Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall
be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO
consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for
any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late
payment or cure of default in payment shall extend the warranty period provided herein.
LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil
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proximately resulting therefrom.
CAUTION
The instrument should be operated only by technically qualified individuals who have fully read and understand
these instructions. The instrument should be operated only in accordance with these instructions.
The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow
and employ all applicable standard laboratory safety procedures.
LECO'" is a registered trademark of the LECO Corporatio
Explain Body Mechanics.
PLUS BRAINLY! and 50 Points
Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.
Explanation:
*
as the mass of an object increases, the force of attraction...
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Answer:
thanks
Explanation:
for answer byebye
how many asteroids do scientists believe exist in the solar system?
Answer:
Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.
Explanation:
If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?
Answer:
96.5 mL
Explanation:
How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?
Force = mass x acceleration:
5N = 1kg x acceleration
Acceleration = 5N / 1 kg
Acceleration = 5 m/s^2
Acceleration is a positive value so it is speeding up
15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.
This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:
[tex]\rho =\frac{m}{V}[/tex]
In such a way, we can proceed as follows:
15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:
[tex]V=2cm*6cm*7cm=84 cm^3[/tex]
And the density turns out to be:
[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]
16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:
[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]
17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:
[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]
Which can be converted to kg/mL as follows:
[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]
18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:
[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]
19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.
Learn more:
(Density) https://brainly.com/question/952755Which best describes why a liquid needs a container when a solid does not?
O Solids fill their containers, and liquids have definite shapes.
Solids have definite shapes, and liquids fill their containers.
Solids particles will expand to fill their containers, and liquid particles will expand as well.
O Solids particles expand to fill their containers, and liquid particles do not.
Answer: Solids have definite shapes and liquids fill their containers.
Explanation: Liquids have got further apart molecules than solids, so the liquid molecules have a higher degree of locomotion than solid molecules, hence able to fill the container though without a definite volume, which is not the case for solid molecules.
what are the electrical signals generated by neurons called?
Answer:
electrons
Explanation:
because it electrons
A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
Heat always moves from hot to cold through the processes of?
Answer: The processes are conduction, convection and radiation.
Explanation: Unless people interfere, thermal energy — or heat — naturally flows in one direction only: from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection and radiation. Sometimes more than one may occur at the same time.
what happens to the state of motion of the object, when you don't exert a force on it???
Answer: It eventually loses its stamina, and would come to a stop.
Explanation:
In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?
The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s
We are given the following facts;
Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.Formula for time taken is;
time = distance/speed
Time taken by swimmer 1 for one leg;
t₁ = 50/3.9
t₁ = 12.82 s
Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;
t₂ = 12.82 -0.45
t₂ = 12.37 s
Thus, speed of swimmer 2;
v = 50/12.37
v = 4.04 m/s
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A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.From the question,
⇒ Given:
M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)⇒ Solve for V
0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/sHence the final speed of the combined masses is 0.21 m/s
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A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?
Name the force used in removing iron scrap from a heap of mixed scrap. (a) Magnetic Force (b) Electrostatic force (c) Gravitational force (d) Friction Force
Answer:
magnetic force
Explanation:
because iron is magnetic so magnet is able to attract iton
is orange orange because its orange or is orange orange because its orange
Answer:
orange it is lol
Explanation:
Answer:
HELP ORANGE DOESNT LOOK LIKE A WORD ANYMORE
Explanation:
A calculator of mass 0.11 kg is lowered from a bookshelf that is 1.6m above the floor to a desk that is 0.85m above the floor. What's the change in GPE?
Answer:
I think it would be 0.1496 but I'm not really sure sorry
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.
The time for the projectile to hit the ground from the given position is 1.5 s.
The given parameters:
Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t) = –16t² + 48t + 190.The time for the projectile to hit the ground is calculated as follows:
when the projectile hits the ground, the final velocity = 0
[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]
Thus, the time for the projectile to hit the ground from the given position is 1.5 s.
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NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?
did you end up getting the answer- im struggling
Answer:
I would think human error could cause differences like not pressing the stop watch on time.
Explanation:
9- Under what circumstances would a vector have components that are equal in
magnitude?
a. if the vector is oriented at 45° from the axes.
b. if the vector is oriented at 90° from the axes.
c. if the vector is oriented at 0° from the X -axis.
d. if the vector is oriented at 0° from the y-axis.
itude of 30 units Vector B is perpendicular to vector A
Explanation:
c. if the vector is oriented at 0° from the X -axis.
Anyone please help thank you
Answer:
A) earth
B) live
C) live
D) earth
Explanation:
hope i help
Maria drove 100 miles in 2 hrs. what was marias speed?
the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?
- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a
[tex]\\ \sf\Rrightarrow F=ma[/tex]
Take a to leftAs it's multiplied on right side it will be divided on right side.[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]
Or
[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]
Given an unknown metal using C= {Q/(M T)} with energy added of 8,000. J, in which the temperature goes from 24.0 C to 28.0 C at a mass of 46.0 g, find its specific heat capacity?
Answer:
47.48 J/g/K or 4.74 × 10⁴J/Kg/K
Explanation:
C(specific heat capacity)= Q(quantity of heat)/M(mass) × ∆T(change in temperature, Kelvin)
Q= 8000J
M= 46g or 46 ×10^-3Kg
T1= 24°C = 297K
T2 = 28°C = 301K
∆T = 301-297
= 4K
C= 8000/46 × 4
= 47.48 J/g/K or 4.74 × 10⁴J/Kg/K
Which of the following is an example of physical weathering?
O calcium carbonate in limestone changes to calcium hydrogen carbonate
O flow water carves erosion channels in a hillside
Ostalactites precipitate in a cave
O acid rain corrodes a monument
Answer:
acid rain corrodes a monument. d.
Explanation:it only makes sense because its doing something to a physical object.and the other ones aren't.
What event will produce the greatest increase in the gravitational force between the two masses?
Question 5 options:
Doubling the distance between the masses
Reducing the small mass by half
Doubling the large mass
Reducing the distance between the masses by half
Answer:
Doubling the large mass
Explanation:
Doubling the destance bewteen the masses will simply make the gravitational force weaker
same with every answer exce
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Gravitational force is directly proportional to product of mass and inversely proportional to product of distance between them. So, on increasing heaver mass greatest increase in the gravitational force.
Event will produce the greatest increase in the gravitational force between the two masses is Doubling the large mass.
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You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?
Answer:
Explanation:
Centrifugal force Fc = m x v2 / r
Weight = mg
As required by the question
Fc = W
v2 /r = g
given radius r = 22 m
v2 /22 = 9.8
Solve for v
required speed v = √(22 * 9.8)
= 14.35 m/s
v=15 m/s
this may help you
The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.
What is centrifugal force?The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.
The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:
[tex]{\displaystyle F=m\omega ^{2}r}[/tex]
Given, the radius of the curve, r = 22m
The acceleration, a = v²/r
The weight of the box, W = mg
We know that, F = ma
mg = m(v²/r)
v = √gr
[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]
v = 14.68 m/s
Therefore, you should drive at a speed of 14.68 m/s
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El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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The decomposition of dinitrogen pentoxide is described by the reaction: 2N2O5(g)→4NO2(g)+O2(g). If O2 is being formed at a rate of 2.40 mol/min, what is the rate at which N2O5 is being used up?
Answer:
4.80 mol N2O5/min
Explanation:
The balanced equation tells us that 2 moles of N2O5 are required for every 1 mole of O2. Therefore:
(2.40 mol O2/min)*(2 mol N2O5/mol O2) = 4.80 mol N2O5/min