how many moles of solute are present in a 2 L of a 25M potassium nitrate solution
a. 0.5 moles
b. 2 moles
c. 50 moles
d. 25 moles

I NEED THIS ANSWER ASAP, im taking the quiz right now and i need HELPPP

Answer:

planets,meteoroids and asteroids  

Explanation:

Answer:

nitrogen in atmospheres of a sample is 0.679

Answer:

The rainforest is teeming with animals and insects, so you would hear  humming. Frogs and birds make some of the loudest rainforest sounds.

howler monkeys, are the loudest so i think that its false cause lost of animals are there but some can be quiet

Answer:

Explanation:

B is the ans

pls mark BRAINLIEST

Answer: The first question is chemical The second one is Physical

Explanation:

Answer:

pH = 9

Explanation:

pOH = -log[OH-] = -log(1.0 x10^-5) = 5

pOH + pH = 14

pH = 14 - 5 = 9

Answer:

The molal concentration of the solution is approximately 0.124 molal

Explanation:

The given parameters are;

The reduced freezing point of the water = -0.23°C

For freezing point depression of a solution, we have;

[tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i

Where;

[tex]\Delta T_f[/tex] = The freezing point depression

[tex]K_f[/tex] = Cyroscopic constant (The freezing-point depression constant) = 1.86° Cm⁻¹ for water

b = The molality of the solution

i = van't Hoff factor = 1

Therefore;

[tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex]

Where;

[tex]T^{\circ}_f[/tex] = The freezing point of pure water = 0°C

[tex]T_f[/tex] = The freezing point of the solution = -0.23°C

∴ [tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex] = 0°C - (-0.23°C) = 0.23 °C

From, [tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i, we have;

0.23°C = 1.86°C/m × b × 1

∴ b  = (0.23°C/1.86°C/m) ≈ 0.124 molal

Therefore, the molal concentration of the solution, b ≈ 0.124 molal.

Answer: a

Explanation:

Bc I just did it and yeah

I did not see any errors, i may be wrong but what i can see is that it is correct

Answer:

because it is

Explanation:

simple

Answer:

Explanation: none

Answer:

Correct

Explanation:

According to the balanced chemical reaction, 2 mol FeBr3 are consumed for every 3 mol Na2S consumed.

A balanced equation obey the law of conservation of mass. The coefficients are the numbers which are added to balance the chemical equation. Here the given mole ratio is correct.

An equation in which the number of atoms of reactants and products on both sides of the equation are balanced is defined as the balanced chemical equation. The coefficients which are added in front of the formula of each component represents the number of the species.

A molar ratio denotes the ratio between the amounts in moles of any two compounds involved in a balanced chemical reaction. By comparing the coefficient of each component, the mole ratio can be determined.

Here for the given reaction, for every 3 moles of Na₂S consumption 2 moles of FeBr₃ is also consumed. So the molar ratio of Na₂S to FeBr₃ is 2/3. Molar ratios are used as the conversion factors between products and reactants in many chemistry problems.

To know more about mole ratio, visit;

https://brainly.com/question/29095152

#SPJ7

Answer:

A. Is your answer

All the other ones are not valid because they are lower to the ground and you wouldn't have enough MOMENTUM to put you up for the top of the star.

Hope this helps!

Answer: 16.32 g of [tex]O_2[/tex] as excess reagent are left.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol[/tex]

[tex]\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]  

According to stoichiometry :

2 moles of [tex]SO_2[/tex] require = 1 mole of [tex]O_2[/tex]

Thus 0.34 moles of [tex]SO_2[/tex] will require=[tex]\frac{1}{2}\times 0.34=0.17moles[/tex]  of [tex]O_2[/tex]

Thus [tex]SO_2[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

Moles of [tex]O_2[/tex] left = (0.68-0.17) mol = 0.51 mol

Mass of [tex]O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g[/tex]

Thus 16.32 g of [tex]O_2[/tex] as excess reagent are left.

Answer: The volume of the gas is 1.98 L.

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=2.2L\\T_1=30^oC=(30+273)K=303K\\V_2=?\\T_2=0^0C=(0+273)K=273K[/tex]

Putting values in above equation, we get:

[tex]\frac{2.2}{303}=\frac{V_2}{273}\\\\V_2=1.98L[/tex]

Thus the volume of the gas is 1.98 L

Answer:

Explanation: Mg(s) + CuSO4 (aq) -> Cu(s) + MgSO4 (aq)

Answer:

The mass of carbon dioxide formed is 12g.

Answer:

1

Explanation:

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it can be expressed as:

[tex]Molarity = \frac{mole}{volume}[/tex]

With the above information in mind, we can obtain the molarity of the hydrochloric acid solution as follow:

Mole of HCl = 3 moles

Volume of water = 3 L

[tex]Molarity = \frac{mole}{volume}\\Molarity = \frac{3}{3}\\Molarity = 1 M[/tex]

Therefore, the molarity of the hydrochloric acid solution is 1 M.

Learn more: https://brainly.com/question/15012982

In this exercise we have to use the knowledge of lunar eclipse to identify the alternatives that correspond to this effect, as follows:

A lunar eclipse happens when the Earth is between the Moon and the Sun, at times when they are aligned. Depending on the position of the Moon, it is total, partial or penumbral. Different stages of a lunar eclipse on a full moon night.

Now,  use the knowledge of solar eclipse to identify the alternatives that correspond to this effect, as follows:

Solar eclipse is an astronomical phenomenon that occurs when the Moon is positioned between the Earth and the Sun, hiding the light emitted by the star towards the planet.

See more about eclipse at brainly.com/question/25105283

Answer:

eukaryotic because it has a nucleus

Explanation:

Answer:

a, to reduce air bubbles

Explanation:

all its asking, is what is the purpose of the cover. and a is the most reasonable out of all of them, even though none of them make any sense.

Answer:

9.643×10^-4 mole is your answer

Explanation:

56 g of iron =1 mole

0.054 g of iron =1×0.054/56=9.643×10^-4 mole

Answer: [tex]H_2SO_4[/tex] is the limiting reagent.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation is:

[tex]3H_2SO_4(aq)+2Al(OH)_3(aq)\rightarrow Al_2(SO_4)_3(aq)+6H_2O(l)[/tex]

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2SO_4 =\frac{30g}{98g/mol}=0.31moles[/tex]

[tex]\text{Moles of} Al(OH)_3=\frac{25g}{78g/mol}=0.32moles[/tex]  

According to stoichiometry :

3 moles of [tex]H_2SO_4[/tex] require = 2 moles of [tex]Al(OH)_3[/tex]

Thus 0.31 moles of [tex]H_2SO_4[/tex] will require=[tex]\frac{2}{3}\times 0.31=0.21moles[/tex]  of [tex]Al(OH)_3[/tex]

Thus [tex]H_2SO_4[/tex] is the limiting reagent as it limits the formation of product and [tex]Al(OH)_3[/tex] is the excess reagent.

Answer:

wait are you talking about the bottom question??

Answer:

its both because your hight can change if u do exercises

Hope it helped.