How many moles of H2O are produced when 3.25 moles of O2 react in the above equation?

a
12.92 moles of H2O

b
3.79 moles of H2O

c
0.06 moles of H2O

d
2.79 moles of H2O

Answer:

no effect

Explanation:

In an SN2 reaction, the mechanism is bi-molecular and first order in both the alkyl halide and the nucleophile.

Hence the rate of reaction is;

Rate = k [1-iodo-2-methylbutane] [cyanide ion]

Given that it is a bimolecular reaction, if we double the concentration of 1-iodo-2-methylbutane and the concentration of the cyanide ion is halved, the rate of reaction remains the same.

Answer:

1) 18.91 mL

2) 2.35 %

Explanation:

1. The volume of base that was required is equal to the difference between the reading at the end of the titration and the reading at the beginning:

2. The mass percent can be written as:

For this problem:

We input the data and calculate the mass percent:

Answer: e. 4.8 h

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

a) for rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{0.77hr}=0.9hr^{-1}[/tex]

b) for 160.0 g to decay to 2.07 g

[tex]t=\frac{2.303}{0.9}\log\frac{160.0}{2.07}[/tex]

[tex]t=4.8hr[/tex]

The time  required for a 160.0-g sample of 158Eu to decay to 2.07 g is 4.8 hours

The formula of Silver (III) Sulfide is Ag2S3.

Hope this helps. Please mark brainliest!

The given question is incomplete, the complete question is:

A buffer is prepared by adding 24.6 mL of 0.65 M NaF to 49.6 mL of 0.28 M HF. What is the pH of the final solution?

Answer:

The correct answer is 3.23.

Explanation:

The calculations of pH in a buffer solution is determined with the help of Henderson-Hasselbalch equation, that is,

pH = pKa + log[conjugate base]/[acid]

= pKa + log[A⁻][HA]

Here Ka is the equilibrium constant.  

Based on the given information, the volume and concentration of NaF is 24.6 ml and 0.65 M. Now the millimoles of NaF can be determined by using the formula,  

millimoles = Molarity × Volume

= (0.65 M) (24.6 ml) (1 mmol/ml/1M)

= 16 mmol

Thus, the millimoles of NaF or F⁻ is 16 mmol.  

On the other hand, the volume and concentration given of HF is 49.6 ml and 0.28 M. Now the millimoles of HF will be,  

Millimoles = 0.28 M × 49.6 ml (1mmol/ml/1M)

Millimoles = 13.9 mmol

Thus, the millimoles of HF is 13.9 mmol.  

The value of Ka for strong acid is 6.8 × 10⁻⁴.  

Now the pH of the buffer solution can be determined by using the above mentioned Henderson-Hasselbalch equation,  

pH = pKa + log[F⁻]/[HF]

= -logKa + log[16 mmol]/[13.9 mmol]

= -log(6.8 × 10⁻⁴) + 0.06

= 3.17 + 0.06

= 3.23.  

Hence, the pH of the solution is 3.23.

Answer:

precise

Explanation:

precise because they are almost the same measurement over and over ( remember in significant digits the last number is considered to be an estimate on measurements). The known value, 8.60 g, is pretty far from the measurements taken so it cant be accurate.

The values obtained in the measurement of the mass of products from the same reaction are precise but not accurate.

Recall that:

In this case, one can see that the repeated measurements of the mass of the products were close to each other with a range of 0.02 g.

The average of the measurement can be calculated such that:

                       8.83 + 8.84 + 8.82/3 = 8.83 g

The predetermined mass of products from the reaction is 8.60 g. The difference from the average measurement can be calculated as:

                         8.60 - 8.83 = 0.23

The difference between the measurement and true value is significant. thus, the result is not accurate.

More on precision and accuracy can be found here: https://brainly.com/question/18974348

Answer:

D) 174 g/mol

Explanation:

Step 1: Given and required data

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 25.0°C + 273.15

K = 298.2 K

Step 3: Calculate the molecular weight (M) of the gas

We will use the following expression derived from the ideal gas equation.

ρ = P × M / R × T

M = ρ × R × T / P

M = 7.10 g/L × (0.0821 atm.L/mol.K) × 298.2 K / 1.00 atm

M = 174 g/mol

Given values:

We know the formula,

→ [tex]PV = nRT[/tex]

or,

→ [tex]PM = \frac{W}{V} RT[/tex]

or,

→ [tex]PM = dRT[/tex]

By substituting the values, we get

[tex]1\times M = 7.10\times 0.0821\times 298[/tex]

     [tex]M = 7.10\times 0.0821\times 298[/tex]

          [tex]=174[/tex]

Thus the answer i.e., "option D" is appropriate.

Learn more about molecular weight here:

https://brainly.com/question/14685031

Explanation:

Chlorophyll make food the plant can use from carbon dioxide, water, nutrients, and energy from sunlight. This process is called photosynthesis. During the process of photosynthesis, plants release oxygen into the air. People and animals need oxygen to breathe.

hope it helps!

Answer:

4A

Explanation:

on the periodic table

Answer:

what grade so i can help

Explanation:

Answer:

I believe it’s Sn-Te > H-S > Si-F

Explanation:

Answer:

1.40.078 u

2.26.981539 u

3.207.2 u

4.56

5.53.9396147 u

6.1.00784 u

Explanation: your welcome

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

Answer:

9.26g of BaSO₄ are formed

Explanation:

The reaction of Ba(OH)₂ with H₂SO₄ is:

Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O.

To solve this question we need to determine the moles of each reactant in order to find the limitng reactant. With the moles of limiting reactant we can find the theoretical moles of BaSO₄ produced and its mass, as follows:

Moles Ba(OH)₂:

50.0mL = 0.050L * (1.00mol / L) = 0.0500moles

Moles H₂SO₄:

83.5mL = 0.0835L * (0.475mol / L) = 0.0397moles

That means limiting reactant is H₂SO₄.

Based on the reaction, 1 mole of H₂SO₄ produce 1 mole of BaSO₄. The theoretical moles of BaSO₄ produced are 0.0397 moles.

The mass is (Molar mass BaSO₄: 233.38g/mol):

0.0397 moles BaSO₄ * (233.38g / mol) =

Answer:

A) They get oxidized into carbon monoxide and carbon dioxide by the oxygen molecules generated on the electrode.

Explanation:

In the electrolysis of Aluminium, the oxygen reacts with the carbon anodes forming carbon dioxide. That is, the anodes are oxidized. To ensure that the reaction completes, the anode must gradually be replaced as the reaction proceeds. The correct option is hence;

A) They get oxidized into carbon monoxide and carbon dioxide by the oxygen molecules generated on the electrode.

Answer:

0.54 mole of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3OH + 3O2 —> 2CO2 + 4H2O

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.

Thus, 0.54 mole of H2O is produced from the reaction.

Answer:both

Explanation:

It depends on where your looking at it from

Answer:

an expierience help prove a theory.

Answer:

[A] = 8.69x10⁻⁵g

Explanation:

Kinetics law of a radioactive atom, A, is:

Ln[A] = -kt + ln[A]₀

Where [A] could be taken as mass of A after time t (In seconds),

k is rate constant = ln2 / Half-Life

[A]₀ is intial mass of A

k = ln2 / 14.9s = 0.04652s⁻¹

Time in seconds:

5min * (60s / 1min) = 300s

Replacing each value:

ln[A] = -0.04652s⁻¹*300s + ln[100.0g]

ln[A] = -9.35

Answer:

5.4 g Na

Explanation:

Calculate the mass of sodium chloride from both reactants. The lesser value is the amount is the theoretical yield. Subtract the mass of the calculated mass of sodium chloride from the mass of the reactants.

Answer:

H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)

HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)

Explanation:

Carbonic acid (H₂CO₃) has 2 acidic protons. When is dissolved in water, it loses the protons (H⁺) in two sequential steps:

- First, it loses 1 proton to form the hydrogen carbonate ion (HCO₃⁻)

H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)

- Then, the acid carbonate anion loses its proton to form carbonate ion (CO₃²⁻):

HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)

Answer:

It's not A, it's likely not C? I'm guessing B or D.

Answer:

I believe the answer would be

b.) valence electrons, all thw electrons that surround the nucleus of an atom

Explanation:

You're welcome

Answer:

3.6132 * 10^24 atoms/molecules of 02

Explanation:

When we look at the balanced chemical equation, we can see that there are 6 moles of O2.

In order to convert from moles to formula units (atoms and molecules),

you need to multiply by avogadro's number.

6 moles * [tex]6.022*10^{23}[/tex]/1 mol = 3.6132 * 10^24 atoms/molecules of 02

Answer:

2.41 * 10^24 atoms of carbon present in the products.

Explanation:

First, we need to find the moles of carbon in the products in order to find the number of atoms.

We see that in the chemical formula, carbon belongs to the compound known as glucose. To get the amount of moles of carbon, we need to divide my the amount of carbon within glucose (in grams) from the total amu ( or grams) of glucose to get the moles.

C6 = 72.066.

C6H12O6 = 180.156

72.066/180.156 = 0.4000199827 moles of Carbon within the Glucose compound

Now we will convert to atoms/molecules by multiplying the moles by avogadro's number..

0.4000199827 moles C * 6.022*[tex]10^{23}[/tex] = 2.408920336 *[tex]10^{24}[/tex] atoms of Carbon present in the products

*Note --> this can be estimated to 2.41 * [tex]10^{24}[/tex] atoms of Carbon

Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

Answer:

Mg and HCI

Explanation:

The combination that she uses to produce hydrogen gas is:

d. Mg and HCl(Magnesium and Hydrochloric acid)

When magnesium reacts with Hydrochloric acid, It leads to the formation of Magnesium chloride as a salt, and hydrogen gas is liberated.

[tex]Mg+2HCl--- > MgCl_2+H_2[/tex]

When a metal reacts with an acid, it leads to the liberation of hydrogen gas and the production of their respective salt.

Thus, option d is correct.

Find more information about Hydrogen gas here:

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Answer:

2.652 g/h.

Explanation:

Burn rate (in mg/min) = 44.2 mg/min

Burn rate (in m/h) =?

We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:

1 mg/min = 0.001 g/min

Therefore,

44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min

44.2 mg/min = 0.0442 g/min

Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:

1 g/min = 60 g/h

Therefore,

0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min

0.0442 g/min = 2.652 g/h

Therefore, 44.2 mg/min is equivalent to 2.652 g/h.

Thus, the burn rate (in m/h) is 2.652 g/h.

Answer:

salt (NaCl)

Explanation:

Pure substance is defined as the substance that consist of a single type of material and does not contain contaminants. A pure substance has uniform composition throughout the process.

sodium chloride (NaCl) also known as table salt is a pure substance because it has a uniform and definite composition that is  1:1 ratio of sodium and chloride ions.

Hence, the correct answer is "salt (NaCl)".