where is the question?
PLSSS HELP
tge question is in the picture
-2 1/2 - (-1 3/4)
When subtracting a negative vile the equation becomes addition:
-2 1/2 + 1 3/4 = -3/4
Answer: -3/4
What is the average rate of change between: x = 1 and x = 2? x = 2 and x = 3? x = 3 and x = 4? x y 1 2 3 4 5 4 8 12
Answer:
The average rate of change between x = 1 to x = 2 is 2, from x = 2 to x = 3 is 4 and from x = 3 to x = 4 is 8.
Step-by-step explanation:
-
4. 3x² - 2x - 1 = 0
A patient is prescribed Coreg 12.5 mg by mouth twice a day. How many tablets should the patient
receive for one dose if the medication available is 6.25 mg/tablet?
Answer:
yes...
Step-by-step explanation:
k
A line that passes through (3, 1) and (0, -3)
What is the y-intercept of the graph of the equation [tex]y=x(1/4) - 2/3[/tex]
A. -2/3
B. 2/3
C. -1/4
D. 1/4
Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = [tex]\frac{1}{4}[/tex] x - [tex]\frac{2}{3}[/tex] ← is in slope- intercept form
with y- intercept c = - [tex]\frac{2}{3}[/tex] → A
Jorge wants to find the height of the house, help him find it.
Answer:
:)
Step-by-step explanation:
:)
Are the following two lines parallel, perpendicular, neither, or the same line?
3x+4y = 2
4x+3y = 2
what are they?
Answer:
Neither.
Step-by-step explanation:
Manipulate the formulas into slope-intercept form which is [tex]y=mx+b[/tex].
In order for them to be parallel, m needs to be the same. Perpendicular, m for one needs to be the negative reciprocal of the other [tex]m=-\frac{1}{m}[/tex].
Let's see what we get.
(1)
[tex]3x+4y=2\\4y=-3x+2\\y=-\frac{3}{4}x+1/2[/tex]
(2)
[tex]4x+3y=2\\3y=-4x+2\\y=-\frac{4}{3}x+2/3[/tex]
They are reciprocals, but they are both negative. So, they are not the same line, perpendicular, nor parallel.
Also, you can graph these equations on desmos and see easily that they have none of these relationships.
how many feet in 13 miles, 176 yards?
Compute the integral Z Z Z U y dV , where U is the part of the ball of radius 2, centered at (0, 0, 0), that lies in the 1st octant. Recall that the first octant is the part of the 3d space where all three coordinates x, y, z are nonnegative. (Hint: You may use cylindrical or spherical coordinates for this computation, but note that the computation with cylindrical coordinates will involve a trigonometric substitution - so spherical cooridnates should be preferable.)
As the hint suggests, convert to spherical coordinates using
x = p cos(u) sin(v)
y = p sin(u) sin(v)
z = p cos(v)
dV = dx dy dz = p² sin(v) dp du dv
Then U is the set
[tex]U = \left\{ (p,u,v) \mid 0\le p\le2 \text{ and } 0\le u\le \dfrac{\pi}2 \text{ and } 0\le v\le\dfrac{\pi}2\right\}[/tex]
and the integral of y over U is
[tex]\displaystyle \iiint_U y \, dV = \iiint_U p\sin(u)\sin(v) \cdot p^2 \sin(v) \, dV[/tex]
[tex]\displaystyle \iiint_U y \, dV = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \int_0^2 p^3 \sin(u) \sin^2(v) \, dp \, du \, dv [/tex]
[tex] \displaystyle \iiint_U y \, dV = \frac{2^4-0^4}4 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \sin(u) \sin^2(v) \, du \, dv [/tex]
[tex]\displaystyle \iiint_U y \, dV = 4 \cdot \left(-\cos\left(\frac\pi2\right) + \cos(0)\right) \int_0^{\frac\pi2} \sin^2(v) \, dv [/tex]
[tex]\displaystyle \iiint_U y \, dV = 4 \cdot \frac12 \int_0^{\frac\pi2} (1-\cos(2v)) \, dv [/tex]
[tex]\displaystyle \iiint_U y \, dV = 2 \left(\left(\frac\pi2 - \frac12 \sin\left(2\cdot\frac\pi2\right)\right) - \left(0 - \frac12 \sin\left(2\cdot0\right)\right) \right)[/tex]
[tex]\displaystyle \iiint_U y \, dV = \pi - \sin(\pi) = \boxed{\pi}[/tex]
QUESTION 7.1 POINT
Translate the given phrase into an algebraic expression and simplify if possible: the difference of -3 and the product of w
and 2
Answer:
-3 - (2w)
Step-by-step explanation:
hope this helps!
30x^8-4x^7+6x^4/-6x^3 perform division
Answer:
[tex]-\frac{x(15x^4-2x^3+3)}{3}[/tex]
Step-by-step explanation:
[tex]\frac{30x^8-4x^7+6x^4}{-6x^3}[/tex]
The first thing I would do is to factor the numerator. All coefficients there are divisible by 2, and all variables are divisible by x⁴. I'll also move the negative sign to the left.
[tex]-\frac{2x^4(15x^4-2x^3+3)}{6x^3}[/tex]
Next, you can simplify 2/6 to 1/3:
[tex]-\frac{x^4(15x^4-2x^3+3)}{3x^3}[/tex]
Finally, the last thing you can do is simplify x⁴/x³ to x/0:
[tex]-\frac{x(15x^4-2x^3+3)}{3}[/tex]
That's as simplified as it gets.
Solve for x and y. (Geometry)
Step-by-step explanation:
All angles of the ∆ are same. So it's a equilateral ∆ . So all sides will also be equal .
16 + y = 46
y = 46 -16 = 30
And ,
60 + x + (180-80) = 180
-20 +x = 0
x = 0 +20
x = 20°
Miss Jurkovac went to Costa Rica for 6 days and saw 42 monkeys. If she saw 84 monkeys, how many days was she there?__________ days
Answer:
Step-by-step explanation:
6 times 2 is 12
42 multiplied by 2 is 84
therefore the answer is 12 days.
Ms. April likes for the twenty students in her
class to have a carton of milk each day at break
time. She sends three of her students down to
the cafeteria to ask for the cartons of milk, but
she likes to mix things up a bit and wants to
send a different group of students down every
day. Will she have enough different groups of
three students in her class of twenty students to
send a different group every day of the school year? (There are 180 days in the school year)
Answer:
Ms. April will not have enough students.
Step-by-step explanation:
This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.
Answer:
Ms. April will not have enough students.
Step-by-step explanation:
This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.
please help me with this sum I will mark you as brainest
Answer:
6/8 × 6 = 9/22/5 × 4 = 8/59/3 × 9 = 277/4 × 8 = 148/6 × 2 = 8/34/9 × 7 = 28/93/8 × 3 = 9/87/2 × 4 = 146/3 × 6 = 12 8/9 × 3 = 8/3Hope It's Help
Which equation represents a line which is parallel to the line y=1/5x -1
5x +y =3
X+ 5y =10
5y - x = -20
5x - y = -3
9514 1404 393
Answer:
(c) 5y - x = -20
Step-by-step explanation:
When the x- and y-terms are on the same side of the equation, the slope of the line will be ...
m = -(coefficient of x)/(coefficient of y)
So, the slopes of the offered choices are ...
a) -5/1 = -5
b) -1/5
c) -(-1)/5 = 1/5 . . . . . parallel to given line
d) -5/-1 = 5
The lines will be parallel when their slopes are the same. The slope of the given line is the coefficient of x, 1/5. Choice C has the same slope.
Does anyone know the answer.With explanation plz.
Answer: He sold 1,800 merchandise
Step-by-step explanation: 426 - 300 = 126 ÷0.07 = 1,800
I dont know if im right though
A 13 foot ladder is placed
5 feet away from a wall
How many feet up the wall
will the ladder reach?
Answer: 12 feet up
Step-by-step explanation:
This problem models a right triangle, in which the ladder is the hypotenuse and the distance away from the wall is one of the legs. Thus, you may use the Pythagorean Theorem (a^2 + b^2 = c^2)
[tex]a^2+b^2=c^2\\5^2+b^2=13^2\\25+b^2=169\\b^2=144\\b=12[/tex]
N.B. There are some very useful sets of numbers that can help you with this unit.
They are called Pythagorean triplets, and they are the sets of whole numbers that make right triangles. The important ones are 3, 4, 5, and 5, 12, 13 (And their multiples, like 6, 8, 10(3,4,5 *2))
Hope it helps :) and let me know if you want me to elaborate further.
which has one solution:
2x + 2y = 180
0.1x + 7y = 78
If 2x - 3x = 3 what is 16x / 64x?
Answer:
[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
The problem [tex]2x - 3x = 3[/tex] is incorrect. The correct answer for that one is [tex]-x \:\sf{or\:-1[/tex]
[tex]\sf{Simplify\: the\: expression.[/tex]
[tex]\sf{\frac{16x}{64x} = \frac{1}{4}[/tex]
[tex]x=\frac{1}{4}[/tex]
Therefore, the answer is [tex]\frac{1}{4}[/tex]
What is the product 1.3 × 0.71? Enter your answer in the box.
Answer:
.923
Step-by-step explanation:
1.3 X 0.71 = .923
:))
find the point (x,y) on the curve where dy/dx = 0
a. By the chain rule,
[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt}\cdot\dfrac{dt}{dx} = \dfrac{dy}{dt}\cdot\dfrac{1}{\frac{dx}{dt}}[/tex]
Given that [tex]y=e^t+e^{-t}[/tex] and [tex]x=e^{-t}[/tex], we have the derivatives
[tex]\dfrac{dy}{dt} = e^t -e^{-t}[/tex]
[tex]\dfrac{dx}{dt} = -e^{-t}[/tex]
and so
[tex]\dfrac{dy}{dx} = \dfrac{e^t - e^{-t}}{-e^{-t}} = 1-e^{2t}[/tex]
Set this equal to zero and solve for t :
[tex]1-e^{2t} = 0[/tex]
[tex]1 = e^{2t}[/tex]
[tex]\ln(1) = \ln\left(e^{2t}\right)[/tex]
[tex]0 = 2t \ln(e)[/tex]
[tex]0 = 2t[/tex]
[tex]t=0[/tex]
This value of t corresponds to x = e⁰ = 1 and y = e⁰ - 1/e⁰ = 1 - 1 = 0. So the only point on the curve where the derivative dy/dx is zero is (1, 0).
b. Compute the second derivative. Since dy/dx is a function of t, we'll momentarily replace it with f(t). By the chain rule,
[tex]\dfrac{d^2}{dx^2} = \dfrac d{dx} \dfrac{dy}{dx} = \dfrac{df}{dx} = \dfrac{df}{dt}\cdot\dfrac{dt}{dx} = \dfrac{df}{dt}\cdot\dfrac{1}{\frac{dx}{dt}}[/tex]
We have
[tex]\dfrac{df}{dt} = -2e^{2t}[/tex]
and we've already committed dx/dt. So
[tex]\dfrac{d^2}{dx^2} = \dfrac{-2e^{2t}}{-e^{-t}} = 2e^{3t} [/tex]
Substitute the first and second derivative into the differential equation:
[tex]\left(\dfrac{d^2y}{dx^2}\right)^2 + \dfrac{dy}{dx} - 1 = 0[/tex]
[tex]\left(2e^{3t}\right)^2 + (1-e^{2t}) - 1 = 0[/tex]
[tex]4e^{6t} -e^{2t}= 0[/tex]
[tex]e^{2t} (4e^{4t} - 1) = 0[/tex]
[tex]4e^{4t} - 1 = 0[/tex]
[tex]4e^{4t} = 1[/tex]
[tex]e^{4t} = \dfrac14[/tex]
[tex]\ln\left(e^{4t}\right) = \ln\left( \dfrac14\right)[/tex]
[tex]4t \ln(e) = -\ln(4)[/tex]
[tex]4t = -\ln(4)[/tex]
[tex]t = -\dfrac{\ln(4)}4[/tex]
Solve this system of linear equations. Separate
the x- and y-values with a comma.
-20x = -16 - 9y
- 14x = -22 - 9y
Answer:
(x, y)
(-1, -4)
Step-by-step explanation:
[tex]-20x=-16-9y\\-14x=-22-9y[/tex]
Solve by elimination, subtract the 2nd row from the 1st row:
[tex](-20x-(-14x))=(-16-(-22))+(-9y-(-9y))\\(-20x+14x)=(-16+22)+(-9y+9y)\\-6x=6[/tex]
Solve for x in the equation above
[tex]-6x=6\\x=-1[/tex]
Now we have the value of X, substitute it into any of the 2 original equations:
[tex]-20x=-16-9y\\-20(-1)=-16-9y[/tex]
Solve for y:
[tex]-20(-1)=-16-9y\\20=-16-9y\\36=-9y\\-4=y\\y=-4[/tex]
Please mark brainliest if this answer helps you. I can provide more information if needed.
What is the slope and y intercept form of -5x + 3y =-9.
What is the slope and y intercept form of -x +2y =-20
fast help.
Answer:
y = 5/3x - 3 and y = 1/2x - 10
Step-by-step explanation:
A. -5x + 3y = -9
In order to go from standard to slope-intercept form, we want to isolate y on the left side. We start by adding 5x to both sides:
3y = -9 + 5x
Next, we divide both sides by 3:
y = (-9 + 5x)/3
And then distribute:
y = -9/3 + 5x/3
And finally simplify:
[tex]y = -3 + \frac{5}{3}x[/tex]
And move the numbers on the right to fit the form y = mx + b:
[tex]y = \frac{5}{3}x-3[/tex]
B. -x + 2y = -20
In order to go from standard to slope-intercept form, we want to isolate y on the left side. We start by adding x to both sides:
2y = -20 + x
Next, we divide both sides by 2:
y = (-20 + x)/2
And then distribute:
y = -20/2 + x/2
And finally simplify:
[tex]y = -10 + \frac{1}{2}x[/tex]
And move the numbers on the right to fit the form y = mx + b:
[tex]y = \frac{1}{2}x - 10[/tex]
a meal came to $16.41 without tax. calculate the 6% sales tax, and then calculate the 15% tip based on the sum of the meal and the tax. what is the total cost of the meal?
Answer:
$20
Step-by-step explanation:
correct me if im wrong(┬┬﹏┬┬)
What is the rectangular form of theta = 3pi/4?
Please answer this question if you 100% know this answer.
a. x - y = 0
b. x - y = 1
c. x + y = 0
d. x + y = 1
The answer was not a.
Answer:
c. x + y = 0
Step-by-step explanation:
The terminal ray of the angle θ = 3π/4 extends to the upper left through the 2nd quadrant with a slope of -1. It lies on the line ...
y = -x
x + y = 0 . . . . . . add x to get this standard form equation
thanks in advance ill mark brainliest
Answer:
100º
Step-by-step explanation:
Cooresponding angles are congruent
11x + 1 = 10x + 10
Subtract 10x from both sides
x + 1 = 10
subtract 1 from both sides
x = 9
θ = 11x + 1
θ = 11(9) + 1
θ = 99 + 1
θ = 100º
Need help with this question ASAP tysm
Step-by-step explanation:
sorry for my bad handwriting, hope it helps
Solve the system of linear equations using any method you choose:
-6x + 3y = 18
10x - y = 4
9514 1404 393
Answer:
(x, y) = (1.25, 8.5)
Step-by-step explanation:
I choose to put these equations into reduced general form, then use the "cross multiplication method" to solve.
2x -y +6 = 0
10x -y -4 = 0
d1 = 2(-1) -10(-1) = 8
d2 = -1(-4) -(-1)(6) = 10
d3 = 6(10) -(-4)(2) = 68
Solutions are ...
x = d2/d1 = 10/8 = 1.25
y = d3/d1 = 68/8 = 8.5
The solution is (x, y) = (1.25, 8.5).
_____
Additional comment
I like a graphing calculator for a quick and easy solution. When the values are not integers, I like an algebraic solution to see what the exact values are.
__
The "cross multiplication method" is similar to Cramer's rule in that determinants of pairs of coefficients are computed. If you look up this method, videos will show you a variation that is slightly different. Here, we determined d1, d2, and d3 as the 2×2 determinant of the coefficients in adjacent columns of the array you get from the general form equations with the first column repeated:
[tex]\begin{array}{cccc}2&-1&6&2\\10&-1&-4&10\end{array}[/tex]
In each pair, the determinant is the difference between the product of numbers on the down-diagonal and the product of numbers on the up-diagonal.
The determinants relate to the x- and y-values by ...
1/d1 = x/d2 = y/d3 ⇒ x = d2/d1, y = d3/d1
There is a Vedic solution method for linear equations that is similar to this, but starts from equations in standard form. As a consequence, the cross-differences are done in a different order.
__
Standard form: ax +by = c
General form: ax +by +c = 0