutrition major
=8/30×11/39
=4/15×11/39= 44/585 =0.075
4 statistics professors and 6 chemistry professors are available to be advisors to a student organization. The student organization needs two of the professors to be advisors. If each professor has an equal chance of being selected, what is the probability that both professors are chemistry professors?
If someone could find the measurement of angle b that would be fantastic!!!
Step-by-step explanation:
hi, this looks complicated, however, let's deal with it.
using sine rule,
we have,
a/sin A= c/sin C
4.83/sin 46= 5.5/sin C
cross multiply
4.83sin C=5.5sin 46
sin C= (5.5sin46)/4.83
sin C= 0.8191
C=sin inverse of 0.8191
C=54.99 approximately 55
since we have C, we can now find B to get b or rather AC
A+B+C=180. (sum of angles in a triangle)
46°+ B + 54.99°=180°
B+ 100.99°=180°
B°=180°-100.99°
B=79°
since we have B, we can find b or rather AC
using cosine rule,
b²=c²+a²-2 x c x a x cos B
b²= 5.5² + 4.83² - 2 x 5.5 x 4.83 x cos 79°
b²=30.25+23.33-53.13cos79
b²=53.58-10.14
b²=43.44
b=6.59 approximately 6.6
Find the volume of the solid enclosed by the surfaces x² + y² + z² = a , x² + y² +z² = b , (a<b) and z = (x² + y² )½
The solid - I'll call it R - is best described in spherical coordinates:
[tex]R = \left\{(\rho,\theta,\varphi) \mid \sqrt{a}\le\rho\le\sqrt{b}, 0\le\theta\le2\pi, 0\le\varphi\le\dfrac\pi4\right\}[/tex]
Then the volume of R is
[tex]\displaystyle\iiint_R\mathrm dV = \int_0^{\frac\pi4}\int_0^{2\pi}\int_{\sqrt a}^{\sqrt b}\rho^2\sin(\varphi)\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi \\\\\\ \displaystyle = \boxed{\frac{2\pi}3\left(b^{\frac32}-a^{\frac32}\right)\left(1-\dfrac1{\sqrt2}\right)}[/tex]
A 17 ft ladder leans against the side of a house. The top of a ladder is 15 ft off the ground. Find X, the angle of elevation of the ladder. Round answer to the nearest TENTH of a degree. (marking BRAINLEST)
Answer:
61.92
Step-by-step explanation:
What is the volume of a gift box in the shape of a rectangular prism that is 3.5 inches high, 7 inches long, and 6 inches wide
Answer:
V=147
Step-by-step explanation:
V=whl
V=6 inches*3.5 inches*7 inches
V=147
। Find the H.C. F. of :
x2+ 2xy+y and 3ax+3ay
Answer:
Factorizing 4x2 - 9y2, we get
(2x)2 - (3y)2, by using the identities of a2 - b2.
= (2x + 3y) (2x - 3y)
Step-by-step explanation:
hellllllllllllllp me
Answer:
the probability is a fraction or a percentage, some times even a decimal
A person invests 3000 dollars in a bank. The bank pays 4% interest compounded quarterly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 6500 dollars? A=P(1+\frac{r}{n})^{nt} A=P(1+ n r ) nt
What is the value of x
Answer:
Step-by-step explanation:
x+15+x+115+90=380 degree(sum of interior angles of four angles is 360 degree)
2x+220=360
2x=360-220
x=140/2
x=70 degree
For vectors u = i + 6j, v = 5i – 3j, and w = 9i – 2j, determine u • w + v • w.
27
18
90
48
Answer:
This is the explanation you can find answer by rolling it.Susan’s ribbon  is 3.8 metres long. What is the length of her ribbon in millimetres?
show working out
3800 mm
Hope it helps you...
Thank you!!
OFFERING 15 POINTS FOR THIS QUESTION PLS DONT SCAM
Answer:
96
Step-by-step explanation:
3^4 = 81
3 * 5 = 15
81 + 15 = 96
Which inequality represents all values of X for which the product below is defined?
Answer:
x ≥6
Step-by-step explanation:
Given the product:
√(x-6)*√(x+3)
The function has to be defined if x ≥0
Hence;
√(x-6)*√(x+3)≥0
Find the product
√(x-6)(x+3)≥0
Square both sides
(x-6)(x+3)≥0
x-6≥0 and x+3≥0
x≥0+6 and x ≥0 - 3
x ≥6 and x ≥-3
Hence the required inequality is x ≥6
The recipe for a fruit smoothie requires 2 cups of fruit per 6 cups of yogurt to maintain a 1/3 ratio. While making the fruit smoothie, Suzy accidentally puts 3 cups of fruit into the pitcher. How many cups of yogurt should be put in the pitcher to maintain the ratio of 1/3?
Simplify the expression using trigonometric identities (csc θ – csc θ · cos^2 θ).
options:
A)
sin^2 θ
B)
sin θ · tan θ
C)
sin^3 θ
D)
sin θ
Answer:
Solution given:
cscθ -cscθcos²θ
taking common
cscθ(1-cos²θ)
we have
1-cos²θ=sin²θ and cscθ=1/sinθ
now
1/sinθ*sin²θ
=sinθ
so
D)
sin θ is a required answer.
A running track has two semi-circular ends with radius 29m and two straights of length 91.3m as shown.
Calculate the total distance around the track rounded to 1 DP.
Answer:
Step-by-step explanation:
Convert 25 miles into kilometres
Answer:
1 miles= 1.609km
so, 25x1.609 = 40.225km
Find the perimeter of this semi-circle with radius, r = 22cm. Give your answer rounded to 1 DP.
Answer:
69.1 cm
Step-by-step explanation:
Circumference of a circle
c = 2πr
Half of that would be a semi-circle
c = πr
c = π * 22
c = 69.115038379
Rounded
69.1 cm
Consider the LD50 of Drug X above. Draw a vertical dashed line starting at 10 mg/kg on the x-axis and ending on the graphed line. Draw a horizontal line starting at 50% on the y-axis and ending on the graphed line. This is the LD50 of Drug X. What is the LD50 of Drug X
Solution :
LD50 is a test that used by the scientist and by the medical practitioners to determine the toxicity of any chemical compounds. It involves introducing the different dose levels of the chemical compound that is to be tested to the group of the experimental subjects.
The LD50 graph of the Drugs X is attached below.
From the graph, we can see that the LD50 level of the drug X is 10 mg/kg.
You play a game where you first choose a positive integernand thenflip a fair coinntimes. You win a prize if you get exactly 2 heads. How should youchoosento maximize your chance of winning
Solution :
The probability of winning when you choose n is = [tex]$^nC_2\left(\frac{1}{2}\right)^n$[/tex]
[tex]$n\left(\frac{n-1}{2}\right)\times \left(\frac{1}{2}\right)^n = n(n-1)\left(\frac{1}{2}\right)^{n+1}$[/tex]
Apply log on both the sides,
[tex]$f(n) = \log\left((n)(n-1)\left(\frac{1}{2}\right)^{n-1}\right) = \log n +\log (n-1)+(n+1) \ \log\left(\frac{1}{2}\right)$[/tex]
Differentiation, f(x) is [tex]$f'=\frac{1}{x}+\frac{1}{(x-1)}+\log\left(\frac{1}{2}\right)$[/tex]
Let us find x for which f' is positive and x for which f' is negative.
[tex]$\frac{1}{x}+\frac{1}{(x-1)} > 0.693$[/tex] , since [tex]$\log(1/2) = 0.693147$[/tex]
For x ≤ 3, f' > 0 for [tex]$\frac{1}{x}+\frac{1}{x-1}+\log\left(\frac{1}{2}\right)>0$[/tex]
[tex]$\frac{1}{x}+\frac{1}{x-1}-0.6931470$[/tex]
That means f(x) is increasing function for n ≤ 3
[tex]$\frac{1}{x}+\frac{1}{x-1}< 0.693147 $[/tex] for x > 4
f' < 0 for n ≥ 4, that means f(n) is decreasing function for n ≥ 4.
Probability of winning when you chose n = 3 is [tex]$3(3-1)\left(\frac{1}{2}\right)^{3+1}=0.375$[/tex]
Probability of winning when you chose n = 4 is [tex]$4(4-1)\left(\frac{1}{2}\right)^{4+1}=0.375$[/tex]
Therefore, we should chose either 3 or 4 to maximize chances of winning.
The probability of winning with an optimal choice is n = 0.375
determine using pascal's method. (2p-3q)^5=(p-q)^5
Hamdan says that when you add fractions with the same denominator, you can add the numerators and keep the same denominator. Is Hamdan correct?
Answer:
Yes, Hamdan is correct.
Step-by-step explanation:
Let the two fractions are q/r and s/r.
Here, the denominator is same for both the fractions.
So, as we add them, add the numerators and the denominators remains same.
[tex]\frac{q}{r}+\frac{s}{r}\\\\=\frac{q + s}{r}[/tex]
For example
[tex]\frac{3}{5}+\frac{4}{5}\\\\=\frac{3 + 4}{5}\\\\=\frac{7}{5}[/tex]
So, Hamdan is correct.
Jon earns $3 for every package he wraps. To take a package to the post office, Jon earns 1.65 times as much as he earns for wrapping a package. How much will Jon earn for wrapping a package and taking it to the post office?
Answer:
a1 = 1, a2 = 2Step-by-step explanation:
Find the length of the diagonal of a rectangle. Round your answer to nearest tenth.
Answer:
19.2m
Step-by-step explanation:
"Slice" the rectangle into two right triangles (slice along the diagonal). Now you can use the Pythagorean theorem to calculate the length of the diagonal:
[tex]a^{2} +b^{2} =c^{2} \\12^{2}+15^{2} =c^{2} \\144+225=c^{2} \\\sqrt{369} =\sqrt{c^{2} }\\19.2m =c[/tex]
Alisa spent 1/4 of her money on a shirt and 2/5 of her money on shoes. What fraction of Alisa's money has been spent?
Answer:
[tex] \frac{13}{20} [/tex]