9514 1404 393
Answer:
1 solution
Step-by-step explanation:
The coefficients of d are different on the two sides of the equation (3d vs 6d), so the equation has one solution.
__
Dividing by 3 gives ...
d +11 = 2(d +33)
d + 11 = 2d + 66
Adding -d-66 to both sides gives ...
-55 = d . . . . . . the one solution
Answer:
The answer is B
Step-by-step explanation:
i took the test and 1 was correct so.
What is the value of j
Write the following equation in the general form Ax+ By+ C:
1/2y -1/3x -1 = 0
a.) -2x +3y -6 = 0
b.) 2x -3y -6 = 0
c.) 2x 3y +6 = 0
Need help ASAP with my math
Answer: The answer is -2
Step-by-step explanation: I want points and trust me this answer is correct
-6(x - 6) = x(16 - 7)
Help please
Answer:
the answer would be x equal 2.4
Step-by-step explanation:
sorry for my bad handwriting
(-8) X 2/3 i NEED the answer help me
-5.33333333333
I used a calulator can I get brainliest please
−20=−4x−6x Find the value of x
Answer:
[tex]\huge\boxed{x=2}[/tex]
Step-by-step explanation:
[tex]-20=-4x-6x\qquad|\text{combine like terms}\\\\-20=-10x\qquad|\text{divide both sides by (-10)}\\\\\dfrac{-20}{-10}=\dfrac{-10x}{-10}\\\\2=x\to x=2[/tex]
What does the value of the LCM represent? How many packs of red sticks and blue sticks should Harold purchase?
Answer:
LCM mean least common multiple
Step-by-step explanation:
The red sticks in a pack of 8 so, to get 24 red sticks, Harold needs = 3 packs. The blue sticks come in a pack of 12 to get 24 blue sticks, Harold need = 2 pack
Answer:
the LCM represents the minimum number of sticks of each color that Harold would have to buy to have the same number of blue sticks and red sticks.
The red sticks come in packs of 8. So, to get 24 red sticks Harold need 3 packs.
The blue sticks come in packs of 12, so to get to 12 blue sticks Harold needs 2 packs.
in conclusion Harold should purchase 3 packs of red sticks and 2 packs of blue sticks.
hope this helped ^^
Tara's website, verdantveggies.com, specializes in the sale of rare or unusual vegetable seeds. Tara sells packets of sweet-pepper seeds for $2.85 each and packets of hot-pepper seeds for $4.29 each. She also offers a 16-packet mixed-pepper assortment combining packets of both types of seeds at $3.30 per packet. How many packets of each type of seed are in the assortment?
Answer:
Let's define the variables:
S = # of sweet pepper seeds in the mix pack.
H = # of hot pepper seeds in the mix pack.
Let's suppose that $3.30 is the mean price of the seeds in the mix pack.
Then we have two equations:
S + H = 16.
(S*$2.85 + H*$4.29)/16 = $3.30
Now let's solve this system.
The first step is isolating one variable in one of the equations, i will isolate S in the first equation.
S = 16 - H.
Now we can replace this in the second equation, and solve it for H.
( (16 - H)*$2.85 + H*$4.29)/16 = $3.30
( (16 - H)*$2.85 + H*$4.29) = $3.30*16 = $52.80
$45.60 + H*$1.44 = $52.80
H*$1.44 = $52.80 - $45.60 = $7.20
H = $7.20/$1.44 = 5
Then in the mix pack there are 5 hot-pepper seeds.
And the other 11 must be sweet-pepper seeds
Algebraic equations are equations that contain unknown variables.
The number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.
Let's represent:is
The number of packets of sweet-pepper seeds = s
The number of packets of hot-pepper seeds = h
Based on this question, our system of equations are:
$2.85 x s + $4.29 x h = $3.30(16)
2.85s + 4.29h = 52.8...........Equation 1
s + h = 16...........Equation 2
s = 16 - h
We substitute 16 - h for s in Equation 1
2.85(16 - h) + 4.29h = 52.8
45.6 -2.85h + 4.29h = 52.8
Subtract 45.6 from both sides
45.6 - 45.6 -2.85h + 4.29h = 52.8 - 45.6
1.44h = 7.2
h = 5
There are 5 hot-pepper seeds in the assortment.
Solving for the number of sweet-pepper seeds.
s = 16 - h
s = 16 - 5
s = 11
There are 11 sweet-pepper seeds in the assortment.
Therefore, the number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.
To learn more, visit the link below:
brainly.com/question/12978834
A florist sold 45 flowers in a day and 60 flowers on the next day. If p is the percent increase in the number of flowers sold, which proportion can be used to calculate p?
Answer:
c
Step-by-step explanation:
i took the test
Answer: C
Step-by-step explanation:
Only one that makes sense and I just took that test
бx + 8 = 50
I need that answer
Answer:
=
7
Step-by-step explanation:
11. Factor for
12 – 8.1 + 16
Answer:
2(6-4.05+8)
Step-by-step explanation:
2(6-48+43.05+8)
The temperature at 4:00 p.m. was 2.5'F. It
dropped 0.75°F each hour for the next 4 hours.
What was the temperature at 8:00 p.m.?
Answer:-0.5; 0.75*4=3, 2-3=-0.5
Step-by-step explanation:
Answer:
-0.5...............
please answer asap!!
Answer:
∠QPR = 40°
Step-by-step explanation:
According to the question the line PQ ⊥ PS which means that they both are perpendicular angles. Perpendicular angles are always 90°, so,
∠QPR + ∠RPS = 90°
=> 7x - 9° + 4x + 22° = 90°
=> (7x + 4x) +(22 - 9)° = 90°
=> 11x + 13° = 90°
=> 11x = 90° - 13°
=> 11x = 77°
=> x = 77/11
=> x = 7
So, now that we have x, we can find ∠QPR,
7x - 9°
=> (7 * 7 - 9)°
=> (49 - 9)°
=> 40°
If my answer helped, kindly mark me as the brainliest!!
Thank You!!
bob is on his way home in his car. he has driven 30 miles so far, which is three-fifths of the way home. what is the total length of his drive?
The length of Bob's drive as a fraction = 5/5
Let the length of his total drive be = x
30 miles driven by Bob as a fraction =
= 3/5 of x = 30
= 3/5x = 30
= 5/x = 30 ÷ 3 ( transposing ×3 from LHS to RHS changes ×3 to ÷3 )
=5/x = 10
= x = 10 × 5 ( transposing ÷5 from LHS to RHS changes ÷5 to ×5 )
= x = 50
Now we have to see what is =
= 2/5 of 50
= 2/5 × 50
= 100/5
= 20 miles
So , total length of Bob's drive = 30 miles + 20 miles = 50 miles .
∴ The total length of Bob's drive is 50 miles .
Evaluate 8 ÷ -2 · 4²+9. Thanks! Will give brainiest if possible
A population has standard deviation g = 17.2.
Part 1 of 2
(a) How large a sample must be drawn so that a 99.8% confidence interval for I will have a margin of error equal to 3.8?
Round the critical value to no less than three decimal places.
Round the sample size up to the nearest integer.
A sample size of is needed to be drawn in order to obtain a 99.8% confidence interval with a margin of error equal to
3.8.
Part 2 of 2
(b) If the required confidence level were 80%, would the necessary sample size be larger or smaller?
(Choose one) because the confidence level is (Choose one)
х
Answer:
idk
Step-by-step explanation:
Factorise fully
40-10g
Please do quick, will mark brainiest!!
Answer:
10(4-g)Step-by-step explanation:
[tex]40 - 10g[/tex]
Rewrite 40 as 4 × 10
[tex]4 \times 10 - 10g[/tex]
Factor out 10
[tex]10(4 - g)[/tex]
The toco toucan, the largest member of the toucan family, possesses the largest beak relative to body size of all birds. This exaggerated feature has received various interpretations, such as being a refined adaptation for feeding. However, the large surface area may also be an important mechanism for radiating heat (and hence cooling the bird) as outdoor temperature increases. Here are data for beak heat loss, as a percent of total body heat loss, at various temperatures in degrees Celsius:
Temperature (degrees Celsius) 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Percent heat loss from beak 35 36 38 28 41 43 55 46 39 54 45 58 60 56 62 67
a. The equation of the least-squares regression line for predicting beak heat loss, as a percent of total body heat loss from all sources, from temperature is: _____ (Use decimal notation. Give your answer to four decimal places.)
b. Use the equation to predict (
±
0.01) beak heat loss, as a percent of total body heat loss from all sources, at a temperature of 25 degrees Celsius.
c. What percent (
±
0.01) of the variation in beak heat loss is explained by the straight-line relationship with temperature?
d. Find the correlation r (
±
0.001) between beak heat loss and temperature.
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data:
Temperature (degrees Celsius) : 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Percent heat loss from beak : 35 36 38 28 41 43 55 46 39 54 45 58 60 56 62 67
Using an online regression calculator ; the regression equation obtained is :
ŷ = 2.0927X + 0.6029
X = independent variable
Y = predicted variable
2.0927 = slope
0.6029 = intercept
B.) temperature = 25
ŷ = 2.0927(25) + 0.6029
= 52.9204
C.) the explained variance is the value of the coefficient of determination (R²) which is the square of the correlation Coefficient
0.8785² = 0.7718
D.) the correlation Coefficient r is 0.8785 using the Coefficient of regression calculator
What is the sign of the product (3)(−25)(7)(−24)?
A. Positive, because the products (3)(−25) and (7)(−24) are negative, and the product of two negative numbers is positive
B. Positive, because the products (3)(−25) and (7)(−24) are positive, and the product of two positive numbers is positive
C. Negative, because the products (3)(−25) and (7)(−24) are negative, and the product of two negative numbers is negative
D. Negative, because the products (3)(−25) and (7)(−24) are positive, and the product of two positive numbers is negative
A student takes a multiple-choice test that has 10 questions. Each question has four choices. The student guesses randomly at each answer. Let X be the number of questions the student gets correct. (a) Find P(X = 3). (b) Find P(X > 2). (c) To pass the test, the student must answer 7 or more questions correctly. Would it be unusual for the student to pass? Explain.
Answer:
1)0.2502
2)0.475
3)0.003505
Step-by-step explanation:
Total No. of question n= 10
There are four choices in each question
So, Probability of success [tex]p = \frac{1}{4}[/tex]
Probability of failure q = [tex]1- \frac{1}{4}=\frac{3}{4}[/tex]
We will use binomial over here
[tex]P(X=x)=^nC_r p^r q^{n-r}[/tex]
1)
[tex]P(X = 3)=^{10}C_3 (\frac{1}{4})^3 (\frac{3}{4})^7\\P(X = 3)=\frac{10!}{3!7!} (\frac{1}{4})^3 (\frac{3}{4})^7\\P(X = 3)=0.2502[/tex]
2) [tex]P(X > 2)=1-P(X\leq 2)[/tex]
P(X>2)=1-(P(X=0)+P(X=1)+P(X=2))
[tex]P(X>2)=1-(^{10}C_0 (\frac{1}{4})^0 (\frac{3}{4})^{10}+(^{10}C_1 (\frac{1}{4})^1 (\frac{3}{4})^9+^{10}C_2 (\frac{1}{4})^2 (\frac{3}{4})^8)[/tex]
[tex]P(X>2)=1-((\frac{1}{4})^0 (\frac{3}{4})^{10}+(\frac{10!}{1!9!} (\frac{1}{4})^1 (\frac{3}{4})^9+\frac{10!}{2!8!} (\frac{1}{4})^2 (\frac{3}{4})^8)[/tex]
P(X>2)=0.475
3)
[tex]P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\P(X\geq 7)=^{10}C_7 (\frac{1}{4})^7 (\frac{3}{4})^{3}+(^{10}C_8 (\frac{1}{4})^8 (\frac{3}{4})^2+^{10}C_9 (\frac{1}{4})^9 (\frac{3}{4})^1+^{10}C_{10} (\frac{1}{4})^{10} (\frac{3}{4})^0\\\\P(X\geq 7)=\frac{10!}{7!3!} (\frac{1}{4})^7 (\frac{3}{4})^{3}+\frac{10!}{8!2!} (\frac{1}{4})^8 (\frac{3}{4})^2+\frac{10!}{9!1!} (\frac{1}{4})^9 (\frac{3}{4})^1+\frac{10!}{10!0!}(\frac{1}{4})^{10} (\frac{3}{4})^0\\\\P(X\geq 7)=0.003505[/tex]
Megan had $235.17 in her bank account. She withdrew $77.98 from the account to spend
on clothing. How much money does she have left in her bank account now?
Answer: 157.19
Step-by-step explanation:
Which correctly solves the equation ab+c=d solve for b.
Answer:
b=(d-c)/a
Step-by-step explanation:
Just gotta switch them around a bit
|3d-3n|-4 if n=2 and d=3
Answer:
-1
Step-by-step explanation:
[tex]|3d-3n|-4[/tex]
Once we have an absolute value, we know that
[tex]|3d-3n| \geq 0[/tex]
[tex]\text{For }n=2 \text{ and } d=3[/tex]
[tex]|3(3)-3(2)|-4[/tex]
[tex]|9-6|-4[/tex]
[tex]|3|-4[/tex]
[tex]3-4[/tex]
[tex]-1[/tex]
Use a system of linear equations with two variables and two equations to solve.
175 students enrolled in a freshman-level chemistry class. By the end of the semester, 4 times the number of students passed as failed. Find the number of students who passed, and the number of students who failed.
Answer:
35 failed and 140 passed
Step-by-step explanation:
Let p = number who passed
f = number who failed
p+f = 175
4 times the number of students passed as failed, so we need to balance this to set it equal
4f = p
Substitute this into the first equation
4r+f = 175
5f = 175
5f/5 =175/5
f = 35
Now find the number who passed
p = 4f
p = 4*35
p =140
9. Determine whether KM and ST are parallel, perpendicular, or neither. K(-1, -8), M(1,6), S(-2,-6), T(2, 10) A Parallel B Perpendicular C Neither Hint(use slope formula)
What is the answer of 10% of 6340
Answer:
604
Step-by-step explanation:
just simple division pls giv 5 out ogf 5 and thanks
Answer:
634
Step-by-step explanation:
2/15 = h/125 need a step by step please
====================================
Work Shown:
2/15 = h/125
2*125 = 15*h .... cross multiply
250 = 15h
15h = 250
h = 250/15
h = (5*50)/(5*3)
h = 50/3
-----------------
Extra info:
50/3 = (48+2)/3
50/3 = (48/3)+(2/3)
50/3 = 16 + (2/3)
50/3 = 16 & 2/3
The improper fraction 50/3 converts to the mixed number 16 & 2/3
Another way to see this is to use long division to get 50/3 = 16 remainder 2.
Show that each conjecture is false by finding a counterexample.
1.For any integer n, n3 > 0.
2. Each angle in a right triangle has a different measure.
3.For many years in the U.S, each bank printed its own currency. The variety of different bills led to widespread counterfeiting. By the time of the Civil War, a significant fraction of the currency in circulation was counterfeit. If one soldier had 48 bills, 16 of which were counterfeit, and another soldier had 39 bills, 13 of which were counterfeit, make a conjecture about what fraction of bills were counterfeit at the time of the Civil War.
Answer:
1. [tex]n: n^3 > 0[/tex] is not true for negative integers
2. [tex]45\ and\ 45[/tex] show that all angles do not have different measure
3. [tex]Fraction = \frac{1}{3}[/tex]
Step-by-step explanation:
Solving (1):
[tex]n: n^3 > 0[/tex]
Take
[tex]n = -1[/tex]
[tex]-1^3 = -1[/tex]
[tex]n: n^3 > 0[/tex] is not true for negative integers
Solving (2):
The angles of a right angled triangle are:
[tex]45, 45\ and\ 90[/tex]
[tex]45\ and\ 45[/tex] show that all angles do not have different measure
Solving (3):
When
[tex]Bills = 48[/tex]
[tex]Counterfeit = 16[/tex]
The fraction is calculated as thus:
[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]
[tex]Fraction = \frac{16}{48}[/tex]
[tex]Fraction = \frac{1}{3}[/tex]
Similarly, when
[tex]Bills = 39[/tex]
[tex]Counterfeit = 13[/tex]
[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]
[tex]Fraction = \frac{13}{39}[/tex]
[tex]Fraction = \frac{1}{3}[/tex]
a hill rises 10 meters over horizontal distance of 8 meters
calculate the slope
Answer:
Slope = 5/4
Step-by-step explanation:
GCF of 10 and 8 is 2, divide both values by two and have the 10 as the rise and 8 as the run.
Solve for X please :(( Will give brainliest.
5x+6+92 = 22x-4
5x+98 = 22x-4
add 5x to both sides
98 = 27x-4
add 4 to both sides
102 = 27x
divide both sides by 27
x = 3 and [tex]\frac{7}{9}[/tex]