How many moles of copper ar there in the copper sample shown?
95.33

A.1.5 mol
B. 29 mol
C. 95.33 mol
D 6.02×10to the 23 power mol​

Answer:

0.0977M is the concentration of the final solution

Explanation:

In a dilution process, to the original solution (Stock solution) you add more solvent in order to decrease its original concentration. To know how many times the solution was diluted you must find the dilution factor (Ratio between the initial and final volume). That is:

Intial Volume: 5.73mL

Final volume: 5.73mL + 20.26mL = 25.99mL

Dilution factor: 25.99mL / 5.73mL = 4.536 → 4.536 times the solution is diluted. The concentration of the diluted solution is:

0.443M / 4.536 =

The concentration of the solution is 0.099 M.

We have to use the dilution formula here;

C1V1 = C2V2

Where;

C1 = initial concentration

C2 = final concentration

V1 = initial volume

V2 = final volume

Now;

C2 = C1V1/V2

C2 =0.443 M × 5.73 mL / (5.73 mL  + 20.26 mL)

C2 = 0.099 M

Learn more about Beers law: https://brainly.com/question/7184331

Answer:

[tex]\lambda=10^{12}\ m[/tex]

Explanation:

Given that,

The frequency of the light, [tex]f=3\times 10^{-4}\ Hz[/tex]

We need to find the wavelength of the light.

The relation between frequency, wavelength and the speed of light is given by :

[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3\times 10^{-4}}\\\\\lambda=10^{12}\ m[/tex]

So, the wavelength of the light is [tex]10^{12}\ m[/tex].

The wavelength of light will be "[tex]10^{12} \ m[/tex]"

Given:

By using the relation,

→ [tex]\lambda = \frac{c}{f}[/tex]

By putting the values, we get

→    [tex]= \frac{3\times 10^8}{3\times 10^{-4}}[/tex]

→    [tex]= 10^{12} \ m[/tex]

Thus the above response is right.

Learn more:

https://brainly.com/question/9860028

Answer:

6.591

explanation

mass of weight is 1.092 , and mass of weight boat and sample = 7.683

mass of the solid sample= (mass of weight boat and sample) - (weight of the boat) = (1.092-7683) = 6.591 g

hence, the mass of the solid sample is 6.591 g

Answer:

oceanic formation is the right answer.

Explanation:

this os becoz they slide a past each other and do not rub against each other

Answer:

neon gas

Explanation:

neon is a noble gas, meaning it has a full outer shell of elections. this means it is stable and is very unlikely to have a reaction with another substance.

Answer:Because When you're cleaning your glassware, you use water to rinse it off. If the burette is not completely dry by the time you use it, the remaining traces of water on the inside will make your titrant more dilute and thereby change its concentration.Before a burette is used, it needs to be cleaned. During the cleaning process, usually, water is introduced into the burette. Be the water clean or not, if the burette is then used without rinsing it with the solution that it is going to be filled with, the result of that analytical exercise will not be precise and accurate. The reason is that water residue in the burette would dillute the solution when it's filled in the burette which would make it impossible to determine the exact concentration of the solution moved by the burette. By rinsing and re-rinsing the burette several times with the solution it is going to be filled with, residue water from the cleaning process would be successfully removed from the burette as are other leftover substances from the cleaning process.

hope this helps have a nice night ❤️❤️❤️

Explanation:

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

Answer:

That would be 4.17742995 * 10^13 :)

Explanation:

Cuz D is cyclo-thingy molecule and its a sugar

(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)

Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.

Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]

The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.

Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.

Therefore, option D. galactose is the monosaccharide.

Learn more about monosaccharides here:

https://brainly.com/question/5282729

Answer:

Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.

Explanation:

Anabolic steroid is a drug that plays the role of testosterone.

Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.

Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate [tex]X_{V}[/tex] = moles of vinyl acetate / total  moles

[tex]X_{V}[/tex] = (0.1498 mol / 3.255 mol) × 100

[tex]X_{V}[/tex]  = 4.6%

mole percent of Ethylene [tex]X_{E}[/tex] = moles of Ethylene / total  moles

[tex]X_{E}[/tex]  = (3.1052 mol / 3.255 mol) × 100

[tex]X_{E}[/tex]  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑[tex]X_{i}[/tex][tex]M_{i}[/tex]

where [tex]X_{i}[/tex] is the fraction ratio and [tex]M_{i}[/tex] is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( [tex]X_{V}[/tex][tex]M_{V}[/tex]) + ( [tex]X_{E}[/tex][tex]M_{E}[/tex])

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

[tex]DP_{n}[/tex] = [tex]\frac{M_{n} }{M}[/tex]

where [tex]M_{n}[/tex] is the number average molecular weight ( 39,870 g/mol )

so we substitute

[tex]DP_{n}[/tex] = 39,870 g/mol / 30.72 g/mol

[tex]DP_{n}[/tex]  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

Explanation:

Hphphphphphphphohoohohhpph

Answer:

you have to shake the soda up

Answer:

(a). (I). 0.816; 0.816

(ii). 0.917.

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Explanation:

So, without mincing words let's get straight into the solution to the question above.

(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;

P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).

P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).

The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.

The value of b = (1.2 + 1.2)/ 1.2 = 0.5.

Thus, putting the values into the equation (1) and (2) above gives;

NB: n = 3.

P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.

P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.

Using the (ii) carother's theory to Determine the critical extent of reaction gelation.

We have the following values for glycerol: k = 0.4, n = 3.

For ethylene glycol; k = 0.6, n = 2.

Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Answer:

comparison microscope

Explanation:

please follow me

Answer:

A, B and D

Explanation:

Gas particles move randmly at high speed, colliding with each other

Answer:

4 g/cm³

Explanation:

Volume(V) = 60 cm³

mass (m) = 240 gm

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 240 / 60

= 4 g/cm³

Hope it will help

Answer:

H-C-H

Explanation:

hydrogen plus carbon hdrocloide

Answer:

sorry i dont know

Explanation:

Answer:

1 mol C₃H₈

Explanation:

Step 1: Write the balanced equation for the combustion of C₃H₈

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.

Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced

We will use the established molar ratio.

3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈

Answer:

Isopropyl has the specific orientation of being attached to a central carbon atom with two CH3 molecules attached (so in IUPAC naming it can become dimethylethyl), whereas propyl is three carbons all attached in a line branching off the main carbon chain, so it's two CH2 molecules and one CH3 molecule.

Explanation:

n-propane are longer chain hydrocarbon whereas isopropane is branched hydrocarbon. Isopropyl radical is more stable than n-propyl radical.

Radicals are reaction intermediates containing one unpaired electron. They are highly reactive species . The stability of radicals depends on the structure and reaction condition.

n -propyl radical is  CH₃-CH₂-CH₂·

Isopropyl radical  is written as CH₃-CH·-CH₃

The isopropyl group contains a branch in the second carbon and its makes the central carbon with secondary structure.

The stability of tertiary radicals is greater than secondary which is greater than primary. Therefore, isopropyl radical is more stable than n -propyl radical.

Find more on isopropane:

https://brainly.com/question/28755428

#SPJ2

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

Answer:an element in a chemical equation is called a subscript.

Explanation:

it represents the the number of atoms of that element present in the compound. hope this helps have a great day yall

The number at the bottom right of an element in a chemical equation is called a subscript.

Subscripts represent the number of atoms of that particular element in a molecule or formula unit. They indicate the ratio of atoms or ions present in a compound. Subscripts are written in a smaller font size and appear slightly below the element's symbol.

For example:

In the chemical compound water [tex](H_2O)[/tex],the subscript '2' indicates that there are two atoms of hydrogen (H) bonded to one atom of oxygen (O). The subscript specifies the ratio of elements in the compound, indicating that there are two hydrogen atoms for every one oxygen atom in water.

Therefore, the term subscript refers to the number on the right of an element in a chemical equation.

learn more about Subscripts here:

https://brainly.com/question/31749666

#SPJ6

Answer:

methane on the other hand is made of one carbon atom and 4 hydrogen atoms. like water, the bonds are covalent.

Liquid methane and Liquid water are both covalent compounds, thus, they both have covalent bonds in common.

Methane is a covalent compound which exists as a gas at room temperature.

Methane is composed of four hydrogen atoms and a carbon atom linked together by covalent bonds.

Water is a covalent compound which exists as a liquid at room temperature.

Water is composed of two atoms of hydrogen and one atom of oxygen linked together by covalent bonds.

Since both liquid water and liquid methane are covalent compounds, they both have covalent bonds in common.

Therefore, liquid methane and liquid water have covalent bonds in common.

Learn more about covalent bonds at: https://brainly.com/question/1853488

Answer:

Unlike other extinguishing agents - water, dry chemical, CO2, etc., a stable aqueous foam can extinguish a flammable or combustible liquid fire by the combined mechanisms of cooling, separating the flame/ignition source from the product surface, suppressing vapors and smothering. It can also secure for extended periods of time against reflash or reignition. Water, if used on a standard hydrocarbon fuel, is heavier than most of those liquids and if applied directly to the fuel surface, will sink to the bottom having little or no effect on extinguishment or vapor suppression. If the liquid fuel heats above 212ºF, the water may boil below the fuel surface throwing the fuel out of the contained area and spreading the fire. For this reason, foam is the primary fire-extinguishing agent for all potential hazards or areas where flammable liquids are transported, processed, stored or used as an energy source.

this is what I found, hope it helps

In contrast to other extinguishing agents such as water, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling, separating the flame source from the product surface, suppressing vapors, and smothering.

The term solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

It can also protect against ref lash or reignition for extended periods of time. Water is heavier than most liquids when used on a standard hydrocarbon fuel and will sink to the bottom if applied directly to the fuel surface, having little or no effect on extinguishment or vapor suppression.

If the liquid fuel heats above 212°F, water may boil beneath the fuel surface, releasing the fuel and spreading the fire.

Thus,  dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling.

To learn more about the solubility, follow the link;

https://brainly.com/question/22185953

#SPJ2

Answer:

B

Explanation:

All elements on both sides of the equation have the same amount of moles

Answer:

a. Speed up, lose

Explanation:

#CARRYONLEARNING

Answer:

b. speed up, gain

Explanation:

Answer:

Pretty sure the answer is B

Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

Answer:

170.68

Explanation:

PV=nRT or 22.4L for every mole of a gas at STP