Hw many years passed between the debut of the 911 and 988 hotlines?

Hw Many Years Passed Between The Debut Of The 911 And 988 Hotlines?

Answers

Answer 1

After considering all the options we conclude that the debut of the 911 and 988 hotlines was for 54 years, which is Option B.

The first 911 emergency call was made in 1968 in Alabama. The 988 hotline is a new national mental health crisis hotline that was mandated by the federal government in October 2020 with an official nationwide start date on July 16, 2022. Therefore, the number of years between the debut of the 911 and 988 hotlines is 54 years.


A hotline refers to a phone line which is provided for  the public so that they can apply it to contact an organization about a particular subject. Hotlines gives people opportunity express their concerns and to obtain information from an organization.
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Related Questions

i need help with this

Answers

The missing values in the triangle are:

∠B = 90°

AB =  20.98

CB = 16.99

How to find the missing values?

First, remember that the sum of the interior angles of any triangle is always equal to 180°, then we can write:

51 + 39 + ∠B = 180

∠B = 180 - 51 - 39 = 90

So we have a right triangle.

Now, to find the values of AB and CB, we can use trigonometric relations, we know that teh hypotenuse is 27 units, then we can use:

cos(51°) = CB/27

27*cos(51°) = CB = 16.99

And:

cos(39°) = AB/27

27*cos(39°) = AB = 20.98

These are the missing values.

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In ΔVWX, w = 600 cm,

m∠V=26° and

m∠W=80°. Find the length of v, to the nearest 10th of a centimeter.

Answers

The length of v is given as follows:

v = 267.1 cm.

What is the law of sines?

The law of sines is used in the context of this problem as we have two sides and two opposite angles, hence it is the most straightforward way to relate the side lengths.

Each side length is related with the sine of the opposite angle as follows:

sin(A)/a = sin(B)/b = sin(C)/c.

The relation for this problem is given as follows:

sin(26º)/v = sin(80º)/600

Hence we apply cross multiplication to obtain the length v is obtained as follows:

sin(26º)/v = sin(80º)/600

v = 600 x sine of 26 degrees/sine of 80 degrees

v = 267.1 cm.

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In a large city, the road system is set up like a Cartesian plane, where streets are indicated by the number of blocks they are from Street A and Street B. For example, a baseball field is located 3 blocks west of Street B and 32 blocks north of Street A. Treat the intersection of Street A and Street B as the origin of a coordinate system, with East being the positive x-axis. Answer parts (a)-(d). (a) Write the location of the baseball field using rectangular coordinates. (Type an ordered pair.) (b) Write the location of the field using polar coordinates. Use the east direction for the polar axis. Express ? in degrees. Type an ordered pair. Round to two decimal places as needed.) (c) A different ballpark is located 2 blocks west of Street B and 28 blocks south of Street A. Write the location of this ballpark using rectangular coordinates (Type an ordered pair) (d) Write the location of this ballpark using polar coordinates. Use the east direction for the polar axis. Express ? in degrees. (Type an ordered pair. Round to two decimal places as needed.)

Answers

(a) The location of the baseball field using rectangular coordinates is (-3,32).

(b) To find the location of the field using polar coordinates, we need to first find the distance r from the origin to the point (-3,32). Using the Pythagorean theorem, we have:

r = sqrt((-3)^2 + 32^2) = 32.28

Next, we need to find the angle theta between the positive x-axis and the line connecting the origin to the point (-3,32). Since the point is in the third quadrant, we know that theta is between 180 and 270 degrees. We can use the tangent function to find theta:

tan(theta) = (opposite side)/(adjacent side) = (-32)/(3)

theta = arctan(-32/3) = 276.87 degrees

Therefore, the location of the baseball field using polar coordinates is (32.28,276.87).
(c) The location of the different ballpark using rectangular coordinates is (-2,-28).
(d) To find the location of the different ballpark using polar coordinates, we need to first find the distance r from the origin to the point (-2,-28). Using the Pythagorean theorem, we have:

r = sqrt((-2)^2 + (-28)^2) = 28.06

Next, we need to find the angle theta between the positive x-axis and the line connecting the origin to the point (-2,-28). Since the point is in the fourth quadrant, we know that theta is between 270 and 360 degrees. We can use the tangent function to find theta:

tan(theta) = (opposite side)/(adjacent side) = (-28)/(-2) = 14

theta = arctan(14) = 83.66 degrees

Therefore, the location of the different ballpark using polar coordinates is (28.06,83.66).

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For problems 1-5, use the following information. On an end-of-year test, the scores of juniors across a large city with many high schools were normally distributed with a mean of 83 and a standard deviation of 5.2.
For random samples of 25 scores, what interval centered on the mean captures 95% of the sample means?

Answers

The 95% confidence interval centered on the mean that captures 95% of the sample means is (80.96, 85.04).

We can use the formula for the confidence interval for the mean of a normally distributed population:

CI = X ± z(α/2) * (σ/√n)

Where:

X = sample mean

z(α/2) = the z-score associated with the desired confidence level and calculated using the standard normal distribution table. For a 95% confidence level, α/2 = 0.025, and the corresponding z-score is approximately 1.96.

σ = population standard deviation

n = sample size

Substituting the given values, we get:

CI = 83 ± 1.96 * (5.2/√25)

CI = 83 ± 2.04

Therefore, the 95% confidence interval centered on the mean that captures 95% of the sample means is (80.96, 85.04).

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what is the length of the curve defined by the parametric equations x(t)=t2−2t and y(t)=t3−4t for 0≤t≤2 ? 4.221 4.221 6.511 6.511 10.819 10.819 28.267

Answers

The length of curve is approximately 6.511. Thus, the correct option is 6.511.

To find the length of the curve defined by the parametric equations x(t) = t^2 - 2t and y(t) = t^3 - 4t for 0 ≤ t ≤ 2, we need to use the arc length formula for parametric equations. The formula is:

Length = ∫(√((dx/dt)^2 + (dy/dt)^2)) dt, where the integral is evaluated from the lower limit to the upper limit.

First, find the derivatives dx/dt and dy/dt:
dx/dt = 2t - 2
dy/dt = 3t^2 - 4

Next, square and sum these derivatives:
(dx/dt)^2 + (dy/dt)^2 = (2t - 2)^2 + (3t^2 - 4)^2

Now, find the square root of this expression:
√((2t - 2)^2 + (3t^2 - 4)^2)

Finally, evaluate the integral of this expression from t = 0 to t = 2:
Length = ∫(√((2t - 2)^2 + (3t^2 - 4)^2)) dt, from 0 to 2

Using a calculator or numerical integration methods, the length of the curve is approximately 6.511. Therefore, the correct option is 6.511.

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4n / 2n 3n determine convergence or divergence of the series. if the series converges, find its sum

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The given series 4^n / 2^n 3^n is convergent.

To see why, we can use the ratio test, which states that if the limit of the ratio of consecutive terms is less than 1, then the series converges. Applying the ratio test to the given series, we get:

lim n→∞ |(4^n+1 / 2^n+1 3^n+1) / (4^n / 2^n 3^n)|

= lim n→∞ |4 / 3(1 + 1/2n+1)|

= 4/3

Since the limit is less than 1, the series converges. To find its sum, we can use the formula for the sum of a convergent geometric series:

S = a / (1 - r)

where a is the first term and r is the common ratio. In this case, a = 4/6 = 2/3 and r = 2/3, so we get:

S = (2/3) / (1 - 2/3) = 2

Therefore, the sum of the series is 2.

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Find the first five nonzero terms of the Maclaurin expansion of f(x)=−e^x-sin(x).
(Express numbers in exact form. Use symbolic notation and fractions where needed.)

Answers

To find the Maclaurin expansion of f(x) = -e^x - sin(x), we can use the Maclaurin series of e^x and sin(x) and combine them with appropriate coefficients.

The Maclaurin series of e^x is:

e^x = 1 + x + x^2/2! + x^3/3! + ...

And the Maclaurin series of sin(x) is:

sin(x) = x - x^3/3! + x^5/5! - ...

Using these series, we can write the Maclaurin expansion of f(x) as:

f(x) = -e^x - sin(x) = -1 - x - x^2/2! - x^3/3! - ... - (x - x^3/3! + x^5/5! - ...)

Simplifying this expression, we get:

f(x) = -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4! - ...

Therefore, the first five nonzero terms of the Maclaurin expansion of f(x) are:

f(x) = -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4! + O(x^5)

This means that for small values of x, f(x) can be approximated by the polynomial -1 - 2x - 5x^2/2! - 19x^3/3! - 87x^4/4!, which becomes more accurate as more terms are added. The term O(x^5) represents the error in this approximation and means that the actual value of f(x) is within a certain range of this polynomial for values of x close to zero.

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A fruit vendor bought 100 kg apples for Rs 9,000, 30 dozen bananas for Rs 1,800 and 50 kg
grapes for Rs 6,000. He spent Rs 900 on transportation and sold all the fruits as per the given
rates.

Answers

The net profit on the sale of these fruits is Rs 6,050.

To calculate the net profit on the sale of these fruits, we need to determine the total revenue generated from the sales and deduct the total expenses.

First, let's calculate the revenue from each type of fruit:

Revenue from apples: 100 kg × Rs 140/kg = Rs 14,000

Revenue from bananas: 30 dozen × Rs 75/dozen = Rs 2,250

Revenue from grapes: 50 kg × Rs 150/kg = Rs 7,500

Next, let's calculate the total revenue:

Total revenue = Revenue from apples + Revenue from bananas + Revenue from grapes

Total revenue = Rs 14,000 + Rs 2,250 + Rs 7,500

Total revenue = Rs 23,750

Now, let's calculate the total expenses:

Total expenses = Cost of apples + Cost of bananas + Cost of grapes + Transportation cost

Total expenses = Rs 9,000 + Rs 1,800 + Rs 6,000 + Rs 900

Total expenses = Rs 17,700

Finally, let's calculate the net profit:

Net profit = Total revenue - Total expenses

Net profit = Rs 23,750 - Rs 17,700

Net profit = Rs 6,050

Therefore, the net profit on the sale of these fruits is Rs 6,050.

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in the long run, perfectly competitive firms produce a level of output such that multiple choice p = mc. p = minimum of ac. p = mc and p = minimum of ac. p > mc.

Answers

In the long run, perfectly competitive firms aim to produce at a level of output where their marginal cost (MC) is equal to the market price (P).

This is because in a perfectly competitive market, there are many firms competing with each other, and they cannot charge a price higher than the market price. Therefore, firms must produce at a level where their MC equals P in order to maximize profits.
Therefore, the answer to the question is that perfectly competitive firms produce a level of output such that P = MC. This is because the other options, P = minimum of AC and P > MC, do not accurately reflect the behavior of perfectly competitive firms. In a perfectly competitive market, firms cannot charge a price higher than the market price, so P will not be greater than MC. Additionally, P will not be equal to the minimum of AC because in a perfectly competitive market, there are no barriers to entry, so firms cannot earn economic profits in the long run. Therefore, they must produce at a level where P = MC to break even in the long run.

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The results of a question from the awesome survey are shown below.
What is the probability of selecting a student who would rather fight 100 duck sized horses, and then selecting a student who would rather fight 10 horse sized ducks (with replacement)?
Round your answer to the nearest hundredth

Answers

Answer:

0.18

Step-by-step explanation:

time-use data show that married american women have cut their housework time roughly in half over the last half-century, while men have:

Answers

Over the last half-century, time-use data has shown that married American women have significantly reduced their housework time, cutting it roughly in half.

This change can be attributed to various factors such as advancements in home appliances, shifting gender roles, and increased participation of women in the workforce. On the other hand, men have gradually increased their contributions to housework during this period.
This shift in housework responsibilities can be attributed to societal changes that promote a more equitable distribution of domestic tasks between partners. As gender norms have evolved, men are increasingly taking on roles that were once predominantly associated with women, leading to a more balanced approach to housework within households. Additionally, the rise in dual-income families has necessitated a more equal division of domestic responsibilities.
In summary, over the past 50 years, married American women have seen a considerable decrease in housework time, while men have increased their contributions. This change reflects evolving gender roles and societal expectations, promoting a more equal division of labor within households.

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7 minus the product of
3
and

x.

Answers

Answer:

7 - 3x

Step-by-step explanation:

Product would cause the 3 and x to combine.

Answer:

7 - 3x

Step-by-step explanation:

the product , multiplication of 3 and x = 3 × x = 3x

now subtract this product from 7 to obtain

7 - 3x

find f. f ′(x) = 1 3 x , f(9) = 67

Answers

To find the function f, we need to integrate f'(x) with respect to x. Thus, we have found the function f with the given derivative f'(x) and initial condition f(9) = 67.

f'(x) = (1/3)x

Integrating both sides with respect to x, we get:

f(x) = (1/3) * (x^2/2) + C

where C is the constant of integration. To find the value of C, we use the given initial condition that f(9) = 67:

f(9) = (1/3) * (9^2/2) + C = 67

Simplifying the equation, we get:

C = 67 - (1/3) * (81/2) = 67 - 13.5 = 53.5

Therefore, the function f is:

f(x) = (1/3) * (x^2/2) + 53.5

Thus, we have found the function f with the given derivative f'(x) and initial condition f(9) = 67.

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early tuesday a truck delivers fresh fruits to a groceries n more dad asks him justin needs to calculate the expanded total sales for 200 plums each plums weighs 80 grams and groceries n more sells of plums for $3.27

Answers

The expanded total sales for 200 plums, each weighing 80 grams, at a price of $3.27 per plum is $52.32.

How to determine expanded total sales for 200 plums each plums weighs 80 grams

We can calculate the total weight of the plums as follows:

Total weight of plums = Weight per plum * Number of plums

Total weight of plums = 80 grams * 200 plums

we need to convert the total weight from grams to kilograms since the price is given per plum. There are 1000 grams in a kilogram, so:

Total weight of plums (in kilograms) = (Total weight of plums in grams) / 1000

Total sales = Total weight of plums (in kilograms) * Price per plum

Let's plug in the values and calculate the total sales:

Total weight of plums = 80 grams * 200 plums = 16,000 grams

Total weight of plums (in kilograms) = 16,000 grams / 1000 = 16 kilograms

Price per plum = $3.27

Total sales = 16 kilograms * $3.27 = $52.32

Therefore, the expanded total sales for 200 plums, each weighing 80 grams, at a price of $3.27 per plum is $52.32.

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Find the volume, and surface area. The base of the pyramid is a square. (h = 15)


type number only, no units:

V = ______in3

S.A. = ______in2

Answers

The volume of the pyramid is 1280 cubic units, and the surface area is 800 square units.

To find the volume and surface area of a pyramid, we can use the following formulas:

Volume of a pyramid = (1/3) · base area · height

Surface area of a pyramid = base area + (1/2) · perimeter · slant height

Given that the base of the pyramid is a square with a side length of 16, the base area can be calculated as:

Base area = side length² = 16² = 256 square units

The height of the pyramid is given as 15, and the slant height is given as 17.

Now, let's calculate the volume of the pyramid:

Volume = (1/3) · base area · height

Volume = (1/3) · 256 · 15

Volume = 1280 cubic units

Next, let's calculate the surface area of the pyramid:

Perimeter of the base = 4 · side length = 4 · 16 = 64 units

Surface area = base area + (1/2) · perimeter · slant height

Surface area = 256 + (1/2) · 64 · 17

Surface area = 256 + 544

Surface area = 800 square units

Therefore, the volume of the pyramid is 1280 cubic units, and the surface area is 800 square units.

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if nominal gdp is $7 trillion, and the money supply is $2 trillion, then what is the velocity of money? a. 7. b. 3.5. c. 2. d. 14.

Answers

Thus, the velocity of money in would be 3.5 .

The velocity of money is a measure of the rate at which money changes hands in an economy. It is calculated by dividing the nominal GDP by the money supply.

Therefore, the velocity of money in this scenario would be 3.5 (calculated as 7 trillion divided by 2 trillion). This means that on average, each dollar in the money supply is spent 3.5 times in a given year to support the production of goods and services that contribute to nominal GDP.The velocity of money can be affected by a variety of factors, including changes in interest rates, consumer and business confidence, and government policies. A higher velocity of money can be an indication of a strong and growing economy, while a lower velocity of money can signal sluggish economic growth. It is important to note that the velocity of money is a theoretical concept and may not always accurately reflect real-world economic conditions. Nonetheless, it remains a valuable tool for economists to understand and analyze the dynamics of the economy.

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suppose your dependent variable, birth weight, was in ounces instead of pounds (16 ounces = 1 pound). what would the coefficient on intercept be? please answer to 2 decimal places.

Answers

The coefficient on the intercept would change if the dependent variable, birth weight, was in ounces instead of pounds. It would be equal to 0.00, rounded to two decimal places.

The intercept coefficient represents the value of the dependent variable when all independent variables are equal to zero. In this case, it would represent the birth weight when all predictors are equal to zero. Since birth weight is measured in ounces, the intercept coefficient would represent the weight of a newborn when all predictors are equal to zero, which is not a meaningful or practical value. Therefore, the intercept coefficient would be equal to 0.00.

This result is expected since changing the unit of measurement of the dependent variable does not change the relationship between the dependent variable and the independent variables, only the scale of the coefficients. The regression equation would still provide useful information about the relationship between birth weight and the predictors, but the coefficients would need to be interpreted differently.

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Suppose that the length X of the life (in years) of a battery for a computer has a distribution that can be described by the pdf: f(x) = 16/49 e^-8x^2/49 Determine the probability that the battery fails before the one year warranty expires on the computer. a) 0.8494 b) 0.2773 c) 0.3506 d) 0.1506 e) 0.3773 f) None of the above

Answers

The answer is (a) 0.8494, to find the probability that the battery fails before the one year warranty expires,

we need to calculate the integral of the given pdf from 0 to 1, as X represents the length of the battery life in years.

So, P(X<1) = ∫(0 to 1) f(x) dx = ∫(0 to 1) (16/49) e^(-8x^2/49) dx ≈ 0.8494

Therefore, the answer is (a) 0.8494.

The given pdf describes the distribution of the length of the battery life, and we are interested in finding the probability that the battery fails before the one year warranty expires.

This can be found by integrating the pdf from 0 to 1, as the warranty lasts for one year.

Using the formula for the probability density function, we calculate the integral of the given pdf from 0 to 1, and get the answer as 0.8494.

This means that the probability of the battery failing before the one year warranty expires is about 84.94%.

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write the taylor series for f(x)=exf(x)=ex about x=2x=2 as ∑n=0[infinity]cn(x−2)n.

Answers

The Taylor series for f(x)=ex about x=2 is given by ∑n=0[infinity]cn(x−2)n where cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.

The Taylor series is a way to represent a function as an infinite sum of terms that involve the function's derivatives evaluated at a specific point.

In this case, we want to find the Taylor series for f(x)=ex about x=2. To do this, we first need to find the derivatives of f(x) at x=2.

We have fⁿ(x) = ex for all n, so fⁿ(2) = e² for all n. We can then use this to find the coefficients cn in the Taylor series.

We have cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.

We can then substitute these coefficients into the Taylor series to get ∑n=0[infinity]cn(x−2)n = ∑n=0[infinity] e²/2! e²/3! ... e²/n!(x−2)n, which is the Taylor series for f(x)=ex about x=2.

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for any n ≥ 1, the factorial function, denoted by n!, is the product of all the positive integers through n: prove that for n ≥ 4, n! ≥ 2n.

Answers

For any n ≥ 1, the factorial function, denoted by n!, is the product of all the positive integers through n, it is proved that for n ≥ 4, n! ≥ 2n.

To prove this statement, we can use mathematical induction. For the base case, n = 4, we have 4! = 24 and 2^4 = 16. Since 24 > 16, the statement holds for n = 4.

Now suppose the statement holds for some integer k ≥ 4, that is, k! ≥ 2k. We need to show that the statement holds for k+1. We have:

(k+1)! = (k+1)k!

≥ (k+1)2k (by the induction hypothesis)

≥ 2·2k (since k+1 > 2 for k ≥ 4)

= 2k+1.

Therefore, the statement holds for k+1. By the principle of mathematical induction, the statement holds for all n ≥ 4. Therefore, we have proved that n! ≥ 2n for n ≥ 4.

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Find The Missing Length. The triangles in each pair are similar

Answers

The length of the side JL is 55 units.

Given that are two similar triangles, Δ LKJ and Δ TUV, we need to find the missing length,

TU = 14

TL = 22

JL = ?

KL = 35

so,

According to the definition of similar triangles,

Triangles with the same shape but different sizes are known as similar triangles.

Two triangles are said to be similar if their corresponding sides are proportionate and their corresponding angles are congruent.

In other words, two triangles are comparable if they can be changed into one another using a combination of rotations, translations, and uniform scaling (enlarging or decreasing).

TU / TV = KL / JL

14 / 22 = 35 / ?

14 x ? = 22 x 35

? = 55

Hence the length of the side JL is 55 units.

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Solve the system by substitution, help me

Answers

Answer: (-8, 8).

Step-by-step explanation:

Start with the first equation:y = -x Substitute this expression for y in the second equation:y = -3x - 16-x = -3x - 16Add 3x to both sides:2x = -16Divide both sides by 2:x = -8Substitute this value of x into either equation to find y:y = -x = -(-8) = 8

Answer:

Step-by-step explanation:

Hello! Can someone explain how to do this? Due tonight hurry asap

Answers

9.172 cm² is the area of the unshaded reason.

It is given that,

From the general formula of the area of the arc of the circle,

Area of the arc = (θ/360) x πr²

where A is the area of the arc, θ is the central angle of the arc (in degrees), and r is the radius of the circle.

The area of the shaded part is given = 56.87 cm²

Angle of the shaded arc = 360-50 = 310

So,

310/360* πr² = 56.87

πr²/360 = 56.87/310

For the 50° part,

Area of the unshaded part = 50/360* πr²

From the above value of the  πr²/360,

Area of the unshaded part = 50*56.87/310

Area of the unshaded part = 9.172 cm²

Therefore, the area of the unshaded reason is 9.172 cm².

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an unpressurized aircraft with 20 occupants other than the pilots will be cruising at 14,000 feet msl for 25 minutes. for how many, if any, of these occupants must there be an oxygen supply?

Answers

There is no requirement for supplemental oxygen.

All 20 occupants can fly without oxygen supply.

Calculation of the oxygen requirements for an unpressurized aircraft flying at high altitudes:

As the altitude increases, the atmospheric pressure decreases, which in turn reduces the partial pressure of oxygen in the air. This reduction in oxygen availability can cause hypoxia, which can lead to impaired judgment, vision, and coordination, and can be fatal in extreme cases.

The calculation of oxygen requirements can involve estimating the total oxygen consumption based on the number of occupants, their age, and their physical condition, and then determining the appropriate type and quantity of oxygen delivery systems to be carried on board the aircraft.

Here we have

An unpressurized aircraft with 20 occupants other than the pilots will be cruising at 14,000 feet msl for 25 minutes.

According to the Federal Aviation Regulations, if an aircraft is flying at an altitude above 12,500 feet MSL for more than 30 minutes,

then oxygen must be supplied to the occupants if:

The cabin pressure altitude exceeds 14,000 feet MSL, or

The cabin pressure altitude exceeds 15,000 feet MSL for any period of time.

In this case, the aircraft is flying at 14,000 feet MSL for 25 minutes, which is less than 30 minutes.

Therefore,

There is no requirement for supplemental oxygen.

All 20 occupants can fly without oxygen supply.

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Olivia bought a new pair of shoes. The regular price was $87.50, they were having a 5% off sale and she had a $10 off coupon. (without tax) what was the total cost?

Answers

The total cost of the shoes, without tax, after the 5% off sale and the $10 off coupon, is $73.125.

To calculate the total cost of the shoes after the discount and coupon, we follow these steps:

Step 1: Calculate the discount amount.

Discount amount = Regular price * (Discount percentage / 100)

Discount amount = $87.50 * (5 / 100)

Discount amount = $87.50 * 0.05

Discount amount = $4.375

tep 2: Subtract the discount amount from the regular price.

Price after discount = Regular price - Discount amount

Price after discount = $87.50 - $4.375

Price after discount = $83.125

Step 3: Subtract the coupon amount from the price after discount.

Total cost = Price after discount - Coupon amount

Total cost = $83.125 - $10

Total cost = $73.125

Therefore, the total cost of the shoes, without tax, after the 5% off sale and the $10 off coupon, is $73.125.

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there are 2^3 times 3^2 times 5 students at the mariemont middle school. evaluate the expression. to determine the number of students at the school. write your answer as a whole number

Answers

The number of students at the mariemont middle school in whole number is 360 students.

How to evaluate exponents?

Exponents refers to the power to which a number, symbol or expression is to be raised.

Number of students at the mariemont middle school = 2³ × 3² × 5

= (2 × 2 × 2) × (3 × 3) × 5

= 8 × 9 × 5

= 360 students

In conclusion, there are 360 total number of students in mariemont middle school.

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the frequency table shows the number of students selecting each type of food which portion of students choose nachos
A.0.5
B. 0.33
C. 0.73
D. 0.45
Please help :(

Answers

Answer:

Step-by-step explanation:

b .33

need these both solved pls nowww

Answers

The simplified rational expressions are given as follows:

[tex]\sqrt[5]{288 \times p^5 \times p^2} = 2p\sqrt[5]{9p^2}[/tex][tex](216r^{9})^{\frac{1}{3}} = 6r^3[/tex]

How to simplify the rational expressions?

The first rational expression is given as follows:

[tex]\sqrt[5]{288p^7}[/tex]

The number 288 can be simplified as follows:

[tex]288 = 2^5 \times 3^2[/tex]

[tex]p^7[/tex], can be simplified as [tex]p^7 = p^5 \times p^2[/tex], hence the simplified expression is given as follows:

[tex]\sqrt[5]{2^5 \times 3^2 \times p^5 \times p^2} = 2p\sqrt[5]{9p^2}[/tex]

(as we simplify the exponents of 5 with the power)

The second expression is given as follows:

[tex](216r^{9})^{\frac{1}{3}}[/tex]

We have that 216 = 6³, hence we can apply the power of power rule to obtain the simplified expression as follows:

3 x 1/3 = 1 -> 6¹.9 x 1/3 = 3 -> r³.

Hence the simplified expression is of:

[tex](216r^{9})^{\frac{1}{3}} = 6r^3[/tex]

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an air filter is rated to catch 90% of airborne particles. if the average particle diameter is 0.5 microns and the population standard deviation is 0.2 microns, what is the largest diameter particle (in microns) that will pass through the filter? assume that the diameter of particles in the air is normally distributed.

Answers

The largest diameter particle (in microns) that will pass through the filter is given as follows:

0.756 microns.

How to use the normal distribution?

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score represents how many standard deviations the measure X is above or below the mean of the distribution of the data-set, depending if the obtained z-score is positive(above the mean) or negative(below the mean).The z-score table is used to obtain the p-value of the z-score, and it represents the percentile of the measure X in the distribution.

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 0.5, \sigma = 0.2[/tex]

The largest diameter is the 90th percentile, which is X when Z = 1.28, as 1.28 has a p-value of 0.9, hence:

1.28 = (X - 0.5)/0.2

X - 0.5 = 0.2 x 1.28

X = 0.756 microns.

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Twenty-five adult citizens of the U.S. were asked to estimate the average income of all U.S. households. The mean estimate was = $45,000 and s = $15,000. (Note: the actual average household income at the time of the study was about $68,000.) Assume the 25 adults in the study can be considered an SRS from the population of all adult citizens of the U.S. Which of the following would cause the most worry about the validity of a 95% confidence interval that you calculate using this information?A)A stemplot of the data shows a mild right-skew.B)You do not know the population standard deviation σ.C)You notice that there is a clear outlier in the data.

Answers

The most worrying factor for the validity of the 95% confidence interval in this case is option C) the presence of a clear outlier in the data for the average.

Let's consider each option and assess which one would cause the most worry about the validity of a 95% confidence interval calculated using the given information (mean estimate = $45,000 and standard deviation s = $15,000).

A) A mild right-skew in the stemplot indicates a slightly non-normal distribution of the data. However, since the sample size is 25, the Central Limit Theorem states that the sampling distribution of the mean should be approximately normal. So, a mild right-skew shouldn't be a significant concern for the validity of the 95% confidence interval.

B) Not knowing the population standard deviation (σ) can be a concern. However, when the sample size is large enough (which is the case here with 25 respondents), using the sample standard deviation (s) as an estimate of σ is acceptable, and the confidence interval calculation can still be valid.

C) A clear outlier in the data can greatly influence the mean estimate and the standard deviation, which may result in an inaccurate confidence interval. Outliers can cause the interval to be wider or narrower than it should be, affecting the validity of the 95% confidence interval.

Given these explanations, the most worrying factor for the validity of the 95% confidence interval in this case is option C) the presence of a clear outlier in the data. This outlier can significantly affect the accuracy and reliability of the confidence interval calculation.


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