How many grams of oxygen are required to combine with 0.750 grams of nitrogen in the compound: N2O5?

Answers

Answer 1

Answer:

2.14 g.

Explanation:

Hello!

In this case, since the mole ratio between nitrogen and oxygen is 2:5 respectively, we realize we first need the moles of nitrogen given it's atomic mass (14.01 g/mol):

[tex]n_N=0.750g*\frac{1mol}{14.01g}=0.0535molN[/tex]

Now, we calculate the moles of oxygen:

[tex]n_O=0.0535molO*\frac{5molO}{2molN}=0.134molO[/tex]

Then, we compute the moles of oxygen given its atomic mass (16.00 g/mol):

[tex]m_O=0.134molO*\frac{16.00gO}{1molO_2} \\\\m_O=2.14gO[/tex]

Best regards!


Related Questions

What happens to a linguist when it releases enough energy

Answers

Answer:

When a liquid releases enough energy, the liquid will freeze and turn into a solid. Phase changes are what causes one state of matter to turn into another. All phase changes are physical changes.

Explanation:

if ur really saying liquid a person accomplished in languages

especially : one who speaks several languages ?

please mark as brainliest

The density of copper is a...

a. chemical property
c. chemical change
b. physical property
d. physical change

Answers

Answer:

B. physical property is the answer

5. A reaction in which them material that starts the reaction is also one of the products and can start another reaction is called

a. An accelerator reaction
b. A moderator reaction
c. A shielding reaction
d. A chain reaction

Answers

Answer:

D it's called a chain reaction

In general chemicals enter Ecosystems through which two spears

Answers

Answer:

biosphere and lithosphere

Explanation:

The biosphere is described as the zone of life on Earth. It is a sum of all ecosystems. The biosphere is composed of living organisms and non-living factors.

The lithosphere is the outer part of the Earth such that this part is rocky. The lithosphere is made up of the brittle crust.

In general, chemicals enter Ecosystems through the biosphere and lithosphere.

Help me please omg

Answer the following question:

How many moles of ammonia are in 375. mL of a 2.25 M aqueous ammonia solution?

Find the numerical answer for this question and make sure to include the following:

What is the chemical formula for ammonia?
What is the formula for molarity?
When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?

Answers

Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

Volume of solution (V): 375. mLMolar concentration of the solution (M): 2.25 MChemical formula for ammonia: NH₃

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

5. If the reaction of carbon monoxide and oxygen gas in question 2
produced 7.03E24 molecules of CO2, what is the mass in grams? Use
44g/mol for M.M. of CO2 and round your answer to the nearest whole
number. *

Answers

Answer: The mass in grams is 514.8.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}[/tex]

given molecules = [tex]7.03\times 10^{24}[/tex]  

Putting in the values we get:

[tex]\text{Number of moles}=\frac{7.03\times 10^{24}}{6.023\times 10^{23}}=11.7moles[/tex]

mass of [tex]CO_2=moles\times {\text {Molar mass}}=11.7mol\times 44g/mol=514.8g[/tex]

The mass in grams is 514.8.

What is the oxidation number of bromine in the BrO3- ion?

Answers

+5 Hope that helps!!!

Draw the structure of the major organic product(s) for the following reaction between an acetylenic anion and an alkyl halide. (The reaction stoichiometry is 1:1.) A carbon carbon triple bond where carbon 1 is a carbanion with a lone pair and carbon 2 is bonded to methyl. This reacts with a 5 carbon chain where carbon 3 has a bromine substituent.

Answers

Answer:

See explanation below

Explanation:

In this case, we are having a reaction between an anion and alkyl halide. The carbon 1 of the anion will act as nucleophile and will attack the electrophile, which is 5 carbon chain with the bromine in the third carbon.

Now, the nucleophyle is an alkyne of 3 carbon. According to the description, it should be:

CH₃ - C ≡ C⁻

And the alkyl halide is:

CH₃ - CH₂ CH(Br) - CH₂ - CH₃

And the final product after the reaction would be the following:

CH₃ - C ≡ C - CH - (CH₂CH₃)₂

However, in the attached picture you can see this better and the mechanism of reaction.

Hope this helps

2 Cu + Cl2 ----> 2 Cuci
If 1.64 moles of chlorine is reacted with 3.23 moles of copper, how many grams of copper I chloride will be made?
(The next question will ask about the limiting and excess reactants for this reaction)
o 320 g
O 160 g
O 162 g
O 325 g

Answers

Answer:

320 g.

Explanation:

Hello!

In this case, according to the balanced chemical reaction, we can compute the grams of copper I chloride produced by each reactant, as shown below:

[tex]m_{CuCl}^{by\ Cu}=3.23molCu*\frac{2molCuCl}{2molCu}*\frac{99.0gCuCl}{1molCuCl} =320gCuCl\\\\m_{CuCl}^{by\ Cl_2}=1.64molCl_2*\frac{2molCuCl}{1molCl_2}*\frac{99.0gCuCl}{1molCuCl} =325gCuCl[/tex]

Thus, since copper produces the fewest grams of CuCl, we infer it is the limiting reactant, therefore the correct mass of copper I chloride is 320 g.

Best regards!

Hello! Please help :((

Find the distance from point B to point C. Enter as a decimal rounded to the nearest tenth. А 61° 5.7 mi B С BC = [?] mi Enter​

Answers

Answer:

BC = 10.28 ≈ 10.3 mi to the nearest tenth

Explanation:

Using the trigonometry rules; SOH CAH TOA,

TOA would be more suitable in this question.

Tan ∅ = Opposite / Adjacent

Tan 61 = BC / AB

1.8040 = BC / 5.7

BC =  5.7 * 1.8040

BC = 10.28 ≈ 10.3 mi

the answer is 10.3, i already rounded it.


If you begin with 14.0g of TiCl4(1), how many liters of H2O(g) will need?

Answers

Answer:

3.32 L

Explanation:

Step 1: Write the balanced equation

TiCl₄(l) + 2 H₂O(g) → TiO₂(s) + 4 HCl(g)

Step 2: Calculate the moles corresponding to 14.0 g of TiCl₄

The molar mass of TiCl₄ is 189.68 g/mol.

14.0 g × 1 mol/189.68 g = 0.0738 mol

Step 3: Calculate the moles of H₂O needed to react with 0.0738 moles of TiCl₄

The molar ratio of TiCl₄ to H₂O is 1:2. The moles of H₂O needed are 2/1 × 0.0738 mol = 0.148 mol

Step 4: Calculate the volume corresponding to 0.148 moles of H₂O(g)

At standard temperature and pressure, 1 mole of H₂O(g) has a volume of 22.4 L.

0.148 mol × 22.4 L/1 mol = 3.32 L

Can someone please rephrase this question, I dont understand what it is asking for.

Which disease might have cures developed as a result of their understanding of structure and function of protein?

Answers

Answer:

Which infection may have fixes created because of their comprehension of construction and capacity of protein?

The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catalyst. The entering pressure was 20 atm and the exit pressure is 2 atm. The feed is equal molar in A and B and the flow is in the turbulent flow regime, with FA0 10 mol/min and CA0 0.4 mol/dm3. Currently 80% conversion is achieved. What would be the conversion

Answers

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

Help~... It's "Science". ^W^
Which term is used to describe the variety of inheritable traits in a species? (1 point)

A. Ecosystem diversity
B. Genetic diversity
C. Natural selection
D. Species diversity

Answers

C. Natural selection

Which of the following are examples of limiting factors? a. water b. sunlight c. available mates d. all of the above

Answers

Answer: I believe the answer is D.) All of the above.

Explanation:

Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?

Answers

Answer:

If your asking what golds natural state of matter is it's solid.

Explanation:

Answer:

the answer is soild

Explanation:

i did it on edge :)

What are mand n in the rate law equation?
Rate = k[A]”[B]"

Answers

A (they are experimentally determined exponents)

Which of Newton's Three Laws is BEST described by the following statement: A ball dropped from the 10th story of a hotel had more force than when the same ball was dropped from the 5th story of the same hotel

Answers

Answer:

I believe the answer is Newton's Second Law

Explanation:

Newton's Second Law states that the acceleration of an object will count on how much mass and the amount of force that is applied.

The bowling ball was dropped from the 10th story window and had more force than when the ball was dropped from the 5th story window because the 10th story window gave the bowling ball more acceleration.

which has more gravity
A. Earth
B. Sun
C. Saturn

Answers

B

the sun!

yay

!!!!!!!!!!!

Answer:

EARTH

Explanation:

Earth‘s gravity, as already noted, is equivalent to 9.80665 m/s² (or 32.174 ft/s²). This means that an object, if held above the ground and let go, will accelerate towards the surface at a speed of about 9.8 meters for every second of free fall.

Why are watersheds important for the maintenance of water quality? Choose all that apply.

Select 2 correct answer(s)
Question 3 options:

they can transfer pollutants


their soil and plants can filter and clean water


they cause precipitation and acid rain


they cause floods

Answers

Answer:

its A and D

Explanation:

i took the quiz

Answer:

a and d

Explanation:

You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be 0.30 g. The distribution coefficient of benzoic acid in diethyl ether and water is approxi- mately 10. Calculate the amount of ben- zoic acid that would be left in the water solution after four 20-mL extractions with ether. Do the same calculation using one 80-mL extraction with ether to determine which method is more efficient.

Answers

Answer:

The extraction with four 20-mL extractions with ether is more efficient.

Explanation:

We are given the following parameters which are going to help in solving this particular Question.

=> The volume of the solution of benzoic acid in water = 100mL, the estimated amount of benzoic acid in the solution = 0.30 g and the distribution coefficient (approximately ) = 10 = 1/ 10 = 0.1

Therefore, the amount of acid that would be left in the water solution after four 20-mL extractions with ether = 0.3( 0.1 × 100 ÷ 10 + 20)^4 = 0.0037 g.

Also, the amount of acid that would be left in the water solution after one 80-mL extractions with ether = 0.3( 0.1 × 100/ 10 + 80)^1 = 0.033 g.

Since 0.033 g > 0.0037 g, the extraction with four 20-mL extractions with ether is more efficient.

After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the Run Experiment button at the end or by clicking the Overview tab and returning to the Experiment tab to select Run Experiment. There are nine reactions you can explore on your own. Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much SO2 would you need to completely react with 6.00 g of O2 such that all reactants could be consumed

Answers

Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]      

[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]  

According to stoichiometry :

1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]

Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex]  of [tex]SO_2[/tex]  

Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]

Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.

HELP I HAVE 3 MINUTES LEFT

Answers

Answer: kinetic energy

Answer:

Kinetic Energy.

Explanation:

All these "forces" rely on specific motion.

5. A reaction in which them material that starts the reaction is also one of the products and can start another reaction is called

a. An accelerator reaction
b. A moderator reaction
c. A shielding reaction
d. A chain reaction

Answers

Answer:

chain reaction

Explanation:

A chain reaction is a sequence of reactions where a reactive product or by-product causes additional reactions to take place.

How many moles of water can be formed from 23.9 mol of oxygen gas?
H2 + O2 --> H20
Hint: Is it balanced?

Answers

Answer:

47.8 moles of H₂O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O

Finally, we shall determine the number of mole of water, H₂O, produced by the reaction of 23.9 moles of O₂. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O.

Therefore, 23.9 moles of O₂ will react to produce = 23.9 × 2 = 47.8 moles of H₂O.

Thus, 47.8 moles of H₂O were obtained from the reaction.


**will give brainlists if correct answer***

Predict all of the products of the incomplete reaction shown below.
K+ Cl2 →
A)KCIO3
B)K2
С)КСІ
D)KCI2

Answers

Answer:

C)

Explanation:

46) How many inches are in 25.8 cm?
A) 0.10
B) 28.3
C) 0.0984
D) 10.2
E) none of the above

Answers

Answer:

10.15748 so it is none of the above

Explanation:

I just know

When rocks slowly crumble due to rain, ice, and wind and
erode away, these processes form what?

Answers

i think the answer should be sediment, hope this helps

The hydronium ion concentration of an aqueous solution of 0.502 M pyridine (a weak base with the formula C5H5N) is

Answers

Answer:

1.99×10¯¹⁴ M

Explanation:

We'll begin by writing the balanced dissociation equation of pyridine. This is illustrated below:

C₅H₅N + H₂O <=> C₅H₆N⁺ + OH¯

From the balanced equation above,

1 mole of C₅H₅N produced 1 mole of OH¯.

Therefore, 0.502 M C₅H₅N will also produce 0.502 M OH¯.

Finally, we shall determine the concentration of hydronium ion, H₃O⁺ in the solution. This can be obtained as follow:

Concentration of Hydroxide ion [OH¯] = 0.502 M

Concentration of hydronium ion [H₃O⁺] =?

[H₃O⁺] [OH¯] = 1×10¯¹⁴

[H₃O⁺] × 0.502 = 1×10¯¹⁴

Divide both side by 0.502

[H₃O⁺] = 1×10¯¹⁴ / 0.502

[H₃O⁺] = 1.99×10¯¹⁴ M

Thus, the concentration of hydronium ion, H₃O⁺ in the solution 1.99×10¯¹⁴ M

Convert the volume, nm^3, to liters (L) by using the box dimensions of 4nm x 8.75nm x 10nm. Use the conversion factor of 1 L = 1 dm^3. Do not convert directly from nm^3 to dm^3

Answers

Answer:

[tex]V=3.50x10^{-22}L[/tex]

Explanation:

Hello there!

In this case, given the dimensions of the box, we first compute the volume by multiplying each side:

[tex]V=4nm*8.75nm*10nm=350nm^3[/tex]

Next, we apply the following conversion factor in order to obtain the corresponding liters:

[tex]V=350nm^3*(\frac{1m}{10^9nm} )^3*\frac{1000L}{1m^3} \\\\V=350nm^3*\frac{1m^3}{10^{27}nm^3} *\frac{1000L}{1m^3}\\\\V=3.50x10^{-22}L[/tex]

Best regards!

Other Questions
Why did Steve and Vic focused on smaller cities rather than Silicon Valley I NEED HELLP NOWWW IM TIMEDDo you think you are more internally or externally motivated to do things? Please read this lab exercise thoroughly, before attempting to write the program.Write a program that reads the pairs of group number and student count from the text file (user must enter name of file) and:Displays the number of groups in the file (5 %)Displays the number of even and odd student count (5%)Displays the sum of the even student count and the sum of the odd student count as well as the sum of all the student count (5%)Displays the group numbers of the largest student count and the smallest student count (5 %)Computes the average of the largest and smallest student count (10 %)Compute the sum of ALL the digits in the largest student count (i.e. 952 Sum is 9+5+2 = 16) (15 %)Assume the contents of the file are as follows but that the pairs of data can change later:1 252 1233 4754 615 776 9107 2348 1389 13410 9511 67412 34513 3114 21115 95216 87317 2218 719 87620 34721 450The following is a sample output: User input in redWhat is name of the input file? integers.datThe number of groups in the file is 21There are 12 odd student count and 9 even student countThe sum of the odd student count is 2645The sum of the even student count is 4390The sum of all the student count is 7035The group number of the largest student count is 15The group number of the smallest student count is 18 The average of 952 and 7 is 479.5The sum of all the digits in the largest student count is 16NOTE:Use two decimal point precision for the averageTo check your code, adjust one of the student count in the file, recompile your code and run again (suggest changing the largest or smallest student count )Even though there are 21 pairs of numbers in the file, the program should NOT presume there will always be 21 pairs of numbers. In other words, you should not solve this problem by declaring 21 pairs of values. If I choose to use another integers.dat file other than the one provided with the assignment, your program should still work correctly with that file as well. All you can assume is that a series of integers will be read in from the file. Therefore, you need to implement a solution that uses the repetition control structures (for, while, dowhile) in the reading and processing of these values to produce your output. What is the answer hurry!!! Find x plsssss!!!!! 10 min A large, heavy cargo container is taken from the surface of the Earth andbrought to the Moon to begin building a base camp. What is MOST differentabout this cargo container on the Moon?abOn the Moon, the cargo container has a different volume.On the Moon, the cargo container has a different shape.On the Moon, the cargo container has a different mass.On the Moon, the cargo container has a different weight.d Find the sum. Write your answer in simplest form.3 8/9 + 1 5/124 36/475 11/364 13/225 1/4 You guys are smart please help me. A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M NaCl 0.1 M Ca(NO3)2 0.1 M KCH3COO The student decides to add some 0.1 M Pb(NO3)2 to a sample of the reagent in question. Upon stirring, a white precipitate formed. Which of the possible solutions is present in the unlabeled container based on this observation? A. 0.1 M KCH3COO B. 0.1 M Ca(NO3)2 C. 0.1 M NaCl Peyton listed five rational numbers. Then he drew a number line to display and compare them escoge la palabra reemplazada con el pronombre. choose the direct object noun replaced in the sentence no puedo encontrarlomaleta pasaporteidentificatin Given that the image below is not drawn toscale, approximately how many times wouldtriangle DBE fit inside of triangle FBG withoutoverlapping?Use the line segment tool to draw and modeleach triangle, then the pencil tool to numberthe triangles in your diagram. Find the area of the composite figure.A) 22mB) 26mC) 30mD) 34m If + 100 = 1560, find the value of H and B THE CRUCIBLE1. In any unfaithful marriage or relationship, who is to blame the adulterous party (John), the counterpart or tempter (Abigail), or the distant spouse (Elizabeth)? Can someone be justified or pushed to cheat on their partner? please help a friend out with nP5 nC4 = 144 PLZ HELP ME PLZZZ I WILL GIVE BRAINLIEST......I REALLY NEED THE ANSWERS. In what direction will heat always flous find the Highest common factor of 42 and 90 $3.00 SummaryEach word is $0.10Answer the Essential Question: How do I add or subtract radical?