How many products might be formed on chlorination of o-xylene (o-dimethylbenzene), m-xylene, and p-xylene

Answer: A volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.1 M,    [tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 0.5 M,       [tex]V_{2}[/tex] = 100 mL

Formula used to calculate the volume of water is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL[/tex]

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M [tex]H_{3}PO_{4}[/tex] from 100 ml of 0.5 M solution.

Answer: The balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, [tex]SO_{2} + O_{2} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]SO_{2}[/tex] by 2 and [tex]H_{2}O[/tex] by 2 on reactant side. Also, multiply [tex]H_{2}SO_{4}[/tex] by 2 on product side.

Hence, the equation can be re-written as follows.

[tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex]

Now, the number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

Since, the atoms present on both reactant and product side are equal. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is [tex]2SO_{2} + O_{2} + 2H_{2}O \rightarrow 2H_{2}SO_{4}[/tex].

Answer:

tungstun

Explanation:

Answer:

tungsten

Explanation:

strongest out of any natural metal (142,000 psi).

Answer:

Explanation:

so u can work out the amount of moles of S8 by using

moles=mass/mr

=16/32.1=0.498moles

then use the molar ratio of

S : Fe

1:1 so the moles of Fe is the same 0.498

The use the equation

mass = mr x moles

=55.8 x 0.498

=27.78

so 27.8 g

hope this make sense :)

Answer:

[tex]P_2=795mmHg[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the final pressure by using the Boyle's law as an inversely proportional relationship in pressure to volume at constant temperature:

[tex]\frac{P_2}{V_2} =\frac{P_1}{V_1}[/tex]

Thus, we solve for our target, P2, to obtain:

[tex]P_2=\frac{P_1V_2}{V_1} =\frac{770mmHg*603mL}{584mL}\\\\P_2=795mmHg[/tex]

Regards!

Answer:

carbon

Explanation:

Atomic radius represents the distance from the nucleus to the outer shell of an element.

The element having the Smallest atomic radius  is Carbon. Hence. Option (3) is correct

The atomic radius of a chemical element is a measure of the size of its atom, usually the mean or typical distance from the center of the nucleus to the outermost isolated electron.

Atomic Radius Increases down the group.

All the given elements belongs to same group ie, 14th Carbon is the top most element of the group.

Therefore, The element having the Smallest atomic radius  is Carbon. Hence. Option (3) is correct

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Answer: Two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.

Explanation:

A solution that helps in resisting change in pH when a small amount of acid or base is added to it is called a buffer solution.

A buffer solution consists of a mixture of weak acid and its conjugate base.

Acetic acid has a chemical formula [tex]CH_{3}COOH[/tex] and its conjugate base is [tex]CH_{3}COO^{-}[/tex].

This base is also called acetate ion.

Acetic acid is a weak acid because it dissociates weakly when added to a solvent like water.

Therefore, acetic acid and acetate ion will form a buffer solution.

Thus, we can conclude that two compounds below that can be used to make a buffer solution are acetic acid and acetate ion.

Answer:

did not mean to type that sorry i'm pretty sure the answers are c and b.

Explanation:

Answer:

Question 9

Explanation:

An everyday chemical reaction is rusting and iron reacts with oxygen to form rust

Question 8

Chemical reactions do not include fusion and fission only nuclear reactions like radioactivity

Answer:

98

Explanation:

I dont even know

Answer:

FeBr3 is the Lewis acid, and FeBr4-1 is the Lewis base.

Explanation:

A Lewis acid is any specie that has empty orbitals into which it can receive a lone pair of electrons.

A Lewis base is any specie that donates a lone pair of electrons to another to form a dative covalent bond.

If we look at the species listed in the options, FeBr3 is lone pair acceptor hence it is a Lewis acid while FeBr4- is a lone pair donor hence it is Lewis base.

Answer:

Hydrogen Bonds

Explanation:

Opposite charges attract one another. The slight positive charges on the hydrogen atoms in a water molecule attract the slight negative charges on the oxygen atoms of other water molecules. This tiny force of attraction is called a hydrogen bond.

Answer:

The needed heat is 47,65 Joules.

The number of Joules of heat is required to change the 21.1g of liquid water into steam at 100°C is 47686 Joules.

The latent heat of vaporization is defined as the amount of heat needed at a constant temperature for the conversion of a liquid at its boiling point to gas. The latent heat of vaporization is different for different liquids.

The particles of water vapor at 100°C  have more energy than that of liquid water. Because the extra energy is in the form of latent heat of vaporization. The word “latent” from the Latin word “latere" means to cover up or hide.

Given, the amount of water, m= 21.1 g

We know that, the heat of vapourization of water = [tex]2260 J/g[/tex]

The latent heat of vaporization (q) is calculated as:

q = mH

q = (21.1 g) × (2260J/g)

q = 47686 J

Therefore, the 47686 Joules are required to boil 21.1 g of water at a temperature of 100°C.

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Answer:

at age 15 the BMR begin to gradually decrease

Answer:

Number of mole of H₃PO₄ = 0.306 mole

Explanation:

From the question given above, the following data were obtained:

Mass of H₃PO₄ = 30 g

Number of mole of H₃PO₄ =?

Next, we shall determine the molar mass of H₃PO₄. This can be obtained as follow:

Molar mass of H₃PO₄ = (3×1) + 31 + (4×16)

= 3 + 31 + 64

= 98 g/mol

Finally, we shall determine the number of mole in 30 g of H₃PO₄ as follow:

Mass of H₃PO₄ = 30 g

Molar mass of H₃PO₄ = 98

Number of mole of H₃PO₄ =?

Mole = mass / molar mass

Number of mole of H₃PO₄ = 30 / 98

Number of mole of H₃PO₄ = 0.306 mole

Answer:

32.7 g of Zn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂

Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

Molar mass of Zn = 65.4 g/mol

Mass of Zn =?

Mass = mole × molar mass

Mass of Zn = 0.5 × 65.4

Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

Answer:

sulphuric acid

nitric acid

carbolic acid

The ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.

Ionic compounds were made up of ions kept together by the attraction of positive and negative ions. One of the most well-known ionic compounds is common salt (sodium chloride). Molecular compounds were made up of distinct molecules that also are kept together through electron sharing (covalent bonding).

Long-term variations in temperature but also weather systems are referred to as climate change.

Therefore, the ionic compounds contribute to climate change that is sulphuric acid, nitric acid and carbolic acid.

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Answer: See image attached!

Good luck with your future exams!

The value of the solubility of product for CaSO₄ in pure water at 0 °C is 1.1881

The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:

mA <=> nC + eD

Ksp = [C]^n × [D]^e

With the above information in mind, we can obtain the solubility of the product. This is illustrated below:

CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)

From the balanced equation above,

1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻

From the balanced equation above,

1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻

Therefore,

1.09 g/L of CaSO₄ will also contain

CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)

Ksp = [Ca²⁺] × [SO₄²⁻]

Ksp = 1.09 × 1.09

Ksp = 1.1881

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Answer:

A

Explanation:

Simple chemicals existing at the time synthesized into the earliest life forms into the sea

Answer:

The answer is A!

Explanation:

edg 2022

Explanation:

pls the question is not clear to me

Answer:

Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Explanation:

(jayaanilanmol's answer)

Answer:

96%

Explanation:

Step 1: Write the balanced neutralization reaction

Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O

Step 2: Calculate the theoretical yield of AlCl₃

According to the balanced equation, the mass ratio of Al(OH)₃ to AlCl₃ is 81.03:133.34.

28 g Al(OH)₃ × 133.34 g AlCl₃/81.03 g Al(OH)₃ = 46 g AlCl₃

Step 3: Calculate the percent yield of AlCl₃

The real yield of AlCl₃ is 44 g. We can calculate the percent yield using the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 44 g / 46 g × 100% = 96%

Answer:

C₂O₂

Explanation:

Step 1: Given data

Step 2: Calculate the molar mass of the empirical formula

M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12 g/mol + 1 × 16 g/mol = 28 g/mol

Step 3: Calculate "n"

We will use the following expression.

n = molar mass of molecular formula / molar mass of empirical formula

n = (56 g/mol) / (28 g/mol) = 2

The molecular formula is:

CO × n = CO × 2 = C₂O₂

Which reactions are you referring to?

Can you add an image please?

or the reactions you are asking about?

Answer: There are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.

Explanation:

Given: Molarity = 3.0 M

Mass of NaCl = 97.9 g

Molar mass of NaCl = 58.44 g/mol

As number of moles is the mass of substance divided by its molar mass.

So, moles of NaCl are calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{97.9 g}{58.44 g/mol}\\= 1.675 mol[/tex]

Molarity is the number of moles of a substance present in liter of a solution.

Therefore, volume of given solution is calculated as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\3.0 M = \frac{1.675 mol}{Volume}\\Volume = 0.558 L[/tex]

Thus, we can conclude that there are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.