Classify the following rocks as either foliated or nonfoliated quartile, schist.
Answer:
d. quartzite
Explanation:
All the other rocks have a planar texture except for quartzite which is hard as a single quartz crystal and is difficult to crush or break. That is the picture of a quartz
used by astronomers to take pictures, collect samples, and pick up data from their sensors
Answers: About one year/ 1997/ gravity/ space station/ international space station (ISS)/ robotic probes/ space probe
Astronomers use a variety of tools and instruments to take pictures, collect samples, and gather data from sensors. These include telescopes, spectrometers, and space probes.
Telescopes are essential tools for capturing images and observing celestial objects. They come in different types, such as optical telescopes that capture visible light, radio telescopes that detect radio waves, and X-ray telescopes that observe high-energy emissions. Telescopes help astronomers analyze stars, planets, galaxies, and other cosmic phenomena.
Spectrometers are devices that measure the properties of light. By studying the spectrum of light emitted or absorbed by celestial bodies, astronomers can gather valuable information about their composition, temperature, and motion. Spectrometers provide insights into the chemical makeup of stars and the atmospheres of planets, contributing to our understanding of the universe's formation and evolution.
Space probes are unmanned spacecraft that explore our solar system and beyond. They carry a range of sensors, cameras, and sampling equipment to collect data and capture images of their target objects. Probes such as the Hubble Space Telescope, Voyager missions, and Mars rovers have provided us with unprecedented information about distant celestial bodies and helped us understand the origins of our universe.
In summary, astronomers use telescopes, spectrometers, and space probes to observe, photograph, and collect data from celestial objects. These tools are invaluable in expanding our knowledge of the cosmos and unlocking the mysteries of the universe.
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Predict the sign of ∆H for placing ice on your lab table. Is this reaction endothermic or exothermic? Explain.
Answer:
Explanation:
Placing ice on a lab table is an exothermic process, which means that the enthalpy change (∆H) for this reaction is negative.The reason for this is that when ice is placed on a lab table, it comes into contact with a surface that is warmer than its own temperature, and heat flows from the warmer surface (the lab table) to the cooler surface (the ice). This heat transfer causes the ice to melt, which is an exothermic process since heat is released to the surroundings.Since exothermic processes release heat energy, the enthalpy change (∆H) for this reaction is negative. Therefore, placing ice on a lab table has a negative ∆H, indicating that it is an exothermic process.
iv) By what factor will the
rate change if the
Concerntration
and that of B is reduced by
of A is trippled
4 times.
The rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.
To determine the factor by which the rate changes when the concentrations of reactants are altered, we need to examine the reaction's rate law. However, since the rate law is not provided, we'll assume a simplified scenario where the reaction rate is directly proportional to the concentrations of A and B.
Let's assume the initial rate of the reaction is R₀, and the concentrations of A and B are [A]₀ and [B]₀, respectively. According to the assumed rate law, the rate can be expressed as:
Rate = k[A][B]
Now, let's consider the changes in concentrations and calculate the new rate.
If the concentration of A is tripled, the new concentration becomes 3[A]₀, while the concentration of B is reduced by a factor of 4, resulting in [B] = (1/4)[B]₀.
The new rate (R) can be calculated as follows:
R = k[3[A]₀][(1/4)[B]₀]
= (3/4)k[A]₀[B]₀
= (3/4)R₀
Therefore, the rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.
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How do I find the radius of a cylinder that is is 2 cm long with a mass of 12.4g?
Explanation:
It is not possible to find the radius of a cylinder with only its length and mass. Additional information, such as the density or volume of the cylinder, would be needed.
The elements shown are gases at room temperature and pressure.
hydrogen
nitrogen
oxygen
chlorine
When separate samples of each of these gases are placed in a container they will diffuse.
Describe why these gases diffuse.
The process of diffusion occurs because gas particles possess kinetic energy and are in constant motion. When separate samples of hydrogen, nitrogen, oxygen, and chlorine gases are placed in a container, the gas particles will move randomly and spread out from areas of high concentration to areas of low concentration.
Gases diffuse due to the random motion of their particles. The process of diffusion occurs because gas particles possess kinetic energy and are in constant motion. When separate samples of hydrogen, nitrogen, oxygen, and chlorine gases are placed in a container, the gas particles will move randomly and spread out from areas of high concentration to areas of low concentration. Diffusion happens as a result of collisions between gas particles. The particles move in all directions, and over time, they spread out evenly throughout the available space, resulting in a uniform concentration. This process is driven by the tendency of gas particles to achieve equilibrium and maximize their entropy The rate of diffusion is influenced by factors such as the molar mass of the gas (lighter gases diffuse faster), temperature (higher temperatures increase the kinetic energy and speed of particles), and the presence of any barriers or obstacles in the container. In summary, gases diffuse because of the inherent kinetic energy and random motion of their particles, which leads to the spreading out of gas particles from regions of higher concentration to regions of lower concentration.
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The specific heat of aluminum is 0.90 J/g x °C. How much heat energy is required to raise the temperature from 20°C to 55°C of 11.0 grams of aluminum?
Answer: 346.50 J if correct sig figs its 3.5 X 10^2 J
Explanation:
q=m x cp x change in T
q= 11.0 X 0.90 X 35=346.50 J
What might have been the advantages and disadvantages of just having
experienced polar explorers at the catlin arctic survey.
While having experienced polar explorers at the Catlin Arctic Survey would have been beneficial in many ways, it would also have been important for them to work collaboratively with the rest of the team.
Advantages:
Experienced polar explorers would have had a wealth of knowledge and skills, such as how to travel over the ice, how to set up camp, and how to handle emergencies.
Experienced polar explorers would have been able to make informed decisions about the best routes to take and the most efficient ways to travel. This could have helped to save time and energy.
Disadvantages:
Experienced polar explorers may have been set in their ways and resistant to new ideas. This could have hindered the team's ability to adapt to changing circumstances and make the most of new opportunities.
Experienced polar explorers may have been overconfident and taken risks that the rest of the team was not comfortable with. This could have put everyone's safety at risk.
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A solution of NaNO3 is diluted from its original volume of 0.93 L
by adding 1.065 L of solvent. If its new concentration is 0.917 M,
what was the original concentration of this solution?
A) 0.24 M
B) 0.89 M
C) 1.43 M
D) 1.97 M
The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the original concentration is . The given options are incorrect.
Molarity of a solution is defined as the number of moles of the solute present per liter of the solution. It is represented as 'M' and it is expressed in the unit mol / L. It is also called the molar concentration.
The equation connecting molarity and volume of two solutions can be given as:
M₁V₁ = M₂V₂
M₁ = M₂V₂ / V₁
0.917 × 1.065 / 0.93 = 1.050 M
Thus the original concentration was 1.050 M.
The given options are incorrect.
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Label the acid, base, and ionic compound in this equation:
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O
Answer:The given reaction is a double displacement reaction as the reactants are exchanging their ions and forming new products. It is also a neutralisation reaction since an acid (HCl) is reacting with a base (NaOH) to form salt and water.
Explanation:Because when hci mixed with NaOH it causes a chain reaction.
1) If I have 8 moles of a gas at a pressure of 15.6 atm and a volume of 42 liters, what
is the temperature?
john dalton law of partial pressure
According to Dalton's law of partial pressures, the total pressure by a mixture of gases is equal to the sum of the partial pressures of each of the constituent gases. The partial pressure is defined as the pressure each gas would exert if it alone occupied the volume of the mixture at the same temperature. The Law of Partial Pressures is commonly applied in looking at the pressure of a closed container of gas and water. The total pressure of this system is the pressure that the gas exerts on the liquid. The gas is made up of whatever sample of gas there is plus the evaporated water. Dalton's law of partial pressures, Pt = P1 + P2 + ..., says that the total pressure of a gas mixture is the sum of the partial pressures of constituent gases. Dalton's law states that the total pressure of a gas is the sum of the individual pressures of all the gas molecules in the container. In other words, it's the average pressure exerted by all the gas particles in a given system.
Ph of a 0.00150 M HNO3 solution
The pH of a 0.00150 M HNO3 solution is 2.82
Rank the viscosity of n-hexane, mineral oil, water and glycerol in order of increasing viscosity. Does the viscosity change with chain length or the make up of the compound? Explain.
find the concentration and ph of Mystery Ca(OH)2
Based on the given pH of 9.2, the estimated concentration of Ca(OH)2 in the solution is approximately 3.16 x 10^(-5) M.
To calculate the concentration of Ca(OH)2 based on the pH of the solution, we need to consider the hydroxide ion concentration (OH-) since Ca(OH)2 is a strong base that dissociates completely in water.
The pH of a solution is determined by the concentration of hydrogen ions (H+), which is related to the concentration of hydroxide ions (OH-) through the autoionization of water.
In a neutral solution, the concentration of H+ and OH- ions are equal, resulting in a pH of 7. In basic solutions, the concentration of OH- ions is higher than H+ ions, leading to a pH greater than 7.
The relationship between pH and OH- concentration can be expressed using the pOH value:
pOH = 14 - pH
In this case, the pH of the solution is given as 9.2. Therefore, the pOH can be calculated as:
pOH = 14 - 9.2
pOH = 4.8
The pOH is a measure of the concentration of hydroxide ions (OH-) in the solution. To convert pOH to OH- concentration, we can use the following relationship:
OH- concentration = 10^(-pOH)
OH- concentration = 10^(-4.8)
OH- concentration ≈ 1.58 x 10^(-5) M
Since Ca(OH)2 dissociates into two OH- ions per formula unit, the concentration of Ca(OH)2 will be twice the concentration of OH- ions. Therefore, the concentration of Ca(OH)2 can be calculated as:
Concentration of Ca(OH)2 ≈ 2 x (1.58 x 10^(-5)) M
Concentration of Ca(OH)2 ≈ 3.16 x 10^(-5) M
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Note the complete question:
User
How to calculate the concentration of Ca(OH)2 if the pH of this solution is 9.2?
Please help
Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.
SO3 2- (aq) ---> SO4 2- (aq)
The balanced half-reaction is:
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
To balance the half-reaction of SO3 2- (aq) to SO4 2- (aq) in acidic solution, we need to add H+ ions and electrons to the left side of the equation to balance the charges of the reactants and products.
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
In the above equation, we have added two H+ ions and two electrons to balance the charges of the reactants and products. The oxidation state of sulfur has increased from +4 to +6, indicating that it has lost two electrons in the reaction.
To balance the number of oxygen atoms on both sides of the equation, we have added one water molecule on the left side of the equation. Finally, the state symbols (aq) and (l) indicate that the species are in aqueous solution and liquid state, respectively.
The balanced half-reaction is:
SO3 2- (aq) + H2O(l) ---> SO4 2- (aq) + 2H+(aq) + 2e-
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air contains O2N2Co2 and other gasses what is the partial pressure of N2 at 101.3kpa if the partial pressure of O2 is 75.1kpa and Co2 is 21.22kpa and the trace gasses are 0.04kpa
The partial pressure of the nitrogen gas from the calculation is 4.94 kPa
What is partial pressure of a gas?When all other gases in a mixture are held constant, a gas's partial pressure is the pressure it exerts on its own. It is calculated by dividing the total pressure of the gas mixture by the percentage of the mixture's total volume occupied by the specific gas.
Partial pressure of nitrogen = Total pressure - (Partial pressure of carbon dioxide + Partial pressure of oxygen + Partial pressure of other gases)
= 101.3 - (21.22 + 75.1 + 0.04)
= 4.94 kPa
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What is the relation of m3(cubic metre) with it's sub multiples?
The m³ is the base unit of volume in SI, representing a 1 meter³ space. The cubic meter has submultiples for smaller volume units.
They follow a consistent pattern, with each submultiple being a fraction of the cubic meter.
What is the relationCommon examples include the cubic centimeter (cm³) equal to 1/1000 of a cubic meter. Commonly used to measure small volumes. 1 m³ = 1,000,000 cm³. A mm³ is 1/1,000,000 of a m³.
A smaller unit of volume, used for precise measurements in scientific and engineering applications. 1 m³ = 1,000,000,000 mm³. Allows for convenient and precise measurements of smaller volumes.
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chemicals in the ___ contribute to erosion
Chemicals in the water contribute to erosion.
Erosion is the process by which soil and rock are gradually worn away by the action of wind, water, or other natural agents. Water is one of the main agents of erosion, and chemicals that are present in the water can contribute to this process.
Chemicals such as acids, salts, and pollutants can increase the erosive power of water by altering its chemical composition and physical properties. For example, acid rain, which is caused by the presence of pollutants in the atmosphere, can lower the pH of water bodies and increase their acidity. This can dissolve minerals in rocks and soil, leading to erosion.
Similarly, high concentrations of salt in water can increase its ability to dissolve minerals and weaken rock and soil, making them more susceptible to erosion. Chemicals such as pesticides and fertilizers can also contribute to erosion by altering the balance of nutrients in the soil and affecting plant growth, which can weaken the soil structure and make it more prone to erosion.
Overall, the presence of chemicals in water can contribute to erosion by altering the chemical and physical properties of the water, soil, and rock.
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Milk of magnesia can be used to relieve indigestion and heartburn. The active ingredient in this substance is magnesium hydroxide, Mg(OH)₂ What is the percent composition of
magnesium hydroxide in this substance?
A 20.0% Mg. 40.0% 0,40.0% H
B. 43.1% Mg. 51.3% 0, 5.6 % H
C. 41.7% Mg. 54.9% 0, 3.4% H
D 47.1% Mg, 48.3 % 0, 4.1% H
Answer:Therefore, the percent composition of magnesium hydroxide in milk of magnesia is option C: 41.7% Mg, 54.9% O, 3.4% H.
Explanation:To find the percent composition of magnesium hydroxide, we need to calculate the molar mass of magnesium hydroxide and then calculate the mass percentage of each element.Mg(OH)₂ has a molar mass of:1 x Mg = 24.31 g/mol
2 x O = 15.99 g/mol x 2 = 31.98 g/mol
2 x H = 1.01 g/mol x 2 = 2.02 g/molTotal molar mass = 24.31 + 31.98 + 2.02 = 58.31 g/molNow, let's calculate the mass percentage of each element in magnesium hydroxide:Mass of Mg = 24.31 g/mol / 58.31 g/mol x 100% = 41.7%Mass of O = 31.98 g/mol / 58.31 g/mol x 100% = 54.9%Mass of H = 2.02 g/mol / 58.31 g/mol x 100% = 3.4%
5. Consider the diprotic acid H2A with K1=1.00x104 and K2=1.00x108. Find the pH and concentrations of H2A, HA, and A-2 in 0.20 M of the acid solution.
In a 0.20 M solution of H2A with [tex]K_1=1.00*10^4[/tex] and [tex]K_2=1.00*10^8[/tex], the pH is 1.88, and the concentrations of [tex]H_2A[/tex],[tex]HA^-[/tex], and[tex]A^2-[/tex] are approximately [tex]0.197 M, 2.54*10^{-3} M[/tex], and [tex]1.95*10^{-15} M[/tex].
To solve this problem, we need to use expressions for the equilibrium concentrations of the species in a diprotic acid:
[tex][H_2A] = [H_2A]0/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]
[tex][HA^-] = K_1[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2) \\[/tex]
[tex][A^2-] = K_1K_2[H_2A]/(1 + K_1/[H+] + K_1K_2/[H+]^2)[/tex]
Given [tex]K_1[/tex] and [tex]K_2[/tex] values, we can assume that [tex]K_2[/tex] is much larger than [tex]K_1[/tex], and thus we can approximate the concentration of [tex]H_2A[/tex] to be equal to its initial concentration. Therefore, we can simplify the above expressions to:
[tex][H_2A][/tex] ≈[tex][H_2A]0/(1 + K_1/[H+])[/tex]
[HA^-] ≈ [tex]K_1[H_2A]/(1 + K_1/[H+])[/tex]
[tex][A^2-][/tex]≈[tex]K_1K_2[H_2A]/[H+]^2[/tex]
Substituting the given values:
[tex][H_2A][/tex] ≈[tex]0.20 M/(1 + 1.00*10^4/[H+])[/tex]
[HA^-] ≈ [tex]1.00*10^4 * 0.20 M/[H+]/(1 + 1.00*10^4/[H+])[/tex]
[tex][A^2-][/tex]≈ [tex]1.00*10^8 * 0.20 M/[H+]^2[/tex]
To find the pH, we can use the equation:
[tex]pH = -log[H+][/tex]
After solving the problem iteratively, we get:
pH ≈ 1.88
[tex][H_2A][/tex]≈ 0.197 M
[HA^-] ≈ [tex]2.54*10^{-3} M[/tex]
[tex][A^2-][/tex] ≈ [tex]1.95*10^{-15} M[/tex]
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--The complete Question is, Consider the diprotic acid H2A with K1=1.00x10^4 and K2=1.00x10^8. If you have a 0.20 M solution of this acid, what are the pH and concentrations of H2A, HA, and A-2 in the solution? --
79.91 grams sample of NaCI is dissolved in 250.0 mL of solution calculate the molarity
The molarity of a sample of NaCl dissolved in 250mL of solution is 5.46 M.
How to calculate molarity?Molarity refers to the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.
The molarity of a solution can be calculated by dividing the number of moles in the substance by its volume as follows;
Molarity = no of moles ÷ volume
According to this question, 79.91 grams of NaCl is equivalent to 79.91g ÷ 58.5g/mol = 1.37 moles.
Molarity = 1.37 mol ÷ 0.250 L = 5.46 M
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N2g+ 3H2g + 2 NH3g Calculate the number of moles of NH; produced from the reaction of 4.0mol of N2 in an excess of H2
The number of moles of NH₃ produced from the reaction of 4 moles of N₂ with excess H₂ is 8 moles
How do i determine the mole of NH₃ produced?The number of mole of NH₃ produced from the reaction of 4 moles of N₂ with excess H₂ can be obtain as illustrated below:
Balanced equation:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 mole of nitrogen gas, N₂ reacted to produced 2 moles of ammonia gas, NH₃
Therefore,
4 moles of nitrogen gas, N₂ will react to produce = (4 mole × 2 mole) / 1 mole = 8 moles of ammonia gas, NH₃
Thus, we can conclude from the above calculation that the number of mole of ammonia gas, NH₃ produced is 8 moles
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A chemistry student needs 95g of thiophene for an experiment. She has available 0.20kg of a 27.8% w/w solution of thiophene in benzene.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Be sure your answer has the correct number of significant digits.
The student should use 687 g of the solution.
To determine the mass of the solution the student should use, we need to use the given information about the concentration of thiophene in the solution.
First, we can calculate the mass of thiophene in the solution using the given concentration:
0.20 kg x 27.8% = 0.0556 kg thiophene
Next, we can use the mass of thiophene in the solution to calculate the mass of benzene in the solution:
0.20 kg - 0.0556 kg = 0.1444 kg benzene
Now we can use the mass of thiophene in the solution to calculate how much solution is needed to obtain 95 g of thiophene:
0.0556 kg thiophene ÷ 0.95 = 0.0585 kg solution
Finally, we convert the mass of solution to grams:
0.0585 kg x 1000 g/kg = 58.5 g
Since the available solution is more than 58.5 g, we can conclude that the student should use 687 g of the solution to obtain the required 95 g of thiophene.
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A student does an experiment to determine the molar solubility of lead fluoride. He constructs a voltaic cell at 298 K consisting of a 0.839 M lead nitrate solution and a lead electrode in the cathode compartment, and a saturated lead fluoride solution and a lead electrode in the anode compartment.
If the cell potential is measured to be 7.61×10-2 V, what is the value of Ksp for lead fluoride at 298 K based on this experiment?
The specific gravity of a patient's urine sample was measured to be 1.008. Given that the density of water is 1.000 g/mL at 4°C, what is the density of the urine sample at 4°C
Answer:
1.008 g/mL
Explanation:
The specific gravity of any substance is the ratio of that substance's original density to the density of the referential substance, in this case, water at 4°C, which is 1.000 mL.
So we have the original density to be 1.008 g/mL, the specific gravity would also be 1.008 g/mL
The density of the urine sample at 4°C is 1.008 g/mL.
The specific gravity of a substance is the ratio of its density to the density of water. In this case, the specific gravity of the urine sample is 1.008, which means that its density is 1.008 times that of water.
Since the density of water is 1.000 g/mL, the density of the urine sample can be calculated as follows:
Density of urine sample = Specific gravity × Density of water
Density of urine sample = 1.008 × 1.000 g/mL
Density of urine sample = 1.008 g/mL
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9) If I have 12.4 moles of gas held at a temperature of 97 °C and in a container with a
volume of 45 liters, what is the pressure of the gas?
The pressure of the gas is 78.1 atm.
The ideal gas law equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin by adding 273.15. So, 97 °C + 273.15 = 370.15 K.
Next, we can plug in the values we have into the ideal gas law equation and solve for pressure:
PV = nRT
P = nRT/V
P = (12.4 mol)(0.08206 L•atm/mol•K)(370.15 K)/(45 L)
P = 78.1 atm
It's important to note that the units used in this calculation are crucial, as the gas constant has different values depending on the units used. We used the value of the gas constant for atmospheres, liters, and moles, which is 0.08206 L•atm/mol•K. If we had used different units, we would have needed to use a different value for R. Additionally, it's always important to check that the units cancel out properly in the equation to ensure that the final unit is correct.
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What are three signs that a chemical change has taken place?
Answer:
Explanation: 1) temperature change
2) colour change
3) odor (any particular smell)
Question
What is the percent by mass of oxygen in CH3OH?
o 50.0
O 44.4
o 32.0
o 16.0
The mass percentage is a way which express the concentration of a solution. The percent by mass of oxygen in CH3OH is 50.0 .
What is Methanol?Methyl Alcohol or Wood Alcohol - commonly referred to as Methanol - signifies a transparent chemical liquid characterized by its molecular structure described using the formula CH3OH.
Classified under simple alcohols' category this particular compound comprises both methyl and hydroxyl groups depicted in notation form respectively under CH3 and OH. In terms of physical properties methanol appears odorless, colorless, and volatile. However it has high levels of flammability that make it easy to ignite with the slightest of spark or flame.
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I NEED HELP ON MY SCIENCE ASAP WHAT ARE TWO DIFFERENCES BETWEEN INTRUSIVE AND EXTRUSIVE IGNEOUS ROCKS?
Answer:
Extrusive and intrusive igneous rocks are the two primary subcategories. Lava, which is magma that has surfaced from beneath the Earth, is what gives rise to extrusive rocks, and they can also be formed by oozing fissures. Meanwhile, Magma cools and solidifies inside the planet's crust, forming intrusive rocks, however because they are inside the earths crust and have solidified there, they are usally the type to penetrate exsisting rocks, inlike extrusive rocks, which form on their own.
Explanation:
I hope this helps, I made this up as I went, with the information i do know. :)