I don’t know it help!

9514 1404 393

Answer:

  1080

Step-by-step explanation:

The first price reduction reduced the price to (1 -20%) = 0.80 times the original. The second price reduction reduced the price to ...

  0.80(1 -25%) = 0.80×0.75 = 0.60

times the original.

The final price was ...

  1800 × 0.60 = 1080

Given:

The polynomial function is

[tex]q(x)=6x^3+19x^2-15x-28[/tex]

Yuri thinks that [tex]\dfrac{3}{4}[/tex] is a root of the given function.

To find:

Why [tex]\dfrac{3}{4}[/tex] cannot be a root?

Solution:

We have,

[tex]q(x)=6x^3+19x^2-15x-28[/tex]

If [tex]\dfrac{3}{4}[/tex] is a root, then the value of the function at [tex]\dfrac{3}{4}[/tex] is 0.

Putting [tex]x=\dfrac{3}{4}[/tex] in the given function, we get

[tex]q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28[/tex]

[tex]q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28[/tex]

[tex]q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28[/tex]

[tex]q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28[/tex]

Taking LCM, we get

[tex]q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}[/tex]

[tex]q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0[/tex]

Since the value of the function at [tex]\dfrac{3}{4}[/tex] is not equal to 0, therefore, [tex]\dfrac{3}{4}[/tex] is not a root of the given function.

Answer:

6. No, they are not similar. The differences in the side angles are not the same for RS and MP. That relationship equals 1.3, but the other side lengths' relationships are equal to 1.25. Thus, due to the fact that the side lengths are not all equal to the same value, the triangles are not similar.

7. No, they are not similar. The angles are not the same for the two triangles. I know this due to how 48+77 is equal to 125. 180-125 is not equal to 66. Similarly, 48+66 is equal to 114, and 180-114 is not equal to 77.

Step-by-step explanation:

Answer:

The total change is £21.02 from the original amount of £78.98. Therefore, the percentage change is directly related to the original amount.

Divide the total change by the original amount to determine the percentage change the new amount represents.

21.02÷78.98=0.15219 which rounds up to two decimal places as 15.22%.

Answer:

09

Step-by-step explanation:

Answer:

53 cookies

Step-by-step explanation:

you divide 1223 and 23, the answer should then be about 53

Answer:

3x + 2

Step-by-step explanation:

Answer:

3x+2

Step-by-step explanation:

Get rid of the parentheses:

(x−1)+(2x+3)

x−1+2x+3

Add up the numbers:

x−1+2x+3

x+2+2x

Combine like terms:

x+2+2x

3x+2

Answer:  AM = 76 and AB = 152

Step-by-step explanation:A little annoying but basically AM times 2 shoud equal AB or (2x+34)*2 = 6x+26 solve to get x equals 21 plug back in to get 76 for AM and 152 for AB

Answer:

81

Step-by-step explanation:

Answer:

81

Step-by-step explanation:

9 in each team and theres 9 teams in all

9*9=81

Answer:

40 extras

Step-by-step explanation:

24 is 60% I would divide 24 by 6 to get 10% 24/6 is 4. 4*10 is 40. There were 40 extra's all together.

Answer:

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that [tex]\mu = 3, \sigma = 0.8[/tex]

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.7 - 3}{0.8}[/tex]

[tex]Z = -1.63[/tex]

[tex]Z = -1.63[/tex] has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.1 - 3}{0.8}[/tex]

[tex]Z = -1.13[/tex]

[tex]Z = -1.13[/tex] has a pvalue of 0.1292

X = 1.7

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.7 - 3}{0.8}[/tex]

[tex]Z = -1.63[/tex]

[tex]Z = -1.63[/tex] has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Answer:

3

Step-by-step explanation:

-3 + 6 would be 3.

hope it helps!

Answer:

522.0

Step-by-step explanation:

10*6=60

60*8.7=522.0

or you can take out the zero either way that's the answer

Answer:

522.0

Step-by-step explanation:

Step-by-step explanation:

10*6=60

60*8.7=522.0

or you can take out the zero either way that's the answer

Answer:

Yes

Step-by-step explanation:

Yes ,a rational number is a number that can be expressed as a fraction. Repeating and terminating decimal are rational number so

5/6 is right since it is a fraction

6.565646 is right since it is a repeating decimal

0.23 is right since it is a terminating decimal

-5 3/8 is right since it is a mixed number

Sqr root of 11 and 0.32416.... is wrong since it creates multiple random unknown digits

Answer:

u = 135

hoped i helped u

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

base² + Altitude² = Hypotenuse²

 x² + 9² = 13²

x² + 81 = 169

       x² = 169 - 81

      x² = 88

      x = [tex]\sqrt{88}[/tex]

     [tex]x = \sqrt{2*2*2*11}=2\sqrt{2*11}\\\\x=2\sqrt{22}[/tex]

Answer:

option - d

Step-by-step explanation:

a^2 + b^2 = c^2

9^2 + b^2 = 13^2

81 +b^2 = 169

b^2 = 169 - 81 = 88

b= [tex]\sqrt{88}[/tex] = [tex]\sqrt{2 x 2 x2 x 11}[/tex] ( take the one doubling out )

           [tex]\sqrt[2]{2 x 11 }[/tex] = [tex]\sqrt[2]{22}[/tex]

Answer:

3(4a−5b+2)

Step-by-step explanation:

The answer should have originally been 3(4a-5b+2)

3(4a+5b+3)= 12a+15b+9 which is incorrect.

Answer:

1 8/21

Step-by-step explanation:

5/7 = 15/21

2/3 = 14/21

15/21+14/21=29/21

Answer:

Step-by-step explanation:

Yvonne is saving money for college, and currently has $1200 in a savings account. She plans to deposit $30 each week from her part-time job and then deposit birthday money from her Aunt Marlene ($40 each birthday). Her goal is to have saved $6,000 by the time she graduates from high school in three years. 1. Write a function that models Yvonne's savings. 2. Simplify your function. 3. Use your function to create a graph of Yvonne's savings.(input your function in your calculator and take a screenshot)

it is 9a+2-6a is 3a+2

it is -p^6 is -531441

5n^2 is 25n2

-10n^4+9-7n^5n^6 i di not know

Using the concepts of domain and range, we have that:

6. Both the domain and the range of the relation are [-2.826, 2.826].

7. The relation is not a function, as each value of x is associated with two values of y, that is: [tex]y = \pm \sqrt{8 - x^2}[/tex].

8. From item 7, we get that there are no points that pass the vertical line test.

Hence, from the graph of the circle, for item 6, both the domain and the range of the relation are [-2.826, 2.826].

A relation is a function only if each value of x is related to only one value of y. Solving the equation of the circle for y, we have that:

x² + y² = 8.

y² = 8 - x²

y = ±sqrt(8 - x²).

Hence each value of x is related to two values of y, meaning that it is not a function, and for item 8, there are no points that pass the vertical line test.

More can be learned about domain and range of functions at https://brainly.com/question/10891721

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