Answer:
It would be 151.832775 because one mole is 44.0095*3.45 i hope this helps!
Explanation:
Which situation describes a reaction with a percentage yield of 100%?
Select one:
a. none of them
b. No competing reactions occur and the limiting reagent is fully consumed.
c. The amounts of reactants initially present are stoichiometric.
d. The product is more than the limiting reagent has the potential to produce.
Answer:
Explanation:
D
If 1 g of radium-226 has an activity of 1 curie, what is the activity of 2 g of radium-226? 1 curie 2 curies 4 curies 10 curies
Answer:
2 curies
Explanation:
This is actually pretty easy to explain.
The Radium-226 which is an isotope of the radium, have an activity of curie. This is basically used in radioactivity of certain elements.
As in both cases we have Radium -226 and we are only varying the mass of the Radium, then, we can just do a rule of 3 to calculate this:
1 g Ra-226 --------> 1 Curie
2 g Ra-226 --------> X Curie
Solving for X:
X = 2 g * 1 Curie / 1 g
X = 2 Curies.You can also see this by taking 2 grams of Ra per separate. On one side you have 1 g of Ra-226 and on the other side, you have another 1 g of Ra-226. Both have 1 Cury of activity. If you put both on the same side, you will have 1 Cury of 1 isotope plus 1 cury of the other isotope, final result? 2 curies.
Hope this helps
Which types of changes must follow the law of conservation of mass?
Both physical and chemical changes
Neither physical nor chemical changes
Only physical changes
Only chemical changes
Answer: both
Explanation:
write and balance the cellular respiration equation of glucose compared with the photosynthesis reaction in the terms of reactants products energy flow in the significance of each.
Answer:
Explanation:
.
If you have 15g of sodium carbonate, what
mass of sodium is present in that sample?
Answer: 6.75 g
Explanation:
Which is the balanced chemical equation showing hydrogen peroxide (H2O2) decomposing into hydrogen (H2) and oxygen (O2)? Multiple Choice H2O2 → H2 + O2 H2 + O2 → H2O2 2 H2 + O2 → 2 H2O2 2 H2O2 → 2 H2 + O2 PrevQuestion 13 of 14 Total13 of 14Visit question mapNext
Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for showing hydrogen peroxide decomposing into hydrogen and oxygen is:
[tex]H_2O_2\rightarrow H_2+O_2[/tex]
what is the name of the compoud H2Co2
a sample of nitrogen gas occupies 1.55l at 27.0c and 1.00 atm what will the volume be at -100.0c and the same pressure
V₂=0.894 L
Further explanationGiven
V₁=1.55 L
T₁=27 + 273 = 300 K
P₁=1 atm
T₂=-100+273 = 173 K
Required
The final volume(V₂)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
Input the value :
V₂=V₁T₂/T₁
V₂=1.55 x 173/300
V₂=0.894 L
Could someone please help me? You can ignore number 3
For Number 2)
THE ELEMENTS TEND TO FORM COMPOUNDS BECAUSE AOMS ARE UNSTABLE AND CAN SHARE ELECTRONS IN THIER OUTER ENERGY LEVELS .
AS WE KNOW, ATOMS OF AN ELEMENT BECOMES MORE STABLE BY LOSING , GAINING AND SHARING ELECTRONS.
Elements react with each other to complete their octet or duplet so as to become stavle in nature. For e.g. Carbon reacts with oxygen to form carbon dioxide. Carbon reacts with four molecules of hydrogen to form methane - CH4.
whats the balance to Sr + O, SrO
Answer:
SrO = Sr + O - Chemical Equation Balancer.
Explanation:
help for brainlist and extra points!!
Answer:
Explanation:
c.
How does the angle of the incoming light affect the intensity of the light that is refracted?
Answer:
A reflected ray always comes off the surface of a material at an angle equal to the angle at which the incoming ray hit the surface. In physics, you'll hear this called the law of reflection. You've probably heard this law stated as "the angle of incidence equals the angle of reflection
Explanation:
How is Muscular Strength measured and why is this important to know?
Answer:
Your ability to move and lift objects refers to muscular strength. It's measured by how much force you can exert for a short period of time and how much weight you can lift.
Explanation:
13.Which shows the order of increasing ionization energy?
a.Si, Al, Mg, Na
b.Ga, Ge, As, Se
c.Be, Mg, Ca, Sr
d.F, Cl, Br, I
What are the three energy's .
Answer:
Energy and how it can change forms. Kinetic, potential, and chemical energy.
Look at the diagram below.
+
Will this atom gain or lose electrons to achieve a stable configuration?
It will gain electrons to fill its outer shell.
It will lose electrons to be left with a full outer shell.
It depends on the situation.
It will neither lose nor gain electrons.
ASAP
Answer:
it will gain electrons to fill its outer shell
Explanation:
This element is boron which has 5 electrons.
How many grams are in 4.3 x 10 -4 moles of calcium phosphate?
Explanation:
Ca3(PO4)2 1 mole has 310.2 g
Ca3(PO4)2 4.3 × 10^-4 moles has 4.3 × 10^-4 × 310.2
= 1,333.86 × 10^-4
= 1.334 × 10^-1
OR 0.1334 g
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g
New rocks are heavier than old rocks.
Use the half-reaction method to balance the following equations :
MnO4- + Br- = MnO2 + BrO3- (Acidic Solution )
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
Further explanationGiven
MnO4- + Br- = MnO2 + BrO3-
Required
The half-reaction
Solution
In acidic conditions :
1. Add the coefficient
2. Equalization O atoms (add H₂O) on the O-deficient side.
3. Equalization H atoms (add H⁺ ) on the H -deficient side. .
4. Equalization of charge (add electrons (e) )
5. Equalizing the number of electrons and then adding the two half -reactions together
Oxidation : Br- → BrO3-
Reduction : MnO4- → MnO2
Equalization O atomsBr- + 3H2O → BrO3-
MnO4- → MnO2 + 2H2O
Equalization H atomsBr- + 3H2O → BrO3- + 6H+
MnO4- + 4H+ → MnO2 + 2H2O
Equalization of chargeBr- + 3H2O → BrO3- + 6H+ + 6e- x1
MnO4- + 4H+ + 3e- → MnO2 + 2H2O x2
Equalizing the number of electrons and then adding the two half -reactions togetherBr- + 3H2O → BrO3- + 6H+ + 6e-
2MnO4- + 8H+ + 6e- → 2MnO2 + 4H2O
Br- + 2MnO4- + 3H2O + 8H+ + 6e- → BrO3- + 2MnO2 + 6H+ + 4H2O + 6e-
Br- + 2MnO4- + 2H+ → BrO3- + 2MnO2 + H2O
Heat from the sun moves through space by the process of
es
A)
circulation.
B)
conduction
C)
convection.
D)
radiation
2
Convert -27°C to Kelvin.
Answer:
-27 C converted to Kelvin is 246.15 Kelvin.
Explanation:
Hope this helps
Answer:
246.15K
Explanation:
Formula: (-27°)C + 273.15 = 246.15K
A __________________ chemical equation shows that the same number of atoms in the reactants are also in the product.
balanced
rearranged
transferred
beautiful
what sre the group 17 elements are known as
Answer:
Halogen
Explanation:
What happens to particles when their energy levels decrease
ASAP
Answer:
The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. If it is cooled the motion of the particles decreases as they lose energy.
Explanation:
why do the properties of a material determine the use of the material?
Answer:
Matter is made up of particles whose properties determine the observable characteristics of matter and its reactivity.
Explanation:
A cylinder of an ideal gas contains 1.2 moles of gas and occupies a volume of 5.0L. If 0.5 moles of a second gas are added to the cylinder, and the cylinder is allowed to expand until it reaches the same temperature and pressure as before, what is the final volume of gas, in liters, that occupies the cylinder?
Answer:
7.08 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.2 + 0.5 = 1.7 moles
Final volume (V₂) =?
From ideal gas equation,
PV = nRT
Divide both by n
PV / n = RT
Divide both side by P
V / n = RT/P
RT/P => constant
Therefore,
V₁ / n₁ = V₂ / n₂
With the above formula i.e
V₁/n₁ = V₂/n₂
We can obtain the final volume of the gas as follow:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.7 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
5 / 1.2 = V₂ / 1.7
Cross multiply
5 × 1.7 = 1.2 × V₂
8.5 = 1.2 × V₂
Divide both side by 1.2
V₂ = 8.5 / 1.2
V₂ = 7.08 L
Therefore, the final volume of the gas is 7.08 L
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.
Answer:
[tex]1.936\times 10^{-18}\ \text{J}[/tex]
Explanation:
[tex]R_h[/tex] = Rydberg constant = [tex]2.178\times 10^{-18}\ \text{J}[/tex]
[tex]n_i[/tex] = Initial shell = 3
[tex]n_f[/tex] = Final shell = 1
We have the relation
[tex]\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}[/tex]
The energy of the photon emitted here is [tex]1.936\times 10^{-18}\ \text{J}[/tex].
The equation below represents chemical reaction that occurs in living cells. C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy How many atoms are represented in the reactants of this equation?
Answer:
36
Explanation:
There are 6 Carbon atoms, 12 Hydrogen atoms, and 18 Oxygen atoms.
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of [tex]CH_4[/tex] is burned in excess oxygen gas
Given: [tex]CH _4 +2O_2\rightarrow CO_2+2H_2O[/tex] ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] weighs = 16 g
Thus we can say:
16 g of [tex]CH_4[/tex] on combustion releases heat = 802 kJ
Thus 24.8 g of [tex]CH_4[/tex] on combustion releases =[tex]\frac{802}{16}\times 24.8=1243.1kJ[/tex]
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ