How much would it cost to purchase 7.5 lbs of walnuts? 3.5 Walnuts in Bulk It costs $3.45 to buy Alb of chopped walnuts. Explain or show your reasoning.​

Answer:

x = 111; y =36; z = 76

Step-by-step explanation:

The sum of the interior angles of a triangle will add up to zero and a line that divides a straight line into to parts will have a sum of angles of 180 degrees. Use this information to add and subtract the angles to find x, y, and z.

Answer:

[tex] \sf8 \: \frac{newspapers}{plie}\: or\: \text{8 newspapers per pile} [/tex]

Step-by-step explanation:

according to the question

Answer:

Solution given:

48 newspaper in 6 pile=48news paper per 6 piles

=48/6=8 news paper per pile

the unit rate of 48 newspapers in 6 piles is 8 news paper per pile

Answer:

i think 18 since 11+7=18

i think this it is not corect 100%100

Answer:

139.36

Step-by-step explanation:

first you do 8*8 because that would be the area of the square part

8*8=64

then find the area of the semicircle

first the Radis of it is 4 because 8/2=4

A=3.14R^2/2

3.14*4^2/2

3.14*16/2

50.24/2

25.12

now because there are 3 of the semicircles you do

25.12*3

75.36

then you add the 64 from the square to get your answer

75.36+64

139.36

Answer:

$20 was how much money he had before he spent any money.

Step-by-step explanation:

So, with any problem like this, all you have to do to figure out the answer is to add how much money is left and how much was spent. So, like this:

Amount left + Amount spent = Original Amount

Answer:

388

Step-by-step explanation:

i looked it up

Answer:

m∠A = 45⁰

m∠B = 75⁰

Step-by-step explanation:

Given question 4;

m∠A = x + 51

m∠B = 81 + x

m∠C = 60⁰

The value of the missing angles can be determined by the finding the value of x first;

m∠A  +  m∠B  + m∠C = 180⁰ (sum of angles in a triangle)

(x + 51)  +  (81 + x)  +  60⁰ = 180

(x + x) + (51 + 81 + 60) = 180

2x + 192 = 180

2x = 180 - 192

2x = -12

x = -12/2

x = -6

Thus, the values of the angles are calculated as follows;

m∠A = x + 51

         = -6 + 51  

          = 45⁰

m∠B = 81 + x

        = 81 - 6

         = 75⁰

Answer:

no because

Fractions and decimals are not integers. All whole numbers are integers (and all natural numbers are integers), but not all integers are whole numbers or natural numbers. For example, -5 is an integer but not a whole number or a natural number.

-6/3 is not an integer.

A number system is defined as a system of writing to express numbers.

We need to check whether -6/3 is a integer or not .

An integer is a whole number (not a fractional number) that can be positive, negative, or zero.

The given number is a fraction which is not comes under the integers.

All whole numbers are integers but  but not all integers are whole numbers or natural numbers.

If the fraction is simplified we get -2 which will be an integer but the fraction form is not considered as integer.

Hence, -6/3 is not an integer.

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Answer:

51 goals

Step-by-step explanation:

Given data

Dyson completed 85% of his field goal attempt

number of attempts = 60

Required

The number of goals

=85/100*60

=0.85*60

=51 goals

Hence he made 51 goals in all

Answer:

$160,500

Step-by-step explanation:

First, find the coming years sales

7% of 1,500,000 is 105000

105,000+1,500,00=1,605,000

1,605,000 is the next year's sales and we do that *0.1 to find the advertising.

1,605,000*0.1=160,500

So 160,500 will be set aside for advertising

Hope this helped!

Answer:

y = 25x – 300

Step-by-step explanation:hope I helped

Answer: Is this the whole question if not i can edit later and answer once i get it all?

Answer:

d. 14 pieces

Step-by-step explanation:

3.5 ÷ 25 = 0.14 = 14

cuz the 0. doesn't have a value

Answer:

£510

Step-by-step explanation:

Simple interest = (principal × rate × time) / 100

Principal = £1700

Rate = 10%

Time = 3 years

Simple interest = (principal × rate × time) / 100

= (1700 × 10 × 3) / 100

= 51,000/100

= 510

Simple interest = £510

Answer:

Steady

Step-by-step explanation:

I understand how you can get confused on this but steady is your keyword because steady means at a proportional rate and has not drastic changes if graphed on a number line.

2x+4<10

Subtract 4 from both sides to cancel it out.

2x+4<10

   -4   -4

2x<6

Now divide 2 from both sides to cancel that out.

2x<6

/2  /2

x<3

So that's the answer.

---

hope it helps

Answer:

5/7

Step-by-step explanation:

Multiply the numerator with the numerator and the denominator with the denominator. This makes the fraction 30/42. Simplify this to get 15/21. You can simplify it again to get 5/7.

Hope this helps

Answer:

6/7

Step-by-step explanation:

Product of slope of perpendicular line = -1

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\[/tex]

          [tex]= \frac{7-0}{3-9}\\\\=\frac{7}{-6}\\\\=\frac{-7}{6}[/tex]

Slope of the  perpendicular line = -1/m = -1 ÷ [tex]\frac{-7}{6}[/tex]

                                                     [tex]= -1 * \frac{-6}{7} = \frac{6}{7}[/tex]

Answer:

figure it out lol

Step-by-step explanation:

u got oofed

Answer:

Multiply the sides and you will get the answer. And then divide by 180

Step-by-step explanation:

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

[tex]\Rightarrow h(t)=-8t^2+16+2[/tex]

Height will be zero once the rocket lands on the ground

So, we can write

[tex]\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s[/tex]

The rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

The given equation is  [tex]\rm h(t)=-8t^2+16t+2\\[/tex], where h(t) is the rocket's height in meters t seconds after launch.

In algebra, a quadratic equation is an equation that can be written in standard form as

[tex]\rm ax^{2}+bx+c=0}[/tex]

where x represents variable, and a, b, and c represent coefficient.

The given equation is

h(t) = 0

[tex]\rm h(t)=-8t^2+16t+2\\h(t)=-8t^2+16t+2 = 0\\[/tex][tex]\rm h(t)=-8t^2+16t+2\\[/tex]

The roots will be

[tex]\rm {\displaystyle t={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}[/tex]

[tex]\rm {\displaystyle t={\frac {16\pm {\sqrt {(-16)^{2}-4\times 8\times 2}}}{16}}.}\\\rm {\displaystyle t={\frac {16\pm {\sqrt{320} }}{16}}}\\\rm {\displaystyle t={\frac{16+17.88}{16}\\[/tex]

Here, we have neglected the negative value of t

t = 2.1 seconds

So, the rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

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Answer:

The measure of A is 93

Step-by-step explanation:

Here, we want to get the measure of angle A

we can start by getting the measure of angle C

Mathematically, we can use sine rule

It states that the ratio of the length of a side of a triangle and the sine of the angle it faces is constant

So to get C, we have the following;

9/sin 38 = 11/sin C

sin C = 11sin 38/9

sin C = 0.7525

C = sin^-1(0.7525)

C = 48.80

This is approximately 49

To get A,

we know that if we added the measure of interior angles of a triangle, the addition is 180 degrees

Thus, we have it that:

38 + 49 + A = 180

A = 180-38-49

A = 93

Answer:

Dilate from center A by scale factor of 2, then reflect over line AC

Step-by-step explanation:

(1) Dilate from center A  by  scale factor 2 and then  reflect  over line AC  

hence option (1) is correct.

Given

AC =6

The sequence of transformations   that would show that Δ ABC and  Δ AED are similar

For similar triangles  we can say that sides are proportional

from Δ ABC and  Δ AED  we write that

[tex]\rm \dfrac{AE}{AB } = \dfrac{ED}{BC}= \dfrac{AD}{AC}\\\\\\\rm \dfrac{4}{8} =\dfrac{2}{4} = \dfrac{3}{AC}[/tex]

We can clearly see that scale factor of dilation is 2  (given AC=6) , also we need reflection over line AC.  hence from given options.

(1) Dilate from center A by scale factor 2  and then  reflect  over line AC  

(2)  Dilate from center A  by  scale factor 2   and then  rotate   60° around angle A.

(3) Translate by directed line segment DC and then reflect over line AC.

(4) Dilate from center A  the by  scale factor 4   and then  reflect  over line AC  

hence option (1) is correct.

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Answer:

D

Step-by-step explanation:

Δ DCA and Δ ABE are similar, thus the ratios of corresponding sides are equal, that is

[tex]\frac{CA}{BE}[/tex] = [tex]\frac{DA}{AE}[/tex] , substitute values

[tex]\frac{18}{10}[/tex] = [tex]\frac{x+8}{8}[/tex] ( cross- multiply )

10(x + 8) = 144 ( divide both sides by 10 )

x + 8 = 14.4 ( subtract 8 from both sides )

x = 6.4 → D

The value of x is the length of BD, so x = 6.So, The correct answer is C. 6.

The value of x is the length of the altitude from vertex B to side AC. We can find this length by using the Pythagorean Theorem on right triangle ABD.

[tex]AB^2 + BD^2 = AD^2\\8^2 + BD^2 = 10^2\\BD^2 = 36\\BD = 6[/tex]

The altitude from vertex B to side AC is equal to the length of BD, so x = 6.

Here is a breakdown of the steps involved in solving for x:

We are given the lengths of sides AB and AC of triangle ABC.

We know that the altitude from vertex B to side AC will be perpendicular to side AC. We can use the Pythagorean Theorem on right triangle ABD to find the length of BD, which is the altitude from vertex B to side AC.

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Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

The product of the expression modeled by the tiles is likely to be (x + 1)(x + 3).

An expression in mathematics is a combination of numbers, variables, and operators that represent a value or a relationship between values. Expressions can be simple or complex, and they can be used to perform mathematical operations or to represent mathematical concepts. For example, the expression 2 + 3 is a simple expression that represents the sum of 2 and 3. The expression x + y is a more complex expression that contains variables, which can take on different values. The expression (x + y)² represents the square of the sum of x and y. In general, an expression can be evaluated to find its value. For example, if we assign the value of 3 to x and the value of 4 to y, then the expression (x + y)²  can be evaluated as (3 + 4)^2 = 7² = 49. Expressions play a fundamental role in mathematics, and they are used in a wide range of mathematical concepts, including algebra, calculus, and geometry.

Here,

This can be deduced from the fact that two tiles with the same x term are placed next to each other and the other two tiles have a constant term.

The product of these two tiles would then be expression (x + 1)(x + 3).

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