How Many texts?please help.

Answer:

We conclude that the slope of the line containing the points (0, -2) and (3, -2) is:

Step-by-step explanation:

Given that the line includes the points

We need to find the slope of the line containing the points between (0, -2) and (3, -2) using the formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

where m is the slope between (x₁, y₁) and (x₂, y₂)

In our case,

now substituting (x₁, y₁) = (0, -2) and (x₂, y₂) = (3, -2) in the slope formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{-2-\left(-2\right)}{3-0}[/tex]

[tex]m=\frac{-2+2}{3}[/tex]

[tex]m=\frac{0}{3}[/tex]

[tex]m = 0[/tex]

Therefore, we conclude that the slope of the line containing the points (0, -2) and (3, -2) is:

Answer:

The solution of the equation [tex]3 + x = 11[/tex] is [tex]x = 8[/tex].

Step-by-step explanation:

Let [tex]3 + x = 11[/tex], we see that number of equation and variables are both the same and can be solved by algebraic means.

1) [tex]3 + x = 11[/tex] Given

2) [tex]x + 3 = 11[/tex] Commutative property

3) [tex]x + [3+(-3)] = 11 + (-3)[/tex] Compatibility with addition/Associative property

4) [tex]x = 8[/tex] Additive inverse/Modulative property/Definition of substraction/Result

The solution of the equation [tex]3 + x = 11[/tex] is [tex]x = 8[/tex].

Answer:

50

Step-by-step explanation:

20+20=40

5+5=10

40+10=50

Answer: P=50

Step-by-step explanation: 20 m = length and 5 m = width

Solution:

P=2(l+w)=2·(20+5)=50

So the perimeter is 50

Answer:

your y intercept is 90 and the equation would be y= 90 and x is unknown

Answer:

5

25/5=5

Step-by-step explanation:

answer:

you need not attach a graph to this. please do that so we can help you with the questions.

Answer:

im pretty sure its 36%

Step-by-step explanation:

Answer: Increasing her speed  by 5km/h, she will take 4.5 hours to complete the journey.

Step-by-step explanation:

Step 1

Speed= Distance  / TIme

Given Speed = 45km/h

and Time = 5 hours

Distance covered = Speed x Time

= 45 km/h x 5 hours

=225 kilometres.

Step 2

Increasing her speed by 5km/h makes the new Speed = 45 +5 = 50 km/h

At the same Distance of 225 km

Therefore she will complete the journey in

Time = Distance/ Speed

=225km/ 50km/h

=4.5 hours

Answer:

The number is

=

109.31

Explanation:

Let the number be

=

x

58

100

(

x

)

=

63.4

x

=

63.4

×

(

100

58

)

x

=

6340

58

x

=

109.31

Answer:

5

Step-by-step explanation:

Answer: (6, -6)

Step-by-step explanation:

so midpoint =([tex]\frac{X1+X2}{2}[/tex],[tex]\frac{Y1+Y2}{2}[/tex])

for x co ordinate

[tex]\frac{-2+X2}{2}[/tex]=2

-2+X=4            (X2=x co ordinate point for b, can be written as just x now)

X=6

x co ordinate of B= 6

y co ordinates of y

[tex]\frac{-8+Y2}{2}[/tex]=-7

-8+Y=-14

Y=-6

co ordinates B (6,-6)

for proof/extra explanation (NOT necessary for working):

[tex]\frac{Y1+Y2}{2}[/tex]

=[tex]\frac{(-2)+6, (-8)+(-6)}{2}[/tex]

=[tex]\frac{4, -14}{2}[/tex]

=(2,-7)

which is the midpoint M

Answer:

yes

Step-by-step explanation:

angle 1 = 180-110 = 70 degrees (linnear pair)

angle 2= 180-115 = 65 degrees (linnear pair)

angle 3 = angle 2 = 65 degrees (corresponding angles)

angle 4= 180 - angle 3 = 180-65 = 115 degrees (linnear pair)

(your teacher might not like this, depends on the cituation, but use 180 degrees in triangle to get 7)

angle 7 = 180 -angle1 -angle 2= 180-70-65= 45 degrees

angle 6 = angle 7 = 45 degrees ( vertical angles)

angle 8= 180- angle 7= 180-45 = 135 ( linnear pair)

angle 9 =angle 6 = 45 degrees (corresponding angles)

angle 5=angle 9=45 degrees (vertical angles)

Answer:

[tex]let \: their \: points \: of \: intersection \: be \to \: x \\ since : \\ \: \overline{MN} \: intersects \: \overline{QL} \: at \: point \: x : \\ and\\ \overline{QL} \: also \: meets \: \overline{MN} \: at \: point \: x : \\ hence \: \overline{QL}\: and \: \overline{MN} \: bisects \: each \: other.[/tex]

Answer:

990 cm²

Step-by-step explanation:

Given ratio of radii = a : b , then

ratio of areas = a² : b²

Here

ratio of radii = 50 : 30 = 5 : 3 , then

ratio of areas = 5² : 3² = 25 : 9

let x be the area of sector DEF , then using proportion

[tex]\frac{25}{2750}[/tex] = [tex]\frac{9}{x}[/tex] ← [tex]\frac{ratio}{area}[/tex]

cross- multiply

25x = 24750 ( divide both sides by 25 )

x = 990

Area of sector DEF = 990 cm²

Answer:17

Step-by-step explanation:

20-3=17

Answer:

C is your Answer

Step-by-step explanation:

Answer:

a or b i will help no further

odpowiedź A aaaaaaaaaaaaaaaaa

Answer:

6.5

Step-by-step explanation:

Hope I helped!

Answer: 43 + x = 90

Step-by-step explanation:

43 + x = 90

x = 90-43

x = 47

Answer:

$5.49

Step-by-step explanation:

Rewrite 23¢ and 2¢ as $0.23 and $0.02, and then combine them:  $0.25.  Now add this result to $5.24.  We get $5.49

Answer:

28

Step-by-step explanation:

Answer:

there are 4 times larger

Step-by-step explanation: 11 x 4 = 44 so its 4 times larger

Answer:

pretty sure it's 35.87 kilometers

Answer:

Step-by-step explanation:

p:c=10:14

p/c=10/14

p/7=10/14

p=7(10)/14

p=5

Answer:

5 plates

Step-by-step explanation:

First, make two fraction bars, one with the ratio 10/14 the other with the top blank and 7 on the bottom. Next, find how much to multiply 7 by to get 14. Use the number you get to divide 10 by. Then you should get 5. Hope this helped!

Answer:

1

Step-by-step explanation:

6+6=12

12/12=1

Step-by-step explanation:

= 6+ 6÷12

= 6+ 1/2

= 13/2

hope this will be helpful to you.

plz mark my answer as brainlist if you find it useful.

Answer:

The two column proof is presented as follows;

Statement                   [tex]{}[/tex]                  Reason

1. Parallelogram SUPN [tex]\overline {SR}[/tex]⊥ [tex]\overline {UN}[/tex] [tex]{}[/tex]   1. Given

and [tex]\overline {MP}[/tex]⊥ [tex]\overline {UN}[/tex]

2. ∠SRU = ∠PMN = 90°   [tex]{}[/tex]                 2. Definition of perpendicular lines

3. ∠SRU ≅ ∠PMN            [tex]{}[/tex]                 2. Definition of congruency

4. [tex]\overline {UP}[/tex] ║ [tex]\overline {SN}[/tex]                      [tex]{}[/tex]                4. Opposite sides of a parallelogram are                                            [tex]{}[/tex]                                                               congruent

5. ∠SNR ≅ ∠PUM             [tex]{}[/tex]               5. Alternate interior angles are congruent

6. [tex]\overline {UP}[/tex] ≅ [tex]\overline {SN}[/tex]                      [tex]{}[/tex]               6. Opposite sides of a parallelogram are                                            [tex]{}[/tex]                                                              congruent

7. ΔPMU ≅ ΔSRN                 [tex]{}[/tex]           7. By AAS rule of congruency

By the Angle-Angle-Side (AAS) rule of congruency, we have that, if two angles and a corresponding adjacent side (∠SRU ≅ ∠PMN, ∠SNR ≅ ∠PUM, [tex]\overline {UP}[/tex] ≅ [tex]\overline {SN}[/tex])  of two triangles (ΔPMU and ΔSRN) are congruent, then the the two triangles are also congruent (ΔPMU ≅ ΔSRN)

Step-by-step explanation: