I need help hhhhhhhhhheeeeeeellllllppppp

Answer:

Its statistical

Step-by-step explanation:

Answer:

x=3.2

Step-by-step explanation:

4(6 – x) + 4 = 2 (3x + 1) – 6

24 - 4x + 4 = 6x + 2 - 6

28 - 4x = 6x -4

-4x - 6x = - 4 - 28

-10x = - 32

divide both sides

x = 16/5 or x = 3.2

hope this helps :)

Answer:

Example 1: - If the item's label displays the weight as 3 lb 2 oz, type the shop name and item's brand, enter 3 in the pounds field, leave the 00 (decimal) value unchanged, enter 2 in the ounces field, leave the 00 (decimal) value unchanged, fill out the Price field and Calculate to get the price per ounce

Answer:

12 ounces

Step-by-step explanation:

3.60 = .3x

divide by .3 on both sides

12 = x

Answer:

8%

Step-by-step explanation:

Starting Principal: $  

3,000.00

Years:    

3

Annual Interest Rate:    

8

%

Results

Future Value, using...

 Simple Interest: $  

3,720.00

 Annually Compounded Interest: $  

3,779.14

Answer:

Step-by-step explanation:

if the speed is 6 bracelets per hour then the table will go like this

2   12

5  30

7  42

11  66

16 and 2/3  hours is 100 bracelets

Answer:

Step-by-step explanation:

Temperature change:

Change in 1 minute:

Answer: 5.4  or  5 2/5 Hope this helps have a GREAT night

Step-by-step explanation:

Answer:

Yes, no, no

Step-by-step explanation:

Answer:10 baskets yes

100 baskets yes

1000 baskets no

Step-by-step explanation:

The number of marbles Peter had when he arrived home was 43 marbles

What is Percentage?

A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, %

Given data ,

The number of marbles Peter had on his way home = 171

The amount of marbles he lost on his way home = ( 3/4 ) th

Now , the amount of marbles Peter have left = 1 - amount of marbles he lost on his way home

The amount of marbles Peter have left = 1 - 3/4

                                                                = ( 1 / 4) th

So , The number of marbles Peter had left when he arrived home is =

Amount of marbles Peter have left x Number of marbles Peter had

The number of marbles Peter had left when he arrived home is = (1/4) x 171

= 171 / 4

= 42.75

≈ 43 marbles

Hence , the number of marbles Peter had left when he reached home is 43

To learn more about percentage click :

https://brainly.com/question/12861068

#SPJ2

Answer:

1. n = 4

2. n = -29

3. n = -28

4. n = -48

5. n = -22

6. n = 97

7. n = 220

8. n = -18

9. n = 36

Step-by-step explanation:

1. -n = -4

Multiply both by -1 to get n = 4

2. 12 + n = -17

Subtract 12 from both sides of the equation to get n = -29

3. -n/14 = 2

Multiply by 14 on both sides of the equation to get -n = 28

Multiply -1 on both sides of the equation to get n = -28

4. -42 = n + 6

Subtract 6 from both sides of the equation to get -48 = n or n = -48

5. -4n = 88

Divide -4 on both sides of the equation to get n = -22

6. n + -3 = 94

Add 3 to both sides of the equation to get n = 97

7. 11 = -n/-20

Multiply by -20 on both sides of the equation to get -220 = -n or -n = -220

Multiply -1 on both sides of the equation to get n = 220

8. -108 = 6n

Divide by 6 on both sides of the equation to get -18 = n or n = -28

9. 67 = 31 + n

Subtract 31 from both sides of the equation to get 36 = n or n = 36

I Hope That This Helps! :)

Answer:

B, B, A, A, B, B

Step-by-step explanation:

i think this is the correct answer! lmk if its good! :)

Answer:

2a=-16

Step-by-step explanation:

all I could think of

Answer:

[tex]\boxed{k = \frac{log_{e}(\frac{L +A }{A} )}{t} }[/tex]

Answer:

[tex]measure angle 1 = 62 ------> given\\measure angle 4 = 62 --------> vertical angle theorem[/tex]

Step-by-step explanation:

vertical angle theorem states that the angle vertical from another angle has to be congruent

p.s. i found it

Answer: Hi wadfasd here plz mark brainliest and answer can be found below ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

I think the answer is the 4th one but let me know if i am wrong!

Step-by-step explanation:

Answer:

The student's GPA = 3.24

Step-by-step explanation:

To determine the student's GPA for the term,

First, we will determine the weighted grade points and then divide the result by the total credit.

The weighted grade point is the sum of the grade points in the courses.

Grade point for a course is calculated by multiplying the grade by the course credit.

For the Math course,

Grade point = 3.6 × 5 = 18.0

For the Music course,

Grade point = 2.5 × 2 = 5.0

For the Chemistry course,

Grade point = 3.0 × 5 = 15.0

For the Journalism course,

Grade point = 3.4 × 5 = 17.0

Hence,

The weighted grade point = 18.0 + 5.0 + 15.0 + 17.0

The weighted grade point = 55.0

Total credit = 5 + 2 + 5 + 5 = 17

∴ The student's GPA = 55.0 / 17 = 3.24

Hence, The student's GPA = 3.24

Answer:

Step-by-step explanation:

Approximate rate of change:

Answer:

Using mid point theorem, A line segment joining the mid points of the two sides of the triangle, is equal to half the length of the third side.

D and E are the mid points. Hence,

DE=

2

1

AC

DE=

2

1

(6.4)

DE=3.2cm

Answer:

AD=BE

Step-by-step explanation:

Because AB and BC are equal, their lengths are also equal and also it is an Isosceles triangle. Therefore the midpoint of AB or the half of AB which is either AD or DE are equal. Vice versa for BC. So AD=BE

Answer:

-5/2 is located on the left of -1

Step-by-step explanation:

Answer:

She will pay $28.4 for the additional gallons.

Step-by-step explanation:

First find the unit amount:

10.65/3 = 3.55

now multiply:

3.55 x 8 = 28.4

Step-by-step explanation:

b(a + c)

=-4(-3+2)

=12-8

=4

Answer:4

Step-by-step explanation:

Steps a (-3) add c (2) is -1

Then you have to times -1 by -4 which is 4 :D

Answer:42

Step-by-step explanation:

I'm assuming

[tex]f(y)=\begin{cases}ky(1-y)&\text{for }0\le y\le1\\0&\text{otherwise}\end{cases}[/tex]

(a) f(x) is a valid probability density function if its integral over the support is 1:

[tex]\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=k\int_0^1 y(1-y)\,\mathrm dy=k\int_0^1(y-y^2)\,\mathrm dy=1[/tex]

Compute the integral:

[tex]\displaystyle\int_0^1(y-y^2)\,\mathrm dy=\left(\frac{y^2}2-\frac{y^3}3\right)\bigg|_0^1=\frac12-\frac13=\frac16[/tex]

So we have

k / 6 = 1   →   k = 6

(b) By definition of conditional probability,

P(Y ≤ 0.4 | Y ≤ 0.8) = P(Y ≤ 0.4 and Y ≤ 0.8) / P(Y ≤ 0.8)

P(Y ≤ 0.4 | Y ≤ 0.8) = P(Y ≤ 0.4) / P(Y ≤ 0.8)

It makes sense to derive the cumulative distribution function (CDF) for the rest of the problem, since F(y) = P(Y ≤ y).

We have

[tex]\displaystyle F(y)=\int_{-\infty}^y f(t)\,\mathrm dt=\int_0^y6t(1-t)\,\mathrm dt=\begin{cases}0&\text{for }y<0\\3y^2-2y^3&\text{for }0\le y<1\\1&\text{for }y\ge1\end{cases}[/tex]

Then

P(Y ≤ 0.4) = F (0.4) = 0.352

P(Y ≤ 0.8) = F (0.8) = 0.896

and so

P(Y ≤ 0.4 | Y ≤ 0.8) = 0.352 / 0.896 ≈ 0.393

(c) The 0.95 quantile is the value φ such that

P(Y ≤ φ) = 0.95

In terms of the integral definition of the CDF, we have solve for φ such that

[tex]\displaystyle\int_{-\infty}^\varphi f(y)\,\mathrm dy=0.95[/tex]

We have

[tex]\displaystyle\int_{-\infty}^\varphi f(y)\,\mathrm dy=\int_0^\varphi 6y(1-y)\,\mathrm dy=(3y^2-2y^3)\bigg|_0^\varphi = 0.95[/tex]

which reduces to the cubic

3φ² - 2φ³ = 0.95

Use a calculator to solve this and find that φ ≈ 0.865.

Using probability concepts, it is found that

a) The value is k = 6.

b) P(Y ≤ .4|Y ≤ .8) = 0.554.

c) The 95th percentile is x = 0.86465.

The density function is:

[tex]f(y) = ky(1 - y)[/tex]

Item a:

The condition that makes it a probability density function is:

[tex]\int_0^1 f(y) dy = 1[/tex]

Thus:

[tex]\int_0^1 f(y) dy = \int_0^1 ky - ky^2 dy[/tex]

[tex]\int_0^1 f(y) dy = k(\frac{y^2}{2} - \frac{y^3}{3})|_{y = 0}^{y = 1}[/tex]

[tex]\int_0^1 f(y) dy = k(\frac{1}{2} - \frac{1}{3})[/tex]

Then

[tex]k(\frac{1}{2} - \frac{1}{3}) = 1[/tex]

[tex]k(\frac{3-2}{6}) = 1[/tex]

[tex]k = 6[/tex]

The value is k = 6.

Item b:

This probability is:

[tex]\int_0.4^0.8 f(y) dy = 6(\frac{y^2}{2} - \frac{y^3}{3})|_{y = 0.4}^{y = 0.8}[/tex]

Then

[tex]p = 6\left(\frac{0.8^2}{2} - \frac{0.8^3}{3} - \frac{0.4^2}{2} + \frac{0.4^3}{3}\right)[/tex]

[tex]p = 0.554[/tex]

Thus, P(Y ≤ .4|Y ≤ .8) = 0.554.

Item c:

This is x for which:

[tex]\int_0^x f(y) dy = 0.95[/tex]

Thus:

[tex]6(\frac{x^2}{2} - \frac{x^3}{3}) = 0.95[/tex]

[tex]-2x^3 + 3x^2 - 0.95 = 0[/tex]

Solving a cubic equation with the help of a calculator, and considering [tex]0 \leq x \leq 1[/tex], this is x = 0.86465.

A similar problem is given at https://brainly.com/question/22223588

Answer:

3 and i use flvs too, also that pfp is fire

Step-by-step explanation:

Answer:

the answer is 3

Answer:

−2.8 or - 2 8/10

Step-by-step explanation:

hope that helps