Answer:
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Explanation:
The balanced reaction is:
Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Na₂CO₃: 1 moles CO₂: 1 moleH₂O: 1 mole NaHCO₃: 2 molesBeing the molar mass:
Na₂CO₃: 106 g/moleCO₂: 44 g/moleH₂O: 18 g/moleNaHCO₃: 84 g/moleThen by stoichiometry the following quantities of mass participate in the reaction:
Na₂CO₃: 1 mole* 106 g/mole= 106 gCO₂: 1 mole* 44 g/mole= 44 gH₂O: 1 mole* 18 g/mole= 18 gNaHCO₃: 2 moles* 84 g/mole= 168 gYou can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?
[tex]mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}[/tex]
mass of Na₂CO₃= 630.95 grams
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃