How many liters of C3H6O are present in a sample weighing 25.6 grams?

Answer:

P = 5.70 atm

Explanation:

Use PV = nRT

P(1.52 L) = (0.52 moles)(0.0821)(203 K)

P = 5.701628947 atm

The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?

Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Explanation:

Given: [tex]Mass_1[/tex] = 1.04 g,      [tex]V_{1}[/tex] = 872 mL

[tex]Mass_2[/tex] = 2.08 g,                [tex]V_{2}[/tex] = ?

As molar mass of chlorine is 35.5 g/mol.

Number of moles is the mass of a substance divided by its molar mass.

Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]

Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.

[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]

Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]

Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Answer:

Molarity = 0.06 mol/L

Molality = 0.063

Explanation:

Complete question

A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices that the volume of the solvent does not change when the styrene dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits

Solution

We must to know:

Molarity is equal to no. of moles divided by volume of solution

No. of moles = Mass/Molecular Mass

No. of moles of C8H8 = 1.5/104 = 0.0144

Molarity = 0.0144/225 = 0.06 mol/L

Molality = no. of moles / mass of solvent  

Substituting the given values, we get -  

Density = mass / V  

Mass = density  x V

1.02 * 225  

= 229.5 g  

Molality = 0.0144 / 229.5  

0.063

The gravitational pull of the Sun keeps them in their orbits. The gravitational pull of the Sun and surrounding stars combined is most likely what gives the Oort cloud its spherical shape.

The Oort Cloud is a spherical layer of ice objects that is thought to be located between 2,000 and 100,000 astronomical units (AU) from our Sun, a star.

The Oort cloud, so named after the Dutch astronomer Jan Oort who first confirmed its existence, is a collection of objects with a combined mass estimated to be 10-100 times that of Earth that are less than 100 km (60 miles) across and maybe trillions in number.

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Answer: Limitations to population growth are either density-dependant or density-independent. Density-dependent factors include disease, competition, and predation. Density-dependant factors can have either a positive or a negative correlation to population size.

Explanation:

Answer:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to  write the chemical equation for this reaction as shown below:

[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]

Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Regards!

Answer:

the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Explanation:

Given the data in the question;

[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄  [tex]CaY^{2-[/tex]

Formation constant Kf

Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰

Now,

[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35

so the equilibrium is;

[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄  [tex]CaY^{2-[/tex] + 4H⁺

Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex]     { 1 mol [tex]Ca^{2+[/tex]  reacts with 1 mol [tex]H_4Y[/tex]  }

so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x

∴

[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄  [tex]CaY^{2-[/tex]

x        + x         0.010-x

since Kf is high, them x will be small so, 0.010-x is approximately 0.010

so;

Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) =  [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] )  = 5.0 × 10¹⁰

⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] )  = 5.0 × 10¹⁰

⇒ 0.010 / ( [x][ 0.35 × x] )  = 5.0 × 10¹⁰

⇒ 0.010 / 0.35x²  = 5.0 × 10¹⁰

⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 5.7142857 × 10⁻¹³

⇒ x = √(5.7142857 × 10⁻¹³)

⇒ x = 7.559 × 10⁻⁷

Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Answer:

A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.

Answer: The pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Explanation:

According to the ideal gas equation:'

[tex]PV=nRT[/tex]

P = Pressure of the gas = ?

V= Volume of the gas  

T= Temperature of the gas = [tex]22.165^0C=(273+22.165)K=295.165K[/tex]  (0°C = 273 K)

n= moles of gas =  [tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]

R= Value of gas constant = 0.0821 Latm/K mol

[tex]P=\frac{mRT}{MV}[/tex]       as [tex]Density=\frac{mass}{Volume}[/tex]

[tex]P=\frac{dRT}{M}[/tex]    where d is density

[tex]P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm[/tex]

Thus  pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Answer:

The moon

Explanation:

The answer is A; Sorry i put the wrong answer by accident. I was trying to get to another question.

Give the answer below brainliest!!!

A. The moon influences the air movement

Answer: the orbital with a hauny dump bell shape is the p- orbital.

Explanation:

An orbital can be defined as part of the nucleus of an atom that consists of an electron of maximum given energy. The shape of this part gives the shape of the orbitals. There are different types of orbitals which include:

--> s-orbitals: This is the type of orbital in which the probability of finding electron is the same in all directions usually at a given distance form the nucleus. Therefore the s-orbitals are SPHERICAL in shape about the nucleus and are non- directional.

--> d-orbitals: This is said to have a clover shape. This is because the electron is pushed out four times during the rotation when an opposite spin proton aligns gluons with three spin-aligned protons.

--> p-orbitals: This is said to have a DUMP-BELL shape. This is because there are three similar p-orbitals which are arranged mutually at right angles to each other along x,y, and z axes. All the three p-orbitals are of the same energy level.

Explanation:

It's argon

As argon has atomic number 18 so it's configuration is

1s2, 2s2, 2p6,3s2, 3p6

Hope it will help :)❤

The given electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).

Each number and letter in the electron configuration corresponds to a specific electron orbital and the number of electrons present in that orbital.

In this case, the electron configuration indicates that:

The first shell (n=1) has 2 electrons in the 1s orbital.

The second shell (n=2) has 2 electrons in the 2s orbital and 6 electrons in the 2p orbital.

The third shell (n=3) has 2 electrons in the 3s orbital and 6 electrons in the 3p orbital.

By adding up the total number of electrons (2 + 2 + 6 + 2 + 6), we find that the configuration represents 18 electrons. The element that has 18 electrons is argon, which has an atomic number of 18.

Therefore, the electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).

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Answer:

Fe(NO₃)₃ = 0.23; FeCl₃ = 0.34

Explanation:

Mass fraction is defined as the ratio between the mass of iron in 1 mol of the compound and the mass of the complete compound.

In Fe(NO₃)₃ there is just 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 241.86g/mol. Thus, mass fraction is:

55.845g/mol / 241.86g/mol =

In FeCl₃ there is 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 162.2g/mol. Thus, mass fraction is:

55.845g/mol / 162.2g/mol =

A major drawback of using fuel cells in a car is a lack of hydrogen filling stations.

A fuel cell is an electrochemical device that converts the energy stored in a fuel, typically hydrogen, directly into electrical energy.

One significant disadvantage of using fuel cells in a car is the scarcity of hydrogen filling stations.

While fuel cell technology has several advantages, including increased efficiency and lower emissions, the infrastructure for producing, transporting, and storing hydrogen is currently limited, making it difficult to refuel fuel cell vehicles on the road.

Because of this limitation, fuel cell vehicles are less suitable for long-distance travel and have a limited market penetration.

Thus, the answer is "a lack of hydrogen filling stations".

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Answer:

its A trust!!!!!

Explanation:

Answer:

5.6 mol

Explanation:

n = N/NA

n: number of moles

N: number of particles

NA: Avogadro's constant

n = 3.4×10²⁴/6.02×10²³ mol^-1 = 5.6 mol

Answer:

And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH .

Explanation:

So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.

Answer:

The total energy absorbed is 32.171 kilojoules.

Explanation:

The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:

[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)

Where:

[tex]m[/tex] - Mass of the ice, in kilograms.

[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.

[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.

[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.

[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.

[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.

[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.

[tex]Q[/tex] - Total energy absorbed, in kilojoules.

If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:

[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]

The total energy absorbed is 32.171 kilojoules.

Answer:

79.1g of weak base must be combined with 56.0g of conjugate acid

Explanation:

that is 1.00 M in the weak base?

The weak base is C5H5N with a pKa of 5.17 (Ka=6.7×10-6)and a desire pH of 5.63

The equilibrium of the weak base is with the bromide salt of the conjugate acid is:

C5H5N(aq) + H2O(l) + Br- ⇄ C5H5NHBr(aq) + OH-(aq)

Where Kb = Kw / Ka = 1x10⁻¹⁴ / 6.7x10⁻⁶

Kb = 1.49x10⁻⁹ is defined as:

Kb = 1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

Where [OH-] = 10^-(14- pH) = 10^-(14- 5.63) = 4.255x10⁻⁹M

[C5H5N] = 1.00M

Replacing:

1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

1.49x10⁻⁹ = [C5H5NHBr] [4.255x10⁻⁹M] / [1.00M]

[C5H5NHBr] = 0.35M

In 1L the moles of C5H5NHBr are 0.35 moles

Mass C5H5NHBr: 160.0118g/mol

0.35 moles * (160.0118g / mol) =

56.0g of C5H5NHBr are necessaries

The mass of C5H5N is -79.1g/mol-:

1.00moles * (79.1g/mol) =

Answer:

Precise but not accurate.

Explanation:

We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.

However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).

Answer: Biomass, Nuclear and Gas are the three forms of non- renewable energy.

Explanation:

Answer:

1. 2.510kJ  

2. Q = 1.5 kJ

Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

[tex]1cal=4.184J\\\\1kJ=1000J[/tex]

Then, we perform the conversion as follows:

[tex]600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ[/tex]

2. Here, we use the general heat equation:

[tex]Q=mC(T_2-T_1)[/tex]

And we plug in the given mass, specific heat and initial and final temperature to obtain:

[tex]Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ[/tex]

Regards!

Answer:

The lowest natural temperature ever directly recorded at ground level on Earth is −89.2 °C

-273.144 degrees celsius. This is close to 'absolute zero', which is equal to -273.15 degrees celsius

Explanation:

Answer:

3s and 3p

Explanation:

From the question given above, the following data were obtained:

Electronic configuration =>

1s² 2s²2p⁶ 3s²3p⁴

Location of valence electron =?

From the electronic configuration given above, we can see clearly that the atom has three (3) shells.

Valence electron(s) are located at the outer most shell of an atom.

The outer most shell of the atom above is 3s and 3p.

Therefore, 3s and 3p will contain the valence electron(s)

Answer:

D

Explanation:

hope this helped and sorry if it didn't but I wish you luck:D

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

Where ΔS is change in entropy = 200J/K

n are moles = 20.0mol

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

Answer:

In these lessons, students become familiar with the four key periods of growth and human development: infancy (birth to 2 years old), early childhood (3 to 8 years old), middle childhood (9 to 11 years old), and adolescence (12 to 18 years old).

Answer:

Explanation:

The Chemical Equation for each one of these compounds would be the following

Sodium Chloride: NaCl  

This compound contains 1 Sodium atom and 1 Chlorine atom

Sodium Oxide: Na₂O

This compound contains 2 Sodium atoms and 1 Oxygen atom.

Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.

These planets are Mercury and Venus

Answer:

Hydrogen

Explanation:

Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).

Answer:

Hydrogen

Explanation:

Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).