how to find the number of atoms present in 22g of co2​

Answers

Answer 1

Answer:

22g of  2

C

O

2

have  3.011×1023

3.011

×

10

23

  2

C

O

2

molecules.

Explanation:

Hope this helps! ^^


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Is this right? If not which is it pls

Answers

Answer:

i believe it is b as well

Explanation:

As an electron in an atom moves from a higher energy state to a lower energy state, the atom
1 becomes a negative ion
2 becomes a positive ion
3 releases energy
4 absorbs energy

Answers

Answer:

3 releases energy

Explanation:

An electron in an energy level has a definite amount of energy associated with it at that level.

Electrons can undergo transitions from one level to another. However, when the electron changes its state, it must absorb or emit the exact amount of energy which will bring it from the initial to the final state.

When the electron is excited, it moves from the ground state to an excited state, it must absorb energy. On returning from an excited state to a lower level or the ground state, energy is emitted, giving rise to a line in the spectrum.

Answer: 3 because it releases energy

What forces typically hold nonmetal atoms together within a molecule?
A. Metallic bonds
B. Covalent bonds
C lonic attractions
D Intermolecular forces

Answers

Answer:

B - Covalent bonds

Explanation:

Covalent bonds are a class of chemical bonds where valence electrons are shared between two atoms, typically two nonmetals. The formation of a covalent bond allows the nonmetals to obey the octet rule and thus become more stable.

Can someone help?? This is really hard.

Answers

Answer:

See Explanation

Explanation:

Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.

2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4

2^1 = 2^1

The rate of reaction is first order with respect to Hbn

Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.

1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4

3^1 = 3^1

The reaction is also first order with respect to CO

b) The overall order of reaction is 1 + 1=2

c) The rate equation is;

Rate = k [CO] [Hbn]

d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4  /[5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4/6.7 * 10^-7

k = 4.7 * 10^2 mmol-1 L s-1

e) The reaction occurs in one step because;

1) The rate law agrees with the experimental data.

2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
P4(s)+NaOH(aq)+H2O(l)➪
PH3(g)+Na2HPO3(aq)

Answers

P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3
, not sure

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal. P₄ + 4NaOH + 2H₂O → 2PH₃ + 2Na₂HPO₃.

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.

A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.

To know more about balanced chemical equation, visit;

https://brainly.com/question/14015590

#SPJ4

Chemistry Conversion: Convert 3.0099 dumps to wigs. 6375.23 dumps = 1 wig Round your answer to 5 sig figs. dumps and wigs is not a real unit just used for example.

Answers

Answer:

There are 0.00047212 wig in 3.0099 dumps.

Explanation:

In this problem, we need to convert 3.0099 dumps to wigs.

6375.23 dumps = 1 wig (given)

1 dump = (1/6375.23) wig

To convert 3.0099 dumps to wigs, multiply 3.0099 by (1/6375.23).

3.0099 dumps = [tex]\dfrac{1}{6375.23}\cdot3.0099[/tex]

= 0.00047 wig

Hence, there are 0.00047212 wig in 3.0099 dumps.

If you have a 17% salt solution, how much salt will need to be added to 71 mL of water?

Answers

Salt added : 14.5 g

Further explanation

Given

17% salt solution

71 ml water

Required

salt needed

Solution

%mass = (mass solute : mass solution) x 100%

71 ml water = 71 g water(density = 1 g/ml)

mass solute = x

[tex]\tt 17\%=\dfrac{x}{x+71}\times 100\%\\\\0.17(x+71)=x\\\\0.17x+12.07=x\\\\0.83x=12.07\\\\x=14.5[/tex]

what is p³×p simplify ​

Answers

Answer:

The answer is p.

Explanation:

You have to apply Indices Law :

[tex] {a}^{m} \times {a}^{n} ⇒ {a}^{m + n} [/tex]

For this question :

[tex] {p}^{3} \times {p}^{1} [/tex]

[tex] = {p}^{(3 + 1)} [/tex]

[tex] = {p}^{4} [/tex]

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