Answer:
0.263 mol
Explanation:
K2SO4 - potassium sulfate
Molar mass (K2SO4) = 2*39.0983 + 32.065 + 4*15.9994 =
= 174.2592≈174.26 g/mol
45.8 g * 1 mol/174.26 g = 0.263 mol
Consider the reaction 2H2(g)+O2(g)→2H2O(l) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) What is the mass of water, H2O(l) H 2 O ( l ) , produced when 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?hen 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?
Answer:
mH₂O = 6.4116 g
Explanation:
Let's write the given reaction:
2H₂ + O₂ -------> 2H₂O
The problem states that 5.7 g of oxygen reacts with excess hydrogen, hence, the limiting reagent is the oxygen. With this mass of oxygen, we can determine the moles, and then, the moles of water with the mole ratio:
moles = mass / atomic weight AW of O₂ = 16 g/mol
Replacing we have:
moles O₂ = 5.70 / (16 * 2)
moles O₂ = 0.1781 moles
According to the balanced reaction, 1 mole of Oxygen produces 2 moles of water, so we have a mole ratio 1:2, therefore the moles of water would be twice the moles of oxygen:
moles H₂O = 0.1781 * 2 = 0.3562 moles
Finally the mass of water can be calculated solving for the mass from the expression of moles, and using molecular mass of water:
m = moles * MM MM H₂O = 18 g/mol
m = 0.3562 * 18
mH₂O = 6.4116 gHope this helps
Excess silver(I) nitrate was added to a 8.500 g mixture containing some amount of barium chloride, and 7.123 g of silver chloride was obtained. The unbalanced equation is
AgNO3 + BaCl2(aq) --> Ba(NO3)2(aq) + AgCl(s).
What is the mass% of BaCl2 in the mixture?
Answer:
60.88%
Explanation:
The balanced equation of the reaction is given as;
2 AgNO3 (aq) + BaCl2 (aq) → 2 AgCl (s) + Ba(NO3)2 (aq)
Since AgNO3 is in excess, the limiting reactant is BaCl2. From the reaction;
1 mol of BaCl2 produces 2 mol of AgCl
Converting to masses;
Mass = Number of mol * Molar mass
BaCl2;
Mass = 1 * 208.23 g/mol = 208.23 g
AgCl;
Mass = 2 * 143.32 g/mol = 286.64 g
208.23 g BaCl2 produces 286.64 g of AgCl
x g BaCl2 produces 7.123 g of AgCl
Solving for x;
x = 7.123 * 208.23 / 286.64 = 5.1745 g
Mass percent = Mass / Total mass of Mixture * 100
Mass Percent = 5.1745 / 8.500 = 0.6088 * 100 = 60.88%
What is the surface composition of planets in the solar system?
A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium
Answer:
B
Explanation:
Most planets in the solar system don't have water. Helium and hydrogen are two of the many gasses in planets. Therefore, B is the best answer.
59. Which one has 0 dipole moment?
a. H2O2 b. Co2 c. HF
d. HBr
Answer:
the answer to this question is A H202
Which of the following is evidence that a chemical
change is occurring?
a. Cherry drink mix is added to water and the resulting
solution is red.
b. A white powder is added to cool tap water in a beaker
and the beaker gets hot.
c. Water is added to coffee until the solution becomes
clear.
d. Water is added to sand and the sand looks darker
Answer:
c. water is added to coffe until the solution becomes clear
Answer:
c
Explanation:
Water is added to coffee until the solution becomes
clear.
does a mole of hydrogen have the same mass as a mole of oxygen? explain your answer
What is the molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution?
Answer:
0.389 M
Explanation:
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 g
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5 g
Number of mole of CuCl₂ =?
Mole = mass / Molar mass
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Number of mole of CuCl₂ = 0.584 mole
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389 M
The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
HOW TO CALCULATE MOLARITY?The molarity of a solution can be calculated
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 gVolume of solution = 1.50 LMolarity of CuCl₂ =?Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5g
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 moles
The determine the molarity of the solution. This can be obtained as follow:
Number of moles of CuCl₂ = 0.584 molesVolume of solution = 1.50LMolarity of CuCl₂ =?Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389M
Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
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Using the van der Waals equation, determine the pressure exerted by 4.30 mol Ar in 3.6 L at 325K.
Answer:
37.7 atm
Explanation:
Using the relation;
(P + an^2/V^2) (V - nb) = nRT
(P + an^2/V^2) = nRT/(V - nb)
a = 0.0341 atm dm^2 Mol^2
b = 0.0237 dm/mol
P = nRT/(V - nb) - an^2/V^2
P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)
P = 114.595/(3.498) - 0.0487
P = 37.7 atm
What is the surface composition of planets in the solar system?
A,. Helium or hydrogen
B,. Rock or gas
C., Rock or water
D,. Water or helium
Answer:
A: Helium or Hydrogen
Explanation:
Terrestrial planets are the 4 inner most planets of the solar system which are mercury, venus, earth, Mars, while the giant planets are the 4 outer most which are Jupiter, Saturn, Uranus and Neptune.
Now, these outer most ones are the surface ones and are surrounded primarily by layers of hydrogen and helium gases.
What is the electrostatic potential energy (Eel) of the ionic bond between a Ca2+ ion and a S2– ion in joules? Before you do the calculation, predict whether the result you get will be less than (more negative) or greater than (less negative) than the Eel value for KCl. The ionic radii of Ca2+ and of S2– are 100 pm and 184 pm, respectively.
Answer: the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Explanation:
Given the data in the question;
I think the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has more charge that is +2 and -2 respectively when compared to Kcl which has +1 and -1 charge.so it will be more negative.
radius = r[tex]_{ca+2}[/tex] + r[tex]_{s-2}[/tex] = 100 + 184 = 284 pm = 2.84 × 10⁻¹⁰ m
we know that; k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
so
Ep = k × q1q2/r
so we substitute
Ep = 2.31 × 10⁻²⁸ × (+2×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Based on the data provided, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
What is electrostatic potential energy?The electrostatic potential energy is the work done in moving the charge from infinity to that point against the electric field.
The electrostatic potential energy between any two charges q1, q2 separated by distance r is derived from Coulomb’s law and mathematically given as:
E = k × [q1q2/r2]where
k is a constant = 2.31 × 10⁻²⁸ Jq1 and q2 are the chargesr is the distance of separationFrom the data provided:
ionic radii of Ca2+ r1 = 100 pm
ionic radii of S2– = 184 pm.
Chargeon Ca2+ = +2
Charge on S2_ = -2
From the data above, it most likely that the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has a greater charge of +2 and -2 respectively compared to Kcl which has +1 and -1 charge.
Calculating the electrostatic potential energy, Ep:
radius = r1 + r2 = 100 + 184 = 284 pm
r = 2.84 × 10⁻¹⁰ m
k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
Then:
Ep = k × q1q2/r
Substituting the values above in the equation:
Ep = 2.31 × 10⁻²⁸ × (+2 ×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J.
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How many moles are there in 2.30 x 1024 atoms of silver?
Answer:
Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).
Step 1
Use dimensional analysis to convert the number of atoms to moles.
1 mole atoms = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag
Step 2
Convert the moles of Ag to mass.
mass (m) = moles (n) × molar mass (M)
n(Ag) = 3.8193 mol Ag
M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag
m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures
The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.
Explanation:
The number of moles that are present is 2.3 × 10²⁴ atoms of silver are 3.8193 moles that can be determined using Avogadro's law.
The calculation for number of moles:One mole:
A mole is defined as 6.022 × 10²³ of some chemical unit, be it atoms, molecules, ions, or others.
1 mole = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms)
n(Ag) = 3.8193 mol Ag
Thus, the number of moles is 3.8193 moles.
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At room temperature, CsF is expected to be:______.
a. a soft solid.
b. a conducting solid.
c. a gas.
d. a brittle solid.
e. a liquid.
Answer:
d. a brittle solid.
Explanation:
Hello!
In this case, since cesium fluoride is widely known as an ionic compound due to the large electronegativity difference, it is possible to discard a. due to its crystalline structure, b. because conducting solids are metals, c. because ionic compounds are not likely to be gases and e. because even when it is soluble in water, the problem is not referring to an aqueous solution; therefore, the answer is d. a brittle solid.
Best regards!
What is the main FUNCTION of the digestive system?
What are some of the main organs of the digestive system?
In the lab activity, the reaction rate was determined by the appearance of a product. However, the reaction rate can also be determined by the disappearance of a reactant. Rate =Δ[product]/Δt or rate−Δ[reactant]Δt. In each situation below, you are given a rate measured by the appearance of one component of the reaction and are asked to predict the rate of appearance or disappearance of another component, based on logic and stoichiometric relationships.
For example, if the reaction is as follows:
A+2B⟶products
For every mole of A that is used, 2 moles of B are used so the rate of disappearance of B is twice the rate of the disappearance of A.
This may be expressed as:
rate=−Δ[B]/Δt=−2[A]/Δt , N2(g)+3H2(g)⟶2NH3(g)
The reaction rate is measured as 0.032 M NH3/s. Determine the rate of disappearance of N2 and the rate of disappearance of H2. Explain how you arrived at your answers.
Answer: Rate of disappearance of [tex]N_2[/tex]= 0.032 M/s
Rate of disappearance of [tex]H_2[/tex] = 0.096 M/s
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]N_2(g)+3H_2(g)\rightarrow 2NH_3(g)[/tex]
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of [tex]N_2[/tex] = [tex]-\frac{1d[N_2]}{dt}[/tex]
Rate in terms of disappearance of [tex]H_2[/tex] = [tex]-\frac{1d[H_2]}{3dt}[/tex]
Rate in terms of appearance of [tex]NH_3[/tex] = [tex]\frac{1d[NH_3]}{2dt}[/tex]
Rate = [tex]-\frac{1d[N_2]}{dt}=-\frac{1d[H_2]}{3dt}=\frac{1d[NH_3]}{2dt}[/tex]
Given : = 0.032 M/s
Rate of disappearance of =
Rate of disappearance of [tex]H_2[/tex] = [tex]-\frac{d[H_2]}{dt}=3\times 0.032M/s=0.096M/s[/tex]
3. Una piedra que se tira verticalmente hacia arriba se mueve según la
leys = 64y - 8t^2, si "s" se mide en pies (ft) y t en segundos, hallar:
a) SU posición y velocidad después de dos segundos y después de tres
segundos.
b) ¿Qué altura alcanzará?
c) ¿A qué distancia se moverá al cabo del cuarto segundo?
Answer:
Explanation:
Para mejor entendimiento, reeescribiremos la ley que pusiste:
S = 64t - 8t² (1)
De acuerdo al enunciado del problema, S tiene unidades de pie y t en segundos, por lo tanto, S, que se refiere a la posición o altura alcanza de la piedra, puede ser determinado usando esa expresión a tiempos específicos.
Para el calculo de velocidad usamos la siguiente expresión:
V = -g * t (2) g: 32.16 ft/s
Tomando en cuenta estas expresiones, veamos los valores de posición y velocidad:
a) Para t = 2 s
S = 64(2) - 8(2)²
S = 96 ft
V = -32.16 * 2
V = -64.32 ft/s
Para t = 3 s
S = 64(3) - 8(3)²
S = 120 ft
V = -32.16 * 3
V = -96.48 ft/s
b) Para saber la altura que alcanzará, usamos la expresión de altura máxima que es la siguiente:
Smáx = -V₀² / 2g (3)
Para el valor de la velocidad inicial, podemos asumir el valor de la velocidad dada por la formula de la ley S, que es 64. Esto porque al ser multiplicado por el valor del tiempo, queda en unidades de distancia, asi que este valor debe tener unidades de velocidad. Reemplazando este valor en la expresión:
Smáx = -(64)² / 2 * 32.16
Smáx = 63.68 ft
c) Para esta parte, usamos nuevamente la formula de la ley S, usando t = 4 s y listo:
S = 64(4) - 8(16)
S = 128 ft
Espero te sirva
Skin color variations were caused by:
a). The change in melanin, the skin's brown pigment
b). The climate of where people migrated to
c)Diets that are rich in Vitamin D
d) All of the above
I'm certain the answer is D: All of the above, but please correct me if I'm wrong ^^
Father, I come to you worn and weary from the hard times I have walked through recently. I come to you seeking your shelter where I know I can find security and rest in your shadow. Father, you are mighty. I know my circumstances are no match for Your great power. Father I place a healing of these people that they feel a conviction in there heart that they would turn from there wicked way and turn to you father. IN JESUS NAME AMEN
Answer:
Fact: There’s only one letter that doesn’t appear in any U.S. state name
And that is Q
Explanation:
The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of an unknown solution:
a. The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
b. The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
c. The equation from the calibration curve can only be linear.
d. Domain and range restrictions must be observed.
Answer:
The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
Domain and range restrictions must be observed.
Explanation:
Calibration curves are tools necessary in understanding the instrumental response for any analyte.
A calibration curve is obtained by preparing a set of standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.
The equation of the best-fit line is used to determine the concentration of the unknown sample.
What is the concentration of a Kl solution of 20.68 g of solute was dissolved in enough water to form 100. ml of solution?
Answer:
1.25M
Explanation:
What is the difference between an introduced species and an invasive species?
Answer and Explanation:
The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.
An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.
Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
Answer:
65.0cp
Explanation:
DNA forms two strands. One of the strands of a piece of a DNA molecule has the bases ATA.
Which bases does the other strand have?
Select one:
A: CAC.
B: TAT.
C: GTG.
D: ATA.
Answer:
b
Explanation:
Combinations between two strands:
T - A
A - T
C - G
G - C
(so if one strand has A for example, then the other strand must have T in the same spot)
Bases which are present on the other strand of DNA are TAT.
What is DNA?DNA or deoxyribonucleic acid is a hereditary material present in humans as well as all living beings. Almost every cell present in the body has DNA. Most DNA are located inside the cell , that is in the nucleus of the cell. But a small portion of DNA can be found in the mitochondria of the cell as well.
The information in DNA is stored as a code which is composed of four chemical bases 1) adenine 2)guanine 3) cytosine 4) thymine . The human DNA consists of 3 billion bases . The order of of these bases determine information which is used for building and maintaining an organism.
The DNA bases can pair with each other .Adenine pairs with thymine and guanine with cytosine to form units which are called as base pairs.Each base apart from other complementary base it also attaches itself to a sugar and a phosphate molecule.
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Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?
Answer:
See explanation
Explanation:
The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of tetraphenylcyclopentadienone and diphenylacetylene are Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.
The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of tetraphenylcyclopentadienone and diphenylacetylene.
Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.
I'LL MARK YOU BRAINLIEST! Please help me balance these chemical reactions. (I'M NOT IN COLLEGE, I'M IN 10TH GRADE) Please help me
Answer:
1. H2 + Cl2 => 2HCl
2. Na2S + 2HCl => 2NaCl + H2S
3. 6HCl + 2Al => 2AlCl3 + 3H2
4. C3H8 + 5O2 => 3CO2 + 4H2O
5. C6H12O6 + 6O2 => 6CO2 + 6H2O
6. 4C12H23O11 + 49O2 => 48CO2 + 46H2O
7. 4NH3 + 7O2 => 4NO2 + 6H2O
8. 2Mg + 02 => 2MgO
hope it helps
La fórmula molecular del pentano y del nonano son
Nose jajajajajaj si mr ayudas te ayudo
8. Label the type and parts of the waves shown here.
longitudinal wave
WORD BANK
engitudinal wave
• transverse wave
compression
• rarefaction
crest
trough
Houghton Mifflin Harcourt
When a chemical reaction is run in aqueous solution inside a calorimeter, the temperature change of the water (and Ccal) can be used to calculate the enthalpy change for the reaction. Here, we will study the reaction of hydrochloric acid with sodium hydroxide in the calorimeter from problem 3. Equal volumes (50.0 mL) of 1.00 M sodium hydroxide and 1.00 M hydrochloric acid are mixed.
HCl+NaOH→NaCl+H2O
1. What is the total change in enthalpy (in Joules) for the reaction?
2. Where initial temperature is 21.2 °C and final temperature is 28.0 °C. Ccal is 1234.28 j
Answer:
The total change in enthalpy for the reaction is - 81533.6 J/mol
Explanation:
Given the data in the question;
Reaction;
HCl + NaOH → NaCl + H₂O
Where initial temperature is 21.2 °C and final temperature is 28.0 °C. Ccal is 1234.28 J
Moles of NaOH = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol
Moles of HCl = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol
so, 0.0500 moles of H₂O produced
Volume of solution = 50.mL + 50.mL = 100.0 mL
Mass of solution m = volume × density = 100.0mL × 1.0 g/mL = 100 g
now ,
Heat energy of Solution q= (mass × specific heat capacity × temp Δ) + Cal
we know that; The specific heat of water(H₂O) is 4.18 J/g°C.
so we substitute
q_soln = (100g × 4.18 × ( 28.0 °C - 21.2 °C) ) + 1234.28
q_soln = 2842.4 + 1234.28
q_soln = 4076.68 J
Enthalpy change for the neutralization is ΔH[tex]_{neutralization}[/tex]
ΔH[tex]_{neutralization}[/tex] = -q_soln / mole of water produced
so we substitute
ΔH[tex]_{neutralization}[/tex] = -( 4076.68 J ) / 0.0500 mol
ΔH[tex]_{neutralization}[/tex] = - 81533.6 J/mol
Therefore, the total change in enthalpy for the reaction is - 81533.6 J/mol
What is the molar mass of Ammonium Carbonate?
Explanation:
Molar mass
96.09 g/mol
glad to help....
Ethane is a hydrocarbon with a formula of C2H6 . How many Carbon and Hydrogen atoms are contained within 3 molecules of ethane ?
Answer:
Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.
Explanation:
3. A very large distillation column is separating p-xylene (more volatile) from o-xylene. The column has two feeds that are saturated liquids. Feed 1 flows into the column at a rate of 90 kmol/h and contains 42 mol% p-xylene. Feed 2 flows at a rate of 20 kmol/h and contains 9 mol% p-xylene. The bottoms product should be 97 mol% o-xylene, and the distillate product should be 99 mol% p-xylene. Compute the distillate (D) and the bottoms (B) products flow rates
Answer:
the distillate (D) and the bottoms (B) products flow rates are;
B = 72.1875 kmol/hr
D = 37.8125 kmol/hr
Explanation:
Given the data in the question;
as illustrated in the image below;
F1 stream, ( 90 kmol/hr ) contains 42 mol% p-xylene and Feed 2 ( 20 kmol/hr) contains 9mol% p-xylene, so;
more volatile → p-xylene
less volatile → o-xylene
now, Overall balance;
F1 + F2 = D + B
90 + 20 = D + B
D + B = 110 ------------- let this be equation 1
p-xylene. component balance;
0.42F1 + 0.09F2 = 0.99D + 0.03B
0.42(90) + 0.09(20) = 0.99D + 0.03B
37.8 + 1.8 = 0.99D + 0.03B
0.99D + 0.03B = 39.6 --------------- let this be equation 2
from equation 1 and 2
input (D = 110 - B) into equation 2
0.99(110 - B) + 0.03B = 39.6
108.9 - 0.99B + 0.03B = 39.6
108.9 - 39.6 = 0.99B - 0.03B
69.3 = 0.96B
B = 69.3 / 0.96
B = 72.1875
now, input B = 72.1875 into equation 1
D + B = 110
D + 72.1875 = 110
D = 110 - 72.1875
D = 37.8125
Therefore, the distillate (D) and the bottoms (B) products flow rates are;
B = 72.1875 kmol/hr
D = 37.8125 kmol/hr