How many moles of O2will be produced from 6.2 moles of water?​

Answer:

The wind pushes the sails from behind, causing the boat to move forward.

Answer:

Wind energy obtained by the machine is converted into kinetic energy as it functions and thus enabling the boat to move.

Together, the forces of drag, from the water, and the pressure from the wind against the sail itself push the craft forward. Angling too sharply into the wind causes the forces on the boat to become unbalanced, and moves the boat sideways in the water.

Answer:

stochiometry works with measuring quantitative relationships and used to determine the amount of products and reactants that are produced or needed in a reaction

Answer:

Stoichiometry is the calculation of reactants and products in chemical reactions in chemistry. Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals.

Answer:

I think its correct

Answer:

D. the atomic mass increases from left to right

Explanation:

Answer:

This is your answer ☺️☺️☺️

Answer:

-23.15

Explanation:

Answer:

The answer is 2 all you do is divide the 6.02 and 3.01 and you get 2

Answer:

Acidic oxides, or acid anhydride, are oxides that react with water to form an acid, or with a base to form a salt. They are oxides of either nonmetals or of metals in high oxidation states.

Explanation:

Answer:

The steps in order are;

1. Obtain a 50-mL volumetric flask

2. Add approximately 10 mL of deionized water to the empty flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

The volume of the acetic acid to be added to the solution is 15 mL

Explanation:

The given steps are;

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

1. Obtain a 50-mL volumetric flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

2. Add approximately 10 mL of deionized water to the empty flask

The given parameters are;

The volume of the volumetric flask = 50-mL

The concentration of the final solution of acetic acid = 0.6 mg/L

The concentration of the stock solution = 2.0 mg/L

Let 'x' represent the volume of the stock solution added, we have;

2.0 mg/L·x + (50 - x)×0 = 0.6 mg/L × 50-mL

x = 0.6 mg/L × 50-mL/(2.0 mg/L) = 15 mL

The volume of the stock solution to be added, x = 15 mL

Answer:

Veja, por exemplo, que os elementos mais eletronegativos são os que estão no canto superior direito da tabela, isto é, o flúor (4,0) e o oxigênio (3,5), e os menos eletronegativos são os que estão no canto inferior esquerdo, que são o frâncio (0,8) e o césio (0,8).

Explanation:

Answer:

mass of CO₂ produced = 5.06 g of CO₂

Explanation:

Equation of the reaction: 2CH₃CH₃ + 5O₂ ---> 4CO₂ + 6H₂O

From the equation of the reaction, 2 moles of gaseous ethane reacts with 5 moles of oxygen gas to produce 6 moles of water.

molar mass of ethane = 30 g/mol

molar mass of oxygen gas = 32 g/mol

number of moles of ethane present in 1.8 g = 1.8/30 = 0.06 moles

number of moles of oxygen gas present in 4.6 g = 4.6/32 = 0.14375 moles

mole ratio of oxygen gas to ethane  = 2.4 : 1

Therefore, oxygen is the limiting reactant

0.14375 moles of oxygen will react with 0.06 moles of ethane to produce 4/5 * 0.14375 moles of CO₂ = 0.115 moles of CO₂

molar mass of CO₂ = 44 g/mol

mass of CO₂ produced = 0.1725 * 44

mass of CO₂ produced = 5.06 g of CO₂

Answer:

David R. Ashbaugh

Explanation:

David R. Ashbaugh is a Canadian police officer known for his extensive research on the friction ridge identification, introducing for the first time the use of the term ridgeology in forensic identification and the ACE-V methodology.

Answer: Hello i am confused are you asking a question?

Explanation:

Answer:

Depends on what you're doing, you could be running and it goes higher, temperature isn't too much of a difference.

Explanation:

Answer:

88%.

Explanation:

The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.

Answer:

Cluster HR Diagrams: Since all the stars in a cluster formed at the same time, they are all the same age. A very young cluster will have a HR diagram with a cluster of T-Tauri stars evolving towards the main sequence. ... Each star is plotted by its color and magnitude on the HR diagram.

Answer:

a. triple bond

b.diatomic atom

c. covalent bond

d. non polar covalent bond

e. covalent bond

f. sigma bonds

Answer:

D.

The substance will have the same chemical properties.

Explanation:

Physical changes do not alter the chemical composition of a substance, so the chemical properties will not change.

The question is complete, the complete question is;

16.1g of bromine are mixed with 8.42g of chlorite to give an actual yield of 21.1g of bromine monochloride.

Answer:

91 %

Explanation:

Br2 + Cl2 ------>2BrCl

Number of moles of Chlorine = 8.42/71 = 0.119 moles

If 1 mole of Cl2 yields 2 moles of BrCl

0.119 moles of Cl2 will yield 0.119 moles * 2/1 = 0.238 moles of BrCl

Number of moles of Br2 reacted = 16.1/160 = 0.1 moles

If 1 mole of Br2 yielded 2 moles of BrCl

0.1 moles of Br2 yields 0.1 * 2/1 = 0.2 moles of BrCl

Bromine is the limiting reactant.

Mass of BrCl produced = 0.2 moles * 115.357 g/mol = 23.07 g

Theoretical yield = 23.07 g

Actual yield = 21.1 g

Percentage yield = Actual yield/Theoretical yield * 100

= 21.1/23.07 * 100 = 91 %

Answer:

I think D. sorry if I'm wrong:)

Answer:

I would say A but not sure

Explanation:

Answer: The molarity of solution is 3.37 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute = 0.614  

[tex]V_s[/tex] = volume of solution in ml = 182 ml

Now put all the given values in the formula of molarity, we get

[tex]Molarity=\frac{0.614\times 1000}{182}=3.37M[/tex]

Therefore, the molarity of solution is 3.37 M

Answer:

i would go for the 2nd as far as i know they were a big continent and an earthquake separes them all

Answer:

They're considered nonrenewable because they take millions of years to develop. They can't be renewed as fast as we're taking them.

Answer:

1.56g/L it will be as per my calculation if I am not wrong so

Answer: D: 1.43

The expected density of the given sample of oxygen gas at STP can be calculated using the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

At STP, the pressure is 1 atm and the temperature is 273 K. We are given that the mass of the oxygen gas is 4.8 g. To find the number of moles of oxygen gas, we can use its molar mass, which is 32.00 g/mol:

n = mass / molar mass = 4.8 g / 32.00 g/mol = 0.15 mol

Using the molar volume of an ideal gas at STP, which is 22.4 L/mol, we can find the volume of the oxygen gas:

V = n × molar volume = 0.15 mol × 22.4 L/mol = 3.36 L

Therefore, the expected density of the given sample of oxygen gas at STP is:

density = mass / volume = 4.8 g / 3.36 L = 1.43 g/L

Therefore, the expected density of the given sample of oxygen gas at STP is 1.43 g/L.