How many moles are in 175g
(Ca(NO3)2

Answer:

10⁰C

Explanation:

10⁰C is equal to 50⁰F

Answer:

407 pm

Explanation:

For any elemental face-centered cubic structure, the relationship between the edge length of the unit cell and the atomic radius of its element is:

Where L is the edge length and r is the atomic radius.

With that in mind we can calculate the edge length:

Answer:

decrease by a factor of 1.5

Answer:

1.10 g/L

Explanation:

Step 1: Calculate Henry's constant (k)

The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.

C = k × P

k = C / P

k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa

Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa

We will use Henry's law.

C = k × P

C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L

Solubility of the gas, if the temperature is held constant and pressure is increased to 150 kPa from 121 kPa, is 1.10 g/L.

Henry's law of gas states at solubility (C) of the dissolved gas is directly proportional to the partial pressure (P) of the gas.

C ∝ P

C = kP, where

k = Henry's constant

Let first we calculate the Henry's constant, when the solubility of a gas is 0.890 g/L at a pressure of 121 kPa is:

k = (0.890 g/L) / (121 kPa)

k = 7.36 × 10⁻³ g/L.kPa

Now we calculate the solubility of the gas, if the pressure is increased to 150 kPa as:

C = (7.36 × 10⁻³ g/L.kPa) (150 kPa)

C = 1.10 g/L

Hence, required solubility is 1.10 g/L.

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Answer:

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

Explanation:

The balanced reaction is:

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of each compound is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?

[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]

mass of Fe₂O₃= 6.65 grams

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

Answer: 0.0285 moles of HCl is present in given amount of solution.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

[tex]0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles[/tex]

Hence, 0.0285 moles of HCl is present in given amount of solution.

Answer:

18 moles of H₂.

Explanation:

The balanced equation for the reaction is given below:

2Al + 6HCl –> 2AlCl₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

Thus, 18 moles of H₂ were obtained from the reaction.

Answer:

c2h6o

Explanation:

find the hcf of the numbers and divide each number by the HCF eg

HCF of 4,12,2 -> 2

4÷2=2

12÷2=6

2÷2=1

therefore

c2h6o

Answer: 100.000%

Explanation:

.

Answer:

[tex]m=3.90mol/kg[/tex]

Explanation:

Hello there!

In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:

[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]

Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:

[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]

Regards!

Answer:

Accuracy decreases

Explanation:

All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.

The accuracy is how close is the measurement to the real value.

If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.

The accuracy of the determined value decreases if all measurement is done with graduated cylinders.

The accuracy is the measurement of how close the calculated value is to the real value.

When a student measures the volume with a graduated cylinder the chances of error increase.

Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.

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Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

[tex]pH=-\log [H^+][/tex]      .....(1)

Given value of pH = 1.5

Putting values in equation 1:

[tex]1.5=-\log[H^+][/tex]

[tex][H^+]=10^{(-1.5)}=0.0316M[/tex]

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex]       .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

[tex]0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol[/tex]

The chemical equation for the reaction of HCl and calcium carbonate follows:

[tex]2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2[/tex]

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, [tex]4.74\times 10^{-4}mol[/tex] of HCl will react with = [tex]\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol[/tex] of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of calcium carbonate = [tex]2.37\times 10^{-4}mol[/tex]

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

[tex]\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g[/tex]

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Answer:

3.1621 × 10²⁵ molecules

Explanation:

From the given information:

Moles of C2H8 = 52.5 moles

number of moles = mass/molar mass

molar mass of C2H8 = (6 *2) + (1*8)

= 12 + 8

= 20 g/mol

∴

52.5 moles = mass of C2H8 / 20 g/mol

mass of C2H8 = 52.5 moles × 20 g/mol

mass of C2H8 = 1050 grams

Recall that;

1 mole = 6.023 × 10²³ molecules

∴ 52.5 moles of C2H8 = (52.5 × 6.023 × 10²³) molecules

=3.1621 × 10²⁵ molecules

Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of [tex]SO_3[/tex] = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

            [tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]

I:             0.700

C:              -2x           +2x           x

E:           0.700-2x      2x            x

Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles

Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]

Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]

Molarity is calculated by using the equation:

[tex]Molarity=\frac{Moles}{Volume}[/tex]

So,

[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]

[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]

[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]

The expression of [tex]K_c[/tex] for above equation follows:

[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]

Plugging values in above expression:

[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]

Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

im missing something though

Answer:

33.4 °C

Explanation:

The final temperature of water will be the equilibrium temperature. This can be obtained as follow:

Mass of copper (M꜀) = 300 g

Initial temperature of copper (T꜀) = 285 °C

Specific heat capacity of copper (C꜀) = 0.385 J/gºC

Mass of water (Mᵥᵥ) = 1000 g

Initial temperature of water (Tᵥᵥ) = 26.5 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Equilibrium temperature (Tₑ) =?

Heat lost by copper = Heat gained by water

M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)

115.5(285 – Tₑ) = 4184(Tₑ – 26.5)

Clear the bracket

32917.5 – 115.5Tₑ = 4184Tₑ – 110876

Collect like terms

32917.5 + 110876 = 4184Tₑ + 115.5Tₑ

143793.5 = 4299.5Tₑ

Divide both side by 4299.5

Tₑ = 143793.5 / 4299.5

Tₑ = 33.4 °C

Therefore, the final temperature of water is 33.4 °C.

I am not sure abt the ans

molar mass= 88

1 molecule = 6.022×10^23

4.44 moles = 6.022×10^23×4.44/88

= 26.73768 × 10^23/88

= 0.3038372727 ×10^23

Answer:

Ionic Bond

Explanation:

The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.

Answer:

4 on the top

He in the middle

2 on the bottom

Explanation:

Correct on plato

The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

The two atoms interact with each other as shown by the equation below;

[tex]^4_2He[/tex]

where;

Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

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#SPJ5

Answer:

OH- is 1x 10^ + 3

Explanation:

- and - = +

Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

Explanation:

The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.

[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]

When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.

Hence, the expression for acid dissociation constant of this reaction is as follows.

[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]

Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Explanation:

When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.

Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.

As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.

When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.

Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Answer:

Un río aluvial es aquel en el que el lecho y las riberas están formados por sedimentos móviles y / o suelo.

Explanation:

Answer:

Explanation:

So,at STP or NTP, one mole of any gas occupies 22.4 litres of volume. To find mass,firstly we have to calculate the no. Of moles present in 11.2 litres of O2 gas which can be calculated as ;

No. Of moles = Given Volume ÷ 22.4 Litre (provided that gas is at STP)

= 11.2 Litre / 22.4 Litre

= 0.5 moles

Now, mass can be calculated by;

Mass = no. Of moles × Molecular mass

= 0.5 × 32 (Molecular mass of O2 is 32u or 32 g, if you are calculating in Grams, also called Gram Molecular Mass)

= 16 g

This is the answer

Answer:

because they were thought in college

Explanation:

hope that helps

Answer:

x~ 34.19 grams del sal o ~ 34 grams!

Explanation:

el porcentaje de masa se escribe como

% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%

aquí, el disolvente se da como 500 g de agua.

usa x en lugar de masa de sal y resuelve usando álgebra

6.4 = x / (x+ 500) * 100

0.064 = x / (x+500)

0.064 x + 32 = x

32 = x-0.064x

32 = 0.936 x

x~ 34.19 grams del sal o ~ 34 grams!

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation: