How many meters are in 5.0 cm?
500
0.050
0.0005
0.5

Answers

Answer 1

Explanation:

100cm=1m

5 cm= x

cross multiple

x=5/100

=0.05m

Answer 2

There are 0.05 meters in 5 cm. The correct option among the following is option (B).

In the metric system, a centimeter (cm) is a unit of length. It is one centimeter (1 cm = 0.01 m) in size. Small distances or measurements, such as the length, height, or width of items, are frequently measured in centimeters. Due to its practical size for many routine measurements, it is also frequently employed in scientific and mathematical computations.

In the International System of Units (SI), the meter serves as the base unit and is frequently used to measure lengths, heights, and other measurements. It serves as the basic building block for other metric units like centimeters (one meter equals one hundred centimeters) and kilometers (one kilometer equals one thousand meters).

So, to convert 5.0 cm to meters:

5.0 cm ÷ 100 = 0.05 m

Hence, 5.0 cm is equal to 0.05 meters. The correct option is (B).

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Related Questions

You walk 10 meters to class in 20 seconds , your average speed is ___ ?

Answers

2 seconds per 1 meter. (20/10=2/1)

The average speed is 1/2 m/s.

To determine the answer, we need to know about average speed.

What is average speed?

Distance covered by an object per unit time is known as average speed.

What is the mathematical formula of average speed?

Mathematically, average speed= Total distance travelled/ total time taken

What is the average speed, if I walk 10 metes in 20s?

Here, total distance travelled = 10m,

         total time taken = 20s

 Average speed = 10/20 = 1/2 m/s

Thus, we can conclude that the average speed is 1/2 m/s.

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If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?

Answers

Answer:

V=u+at

=4+4*2.5

=14m/s

Explanation:

Initial velocity =4m/s

acceleration =4m/(second) squared

time =2.5 seconds

v=u+at

v=4+4*2.5

v=14m/s

A long, thin, insulated wire carries a current I1=1A out of the plane of the paper. The wire is surrounded by a long cylinder of radius a=12cm. The cylinder carries a current I2=9A that is unformly distributed over its cross section and flows into the plane of the paper.
Find the radius r at which the amgnetic field is zero.

Answers

Answer:

The magnetic field is zero at a radius r = 4 cm.

Explanation:

The magnetic field due to the wire is given by B₁ = μ₀I₁/2πr where I₁ = current in wire = 1 A and r = distance of point where magnetic field is zero from wire.

Now, since the current is uniformly distributed in the cross section of the cylinder, its current density is constant.

So, with current I₂ = 9 A flowing in the cylinder and radius, a = 12 cm. Let I' = current at radius r where the magnetic field is zero. So,

I'/πr² = I₂/πa²

I' = I₂r²/a²

Using Ampere's Law, the magnetic field B₂ at the distance r is given by

∫B.ds = μ₀I'

∫Bdscos0 = μ₀I' (since the magnetic field is parallel to the path)

B∫ds = μ₀I'   ∫ds  = 2πr

B2πr = μ₀I'

2Bπr = μ₀I₂r²/a²

B₂ = μ₀I₂r/2πa²

So, when the net magnetic field is zero, B₁ = B₂

So,  μ₀I₁/2πr = μ₀I₂r/2πa²

I₁/r = I₂r/a²

I₁/I₂ = r²/a²

r² = I₁/I₂a²

taking square root of both sides,

r = a√(I₁/I₂)

substituting the values of the variables, we have

r = 12√(1/9)

r = 12/3

r = 4 cm

The magnetic field is zero at a radius r = 4 cm.

Drive-reduction theory states that motivation comes from a combination of both reinforcement and drive.
ОА.
True
OB. False

Answers

The correct answer is A) True

A pendulum is 0.760 m long, and the bob has a mass of 1,00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. The tension is greater than the weight of the bob because Multiple Choice 0 its horizontal component is increasing from zero. O the bob has a downward acceleration, so the net Fy must be downward O O the bob has zero acceleration. O ( the bob has an upward acceleration, so the net Fy must be upward Required information A pendulum is 0.760 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. What is the tension in the string at the bottom of the swing?

Answers

Answer:

  T = 13.17 N

the correct one is there is a digested centripetal acceleration towards upward

Explanation:

For this exercise we can use Newton's second law at the bottom of the pendulum's path

we will assume that the upward direction is positive

              T - W = m a

in this case it is describing a circle the acceleration is central

              a = v² / R

where the radius of the trajectories equals the length of the pendulum

             R = L

we substitute

            T = mg + m v² / L

             T = m (g + v² / L)

When reviewing the different statements, the correct one is there is a digested centripetal acceleration towards upward

let's calculate the tension of the rope

             T = 1 (9.8 + 1.6 2 / 0.760)

             T = 13.17 N

Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum). How far (in meters) into space did the signal travel during the first 10 minutes?

Answers

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

Given three vectors A = 24i + 33j, B = 55i - 12j and C = 2i + 43j (a) Find the magnitude of each vector. (b) Write an expression for the vector difference A - C. (c) Find the magnitude and direction of the vector difference A-B. (d) In a vector diagram show vector A + B, and A - B, and also show that your diagram agrees qualitatively with your answer.

Answers

Answer:

(a) , .  and .

(b)[tex]\vec A - \vec C=22 \hat i -10 \hat j[/tex].

(c)[tex]|\vec A - \vec B|=63.13[/tex] and the direction [tex]\theta =[/tex] 124.56°.

Explanation:

Given that,

,

and

[tex]\vec {C}=2 \hat i +43 \hat j[/tex]

(a) The magnitude of a vector is the square root of the sum of the square of all the components of the vector, i.e. for a ,.

So, the magnitude of the is

[tex]|\vec A|=\sqrt {24^2+ 33^2}[/tex]

[tex]\Rightarrow |\vec A|=\sqrt {1665}[/tex]

.

The magnitude of the is

[tex]|\vec B|=\sqrt {55^2+ (-12)^2}[/tex]

[tex]\Rightarrow |\vec B|=\sqrt {3169}[/tex]

.

And, the magnitude of the is

[tex]|\vec C|=\sqrt {2^2+ 43^2}[/tex]

[tex]\Rightarrow |\vec C|=\sqrt {1853}[/tex]

.

(b) The difference between the two vectors is the difference between the corresponding components of the vectors. So, the required expression of is

[tex]\vec A - \vec C=(24 \hat i +33 \hat j) - (2 \hat i +43 \hat j)[/tex]

[tex]\Rightarrow \vec A - \vec C=24 \hat i +33 \hat j - 2 \hat i -43 \hat j[/tex]

[tex]\Rightarrow \vec A - \vec C=22 \hat i -10 \hat j[/tex]

(c) The expression of is

[tex]\vec A - \vec N=(24 \hat i +33 \hat j) - (55 \hat i -12 \hat j)[/tex]

[tex]\Rightarrow \vec A - \vec B=24 \hat i +33 \hat j - 55\hat i +12 \hat j[/tex]

[tex]\Rightarrow \vec A - \vec B=-31 \hat i +45 \hat j\;\cdots (i)[/tex]

The magnitude of is

[tex]|\vec A - \vec B|=\sqrt {(-31)^2+55^2}[/tex]

[tex]\Rightarrow |\vec A - \vec B|=\sqrt {3986}[/tex]

[tex]\Rightarrow |\vec A - \vec B|=63.13[/tex]

Now, if a vector [tex]\vec V= -\alpha \hat i +\beta \hat j[/tex] in 3rd quadrant having direction [tex]\theta[/tex] with respect to [tex]\hat i[/tex] direction, than

in the anti-clockwise direction.

Here, from equation (i), for the vector [tex]\vec A - \vec C[/tex], [tex]\alpha=31[/tex] and [tex]\beta=45[/tex].

[tex]\Rightarrow \theta = \pi-\tan ^{-1}\left(\frac {45}{31}\right)[/tex]

180°-55.44° [as \pi radian= 180°]

124.56° in the anti-clockwise direction.

(d) Vector diagrams for [tex]\vec A +\vec B[/tex] and [tex]\vec A - \vec B[/tex] has been shown  

in the figure(b) and figure(c) recpectively.

Vector [tex]\vec A - \vec B[/tex] is in 3rd quadrant as calculated in part (c).

While Vector [tex]\vec A +\vec B=(24 \hat i +33 \hat j)+(55 \hat i -12 \hat j)[/tex]

[tex]\Rightarrow \vec A +\vec B=79 \hat i +21 \hat j[/tex], which is in 1st quadrant as both the components are position has been shown in figure(b).

(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?

Answers

Answer:

The new period will be reduced by 50%

Explanation:

The period of pendulum is given by;

[tex]T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}[/tex]

When the length is decreased by 25%, the new length L₂ is given by;

L₂ = 25/100(L₁)

L₂ = 0.25L₁

[tex]\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T[/tex]

Thus, the new period will be reduced by 50%

11. एक समान चुम्बकीय क्षेत्र में लम्बवत प्रवेश करने वाले किसी आवेशित कण द्वारा प्राप्त वृत्तीय पथ की
7 त्रिज्या का सूत्र ज्ञात कीजिए।
2
Find the formula of radius obtained by a charged particle entering perpendicularly
in a uniform magnetic field.​

Answers

Answer:

r=mv/Be

Explanation:

If a positive charge enters a magnetic field at 90 degrees the charge is deflected in a circular path by a force that acts perpendicular to it in line with Flemings right-hand rule

to derive the radius of the path of the charge we apply

F= mv^2/r=Bev

where

m= mass of the electronic charge

e=charge

B=magnetic field

v=average speed

r=radius

 

rearranging we have

r=mv^2/Bev

r=mv/Be

A sports car starts from rest at an intersection and accelerates toward the east on a straight road at 9.0 m/s2. Just as the sports car starts to move, a bus traveling east at a constant 16 m/s on the same straight road passes the sports car. When the sports car catches up with and passes the bus, how much time has elapsed

Answers

Answer:

3.6s

Explanation:

Have In mind that the sports car will catch up with bus when their positions are equal

So

S = ut + 1/2at²

where u is initial velocity

For sports car we have

x = 0 + 1/2 x 9 x t²

For Bus

S= 16ts + 0

Equating the two

1/2 x 9 x t² = 16t

4.5 x t = 16

t = 3.6s


65°F to degrees Celsius​

Answers

Answer:

18.3 C

Explanation:

Answer: 55/3 °C

Explanation:

Formula:

C=5/9(F-32)

Given:

F=65

Solve:

C=5/9(F-32)

C=5/9(65-32)

C=5/9(33)

C=55/3

Father drove 176 km in 7 hours. For the first 92 km, he spent
for 4 hours. What was his average speed for the remaining
journey?
km/h

Answers

Answer:

28km/h

Explanation:

92km = 4 hours

176 - 92 = 84

84km = 3 hours

84/3 = 28

28km/h

Hopefully this helps you :)

pls mark brainlest ;)

If you push a book 1.5 m across a table using a constant force of 10.0 N, how much work do you
do on the book?

Answers

Answer:

The answer is

15.0 J

Explanation:

To calculate the work done by a body we use the formula

work done = force × distance

From the question

force = 10 N

distance covered = 1.5 m

So the work done is

work done = 10 × 1.5

We have the final answer as

15.0 J

Hope this helps you

A watermelon is dropped from the edge of the roof of a build- ing and falls to the ground. You are standing on the sidewalk and see the watermelon falling when it is 30.0 m above the ground. Then 1.50 s after you first spot it, the watermelon lands at your feet. What is the height of the building

Answers

Answer:

The hight of the building is 38.16 m

Explanation:

These two pieces of information given, first, the watermelon is 30 m  above the ground and after 1.50 s the watermelon has been spotted. Now we are required to find the height of the building.

Use the below formula to find the height of buildings.

S = ut + ½ gt^2

30  =1.5u + (1/2) × 9.8 (1.5)^2

u = 12.65 m/sec

v^2 – u^2 = 2gs

(12.65)^2 = 2×9.8 s’

S’ = 8.16 m  

h = s + s’

h = 30 + 8.16 = 38.16 m

The hight of the building is 38.16 m.

The height of the building is 38.16 m.

Given data:

The height above the ground is, h = 30.0 m.

The time interval after observation of first spot is, t = 1.50 s.

We need to find the height of building. And since two pieces of information given, first, the watermelon is 30 m  above the ground and after 1.50 s the watermelon has been spotted. So, using the second kinematic equation of motion as,

[tex]h = ut + \dfrac{1}{2}gt^{2}[/tex]

Here, u is the initial speed. Solving as,

[tex]30 = (u \times 1.50) + \dfrac{1}{2} \times 9.8 \times (1.50)^{2}\\\\u =12.65 \;\rm m/s[/tex]

Now landing distance (s') is calculated using the third kinematic equation of motion as,

[tex]v^{2} =u^{2}+2(-g)s\\\\0^{2} =12.65^{2}+2(-9.8)s\\\\s = 8.16 \;\rm m[/tex]

Then the height of building is given as,

H = h + s

H = 30 m + 8.16 m

H = 38.16 m

Thus, we can conclude that the height of the building is 38.16 m.

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If you walk 5 km north and then 12 km east. Your resultant displacement is____.a. magnitude: 1.1km; direction: 53.1 degrees east of north.b. magnitude: 2.00; direction: 53.1 degrees east of north.c. magnitude: 2.00; direction: 36.9 degrees east of north.d. magnitude: 1.1km; direction: 36.9 degrees east of north.

Answers

Answer:

Resultant = 13km

Direction = 67.38° East of North

Explanation:

Given the following :

5km North ; 12km East

Resultant Displacement (r) :

r² = 5² + 12²

r² = 25 + 144

r² = 169

r = √169

r = 13

Direction:

Tangent = opposite / Adjacent

Tanθ = opposite / Adjacent

Opposite = 12 ; adjacent = 5

Tanθ = (12/5)

Tanθ = 2.4

θ = tan^-1(2.4)

θ = 67.38° east of north

27.
In a graph showing how temperature of a material changes over time, temperature
change is the:
A. dependent variable
C. variable with the smallest range
B. independent variable
D. variable with the largest range

Answers

Answer:

A. Dependent variable

Explanation:

In a graph showing how temperature of a material changes over time, temperature is taken on y-axis and time is taken on x-axis. It shows how temerature altered as the time changes.

In temperature-time graph, temperature is directly dependent on time. With the increase in time, temperature rises, falls or remains constant. It implies that temperature is dependent variable that depend on time.

Hence, the correct option is (A).

Using the equation for Impact, can you explain the following:
Why are car steering rods designed to collapse?
Why are highway guard rails designed to crumple up on impact?
Why are traffic saftey barrels filled with water or sand?

Answers

Explanation:

Equation for Impact

FΔt = ΔP,

F = force

Δt  = Impact of time

ΔP = Change in momentum

Car steering is engineered to fail in order to maximize the time of contact and hence reduce the initial impact and mitigate the damage incurred.

Road guard railing crumple on contact to maximize impact time and hence reduce impact intensity and mitigate damage.

Road safety containers are loaded with liquid or sand as they improve the period of impact.

The x vector component of a displacement vector has a magnitude of 94.8 m and points along the negative x axis. The y vector component has a magnitude of 149 m and points along the negative y axis. Find (a) the magnitude and (b) direction of . Specify the direction as a positive angle with respect to the negative x axis.

Answers

Answer:

We use pythagorean theorem

So that

r = √(x² + y²)

r = √(94.8)² + (-149)² )

r =√ 9682.6 + 22201

= 178.6

direction we use

စ = tan^-1(98.4/149)

= tan^-1 (0.6604)°

Two cylindrical resistors are made from the same material. The shorter one has a length LL and diameter DD . The longer one has a length 16L16L and diameter 4D4D . How do their resistances compare? The resistance of the longer resistor is four times the resistance of the shorter resistor. The resistance of the longer resistor is twice the resistance of the shorter resistor. The resistance of the longer resistor is the same as the resistance of the shorter resistor. The resistance of the longer resistor is half the resistance of the shorter resistor. The resistance of the longer resistor is a quarter of the resistance of the shorter resistor.

Answers

Answer:

The resistance of the longer resistor is a quarter of the resistance of the shorter resistor.

Explanation:

If Two cylindrical resistors are made from the same material, then their resistivity will be the same.  Formula for calculating resistivity of a material is expressed as;

[tex]\rho = \frac{RA}{L} \ where \ A = \frac{\pi d^2}{4}[/tex] where;

R is the resistance

A is the cross sectional area of the material

L is the length of the material

For the shorter cylinder:

Length = L

diameter = D

[tex]\rho = \dfrac{R_s(\frac{\pi D^2}{4})}{L} \\\\\rho = \dfrac{R_s{\pi D^2}}{4L}[/tex]

For the longer cylinder:

Length = 16L

diameter = 4D

[tex]\rho = \dfrac{R_l(\frac{\pi (4D)^2}{4})}{16L} \\\\\\\rho = \dfrac{R_l(\frac{\pi (16D^2)}{4})}{16L} \\\\\rho = \dfrac{R_l{16\pi D^2}}{16L}\\\\\rho = \dfrac{R_l{\pi D^2}}{L}[/tex]

Since their resistivity are the same then;

[tex]\dfrac{R_s{\pi D^2}}{4L} = \dfrac{R_l{\pi D^2}}{L} \\\\ \dfrac{R_s}{4} = {R_l} \\\\R_s = 4R_l\\\\R_l = \frac{R_s}{4}[/tex]

Hence the resistance of the longer resistor is a quarter of the shorter resistor.

An object, initially at rest, moves 250 m in 17 s. What is its acceleration?

Answers

Answer:

1.73 m/s²

Explanation:

Given:

Δx = 250 m

v₀ = 0 m/s

t = 17 s

Find: a

Δx = v₀ t + ½ at²

250 m = (0 m/s) (17 s) + ½ a (17 s)²

a = 1.73 m/s²

The acceleration of this object is 1.730 meter per seconds square.

Given the following data:

Initial velocity = 2.5 m/s (since the object is starting from rest).Time = 17 seconds.

To find the acceleration of this object, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S = ut + \frac{1}{2} at^2[/tex]

Where:

S is the displacement or distance covered.u is the initial velocity.a is the acceleration.t is the time measured in seconds.

Substituting the given values into the formula, we have;

[tex]250 = 0(17) + \frac{1}{2} (a)(17^2)\\\\250 = \frac{1}{2} (289)a\\\\250 = 144.5a\\\\a = \frac{250}{144.5}[/tex]

Acceleration, a = 1.730 [tex]m/s^2[/tex]

Therefore, the acceleration of this object is 1.730 meter per seconds square.

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You are jogging with a velocity of 2 meters/second to the west, when you feel thirsty and stops to drink water after 5 seconds. First find your velocity the moment you stopped running. Then, find your acceleration during that motion. What are the units for acceleration? What is the direction of acceleration in this motion? Show your work.

Answers

Answer:

The velocity when the runner stopped is v =0 m/s

The acceleration is [tex]a = 0.4 \ m/s [/tex]

Explanation:

From the question we are told that

The initial velocity is [tex]u = 2 \ m/s[/tex]

The time taken is [tex]t = 5 \ s[/tex]

Generally from the question we are told that the person stopped running so the person velocity at that moment is v =0 m/s

Now the acceleration is mathematically represented as

[tex]a = \frac{v - u}{t}[/tex]

=> [tex]a = \frac{0 - 2}{5}[/tex]

=> [tex]a = 0.4 \ m/s [/tex]

Calculate the average speed 

1) between 0 min and 3 min.


2) between 3 min and 5 min. 



3) between 5 min and  10 min 


4) between 0 min and 10 min​

Answers

Answer:

000000000000000000000000000

PLZ PLZ PLZ I VOTE BRAINLY PLZPLZPLZ what is the theory of an atom created by a Dr. VAN C.

Answers

Answer: Bohr developed the Bohr model of the atom, in which he proposed that energy levels of electrons are discrete and that the electrons revolve in stable orbits around the atomic nucleus but can jump from one energy level (or orbit) to another. ... During the 1930s Bohr helped refugees from Nazism.

What the answers due in 2 min

Answers

Hello ┬┴┬┴┤◕3◕)づ├┬┴┬┴

The answer is 3 m

the gap in between 4s and 6s is 5s

you follow your finger up to the purple like, and follow the purple line in a straight line to the left. It ends at 3m and that is your answer.

Which of the following is not one of the emotional expressions that are universally recognized?
OA. Happiness
OB. Disgust
OC. Sadness
OD. Love
HELPP!

Answers

Answer:

B

Explanation:

The answer should be B.

A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min until you find a gas station. (A) What is the displacement of the total trip? (B) How long does the entire trip take? (C) What is the average velocity of the entire trip?

Answers

Answer:

A- 12 km

B- 42 minutes

C- 17.14 km per hour

Explanation:

A- The displacement of the total trip is 12 kilometers, which emerges by adding the 10 kilometers traveled by car to the 2 kilometers traveled on foot.

B- The trip, in total, took 42 minutes, which arises from adding the 30 minutes of the journey on foot, plus 12 minutes of travel by car at 72 km / h (72/60 x 10 = 12).

C- While 12 km were covered in 42 minutes, the average speed of the trip was 17.14 km / h. This arises from the following calculation:

42 = 12

60 = X

(60 x 12) / 42 = X

17.14 = X

Why is it important not to present a biased argument as a public speaker?
A.
Because it is unconvincing
B.
Because it is immoral
C.
Because it is unfair
D.
Because it is pointless

Answers

Answer:

Explanation:

a) because it's immoral as you're trying to convince people of your views when you should be giving both sides of the story so people are able to come up with their own opinions on what you're talking about

A ball with mass kg is thrown upward with initial velocity m/s from the roof of a building m high. Neglect air resistance. Use m/s2. Round your answers to one decimal place. (a) Find the maximum height above the ground that the ball reaches. meters (b) Assuming that the ball misses the building on the way down, find the time that it hits the ground. s

Answers

Answer:

Explanation:

The question is incomplete. Here is the complete question.

A ball with mass m kg is thrown upward with initial velocity 22 m/s from the roof of a building 17 m high. Neglect air resistance. Use g=9.8 m/s2. Round your answers to one decimal place. (a) Find the maximum height above the ground that the ball reaches. xmax= meters (b) Assuming that the ball misses the building on the way down, find the time that it hits the ground.

a) Using the equation of motion formula;

v² = u²+2gH where;

u is the initial velocity

v is the final velocity

theta is the angle of launch

g is the acceleration due to gravity.

H is the maximum height reached by the ball

Since the ball is thrown upwards, the acceleration due to gravity will be negative. The equation then becomes;

v² = u²-2gH

Given

v = 0m/s

u = 22m/s

g = 9.8m.s²

0² = 22²-2(9.8)H

-22² = -19.6H

H = -22²/-19.6

H = 24.69m

If the biuliding is 17m high, the maximum height above the ground that the ball reaches will be;

Hmax = 24.69+17

Hmax = 41.69m

b) The time it takes to hit the ground can be expressed using the formula

v = u-gt

0 = 22-9.8t

-22 = -9.8t

t = -22/9.8

t = 2.45secs


A stone is thrown vertically downward with an initial speed of 12.0 m/s from the top of a
building. The stone takes 1.54 s to reach the ground.

Answers

The question is incomplete; However, the height from which the stone is thrown is most likely to be what's required of the question

Answer:

See Explanation

Explanation:

Given

[tex]Initial\ Speed, u = 12.0m/s[/tex]

[tex]Time, t = 1.54\ s[/tex]

Required

Determine the height

This question will be answered using the following equation of motion;

[tex]S = ut + \frac{1}{2}gt^2[/tex]

Take g as 9.8

This gives:

[tex]S = 12 * 1.54 + \frac{1}{2} * 9.8 * 1.54^2[/tex]

[tex]S = 12 * 1.54 + \frac{1}{2} * 9.8 * 2.3716[/tex]

[tex]S = 18.48 + 11.62084[/tex]

[tex]S = 30.10084[/tex]

[tex]S = 30.1\ m[/tex] (Approximated)

Hence; Height = 30.1m

what are two examples of population distribution?

Answers

Three basic types of population distribution within a regional range are (from top to bottom) uniform, random, and clumped.
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