How many people were survey in all?

Answer:

Slope is equal to the change in y over the change in x , or rise over run.

m=change in y/ change in x

The change in x is equal to the difference in x-coordinates (also called run), and the change  in y is equal to the difference in y-coordinates (also called rise).

m=y2−y1/x2−x1

Substitute in the values of x and y into the equation to find the slope.

m=0−(2)/9−(5)

Simplify.

m=−12

Step-by-step explanation:

Answer: (7, 1)

Midpoint formula = ([tex]\frac{x1 , x2}{2}[/tex] , [tex]\frac{y1, y2}{2}[/tex])

5 + 9 / 2 = 7

2 + 0 / 2 = 1

Answer:

Step-by-step explanation:

Use the rise over run formula

y2-y1/x2-x1

1992-1990/3317-3038

2/-279

-139.5

Answer:

19.47

Step-by-step explanation:

I plugged it into a right triangle trig calculator

Answer:

HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .

See attachment below!

Step-by-step explanation:

If your in High school Geometry, I could help with that and more!

If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!!  I took Geometry and have good notes!

Answer:

x=[tex]-3+\frac{1}{2}\sqrt{2}[/tex]  

x=[tex]-3+\frac{-1}{2} \sqrt{2}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

5x⁴ - 2x³ + 12x² + 24x - 26

Degree = 4

Leading term = 5x⁴

Leading coefficient = 5

9514 1404 393

Answer:

  an = 13 -5(n -1)

Step-by-step explanation:

The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...

  an = a1 +d(n -1)

  an = 13 -5(n -1)

Step-by-step explanation:

y = 6x-11

substitute y into 2x+3y=7

2x+3(6x-11)=7

2x + 18x-33 = 7

20 x = 7+33

x = 2

y?

y= 6(2)-11

y = 12-11 = 1

so, x = 2 and y = 1

The uninhabited growth represented by the function is [tex]N(t) = N_0e^{kt}[/tex]. The correct option is A.

Uninhibited Growth and Decay Models: Things that expand or deteriorate in a limitless, proportional manner are said to exhibit "uninhibited" growth or decay. Examples include population increase, bacterium growth, and radioactive decay.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

The expression for the uninhabited growth is,

[tex]N(t) = N_0e^{kt}[/tex]

To know more about uninhabited growth follow

https://brainly.com/question/17852783

#SPJ2

Answer:

y=2/7x

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

y=2/7x+0

y=2/7x

Answer:

9/4y+10

Step-by-step explanation:

1/4y+10+2y

9/4y+10

unless u meant y^2 then the answer would be

0.25(y+40+4y^2)

Answer:

The correct option is B

Step-by-step explanation:

just did the test on Ed.

Answer:

-14

Step-by-step explanation:

Line is passing through the points (5, -8) and (4, 6).

Therefore,

[tex]slope = \frac{ - 8 - 6}{5 - 4} \\ \\ = \frac{ - 14}{1} \\ \\ = - 14[/tex]

Answer:

C

Step-by-step explanation:

Answer:

Math (way) is good if you wanna try that.

ee

Step-by-step explanation:

Answer:

the graph of f(x) = 7x. 3x + 4 = 7x

Answer:

The chance of picking a yellow marble twice in a row without replacement is 0.22

Step-by-step explanation:

The given number of marbles in the bag = 25 marbles

The number of red marbles in the bag = 5 red marbles

The number of blue marbles in the bag = 8 blue marbles

The number of yellow marbles in the bag = 12 yellow marbles

The chance of picking a yellow marble = 12/25

The chance of picking another yellow when the first one is not replaced = 11/24

Therefore, the chance of picking a yellow marble twice in a row = 12/25 × 11/24 = 1/25 × 11/2 = 11/50

Therefore;

The chance of picking a yellow marble twice in a row without replacement = 11/50 = 0.22

Answer:

Step-by-step explanation:

c

Answer:

fafafasda

Step-by-step explanation:

wdwasdsa wr 1+11123121

Answer:

x = 9

m∠1 = m∠2 = 54°

Step-by-step explanation:

Two lines r and s are the parallel lines and a transversal line is intersecting these lines at two distinct points.

a). ∠1 ≅ ∠2 [Corresponding angles]

    Therefore, m∠1 = m∠2

    (63 - x)° = (72 - 2x)°

    2x - x = 72 - 63

    x = 9

b). m∠1 = (63 - x)°

            = 63 - 9

            = 54°

    m∠2 = (72 - 2x)°

             = 72 - 18

             = 54°

Answer:

9/8 of a bag

she doesn't have enough beads.

Step-by-step explanation:

Bag of bead poppy has = 1

Bag of bead needed for necklace 1 = 3/8 of a bag

Bag of bead needed for necklace 2 = 1/8 of a bag

Bag of bead needed for necklace 3 = 5/8 of a bag

Total bag of beads needed = 3/8 + 1/8 + 5/8

= (3+1+5)/8

= 9/8

She needs 9/8 of a bag of bead

9/8 = 1 1/8

Therefore, she doesn't have enough beads.

Answer:

28.5

Step-by-step explanation:

Plzz mark brainlies thanks!!

Answer:

2 should be added to the data

Step-by-step explanation:

Hope this helps!

If im wrong im sorry!

Answer:

18 should be added

Step-by-step explanation:

So we have one 10 and one 11 in this data set, and we need to figure out which number we need to add to get a mean of 13

let's make this unknown number x

to find the mean, we add up all the values of the numbers on the data set, and divide it by how many numbers we have.

we have 3 numbers, and our numbers are 10, 11, and x. When we add 10, 11, and x together, and then divide by 3, the value is 13

as an equation we will have:

(10+11+x)/3=13

combining like terms in the numerator, it will be:

(21+x)/3=13

We need to solve this equation, and the denominator of 3 just makes harder to do that.

Clear the fraction by multiplying both sides by 3

21+x=39

subtract 21 from both sides

x=18

so that means that 18 should be added to the data set to get a mean of 13.

Hope this helps!

Answer:

La²+8La+16 = La²+70

Step-by-step explanation:

8La+16 = 70

8La=70-16

La=54/8

La= 6.75

Area b = (6.75+4)*(6.75+4)

Area b = 10.75*10.75

Area b =115.563

The area of a square is the square of its side lengths

The area of square B is 116 centimeter square

Let the side length of square A be (a), and the side length of square B be (b)

So, we have:

[tex]\mathbf{A_a = a^2}[/tex]

[tex]\mathbf{A_b = b^2}[/tex]

From the question, we have:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

[tex]\mathbf{b = 4 + a}[/tex]

Take square of both sides

[tex]\mathbf{b^2 = (4 + a)^2}[/tex]

[tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex]

Substitute [tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex] in [tex]\mathbf{A_b = b^2}[/tex]

[tex]\mathbf{A_b = 16 + 8a+ a^2}[/tex]

So, we have:

[tex]\mathbf{16 + 8a+ a^2 = 70 + a^2}[/tex]

Subtract a^2 from both sides

[tex]\mathbf{16 + 8a = 70}\\[/tex]

Subtract 16 from both sides

[tex]\mathbf{8a = 54}[/tex]

Divide both sides by 8

[tex]\mathbf{a = 6.75}[/tex]

Recall that:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

So, we have:

[tex]\mathbf{A_b = 70 + 6.75^2}[/tex]

[tex]\mathbf{A_b = 115.5625}[/tex]

Approximate

[tex]\mathbf{A_b = 116}[/tex]

Hence, the area of square B is 116 centimeter square

Read more about areas at:

https://brainly.com/question/1658516

Answer:

A

Step-by-step explanation:

The chance the coin will show 'tails' is 1/2, since there are only 2 sides to a coin. The chance that the die will show an even number is also 1/2, since half of the numbers on a die are even, and half are odd. But, since both of these events depend on each other, or in other words, are dependent, we have to multiply both numbers. 1/2 x 1/2 = 1/4, therefore your answer is A.

Answer:

[tex]\displaystyle 5[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

OR

[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

Yes, They are similar by SSS PMK similar to LMQ.

Step-by-step explanation:

Similar triangles corresponding side lengths are in a proportion.

KM corresponds with MQ

PM corresponds with LM.

Set up this proportion.

[tex] \frac{km}{pm} = \frac{lm}{mq} [/tex]

[tex] \frac{15}{28} = \frac{21}{39.2} [/tex]

Cross multiply

[tex]588 = 588[/tex]

So the triangles ARE Similar.