Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3O^+ (aq) At a certain temperature, a chemist finds that a 5.6 L reaction vessel containing an aqueous solution of hydrofluoric acid, water, fluoride anion, and hydronium cation at equilibrium has the following composition: Calculate the value of the equilibrium constant K_C for this reaction. Round your answer to 2 significant digits. K_C =

Answer:

D. A pond freezing over is not a chemical reaction, it is a physical reaction.

Answer:

[tex]n=0.00259 mol[/tex]

Explanation:

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In this case, since the Faraday's constant is 96500 Coulombs per mole, we can set up the following process to obtain the moles in 250 Coulombs:

[tex]n=\frac{250C}{96500C/mol}\\\\n=0.00259 mol[/tex]

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Answer:

A

I honestly think it's A, but I could be wrong. It might be B, but I don't think so.

Answer:

HPRT

Explanation:

HPRT catalyzes the salvage reactions of hypoxanthine and guanine with PRPP to form IMP and GMP

The formation of GMP from IMP requires oxidation at C-2 of the purine ring, followed by a glutamine-dependent amidotransferase reaction that replaces the oxygen on C-2 with an amino group to yield 2-amino,6-oxy purine nucleoside monophosphate, or as this compound is commonly known, guanosine monophosphate.

Answer:

176 grams of sugar

explanation is down

Explanation:

250 / 22 = 2000 / x250 ml to 22 grams = 2000 ml to x grams

cross multiply

(250)(x) = (2000)(22)

250x = 44,000

x = 44,000/250

x = 176 grams of sugar 

Answer:

a

Explanation:

Answer: A person engaged in the practice of anthropology. Anthropology is the study of aspects of humans within past and present societies. Social anthropology, cultural anthropology and philosophical anthropology study the norms and values of societies.

Explanation: I HOPE THIS HELPS U AND ANSWERS UR QUESTION!!! Stay safe and healthy!

Answer:

Longer bonds have lower attractive force

Answer:

A 70%

B 92%

C 87%

D 79%

Explanation:

This excercise is about dividing water by liquid.

Answer:

a. pH = 7.0

b. pH = 12.52

c. pH = 12.70

d. pH = 12.78

Explanation:

a. Deionized water has the [H⁺] of pure water = 1x10⁻⁷ (Kw = 1x10⁻¹⁴ = [H⁺][OH⁻] - [H⁺] = [OH⁻ -)

pH = -log[H⁺] = 7

b. Moles NaOH = 5x10⁻³L * (0.10mol / L) = 5x10⁻⁴moles OH⁻ / 0.015L = 0.0333M = [OH⁻]

-Total volume = 10mL+5mL = 15mL = 0.015L

pOH = -log[OH⁻] = 1.48

pH = 14-pOH

pH = 12.52

c. Moles NaOH = 0.010L * (0.10mol / L) = 1x10⁻³moles OH⁻ / 0.020L = 0.0500M = [OH⁻]

-Total volume = 10mL+10mL = 20mL = 0.020L

pOH = -log[OH⁻] = 1.30

pH = 14-pOH

pH = 12.70

d. Moles NaOH = 0.015L * (0.10mol / L) = 1.5x10⁻³moles OH⁻ / 0.025L = 0.060M = [OH⁻]

-Total volume = 10mL+15mL = 25mL = 0.025L

pOH = -log[OH⁻] = 1.22

pH = 14-pOH

pH = 12.78

Answer:

71.1%. , is a fertilizer.

The total mass of the compound guanidine is 59 g/mo. It contains 3 nitrogen atoms. Hence, the percent composition of nitrogen in this fertilizer is 71.18 %.

The mass percent or percent composition of an element in a compound is the measure of amount of that element in 100 g of the compound. Thus, it is the ratio of mass of that element in the compound to the total mass multiplied by 100.

mass percent = mass of the element in the sample/ total mass × 100

The given compound is guanidine with the formula, HNC(NH2)₂ .

atomic mass of N = 14 g/mol

mass of carbon = 12 g/mol

hydrogen = 1 g/mol.

Then total mass of guanidine = 14 + 12 + 1 + 2(2 + 14) = 59 g/mol.

there are 3 nitrogen.

mass of three nitrogen = 42 g.

Then mass percent of N in guanidine = 42 g/ 59 g × 100= 71.1%.

Therefore, the percent by mass of nitrogen in guanidine is 71.18%.

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Answer:

X axis shows the independent and Y axis shows the dependent.

Explanation:

Answer:

A zwitterion or a hybrid ion is an ion that has both a positive and negative charge and can act as either a base or an acid.

Explanation:

A zwitterion or a hybrid ion is an ion that has both a positive and negative charge and can act as either a base or an acid. The net charge on a zwitterion is zero since it has equal number of positive and negative charges.

Alanine, is a monoamino monocarboxylica acid that is diprotic when fully protonated. The carboxylic acid group, COOH and the amino group, NH₃⁺, are able to produce one proton each. At a pH equal to the isoelectric point of alanine, it exists mainly in the zwitterionic form with the α-amino group protonated as NH₃⁺ and the α-carboxyl group deprotonated as COO⁻ . This is because at the isoelectric point of alanine (6.0), pI is greater than the acid dissociation constant, pKa of the α-carboxyl group whereas, pI is less than the acid dissociation constant, pKa of the α-amino group, so the two groups are negatively and positively charged respectively.

Answer:

B and D

Explanation:

Because its adaptions they need to survive in the cold.

Answer:

A.

Explanation:

A decomposition reaction is when one reactant (the substances to the left of the arrow in the reaction) breaks apart into two or more products (the substances to the right of the arrow).

Because KClO3 is breaking down into KCl and O2, it's a decomposition reaction.

Answer:

your finger becomes negatively charged

Explanation:

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Answer:

77.81 g of CuNO₃

Explanation:

6 CuNO₃  +  Al₂(SO₄)₃  ⇒  3 Cu₂SO₄  +  2 Al(NO₃)₃

This is your chemical equation.  We will need this information for converting from Al(NO₃)₃ to CuNO₃.

First, convert grams of Al(NO₃)₃ into moles using the molar mass.

[tex]44.0g*\frac{mol}{213.01g} = 0.2065mol[/tex]

Next, convert moles of Al(NO₃)₃ to moles of CuNO₃.  You can do this by using the stoichiometry (the numbers in front of the compounds).  For every 6 moles of CuNO₃, you will get 2 moles of Al(NO₃)₃, causing the ratio of CuNO₃ to Al(NO₃)₃ to be 6:2.

[tex]0.2065mol*\frac{6}{2} =0.6197mol[/tex]

Now that you moles of CuNO₃, convert this to grams using its molar mass.

[tex]0.6197 mol * \frac{125.56g}{mol} =77.81 g[/tex]

You will need 77.81 grams of CuNO₃ to produce 44.0 grams of Al(NO₃)₃.

Answer:

1.4×10⁸ g of CaO

Explanation:

We'll begin by converting 250 tonnes to grams (g). This can be obtained as follow:

1 tonne = 1×10⁶ g

Therefore,

250 tonne = 250 × 1×10⁶

250 tonne = 2.5×10⁸ g

Next, the balanced equation for the reaction.

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (16×3)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16

= 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Finally, we shall determine the mass of CaO produced by the decomposition of 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃. This can be obtained as follow:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 2.5×10⁸ g of CaCO₃ will decompose to produce =

(2.5×10⁸ × 56)/100 = 1.4×10⁸ g of CaO.

Thus, 1.4×10⁸ g of CaO will be obtained from 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃.

Answer:

NaNH₂₀

Explanation:

0.5 mol Na, 0.5 mol N, and 10 mol H

To obtain the empirical formulae, we find the mole ratio between the elements and this is done by dividing all through by the smallest mol (0.5)

Na = 0.5 / 0.5 = 1

N = 0.5 / 0.5 = 1

H = 10 / 0.5 = 20

The mole ratio is used to write the empirical formulae. It is given as;

NaNH₂₀

Answer:

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Explanation:

Aluminum sulfate Al₂(SO₄)₃ has a molar mass of 342.15 g/mol.

Molar mass is the amount of mass that a substance contains in one mole of a substance, which can be an element or a compound.

So in this case you can apply the following rule of three: if 342.15 grams are present in 1 mole of aluminum sulfate, how much mass is present in 0.063*10⁻⁴ moles of the compound?

[tex]mass of aluminum sulphate=\frac{0.063*10^{-4}moles*342.15 grams }{1 mole}[/tex]

mass of aluminum sulphate= 2.15*10⁻³ grams

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Answer:

The deviation in the results will be too large when compared with the actual result

Explanation:

The effect this will have on the results of the samples run using this Calibration solution is that the deviation in the results will be too large when compared with the actual result that was supposed to be obtained. and this will also lead to wrong analysis by the technician .

This will cause a result that is very different from the actual result, which will lead to errors in the analysis.

We can arrive at this answer because:

As we can see from the question above, the lab technician used a much higher calibration than what was recommended in the lab. This will lead to inaccurate and incorrect results.

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Answer:

the scientific name is Angiosperms

Explanation:

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Answer:

ch4+h2o----725°-->co+2h2

Answer:

I believe it is 5.00

Explanation:

Answer:

3.5 mol

Explanation:

Step 1: Given data

Moles of HCl: 7.0 mol

Step 2: Write the balanced equation

Fe(s) + 2 HCl(aq) ⇒ FeCl₂(aq) + H₂(g)

Step 3: Calculate the moles of H₂ gas produced from 7.0 moles of HCl

According to the balanced equation, the molar ratio of HCl to H₂ is 2:1.

7.0 mol HCl × 1 mol H₂/2 mol HCl = 3.5 mol H₂

Answer:

the mole ratio of chromium to nickel atoms in the steel is 2.383

Explanation:

Given the data in the question;

Chromium  = 19% ( by mass )

Nickel = 9% ( by mass )

now, let the mass of the steel = 100 g

so mass of Chromium  = 19g

mass of nickel = 9g

We know that; Atomic mass of Cr is 52 g/mol, Atomic mass of Ni is 58.7 g/mol

Moles of Cr =  mass/atomic number = 19/52 mol

Moles of Ni =  mass/atomic number = 9/58.7 mol

The mole ratio of of Cr to Ni atom  will be;

⇒ Moles of Cr / Moles of Ni

= (19/52) / (9/58.7)

= 19×58.7 / 9×52

= 2.383

Therefore, the mole ratio of chromium to nickel atoms in the steel is 2.383

Answer:

d

Explanation:

Answer:

hopen it helps soo much thanks for the points