I need help , Please help .

Answer:

it's 10 you can see it goes by 2 and the others fo by 1 pretty simple

Answer:

1. The specific heat of the meatal is approximately 0.266 J/(g·°C)

2. 46.6334 kJ

Explanation:

1. The given mass of the sample of metal, m = 110.0 g

The temperature change of the metal when heat is added, ΔT = 10.0°C

The amount of head that was added, ΔH = 70.0 Calories = 292.88 Joules

The formula for heat heat capacity of a material is given as follows

Q = m × c × ΔT

Where;

Q = The quantity of heat added = 292.88 Joules

m = The mass of the material = 110.0 g

ΔT =  The temperature change = 10.0°C

c = The specific heat capacity of the material

We get;

c = ΔH/(m × ΔT)

Which gives;

c = 292.88 J/(110.0 g × 10.0°C) ≈ 0.266 J/(g·°C)

2. The given mass of aluminum, m = 550.0 g

The initial temperature of the aluminum, T₁ = 14.0°C

The final temperature of the aluminum, T₂ = 108.0°C

The specific heat of aluminum, c = 0.902 J/(g·°C)

We get;

Q = m × c × (T₂ - T₁)

Q = 550.0 g × 0.902 J/(g·°C) × (108.0°C - 14.0°C) = 46,633.4 joules = 46.6334 kJ

The heat that must be supplied to 550.0 g of aluminum pan to raise the temperature of the pan from 14.0°C to 108.0°C, Q = 46.6334 kJ.

Answer: the divergent one goes where it looks like there a crack because when you think about divergent it means dividing like seperating.(igneous rock) is where the divegent one goes.

the one that is no plate boundary is sedimentary rock and it occurs by because there is nothing there for it todo there

Explanation:

Answer:

Explanation:

When resistors are connected in parallel combination, then equivalent resistance is given by,

[tex] \to \quad \bf{ \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p}}[/tex]

Inserting values,

[tex] \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p} } \\ \\ \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{221} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{(R_1)(221)} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{221R_1} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { 120.7(221+R_1) = 221R_1(1)} \\ \\ \to \quad \bf { 26674.7 + 120.7R_1= 221R_1} \\ \\ \to \quad \bf { 26674.7= 221R_1- 120.7R_1} \\ \\ \to \quad \bf { 26674.7 = 100.3R_1} \\ \\ \to \quad \bf { \dfrac{26674.7 }{100.3} =R_1} \\ \\ \to \quad\underline{\boxed{ \bf { 265.9 \; \Omega=R_1}}} \\ [/tex]

Answer:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

Explanation:

Materials when heated emit a continuous spectrum with all wavelengths.

Hot gas gases emit a spectrum that depends on the transitions between atomic states, therefore it is a discrete spectrum.

When reviewing the answers, the correct one is:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

Answer:

The collision is inelastic

Explanation:

There are two kinds of collision; elastic collision and inelastic collision. In an elastic collision, both momentum and kinetic energy are conserved.

However, in an inelastic collision, kinetic energy is not conserved. So, when the bumper of two cars collide, the cars come to a stop because the collision is inelastic.

Answer:

T₂ = 1937.68 N

Explanation:

First, we will calculate the weight of the object:

[tex]W = mg = (478\ kg)(9.81\ m/s^2)\\W = 4689.18\ N[/tex]

Now, we will calculate the resultant tension in the ropes. Since the ropes are perpendicular. Therefore,

[tex]T = \sqrt{T_1^2+T_2^2}\\[/tex]

where,

T = Resultant Tension

T₁ = Tension in rope 1

T₂ = Tension in rope 2

According to the given condition tension in the first rope is 2.2 times the tension in the second rope:

T₁ = 2.2 T₂

Therefore

[tex]T = \sqrt{(2.2T_2)^2 + T_2^2}\\\\T = 2.42T_2[/tex]

Now, the weight of the object must be equal to the resultant tension for equilibrium:

[tex]T = W\\2.42T_2 = 4689.18\ N\\\\[/tex]

T₂ = 1937.68 N

Answer:

rhastuutse5r says he n and happiness of

Explanation:

UKDIAMOND is a great place to live and live and live in the world best friend tum jio hjaro and happiness of the day and the day of the day of the day of the day of the day of the day of 2nd century and the day of the day of

Answer:

Isolated

Explanation:

According to the law of conservation of momentum, in a(n) isolated system, the initial total momentum before a collision equals the final total momentum. I just did it on A p e x.

Answer:

negative charge

Explanation:

On an atomic scale, those are called "ions", and negatively charged ions are called anions.

The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is

Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.

Explanation:

Given: Frequency = 140 Hz

Speed = 340 m/s

wavelength = ?

Formula used to calculate the wavelength is as follows.

[tex]\lambda = \frac{v}{f}[/tex]

where,

[tex]\lambda[/tex] = wavelength

v = speed

f = frequency

Substitute the values into above formula.

[tex]\lambda = \frac{v}{f}\\= \frac{340 m/s}{140 Hz} (1 Hz = 1 s^{-1})\\= 2.43 m[/tex]

Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.

Answer:

B. It changes the objects direction

Answer:

i would say the third one

Explanation:

may i be brainliest?

Answer:

C. Photosynthesis

Explanation:

Photosynthesis is a process by which plants and photosynthetic bacteria obtain their food in presence of sunlight from water and carbon dioxide. They produce glucose as the food and oxygen is emitted as the byproduct. The equation for photosynthesis is - 6H2O+6CO2 → C6H12O6 + 6O2

Thus, the correct answer is 'C.Photosynthesis.'

Answer:

the right answer is option 2

Answer:

Ține ogaru ca să o lingă pe măta în cur să nu mai facă alt prost ca tine

increase air resistance, which decreases gravitational acceleration

Answer:

how tightly strung the wire is

-- Make the string tighter or looser.

-- Keep the same length, but make the string thicker or thinner.

-- Touch the string at a point exactly 1/2, 1/3, 1/4, or 1/5 of its length from one end.

Answer: Friction that acts on a sliding object

Explanation:

Answer:

15.4

Explanation:

770x14% = 107.8

rearrange f =kx to get k (constant)

k = f/x

x is the distance stretched , so 42 - 35 =7

so 107.8/7 =15.4

can someone double check

Answer:

k = 44000 N/m is the answer.

Explanation:

Gravitational Potential Energy = 770J

Elastic Potential Energy = 14% of 770J

= 14/100 × 770

= 107.8J

Extension (x) = 42 - 35 = 7cm = 7 × 10⁻²m

To find the spring constant (k)

Elastic Potential Energy Formula:

[tex]U = \frac{1}{2}kx^2[/tex]

107.8 = 1/2 × k × (7 × 10⁻²)²

215.6 = 0.0049 × k

k = 215.6/0.0049

k = 44000 N/m

Answer:

Polished surfaces reduce heat loss

Answer:

(This will depend on the type of fuel, I will assume that the fuel is petrol)

First, let's find the expected energy consumption in the US for the next 10 years.

We know that in one year, a person consumes 3.5*10^11 joules.

There are 310,000,00 people on the US

Then the total consumption in one year is:

310,000,000*3.5*10^11 joules = 1.085*10^20 J

In 10 years the consumption is 10 times the consumption of a single year, then the expected energy consumption in the US for the next 10 years is:

10*1.085*10^20 J = 1.085*10^21 J

Now let's find the mass of fuel required.

We know that a liter of petrol has 31,536,000 joules of energy,

And a liter of petrol weights 0.75 kg

To find the number of liters of petrol that we need, we need to find the quotient between the expected energy consumption in the next 10 years and the energy of a single liter of petrol, this is:

N = (1.085*10^20 J)/(31,536,000 j) = 3.44*10^13

We will need  3.44*10^13 liters of petrol.

And the total mass of petrol will be:

M = 3.44*10^13*0.75 kg = 2.58*10^13 kg of fuel.

Answer:

The equivalent resistance of the three resistors is 18 ohms.

Explanation:

The value of three resistors are 6 ohms.

We need to find the equivalent resistance of the resistors. In series combination, the equivalent resistance is given by :

R = R₁ + R₂ + R₃ +.....

Put all the values,

R = 6+6+6

R = 18 ohms

Hence, the equivalent resistance of the three resistors is 18 ohms.

Answer:

B

Explanation:

remember that you are looking for the value of the graph

to take into account or value a lot: prize, estimate to value your opinion. 2nd: estimate or assign the monetary value of: appraise a necklace. b: qualify or scale in utility, importance or general value: evaluate. value.

Answer:

elephant fall faster then a mouse because of the air resistance.

hope it helps.

Explanation:

elephant fall faster than a mouse and because of the air resistance .

hope it is helpful to you

Explanation:

[tex]speed : U = 20 \: m {s}^{ - 1} \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {20}^{2} + (2 \times a \times S) \\ a = \frac{200}{S} \: m {s}^{ - 1} [/tex]

Q.1 - V = u + at

u = 0, a = g = 9.8, t = 1

V = 0+9.8*1 = 9.8 m/s

Q 2- In horizontal position the velocity remains same hence a= dv/t, since change in velocity is zero the acceleration also equal to zero

Q.3- After neglecting the air resistance at 45° angle the maximum range is obtained.

let's prove, consider the range have maximum angle at θ, now range is given by

R = u²Sin2θ/g where sin2θ can we written as 2sinθ.cosθ.

Now the range value is directly proportional to the product of sin & cos of firing angle & this maximum value is obtained at 45°

Q.4 The range of two angle will be same if and only if they give 90° on addition.

20+x = 90,

x = 90-20 = 70°

Q.5 The motion with constant acceleration is known as uniformly accelerated motion.

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Answer:

Explanation:

1.

u=0m/s

v=?

a=9.8m/s²

t=1sec

now

we have

v=u+at

v=0+9.8*1

v=9.8m/s

3.

angle is measured in sin and cos angle where maximum angle's value is gained by 45°

4.

we have

range

R=[tex]\frac{u²sin2\theta}{g}[/tex]

For

angle =20°

R1=[tex]\frac{u²sin2*20}{g}[/tex].......[1]

another angle be [tex]\theta[/tex]

R2=[tex]\frac{u²sin2\theta}{g}[/tex].......[2]

since R1=R2

By comparing we get

Sin40=Sin([tex]2\theta[/tex])

Sin(180-40)=Sin([tex]2\theta[/tex])

we

140=[tex]2\theta[/tex]

[tex]\theta[/tex]=70°