how to get over a guy u have liked for a year and 4 months

Answers

Answer 1

Answer:

Try to find someone who is interested in you as well as you are with him. But be chill about it and never ever let yourself think your not perfect enough cause you are thee most phenomenal person in the entire planet and there is no one like you, you are special. P.S. there are alot of cute guys out there you just gotta wait until he finds you or you find him.

Explanation:

Answer 2

Answer:

huh

Explanation:


Related Questions

Why does air with higher amounts of water vapor have a lighter density?

Answers

Answer:

moist air is less dense than dry air because water has a lower molecular weight than nitrogen and oxygen

Answer:

Water vapor is a relatively light gas when compared to diatomic Oxygen and diatomic Nitrogen. Thus, when water vapor increases, the amount of Oxygen and Nitrogen decrease per unit volume and thus density decreases because mass is decreasing.

If the energy of a photon of light is 3.37 x 10–19 J, what is the frequency of the light? A. 1.12 x 10–27 s –1 B. 8.90 x 1026 s –1 C. 5.09 x 1014 s –1 D. 6.70 x 10–44 s –1 E. 1.01 x 10–10 s –1

Answers

Answer:

The appropriate alternative is option C "[tex]5.09\times 10^{14} \ s[/tex]".

Explanation:

The given value is:

Energy of photon,

E = [tex]3.37\times 10^{-19} \ J[/tex]

As we know,

h = [tex]6.626\times 10^{-34} \ Js[/tex]

Now,

The frequency of the light will be:

⇒  [tex]E=hv[/tex]

On substituting the given values, we get

⇒  [tex]3.37\times 10^{-19}=6.626\times 10^{-34}\times v[/tex]

On solving, we get

⇒                    [tex]v=5.09\times 10^{14} \ s[/tex]

If the energy of a photon of light is 3.37 x 10⁻¹⁹ J, then the frequency of the light is 5.09 x 10¹⁴ per sec.

How we calculate frequency?

Frequency of light will be calculated by using the below formula:
E = hυ, where

E = energy of photon = 3.37 x 10⁻¹⁹ J

h = plank's constant = 6.626 × 10⁻³⁴ Js

Putting these values on the above equation and calculate for the frequency as:

υ = 3.37 x 10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js = 5.09 x 10¹⁴ per sec

Hence, option (C) is correct i.e. 5.09 x 10¹⁴ per sec.

To know more about frequency, visit the below link:
https://brainly.com/question/254161

A sample of gas has a volume of 2.0 liters at a pressure of
1.0 atmosphere. When the volume increases to 4.0 liters, at constant temperature, the pressure will be


a. 0.50 atm
b. 2.0 atm
c. 0.25 atm
d. 1.0 atm

Answers

x= 2.0atm when u substitute for V1P1=V2P2

PLEASEEEE HELP URGENTTTT

Answers

Answer:

i don't see the question

Explanation:

Write the formulas for the following ionic compounds.

potassium iodide
magnesium phosphide
silver sulphide
iron(III) bromide
magnesium hydroxide
sodium sulphate
lead (IV) nitrate
ammonium carbonate

Answers

Answer:

1) KI

2) Mg3P2

3) Ag2S

4) FeBr3

5) Mg(OH)2

6) Na2SO4

7) Pb(NO3)4

8) (NH4)2CO3

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