How many grams of NaOH (MW = 40.0) are there in 500.0 mL
of a 0.175 M NaOH solution?
A) 3.50
B) 114
C) 14.0
D) 2.19x10

Answers

Answer 1

Answer:

3.5

Explanation:

500*0.175= 8.75 *40/1000=3500/1000=3.5

Answer 2

Answer:

3.50 grams

Explanation:

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Related Questions

What is the molarity of ZnCl, that forms when 20.0 g of zinc completely reacts with CuCl2, according to the following reaction? Assume a final
volume of 285 mL

Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)

Answers

1.61m :) use the photo below

Which of the following compounds is the most stable?​

Answers

Answer:

Hey mate......

Explanation:

This is ur answer......

fluorides

Thus, fluorides are the most stable while iodides are the least stable.

Hope it helps!

Mark me brainliest pls.....

Follow me! :)

Answer:

LICI

Explanation:

a p e x :)

What is the name of PbS2

Answers

Answer:

Lead  sulfide.

Explanation:

Explain why water and syrup are able to mix?​

Answers

you can’t because the water would rise and the syrup consistency would not mix

The distance that is covered by the wave in one second is called​

Answers

Answer:

The distance that is covered by the wave in one second is called​ frequency.

Explanation:

Consider the Fischer ester synthesis of methyl benzoate from benzoic acid and methanol in the presence of sulfuric acid as a catalyst. A reaction was performed in which 3.8 g of benzoic acid was reacted with excess methanol to make 2.0 g of methyl benzoate. Calculate the theoretical yield and percent yield for this reaction.

Answers

Answer:

48.8%

Explanation:

The reaction has a 1:1 mole ratio so;

Number of moles of benzoic acid reacted = mass/molar mass = 3.8 g/122.12 g/mol = 0.03 moles

So;

0.03 moles of methyl benzoate is formed in the reaction

Mass of methyl benzoate formed = 0.03 moles * 136.15 g/mol = 4.1 g

percent yield = actual yield/theoretical yield * 100/1

percent yield = 2.0 g/4.1 g * 100 = 48.8%

What is the percent yield of LiCl if I produced 30.85g LiCl and my theoretical yield was calculated to be 35.40g LiCl?

Answers

Answer:

87.15%

Explanation:

To find percent yield, we can use this simple equation

[tex]\frac{Actual}{Theoretical} *100[/tex]

Where "Actual" is the amount in grams actually collected from the reaction, and "Theoretical" is, well, the theoretical amount that should have been produced.

They give us these values, so to find the percent yield, just plug the numbers in.

[tex]\frac{30.85}{35.40} *100\\\\ =87.15[/tex]

So, the percent yield is 87.15%

An easy trick to remember how to do this is just to divide the smaller number by the bigger number and move the decimal back two places. If you have a percent yield greater than 100%, something is wrong in the reaction.

To determine the concentration of a sodium thiosulfate solution as in this experiment, a student pipetted 25.0 mL of 0.0100 M potassium iodate (KIO3) solution into a 125 mL Erlernmeyer flask. Potassium iodide and sulfuric acid were added as in this experiment. The titration needed 15.21 mL of the sodium thiosulfate to reach the end point. What is the concentration of the sodium thiosulfate solution

Answers

Answer:

0.0986M is the concentration of the Na₂S₂O₃ solution

Explanation:

Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:

KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI

To solve this question we must find the moles of sodium thiosulfate that reacts as follows:

Moles KIO₃:

0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃

Moles Na₂S₂O₃:

2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃

Molar concentration:

1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =

0.0986M is the concentration of the Na₂S₂O₃ solution

How many moles of Ag can be obtained from 2.77 moles Cu using the following
balanced reaction?
2AgNO3
+ Cu
Cu(NO3)2
+ 2Ag

Answers

Answer:

2.77×2= 5.4 mol Ag can be obtained

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