How many resistors are found in this circuit?
A) 0
B) 1
C) 2
D) 3

Answers

Answer 1
Show us the pictures I don't see it

Related Questions

In any vector space au=bu implies a=b ? Trou or False​

Answers

Answer:

False

Explanation:

(I guess if it were written "properly" it would be ax=bx implies a=b).

Given the axioms we were given, it would seem that the statement should be true, no?

A related statement -- also listed as false -- is that "in any vector space, ax=ay implies that x=y." Again, given the axioms we have.

Answer:

False

Explanation:

Simply use the counterexample u = 0

For zero vector:

au=bu=0

holds for a=3, b=4

False

Which of the following features make Earth and Venus similar to each other?

Answers

Answer:

A. size and mass

Explanation:

2. Which one of the following liquids is more suitable for making a simple barometer?​

Answers

Answer:

Emm I don't see the liquid options but usually mercury is used for making barometers...

Explanation:

A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?

Answers

Answer: 0.2kg m/s

Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3

v3=.26m/s 2.5+70

A 7.0kg object rests on a horizontal frictionless surface. What is the magnitude of the horizontal

force that is required to accelerate it at the rate of 2.3m/s2

?if you can show work it would be perfect

Answers

Answer:

16.1 N

Explanation:

From the question,

F = ma.............................. Equation 1

Where F = horizontal force, m = mass of the object, a = acceleration .

Given: m = 7.0 kg, a = 2.3 m/s²

Substitute this values into equation 1

F = (7.0×2.3)

F = 16.1 N.

Hence the magnitude of the horizontal force is 16.1 N

Infer Which of the following is NOT true of gravitational force?

Answers

do you have the options?

Answer:

I think it's a repulsive force

A lever with a mechanical advantage of .4 is more advantageous than just picking up the object with your hands and lifting it up.
True

False

Answers

Answer:

true

Explanation:

One mole of iron (6 x 10^23 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 x 10^-10 m. You have a long thin bar of iron, 2.3 m long, with a square cross section, 0.12 cm on a side. You hang the rod vertically and attach a 149 kg mass to the bottom, and you observe that the bar becomes 1.17 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.

ks = 20014.1 N/m
Number of side-by-side long chains of atoms = 4.81e^12
Number of bonds in total length = 1.096e^10

What is the stiffness of a single interatomic "spring"?

Answers

Answer:

Explanation:

Given that:

length l = 2.3 m

a = 0.12 cm = [tex]0.12 \times 10^{-2} \ m[/tex]

[tex]x = 1.17 \ cm = 1.17 \times 10^{-2}\ m[/tex]

m = 149 kg

[tex]\delta = 7.87 \ g/cm^3[/tex]

[tex]da = 2.28 \times 10^{-10}\ m[/tex]

[tex]F_{net} = F-mg\\ \\0 = F - mg \\ \\ F = mg \\ \\ k_sx = mg \\ \\[/tex]

[tex]k_s = \dfrac{149(9.8)}{1.17 \times 10^{-2}} \\ \\ k_s = 124803.42 \ N /m[/tex]

[tex]N_{chain} = \dfrac{A_{wire}}{A_{atom}} = \dfrac{A_w}{da^2}[/tex]

[tex]N_{chain} = \dfrac{(a)^2}{(da)^2} = (\dfrac{a}{da})^2[/tex]

[tex]N_{chain} = (\dfrac{0.12 \times 10^{-2} }{2.28 \times 10^{-10}})^2[/tex]

[tex]N_{chain} = 2.77 \times 10^{13}[/tex]

[tex]N_{bond} = \dfrac{L}{da} \\ \\ = \dfrac{2.3}{2.28 \times 10^{-10}} \\ \\ N_{bond} = 1.009 \times 10^{10}[/tex]

[tex]\text{Finally; the stiffness of a single interatomic spring is:}[/tex]

[tex]k_{si} =\dfrac{N_{bond}}{N_{chain}}\times k_s[/tex]

[tex]k_{si} =\dfrac{(1.009 \times 10^{10})}{2.77*10^{13}}}\times (124803.42)[/tex]

[tex]\mathbf{k_{si} =45.46 \ N/m}[/tex]

REAL ANSWER = BRAINLIST LOOK AT PICS ATTACHED

Answers

Answer:

there are no pictures attached.

Speed versus Time
The graph below suggests

A. a constant speed of 3 m/s followed by speed of 1 m/s
B. a constant velocity of 2 m/s followed by speed of zero
C. a constant speed of 4 m/s followed by speed of zero
D. a constant acceleration of 2 m/s followed by speed of zero
F. a constant speed of 2 m/s followed by speed of zero

Answers

A since it’s the only one that makes sense! So A is correct.

Answer:

a constant speed of 2 m/s followed by speed of zero

Explanation:

I got it right on the test.

The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 4190 J/(kg K). Water's latent heat of fusion is 333,000 J/kg. If you have a 2kg block of ice at -90°C and you add 1,000,000 J of heat, what is its new temperature?

a. 0°C
b. 14°C
c. 49°C
d. 149°C

Answers

Answer:

d. 149 ⁰C.

Explanation:

Given;

mass of the block of ice, m = 2 kg

specific heat capacity of the ice, C = 2090 J/(kgK)

initial temperature of the ice, t₁ = -90 ⁰C

heat added to the ice, H = 1,000,000 J

let the final temperature of the ice = t₂

The final temperature of the ice after adding the heat is calculated as follows;

[tex]H = mC_{ice} \Delta t\\\\H = mC_{ice} (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C[/tex]

Therefore, the new temperature of the water is 149 ⁰C.


6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
b) Increases to its doute
d) Remains constant
a) Remains constant,
c) Increases to its four times

Answers

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

The law of universal gravitation states that any two objects in the universe, without exception,
a
repel each other

b
attract each other
c
create friction

Answers

Answer:

attract each other

Explanation:

..........

The description of the structure of the atom is called the??

Answers

I think for this it is atomic model

A rain drop of radius 0.3mm has terminal velocity 1m/s in air. The viscosity of air is 18X10-5 poise, then viscous force is​

Answers

Answer:

F = 1.0178 × 10^(-2) dyne

Explanation:

From stokes law, the viscous force also known as drag force on rain drop is given by the formula;

F = 6πηrv

Where;

η is viscosity

r is radius

v is velocity

We are given;

η = 18 × 10^(-5) poise

r = 0.3 mm = 0.03 cm

v = 1 m/s = 100 cm/s

Thus;

F = 6π × 18 × 10^(-5) × 0.03 × 100

F = 1.0178 × 10^(-2) dyne

A ball has a mass of 140 g what is the force needed to accelerate the mall at 25 m/s squared

Answers

3.5 Newton of force is needed to accelerate 140g of ball at 25 m/s^2 using the formula f=ma
Change 140g to kg

Answer:

[tex]\boxed {\boxed {\sf 3.5 \ Newtons}}[/tex]

Explanation:

Force is the product of mass (in kilograms) and acceleration (in meters per square second).

[tex]F=ma[/tex]

The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.

1 kg=1000 g[tex]140 \ g *\frac{1 \ kg}{1000 \ g}=\frac{140}{1000} \ kg =0.14 \ kg[/tex]

Substitute the values into the formula.

[tex]F= 0.14 \ kg * 25 \ m/s^2[/tex]

Multiply.

[tex]F= 3.5 \ kg*m/s^2[/tex]

1 kilogram meter per square second is equal to 1 NewtonOur answer equals 3.5 Newtons

[tex]F= 3.5 \ N[/tex]

3.5 Newtons of force are required.

What is the fastest bird​

Answers

She is correct I looked it up

Answer:

Peregrine Falcon/hawk

Explanation:

i really dunno if you are talking about brids that can't fly or not.

How many meters across is a road sign that has an angular size of 120 arcseconds and is 1 km away?

Answers

That’s the one I’m struggling withhhh aswellll

4. You are walking at a leisurely pace of .75 m/s when you hear the train coming and start running to catch it. Over the next 10 seconds, you speed up to 3.5 m/s and catch your train! What was your acceleration over that time?

Answers

Answer:

0.275 m/s²

Explanation:

The acceleration of an object is defined as the change in velocity over the change in time.

a = Δv/Δt a = (v - v₀)/t

We are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.

The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.

a = (3.5 - 0.75)/10 a = 2.75/10 a = 0.275 m/s²

Our acceleration over that time was 0.275 m/s² in order to catch the train.

PSYW - Please Show Your Work

A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg
and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.
Determine the energy required to raise the temperature of the radiator-water system by
1°K

Answers

Answer:

9.66E4 J

Explanation:

We have that  the energy required to raise the temperature of the radiator-water system by

1°K

E=116.85KJ

From the question we are told  

A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg  and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.

Determine the energy required to raise the temperature of the radiator-water system by  1°K

Generally the equation for the Energy  is mathematically given as

[tex]E=((mc)_i+mc_w)dt\\\\Therefore\\\\E=(45* 450 +4200*23)1\\\\E=116850J\\\\E=116.85KJ\\\\[/tex]

Therefore

the energy required to raise the temperature of the radiator-water system by

1°K

E=116.85KJ

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why an inclined is considered as simple machine​

Answers

Simple machines are meant to help make work be done more easily and efficiently, and an incline does exactly that. An incline allows you to move an object to a greater height with less force that is needed to simply lift the object.

hope this helps.

Lithium (chemical symbol Li) is located in Group 1, Period 2. Which is lithium most likely to be? O A. A soft, shiny, highly reactive metal OB. A soft, shiny, highly reactive nonmetal O C. A gaseous, highly reactive nonmetal O D. A metalloid with properties of both metals and nonmetals SUBMIT​

Answers

Answer:

A. A soft, shiny, highly reactive metal

Explanation:

Lithium  is located in Group 1, Period 2. lithium is most likely to be soft, shiny, highly reactive nonmetal. Hence option A is correct.

What is Atom ?

Atom is smallest entity of a body. Body is made up of atoms. it is basic building block of a body. An atom consist of electrons, protons and neutrons as sub atomic particle. whole mass of the atom is concentrated at the center of the atom which we call it as nucleus, nucleus consist of proton and neutron. Electron revolve around the nucleus at determined(fixed) orbit. Total number of protons in the atom decides the atomic number and the elements in the periodic table.

The electrons which are completely filled orbitals are called as core shell electrons and which are not filled completely are called as valence electron. valence electrons are responsible for physical and chemical properties of the element. Elements which are on same column in periodic table have same number of valence electrons .

Hence option A is correct.

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Timed plz hurry
Enlarged brain ventricles are presumed to signify
A. an excess of dopamine activity
B. frontal lobe abnormalities
C. development of brain tissue
D. a deterioration of brain tissue

Answers

Answer:

D. a deterioration of brain tissue

A deterioration of brain tissue cause enlargement of brain ventricles

When an injury or illness alters the circulation of CSF, one or more of the ventricles becomes enlarged as CSF accumulates. In an adult, the skull is rigid and cannot expand, so the pressure in the brain may increase profoundly. Hydrocephalus is a chronic condition in which  is the buildup of fluid in the cavities (ventricles) deep within the brain. It can be controlled, but usually not cured.What is CSF?Cerebrospinal fluid (CSF) is a clear, colorless liquid found in your brain and spinal cord. They combinedly form central nervous system.Central nervous system controls and coordinates everything you do including  muscle movement, organ function, and even complex thinking and planning

Hence, D) is the correct option.

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This graph shows the path length based on the number of speciation events in a evolution path.

Speciation Events vs. Path Length gradual evolution Path Length punctuational evolution Number of Speciation Events

What does the graph suggest about the evolution path length


a. The punctuational evolution path is the same as the gradual evolution path
b. The gradual evolution path is longer that the punctuational evolution path
c. Gradual evolution does not effect the evolution path length
d. Punctuational evolution does not effect the evolution path length

Answers

Answer:

Nbhb

Explanation:

what instrument will be used to measure the volume of a box​

Answers

Answer:

A ruler.

Explanation:

Just measure height, length and width and multiply each.

Examine the diagram of a cell.
Which organelle is marked with an X?
cell membrane
mitochondrion
nucleus
ribosome

Answers

Answer:

It is the Nucleus

Answer:

Nuclease

Explanation:


Find the magnitude of the sum
of these two vectors:
5.00 mA,
30.0°
B4
6.00 m
magnitude (m)​

Answers

Answer:

Approximately [tex]3.01\; \rm m[/tex].

Explanation:

Decompose each vector into the sum of two vectors: a horizontal one (parallel to the arrow that points to the right) and a vertical one (parallel the arrow that points upwards.)

Vector [tex]\sf A[/tex] is horizontal and is at an angle of [tex]0^\circ[/tex] with the horizon.  

Horizontal component of vector [tex]\sf A[/tex]: to the right, with a length of [tex]5.00\; \rm m \cdot \cos\left(0^\circ \right) = 5.00\; \rm m[/tex].Vertical component of vector [tex]\sf A[/tex]: [tex]5.00\; \rm m \cdot \sin\left(0^\circ \right) = 0\; \rm m[/tex].

Vector [tex]\sf B[/tex] is at an angle of [tex]30^\circ[/tex] below the horizon.

Horizontal component of vector [tex]\sf B[/tex]: to the right, with a length of [tex]\displaystyle 6.00\; \rm m \cdot \cos\left(30^\circ \right) = (6.00\; \rm m) \times \frac{\sqrt{3}}{2}\approx 5.19615\; \rm m[/tex].Vertical component of vector [tex]\sf B[/tex]: downwards, with a length of[tex]\displaystyle 6.00\; \rm m \cdot \sin\left(30^\circ \right) = 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m[/tex].

Calculate the sum of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex].

The horizontal component of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex] are opposite to one another. Therefore, the length of the horizontal component of [tex]\sf (A + B)[/tex] would be the difference between the length of the horizontal components of vector [tex]\sf A\![/tex] and of vector [tex]\sf B\![/tex]:

[tex]\displaystyle (6.00\; \rm m) \times \frac{\sqrt{3}}{2} - 5.00\; \rm m \approx 0.196152\; \rm m[/tex].

The length of the vertical component of vector [tex]\sf A[/tex] is [tex]0\; \rm m[/tex]. Therefore, the length of the vertical component of [tex]\sf (A + B)[/tex] would be equal to the length of the vertical component of vector [tex]\sf B[/tex], [tex]\displaystyle 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m[/tex].

Therefore, the length of the horizontal and vertical component of [tex]\sf (A + B)[/tex] are approximately [tex]0.196152\; \rm m[/tex] and [tex]3.00\; \rm m[/tex], respectively. The length of vector [tex]\sf (A + B)\![/tex] would be approximately:

[tex]\displaystyle \sqrt{(0.196152\; \rm m)^{2} + (3.00\; \rm m)^{2}} \approx 3.01\; \rm m[/tex].

What are 4 ways individuals can influence the government?

Answers

Voting, running, speaking in front of government

Which experimental result led to the inference that atoms have a dense,
positive center?

A. A few alpha particles bounced off a thin sheet of gold foil.

B. Most alpha particles passed straight through a thin sheet of gold
foil.

C. The beam in a cathode ray tube was moved by a magnetic force.

D. The beam in a cathode ray tube was moved by an electric force.

Answers

A few alpha particles bounced off a thin sheet of gold foil.

The correct option for the given question about Rutherford Gold Foil Experiment is Option A) "A few alpha particles bounced off a thin sheet of gold foil".

What caused Rutherford's gold-foil experiment's alpha particles to bounce off?

Rutherford predicted that the particles will pierce the foil without any resistance. But he discovered that as the particle bounced off through the foil, its course would change or be deflected. Like charges repel one another, which is the reason behind this.

Thus we can conclude that Rutherford Gold Foil Experiment (A few alpha particles bounced off a thin sheet of gold foil) results led to the inference that atoms have a dense positive centre.

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All of the following are possible transition points that occur during adulthood except __________.
A.
marriage
B.
rapid physical growth
C.
parenthood
D.
divorce

Answers

Answer:

B

Explanation:

.....................

Answer:

B. Rapid Physical Growths

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