The question is incomplete, the complete question is;
One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO How many grams of NO and of H20 form? Enter your answers numerically separated by a comma. 4NH3(g) +502(g)------->4NO(g)+6H2O(g)
In a certain experiment, 1.10 g of NH3 reacts with 2.02 g of O2. How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures.
Answer:
Mass of excess ammonia 0.034 g of ammonia
Mass of water formed= 1.37g
Mass of NO formed = 1.50g
Explanation:
The limiting reactant is the reactant that yields the least number of moles of product.
For NH3, molar mass of ammonia = 17g mol-1
Number of moles of ammonia reacted= 1.10g/17 gmol-1 = 0.065 moles of ammonia
According to the reaction equation;
4 moles of ammonia yields 4 moles of NO
Hence 0.065 moles of ammonia will yield 0.065 ×4/4 = 0.065 moles of NO
For oxygen, molar mass of oxygen gas = 32gmol-1
Number of moles of oxygen gas= 2.02g/32gmol-1 = 0.063 moles of oxygen
From the reaction equation;
5 moles of oxygen gas yields 4 moles of NO
0.063 moles of oxygen will yield 0.063 ×4 /5 = 0.050 moles of NO
Hence oxygen is the limiting reactant and ammonia is the excess reactant.
Amount of excess ammonia = Amount of ammonia - amount of oxygen
Amount of excess ammonia= 0.065-0.063= 2×10^-3 moles
Mass of excess ammonia = 2×10^-3 moles × 17 gmol-1 = 0.034 g of ammonia
Mass of NO formed is obtained from the limiting reactant. Since molar mass of is 30gmol-1. Then mass of NO formed = 0.050 moles of NO × 30gmol-1 = 1.50 g of NO
For water;
5 moles of oxygen yields 6 moles of water
Hence 0.063 moles of oxygen yields 0.063 × 6/5 = 0.076 moles of water
Molar mass of water = 18gmol-1
Hence mass of water = 0.076 moles × 18gmol-1 = 1.37g of water
MnBr2 molecular or ionic:
name:
molecular or ionic
Answer: Manganese(II)bromide
Explanation:
Because it is a chemical compound composed of manganese and bromine
How many carbon atoms are represented by the model below
A) 0
B) 3
C) 2
D) 1
Answer:
Option (B) 3.
Explanation:
In the model represented above, the two extreme represent carbon atoms since no other group are attached to it. The joint at the middle also represent carbon atom.
Thus, we can write a more simplify illustration for the model above as
C—C—C
From the above illustration, we can see that the model contains 3 carbon atom.
What is a rate law?
A. An equation that relates the rate of a reaction to the equilibrium
position
B. An equation that relates the reaction rate to the concentrations of
the reactants
C. An equation that relates the rate constant to the temperature of a
reaction
D. An equation that relates the concentrations of reactants to the
rate constant
Answer:
B
Explanation:
The rate law is a way for us to measure the rate of a given reaction by comparing it to the concentration of the reactants. Based on the mole ratios of the reactants, we can hypothesize that adding more reactant will speed up the rate of reaction due to the simple principle that if there is more of an opportunity for molecules or atoms to collide, then the rate of reaction will be faster. Hope that helps :)
A rate law is an equation that relates the reaction rate to the concentrations of the component reactants.
Rate lawsIn chemistry, rate laws are mathematical expressions that relate the rate of a reaction to the concentrations of the component reactants in the reaction.
For example, consider the following reaction:
A + B -----------> C + D
The rate law for the reaction is given as:
Rate = k[tex][A]^m[B]^n[/tex] where k = rate constant and m/n = order of reactions.
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What is the rate constant of a reaction if rate = 1.5 (mol/L)/s, [A] is 1 M, [B] is
3 M, m = 2, and n = 1?
k=
rate
[A]" [B]"
A. 0.17
B. 13.5
C. 0.5
D. 4.5
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Rate Constant.
Here, the "K" is the Rate Constant.
so the ANSWER IS C.) 0.5
The rate of constant is 0.5.
The answer is option C.
How do find the rate of constant?To determine the fee regulation from a desk, you have to mathematically calculate how differences in molar concentrations of reactants affect the response charge to parent out the order of every reactant. Then, plug in values of the response charge and reactant concentrations to discover the particular rate constant.
What's the rate of constant?The particular rate constant is the proportionality steady touching on the rate of the reaction to the concentrations of reactants. The fee regulation and the unique charge constant for any chemical response need to be decided experimentally. The price of the fee regular is temperature-established.
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Identify the type of solid for AgCl. Identify the type of solid for AgCl. metallic atomic solid nonbonding atomic solid molecular solid ionic solid networking atomic solid
Silver chloride (AgCl) is a crystalline solid substance that is composed of silver and chloride ions. AgCl is an ionic solid. Thus, option D is correct.
What are ionic solids?Ionic solids are substances that show the properties of solid matter and have ionic, positive, and negative charges in them. They are linked together by the attraction of the opposite charges.
The silver metal in the molecule has a positive charge and the chloride ions are negative in charge making them establish an ionic bond.
The solid molecule is held together by ionic bonds and not the covalent or other metallic bonds. The cations and anions of AgCl are linked together by the electrostatic forces that make their structure appear strong and brittle.
Therefore, AgCl has been known as an ionic solid.
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how many moles of a solute is present in 4.00L of an 8.30M solution
Answer:
The number of moles of solute present in 4.00 L of an 8.30 M solution is 33.2
Explanation:
The Molarity (M) or Molar Concentration is the number of moles of solute per liter of solution; in other words it is the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units ([tex]\frac{moles}{liter}[/tex]) or M.
In this case:
molarity= 8.30 Mnumber of moles of solute= ?volume= 4.00 LReplacing:
[tex]8.30 M=\frac{number of moles of solute}{4 L}[/tex]
Solving:
number of moles of solute= 8.30 M* 4 L= 8.30 [tex]\frac{moles}{liter}[/tex] * 4 L
number of moles of solute =33.2
The number of moles of solute present in 4.00 L of an 8.30 M solution is 33.2
Answer:
33.2 is the answer
Explanation:
did the test already :)
what is the modification of the Dalton's atomic theory
Answer:
Dalton's theory had to be modified after mass spectrometry experiments demonstrated that atoms of the same element can have different masses because the number of neutrons can vary for different isotopes of the same element
You've just synthesized a new molecule and need to purify it by recrystallization. You find that it is poorly soluble in water and highly soluble in ethanol, even when cooled in ice. What solvent should work in this situation
Answer:
Water is used as a solvent.
Explanation:
In order to purify the new molecule, recrystallization occurs in which the new molecule should be added in water and heated the water in order to increase the solubility of the solution. The new molecule dissolve in water while the impurity remains undissolved which can be removed from the solution and then remain the solution to be cold down and the new molecule will again undissolved and the molecule can be extracted without any impurities. We use water instead of ethanol due to lower solubility.
What is science?
O A. Attempting to solve ethical problems through research
O B. Learning about the physical world through observation
O C. Determining a body of knowledge that never changes
O D. Using rules and patterns to predict what humans will do
SUBMIT
Answer:
The answer is B
Explanation:
Answer:
B. Learning about the physical world through observation
Explanation:
A p e x 2021 :) Trust me!
Aqueous calcium chloride reacts with aqueous potassium carbonate in a double-displacement reaction. Write a balanced equation to describe this reaction. Include states of matter in your answer. Click in the answer box to open the symbol palett
Answer: [tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The balanced reaction between aqueous calcium chloride reacts with aqueous potassium carbonate is shown as:
[tex]CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)[/tex]
why homoannular diene in uv spectrometry have higher wavlenth than hetroannular diene?
Answer:
Homoanular dienes have a greater base value than heteroanular dienes
Explanation:
Woodward in 1945 gave a set of rules relating the wavelength of maximum absorption to the structure of a compound. These rules were modified by Fieser in 1959. These sets of rules describe the absorption of organic molecules in the UV region of the electromagnetic spectrum.
Each system of diene or triene has a given fixed value at which maximum absorption is expected to occur according to Woodward rules. This given fixed value is called the base or parent value. If the two double bonds are trans to each other, the diene is said to be transoid. If the two double bonds belong to different rings, the system is said to be heteroanular and the base value in each case is 215nm. If the double bonds are cis to each other (cisoid), or the two double bonds are in the same ring (homoanular), then the base value is 253nm.
Since λmax = base value + ∑ substituent contributions + ∑ other contributions, if the other contributions are not very significant, homoanular diene will have a greater λmax because of its larger base value compared to heteroanular diene. This correlates well with the fact that conjugated systems absorb at a longer wavelength.
How many grams of LiNO3 must be added to 25.0 g of water to prepare a 5.00% (m/m) solution of LiNO3?
Answer:
1.25 g.
Explanation:
5% or 25 g
= 0.05 * 25
= 1.25 g (answer).
Consider the three statements below. Which numbered response contains all the statements that are true and no false statements?
I. Hydration is a special case of solvation in which the solvent is water.
II. The oxygen end of water molecules is attracted toward Ca2+ ions.
III. The hydrogen end of water molecules is attracted toward Cl- ions.
a) I, II, and III
b) I and II
c) III
d) I
e) II
Answer:
a) I, II, and III
Explanation:
For the first statement;
Solvation, is the process of attraction and association of molecules of a solvent with molecules or ions of a solute. if the solvent is water, we call this process hydration.
This means the statement is TRUE.
For the second statement;
The negatively-charged side of the water molecules are attracted to positively-charged ions. In the case of water, the oxygen end is the negatively charged side of water. This means the statement is TRUE.
For the third statement;
The positively-charged side of the water molecules are attracted to the negatively-charged chloride ions. In the case of water, the hydrogen end is the positively charged side of water. This means the statement is TRUE.
Going through the options, we can tell that the correct option is option A.
A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 degree C.) Be sure your answer has the correct number of significant digits.
Answer: The pH of the solution is 11.2
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]Ba(OH)_2[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.867g}{171g/mol}=0.00507mol[/tex] (1g=1000mg)
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.00507\times 1000}{170}[/tex]
[tex]Molarity=0.0298[/tex]
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pOH=-\log [OH^-][/tex]
[tex]Ba(OH)_2\rightarrow Ba^{2+}+2OH^{-}[/tex]
According to stoichiometry,
1 mole of [tex]Ba(OH)_2[/tex] gives 2 mole of [tex]OH^-[/tex]
Thus 0.0298 moles of [tex]Ba(OH)_2[/tex] gives =[tex]\frac{2}{1}\times 0.0298=0.0596[/tex] moles of [tex]OH^-[/tex]
Putting in the values:
[tex]pOH=-\log[0.0596]=2.82[/tex]
[tex]pH+pOH=14[/tex]
[tex]pH=14-2.82[/tex]
[tex]pH=11.2[/tex]
Thus the pH of the solution is 11.2
There are five constitutional isomers with the molecular formula C6H14. When treated with chlorine at 300°C, isomer A gives a mixture of two monochlorination products. Under the same conditions, isomer B gives a mixture of five monochlorination products, isomer C gives four monochlorination products, and isomer D gives a mixture of three monochlorination products. From this information, draw the structural formula of isomer D.
Answer:
Pentane or 2,2-dimethylbutane
Explanation:
I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.
The results are
Isomer 1— three sets of equivalent hydrogens
Isomer 2— five sets of equivalent hydrogens
Isomer 3— four sets of equivalent hydrogens
Isomer 4— two sets of equivalent hydrogens
Isomer 5— three sets of equivalent hydrogens
Each set will give one monochloro substitution product.
4 = A. Two monochloro isomers.
2 = B. Five monochloro isomers.
3 = C. Four monochloro isomers.
Isomers 1 and 5 each give three monochloro isomers.
Thus, we cannot assign Structure D definitively.
D is either pentane or 2,2-dimethylbutane.
What is T2, if T1= 500 k, v1=10L, V2=8L,P1=600 torr,P2=200 torr?
Answer:
T2 = 133.333°K
Explanation:
Using Combined Gas Laws:
(600 torr)(10L)/500°K = (200 torr)(8L)/x°K
[tex]\frac{600 torr(10L)}{500K} =\frac{200 torr(8L)}{xK}[/tex]
Cross multiply:
x°K (600 torr)(10L) = 500°K(200 torr)(8L)
Divide:
x°K = (500°K(200 torr)(8L))/(600 torr)(10L)
[tex]xK = \frac{500K(200 torr)(8L)}{600 torr(10L)}[/tex]
x = 400/3°K or 133.333°K
Need help asap!!! Can someone please help me?
Answer:
The answer is option C.
voltage (V) = Current( I ) × Resistance (R)
V = IR
I = V/ R
V = 10V R = 20Ω
I = 10/20 = 1/2
I = 0.50A
Hope this helps
Helium (He) is the lightest noble gas component of air, and xenon (Xe) is the heaviest. Perform the following calculations, using R = 8.314 J/(mol·K) and ℳ in kg/mol. (a) Find the rms speed of He in winter (0.°C) and in summer (30.°C). Enter your answers in scientific notation. × 10 m/s (winter) × 10 m/s (summer) (b) Find the ratio of the rms speed of He to that of Xe at 30.°C. (rate He)/(rate Xe) (c) Find the average kinetic energy per mole of He and of Xe at 30.°C. Enter your answers in scientific notation. × 10 J/mol for He × 10 J/mol for Xe (d) Find the average kinetic energy per molecule of He at 30.°C. Enter your answer in scientific notation. × 10 J/He atom
Answer:
Explanation:
Hello,
Data;
R = 8.314J/(mol.K)
Temp (winter) = 0°C = (0 + 273.15)K = 274.15K
Temp.(summer) = 30°C = (30 + 273.15)K = 303.15K
Molar mass of He = 4g/mol = 0.004kg/mol
Molar mass of Xe = 131.29g/mol = 0.131kg/mol
a) rms speed in winter and summer
Vrms = √(3RT/M)
R = gas constant
T = temperature of the gas
M = molar mass of the gas
In winter,
Vrms = √(3×8.314×273.15) / 0.004
Vrms = 1.30×10³m/s
In summer
Vrms = √(3×8.314×303.15) / 0.004
Vrms = 1.37×10³m/s
b) Vrms of Xe at 30°C
Vrms = √(3 × 8.314 × 303.15) / 0.131
Vrms of Xe = 240.24m/s = 2.40×10²m/s
Vrms of He = 1.37×10³m/s
Rate of He / rate of Xe = 1.37×10³ / 2.40×10²
Rate of He / rate of Xe = 5.7
c) K.E per mole
At 30°C
K.E of He = (3/2) × 8.314 × 303.15
K.E of He = 3.78×10³J/mol
K.E of Xe = (3/2) × 8.314 × 303.15
K.E of Xe = 3.78×10³J/mol
d) K.E per molecule = ½mv²
K.E of He molecule = ½ × 0.004 × 1.37×10³
K.E = 2.74J
The rms speed of He in winter and in summer are 1.30×10³m/s & 1.37×10³m/s respectively, ratio of the rms speed of He to that of Xe at 30 degree celsius is 5.7, average kinetic energy per mole of He and of Xe and average kinetic energy per molecule of He are discussed below.
How do we calculate the root mean square velocity?Root mean square velocity of the gases will be calculated as:
Vrms = √(3RT/M), where
R = universal gas constant = 8.314J/(mol.K)
M = molar mass of gas in kg/mol
T = temperature in K
Root mean square velocity of Helium at 0°C or 273.15K and 30°C or 303.15K will be calculated as:At 273.15K-
Vrms = √(3×8.314×273.15) / 0.004 = 1.30×10³m/s
At 303.15K-
Vrms = √(3×8.314×303.15) / 0.004 = 1.37×10³m/s
Vrms (winter×summer) = 1.30×10³m/s × 1.37×10³m/s = 1.78×10⁶m/s
Vrms of Xe at 303.15KVrms = √(3 × 8.314 × 303.15) / 0.131
Vrms of Xe = 240.24m/s = 2.40×10²m/s
Vrms of He = 1.37×10³m/s
Rate of He / rate of Xe = 1.37×10³ / 2.40×10²
Rate of He / rate of Xe = 5.7
Average kinetic energy will be calculated as:K.E = 3RT / 2N, where
N = avgadros number = 6.022×10²³ atoms/mole
Average kinetic energy per mole of He & Xe at 303.15K is same as:
K.E = 3/2(1.38 × 10⁻²³J/K)(303.15K) = 6.2 × 10⁻²⁵J/mol
Average kinetic energy per molecule of He will be calculated as:K.E of He molecule = ½ × 0.004 × 1.37×10³
K.E = 2.74J
Hence, calculations for the given points are described above.
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What causes the electrons to flow through a wire in a lead-acid battery?
Answer:
The potential difference between the cathode and anode are set up from the chemical reaction. Inside the battery electrons are pushed by the chemical reaction toward the positive end creating a potential difference. It is this potential difference that drives the electrons through the wire.
Calculate the theoretical percentage of water for the following hydrates.
(a) manganese(II) monohydrate, MnSO4 H2O
(b) manganese(II) tetrahydrate, MnSO4 4H2O
Answer:
(a) [tex]\% H_2O=10.65\%[/tex]
(b) [tex]\% H_2O=32.2[/tex]
Explanation:
Hello.
For this questions we must consider the ratio of the molar mass of water to hydrated compound molar mass as shown below:
(a) In this case, we can consider that inside the manganese (II) sulfate monohydrate, whose molar mass is 169.02 g/mol, there is one water molecule that has a molar mass of 18 g/mol, for which the theoretical percentage of water is:
[tex]\% H_2O=\frac{18g/mol}{169.0g/mol} *100\%\\\\\% H_2O=10.65\%[/tex]
(b) In this case, we can consider that inside the manganese (II) sulfate tetrahydrate, whose molar mass is 223.1 g/mol, there are four water molecules that have a molar mass of 4*18 g/mol, for which the theoretical percentage of water is:
[tex]\% H_2O=\frac{4*18g/mol}{223.1g/mol} *100\%\\\\\% H_2O=32.27\%[/tex]
Best regards.
How are sodium (Na) and potassium (K) similar?
O
A. They rarely react.
B. They are hard metals.
O O
C. They are highly reactive.
D. They are soft nonmetals.
Answer:
They are also relatively soft metals: sodium and potassium can be cut with a butter knife.
Answer:A
Explanation:
A student has a sample of CaSO4 hydrate and it weighs 0.4813 grams. He heats it strongly to drive off the water of hydration, and after subsequent heatings, the student finds the anhydrous compound has a constant mass of 0.3750 grams. Find the formula of the hydrate.(2 points)
Answer:
CaSO4•3H2O.
Explanation:
Let the compound be CaSO4.xH2O.
The following data were obtained from the question:
Mass of hydrated compound (CaSO4.xH2O) = 0.4813g
Mass of anhydrous compound (CaSO4) = 0.3750g
Next we shall determine the mass of the water is the hydrated compound.
This is illustrated below:
Mass of water = mass of hydrated – mass of anhydrous.
Mass of water = 0.4813 – 0.3750
Mass of water = 0.1063g
Next, we shall determine the number of mole of the anhydrous compound and the number of mole of the water present in the compound. This is illustrated below:
Molar mass of anhydrous CaSO4 = 63.5 + 32 + (16x4) = 159.5g/mol
Mass of anhydrous CaSO4 = 0.3750g
Mole of anhydrous CaSO4 =...?
Mole = mass /Molar mass
Mole of anhydrous CaSO4 = 0.3750/159.5 = 2.35×10¯³ mole
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H2O = 0.1063g
Number of mole of H2O =.?
Mole = mass /Molar mass
Mole of H2O = 0.1063/18 = 5.91×10¯³ mole
Next we shall determine the ratio of number of mole of anhydrous CaSO4 to that of H2O. This is illustrated below:
Mole of anhydrous CaSO4 = 2.35×10¯³ mole
Mole of H2O = 5.91×10¯³ mole
Ratio of anhydrous CaSO4 to H2O =>
CaSO4 : H2O => 2.35×10¯³ /5.91×10¯³
CaSO4 : H2O => 1 : 3
Therefore, for 1 mole of the anhydrous CaSO4, there are 3 moles of H2O.
Therefore, the formula for the hydrate compound CaSO4.xH2O => CaSO4•3H2O.
Drag the description to the category
Answer:
ok
Explanation:
The two reactions above, show routes for conversion of an alkene into an oxirane. If the starting alkene is cis-3-hexene the configurations of the oxirane products, A and B are Product A: _______ Product B: _______ Will either of these two oxirane products rotate the plane of polarization of plane polarized light? _____
Answer:
Product A: cis; no
Product B: cis: no
Explanation:
Two common methods of forming oxiranes from alkenes are:
Reaction with peroxyacids Formation of a halohydrin followed by reaction with base
1. Reaction with peroxyacids
(a) Stereochemistry
The reaction with a peroxyacid is a syn addition, so the product has the same stereochemistry as the alkene.
The starting alkene is cis, so the product is cis-2,3-diethyloxirane.
(b) Configuration
The product is optically inactive because it has an internal plane of symmetry.
It will not rotate the plane of polarized light.
2. Halohydrin formation
(a) Stereochemistry
The halogenation of the alkene proceeds via a cyclic halonium ion.
The backside displacement of halide ion by alkoxide is also stereospecific, so a cis alkene gives a cis epoxide.
The product is cis-2,3-diethyloxirane.
(b) Configuration
The cyclic halonium ion has an internal plane of symmetry, as does the product (meso).
The oxirane will not rotate the plane of polarized light.
oxidation number of Se in Se8
Answer:
0.
Explanation:
All elements existing on their own in their free states has an oxidation number of 0.
The oxidation number of Se in Se8 is 0. The element Se in its elemental state has an oxidation number of 0.
Chemistry uses the idea of oxidation number, also known as oxidation state, to describe the charge that an atom seems to have when it forms a compound or ion. It is a notion that aids in our comprehension of how electrons are distributed within a molecule or ion. Oxidation numbers can be used to balance chemical equations and identify the many kinds of chemical reactions that may take place. For a better understanding of the reactivity and bonding of various elements in compounds, they offer insights into the transfer or sharing of electrons between atoms. Se in Se8 has an oxidation number of 0. Se has an oxidation number of 0 when it is in its purest form.
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Question 4
2 pts
A careless chemistry student performed a chemical reaction where his theoretical yield of
Magnesium oxide was 57.82 grams, but he actually produced 12.89 grams. What is his percent yield
for this experiment? (include the number with 4 significant figures but no units)
Answer:
22.29%
Explanation:
Percent yield = experimental yield / theoretical yield * 100
= 12.89 / 57.82 * 100 = 22.29%
Once the chromatographic column has been prepared, why is it important to allow the level of the liquid in the column to drop the level of the alumina before applying the solution of the compound to be separated?
Answer: Chromatography is a technique which is used for the separation of components present in a mixture into sub-components.
Explanation:
The solvent or liquid used for the separation of the chromatographic mixture should lie below the spot point where the mixture is loaded in an alumina column. This is done to prevent the air bubbles formations, which can lead to poor sanitation. Also this is done to prevent the mixing of the mixture to be separated with the solvent instead of running with the solvent via capillary action.
Lewis structure of methyl metcaptain
Answer:
The lewis structure of the compounds can be drawn by making the skeleton of the molecule first. Then the different atoms are arranged and the electrons are arranged in their bonding pattern. The lone pair of the atoms, which are not involved in the bonding are represented by the dots.
So the lewis structures of both the compound methyl mercaptan has been in the attached image:
Spelling of methyl metcaptain is wrong, the correct spelling is methyl mercaptan.
Answer:
Methyl mercaptan is also known as Methanethiol with the chemical formula CH3SH and it is an organosulfur compound.
For lewis structure of methyl mercaptan (CH3SH), there are total 14 valence electrons. Four hydrogen atoms has one valence electron each, carbon has four valence electrons and sulfur has six valence electrons. Carbon form one bond with three hydrogen atoms by sharing one electron with each, carbon form one single bond with sulfur atom by sharing one electron with it and sulfur form one single bond with hydrogen. Sulfur left with four unpair electrons.
(a) How many stereoisomers are possible for 4-methyl-1,2-cyclohexanediol? ___ (b) Name the stereoisomers formed by oxidation of (S)-4-methylcyclohexene with osmium tetroxide. If there is only one stereoisomer formed, leave the second space blank. Isomer #1: Isomer #2: (c) Is the product formed in step (b) optically active? _____
Answer:
See explanation
Explanation:
For the first part of the question, we have to check the chiral carbons in 4-methyl-1,2-cyclohexanediol. In this case carbons, 1 and 2 are chiral, if we have 2 chiral carbons we will have 4 isomers. We have to remember that formula 2^n in which "n" is the number of chiral carbons, so:
2^n = 2^2 = 4 isomers
And the isomers that we can have are:
1) (1R,2S)-4-methylcyclohexane-1,2-diol
2) (1S,2S)-4-methylcyclohexane-1,2-diol
3) (1S,2S)-4-methylcyclohexane-1,2-diol
4) (1S,2R)-4-methylcyclohexane-1,2-diol
See figure 1
For the second part of the question, we have to remember that the oxidation with [tex]OsO_4[/tex] is a syn addition. In other words, the "OHs" are added in the same plane. In this case, we have the methyl group with a wedge bond, so the "OH" groups will have a dashed bond due to the steric hindrance. Due to this we only can have 1 isomer ((1S,2R,4S)-4-methylcyclohexane-1,2-diol). Finally, on this molecule, we dont have any symmetry planes (this characteristic will cancel out the optical activity), so the product of this reaction has optical activity.
See figure 2
I hope it helps!
What would have happened to your % Transmittance reading and to your calculations of Keq if the spectrophotometer had been set at 520 nm rather than 447nm
Answer:
On the off chance that the wavelength(λ) maximum worth has been changed to 520 nm from 470 nm on the spectrophotometer, less light would be absorbed and in this way %T would be higher than the one found at 470 nm. The wavelength utilized at 520 nm isn't adequate for the excitation and consequently lesser light is absorbed by the arrangement.
Explanation:
A spectrophotometer is an analytical equipment used to quantitatively gauge the transmission(passage) or impression of visible light, UV light or infrared light through a medium.
Transmittance (τ) is the ratio of the brilliant or luminous flux at a given wavelength that is transmitted to that of the incident radiation.
where, Keq is the equilibrium constant.
On the off chance that the wavelength(λ) has been changed to 520 nm from 470 nm on the spectrophotometer, less light would be absorbed and in this way %T would be higher than the one found at 470 nm.
What happens to Transmittance?A spectrophotometer is an analytical equipment used to quantitatively gauge the transmission(passage) or impression of visible light, UV light or infrared light through a medium. Transmittance (τ) is the ratio of the brilliant or luminous flux at a given wavelength that is transmitted to that of the incident radiation. The wavelength utilized at 520 nm isn't adequate for the excitation and consequently lesser light is absorbed by the arrangement. As the concentration goes up, more radiation is absorbed and the absorbance goes up. Therefore, the absorbance is directly proportional to the concentration.
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