Answer:
[tex]m_{solution}=446.4g[/tex]
Explanation:
Hello,
In this case, by-mass percent is computed in terms of the mass of the solute and the mass of the solvent as shown below:
[tex]\% m=\frac{m_{solute}}{m_{solution}} *100\%[/tex]
Thus, solving for the mass of the solution, we obtain:
[tex]\frac{x}{y} m_{solution}=\frac{m_{solute}}{\% m}*100\%\\ \\m_{solution}=\frac{62.5g}{14.0\%}*100\% \\\\m_{solution}=446.4g[/tex]
Regards.
How much would it cost to drive from San Jose to Las Vegas (847 miles) is gasoline cost
$3.20 per gallon and your car gets 28 miles per gallon?
Answer:
$96.8
Explanation:
divide 847 by 28 because each gallon gets the car 28 miles and there's 847 miles in total and you get 30.25 and you multiple that by the cost so it be 30.25×3.20=$96.8
A pool is 41.4 m long and 28.2 m wide. If the average depth of water is 5.00 ft, what is the mass (in kg) of water in the pool? Enter your answer in scientific notation. The density of water is 1.0 g/mL.
Answer:
[tex]m=1.779x10^{6}kg[/tex]
Explanation:
Hello,
In this case, mass and volume define density as shown below:
[tex]\rho =\frac{m}{V}[/tex]
Whereas the mass is computed by:
[tex]m=\rho *V[/tex]
Thus, knowing the dimensions of the pool, we compute its volume:
[tex]V=41.4m*28.2m*(5.00ft*\frac{1m}{3.281ft} )=1779.15m^3[/tex]
But in cubic centimetres:
[tex]V=1779.15m^3*\frac{1x10^6cm}{1m^3} \\\\V=1.779x10^{9}cm^3[/tex]
Therefore, the mass in kilograms turns out:
[tex]m=1\frac{g}{cm^3} *1.779x10^{9}cm^3*\frac{1kg}{1000g}\\ \\m=1.779x10^{6}kg[/tex]
Regards.
Read this for the next two problems: When a 125 g obsidian rock is placed into a graduated
cylinder, the water level rises from the 15 mL to the 47 mL mark.
29. What is the rocks volume?
a) 62 mL
b) 32 mL
c) 15 mL
d) 47 mL
30. What is the rocks density?
a) 0.25 g/mL b) 1 g/mL
c) 2.0 g/mL d) 3.9 g/mL
31. If you add a mass of 3.7 g to a mass of 9.495 9. the sum with the correct number of
significant digits is
a) 13.29 b) 13.209 c) 13.199 d) 13.1959
Answer:
29. Option (b) 32 mL
30. Option (d) 3.9 g/mL
31. Option (d) 13.195 g
Explanation:
29. Determination of the volume of the rock.
Volume of water = 15 mL
Volume of water + Rock = 47 mL
Volume of Rock =.?
Volume of Rock = (Volume of water + Rock) – (Volume of water)
Volume of Rock = 47 – 15
Volume of Rock = 32 mL
30. Determination of the density of the rock.
Density of a substance is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, the density of the rock can be obtained as follow:
Mass (m) of Rock = 125 g
Volume (V) of Rock = 32 mL
Density (D) =?
D = m/V
D = 3.9 g/mL
Therefore, the density of the rock is 3.9 g/mL.
31. Determination of the sum of 3.7 g and 9.495 g.
The sum of 3.7 g and 9.495 g can be obtained as follow:
3.7 g + 9.495 g = 13.195 g
Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides.b. cocamide DEA.c. folic acid.d. iron.e. chromium ion.f. peroxide.g. lauryl glucoside.h. disodium phosphate.
Answer:
The options are a, c, d and h
Explanation:
The following ingredients can be found in a packaged food cereal
Monoglycerides are used as emulsifiers and they are also added to cereals to improve there texture and shelf-life.
Folic acid or folate is a vitamin that most cereals are fortified with to act as dietary supplement.
Iron is an essential mineral element, meaning your body needs it (basically for blood production). Cereals are usually fortified with iron for this reason.
Disodium phosphate is also a food additive used to improve the quality of food and is also found in cereals.
Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 35.6 g?
volume
mL
Answer:
45.069 mL
Explanation:
mass/density=volume.
If we fill in the numbers provided, we would have:
35.6/0.7899=45.069
Don't forget to add your measurements!
45.069 mL
A gold nugget has a mass of 24.41 G , What is the mass in ounces ? (1 oz =28.3459)
Answer:
24.41 grams=0.861 ounces
Explanation:
Since, 1 ounce = 28.3495 grams
We need to find the mass of 24.41 grams of a gold nugget.
We can say that, [tex]1\ \text{gram}=\dfrac{1}{28.3459}\ \text{ounces }[/tex] ....(1)
To find mass of 24.41 grams of a gold nugget multiply RHS of the equation 1 by 24.41.
So,
[tex]24.411\ \text{gram}=\dfrac{1}{28.3459}\times 24.41\ \text{ounces }\\\\=0.861\ \text{ounce}[/tex]
Therefore, 24.41 grams is equal to 0.861 ounces.
Which one of the following is an example of a covalent network solid?a.SiO2b. Kc. I2d. CaCl2e. None of these.
Answer:
SiO2
Explanation:
A covalent network solid is a solid substance held together by a network of covalent bonds. Silicon dioxide forms a three dimensional covalent network solid structure.
Silicon dioxide is comprised of a network in which each silicon atom is at the centre of a tetrahedron of four oxygen atoms. Each of the oxygen atoms is also bonded to another silicon atom, at the centre of its own tetrahedron of oxygen atoms. This gives rise to a crystalline solid structure which is hard, having a high melting point.
Calculate the mass of 2.500 mol of magnesium hydroxide.
Answer:145g
Explanation:
The pH of a solution is 8.83±0.048.83±0.04 . What is the concentration of H+H+ in the solution and its absolute uncertainty?
Answer:
The concentration of [tex]H^{+}[/tex] is 1.48 × [tex]10^{-9}[/tex] M
The absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M
The concentration of [tex]H^{+}[/tex] is written as 1.48(±0.12) × [tex]10^{-9}[/tex] M
Explanation:
The pH of a solution is given by the formula below
pH = [tex]-log_{10}[{H^{+}][/tex]
∴ [tex][H^{+}] = 10^{-pH}[/tex]
where [tex][{H^{+}][/tex] is the [tex]H^{+}[/tex] concentration
From the question,
pH = 8.83±0.04
That is,
pH =8.83 and the uncertainty is ±0.04
First, we will determine [tex][{H^{+}][/tex] from
[tex][H^{+}] = 10^{-pH}[/tex]
[tex][{H^{+}] = 10^{-8.83}[/tex]
[tex][{H^{+}] = 1.4791[/tex] × [tex]10^{-9}[/tex] M
[tex][{H^{+}] = 1.48[/tex] × [tex]10^{-9}[/tex] M
The concentration of [tex]H^{+}[/tex] is 1.48 × [tex]10^{-9}[/tex] M
The uncertainty of [tex][{H^{+}][/tex] ( [tex]U_{[H^{+}] }[/tex] ) from the equation [tex][H^{+}] = 10^{-pH}[/tex] is
[tex]U_{[H^{+}] } = 2.303 \\[/tex] × [tex]{[H^{+}] }[/tex] × [tex]U_{pH }[/tex]
Where [tex]U_{[H^{+}] }[/tex] is the uncertainty of [tex][{H^{+}][/tex]
[tex]U_{pH }[/tex] is the uncertainty of the pH
Hence,
[tex]U_{[H^{+}] }[/tex] = 2.303 × 1.4791 × [tex]10^{-9}[/tex] × 0.04
[tex]U_{[H^{+}] }[/tex] = 1.36 × [tex]10^{-10}[/tex] M
[tex]U_{[H^{+}] }[/tex] = 0.12 × [tex]10^{-9}[/tex] M
Hence, the absolute uncertainty of [tex][{H^{+}][/tex] is ±0.12 × [tex]10^{-9}[/tex] M
If you put 5.0 mL of alcohol into 100.0 mL of water, what is the solvent and what is the solution?
Sulfur hexachloride is an ionic compound. True False
Sulfur hexachloride is not an ionic compound, it is a covalent compound.
Ionic compounds are formed by the bond of metals with nonmetals, in which metals lose electrons to nonmetals that gain electrons. In that way, they all complete their octets.
Covalent compounds are formed by the bond between nonmetals, in which both nonmetals share pairs of electrons to complete their octets.
Sulfur hexachloride (SCl₆) is formed by 2 nonmetals, sulfur and chlorine. Thus, it is not an ionic compound but a covalent one.
Sulfur hexachloride is not an ionic compound, it is a covalent compound.
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i need to know the measurements of this to the appropriate amount of significant figures
Answer:
[See Below]
Explanation:
25 ml.
Abby fills a graduated cylinder with 3 mL of water. She then drops a
small rock into the cylinder, and the water level rises to the 5 ml
mark. What is the volume of the rock?
mL
Answer: 2ML
Explanation: all you needed to do was to subtract
What is the major driving force for losing a proton as the last step in an electrophilic aromatic substitution reaction?
Answer:
Explanation:
In the following reaction we have shown an example of aromatic substitution reaction .
C₆H₆ + RCl = C₆H₅R + HCl
This reaction takes place in the presence of catalyst like AlCl₃ which is a lewis acid .
First of all formation of carbocation is made as follows .
RCl + AlCl₃ = R⁺ + AlCl₄⁻
This R⁺ is carbocation which is also called electrophile . It attacks the ring to get attached with it .
C₆H₆ + R⁺ = C₆H₅R⁺H.
The complex formed is unstable , though it is stabilized by resonance effect . In the last step H⁺ is kicked out of the ring . The driving force that does it is the steric hindrance due to presence of two adjacent group of H and R⁺ at the same place . Second driving force is attack by the base AlCl₄⁻ that had been formed earlier . It acts as base and it extracts proton ( H⁺ ) from the ring .
C₆H₅R⁺H + AlCl₄⁻ = C₆H₆ + AlCl₃ + HCl .
The formation of a stable product C₆H₆ also drives the reaction to form this product .
Write the chemical symbols for three different atomic anions that all have 34 protons.
Answer:
Explanation:
First of all it should be noted that number of protons is called atomic number in chemistry. The atom that has the atomic number of 34 in the periodic table is Selenium (Se). Anions are negatively charged atoms; the negative charge means the atoms have lost electron(s) while still having the same number of protons.
From the above, we can deduce that the only atom that can have 34 protons is Se and for it to become negatively charged (anion), it must lose electron(s).
The different chemical symbols thereof will be Se⁻,Se²⁻, Se³⁻ if it loses one, two or three electrons respectively while still having the atomic number of 34
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f-orbital can accommodate maximum of... electron?
Explanation:
S= 2
P=6
D=10
F= 14
F orbital holds a maximum of 14 electrons
Answer:
14.
Explanation:
The f level consists of 7 orbitals and each can accommodate up to 2 electrons.
a strong acid will react with a molecule of water to form a(n) _ ion
Answer:
hydroxide ion
Explanation:
acids produce hydrogen ion when dissolved in water
2 N2 (g) + O2 (g) ---> 2 N2O (g) H= +163.2 kj/mol
How much heat is required to produce 25.0 g of N2O by this reaction? Show all calculations.
Answer:
46.3 kJ
Explanation:
Step 1: Write the thermochemical equation
2 N₂(g) + O₂(g) ⇒ 2 N₂O(g) ΔH= +163.2 kJ/mol
Step 2: Calculate the moles corresponding to 25.0 g of N₂O
The molar mass of N₂O is 44.01 g/mol.
25.0 g × (1 mol/44.01 g) = 0.568 mol
Step 3: Calculate the heat released when 0.568 moles of N₂O are produced
According to the thermochemical equation, 163.2 kJ are required per 2 moles of N₂O.
0.568 mol × (163.2 kJ/2 mol) = 46.3 kJ
For the neutralization reaction between methylamine and acetic acid, draw curved arrows to indicate the direction of electron flow. Draw curved arrows to show the movement of electrons in this step of the mechanism.
Answer:
This is required answer.
Explanation:
Given that,
The neutralization reaction between methylamine and acetic acid
We know that,
According to proton theory of acid and base,
An acid is a substance which denotes the hydrogen as proton.
Base is a substance which accept the proton.
We need to draw curved arrows to indicate the direction of electron flow
According to diagram,
Diagram shows the movement of electrons in this step of the mechanism.
Hence, This is required answer.
The reaction between nitric oxide and oxygen is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.
Answer:
2NO(g) + O2(g) ---> 2NO2(g)
Explanation:
The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;
NO(g) +O2(g) ----> NO2(g) + O(g)
NO(g) + O(g) ----> NO2(g)
Hence overall balanced reaction equation;
2NO(g) + O2(g) ---> 2NO2(g)
Answer:
NO(g)+O(g)---->NO_2(g)
Explanation:
Give a systematic name for the following compound: CH3CH2CHCH2CHCH3, with a CH3 group attached to the third (from left to right) carbon and a Br atom attached to the fifth carbon.
Answer:
2-bromo-4 methylheane
Explanation:
Numbering from right to left, the bromine atom falls on the second (2) carbon, while the methyl branch on the 4th.
The systematic naming (IUPAC) of haloalkanes follows the alphabetical rule in naming the substituents, be it alkyl groups or halogens.
I hope the explanation would suffice.
The moon appears larger than most of the planets in our solar system because ______?
its closer than us than the planets
:)
What is the volume of a sample that has a mass of 20 g and a density of 4 g/mL?
Answer:
The volume of a sample is 5 ml.
what could cause a test tube to crack?
Answer:
heated test tube in cold water
modern commercial airlines are largely made of aluminum, and light and strong metal. But the fact that aluminum is cheap enough that airplanes can be made out of it is a bit of historical luck. before the discovery of the Hall-Heroult process in 1886, aluminum was as rare and expensive as gold. What would happen if airplanes had to be made of steel? The fuselage of a Boeing 787, which can carry 400 passengers, is approximately a hollow aluminum cylinder without ends, 70.7 m long, 6.5 m wide, and 2.5 mm thick. Suppose this fuselage was made of steel (density 7.87 g/cm^{3}) instead of aluminum (density 2.7g/[tex]cm^{3}), and let's say the average passenger has a mass of 81 kg. We'll also assume the engines can't lift any greater mass than they already do. Calculate the number of passengers that the Boeing 747 could carry if its fuselage was made of steel.
Answer:
170 passenger . ( approx )
Explanation:
Total volume of metal making fuselage = π ( r₂² - r₁² ) l
r₂ is outer radius of cylindrical tube like fuselage
= 6.5 / 2 + .0025 = 3.2525 m
r₁ is inner radius of cylindrical tube like fuselage
= 6.5 / 2 = 3.25 m
l = 70.7 m
Total volume of fuselage = π ( r₂² - r₁² ) l
= 3.14 x 70.7 x ( 3.2525² - 3.25² )
= 221.998 ( 10.57875 - 10.5625)
= 3.60747 m³
If it is made of aluminium , its mass
= volume x density
= 3.60747 x 2700 kg
= 9740.16 kg
weight of passenger = 81 x 400 = 32400 kg
Total mass = 32400 + 9740.16
= 42140.16 kg
If it is made of iron , its mass
= volume x density
= 3.60747 x 7870 kg
= 28390.79 kg
If number of passenger required be n
81 n + 28390.79 = 42140.16 ( as per condition given )
n = 170 passenger . ( approx )
PLEASE ANSWER FAST!
A sphere with a mass of 12 g has a radius measuring 2 cm. What is its density?
Answer:
0.36 g/cm3 I hope this helps
Answer:
0.36 hope it helped
Explanation:
QUESTION 4 What is the maximum pressure (in Torr) that will afford a N2 molecule a mean-free-path of at least 1.00 m at 25 oC
Answer:
Maximum pressure P = 4.9 × 10⁻⁵ Pa
Explanation:
From the information given, the mean free path can be expressed with the formula:
[tex]\lambda = \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times P}[/tex]
Making Pressure P the subject of the formula because we intend to find the maximum pressure, we have:
[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]
At standard conditions
R = gas constant = 8.314 J/mol.K
T = temperature at 25°C = (273 + 25) = 298 K
π = pi = 3.14
d = (364× 10⁻¹²m)²
[tex]N_A[/tex] = avogadro's number = 6.023 × 10²³
λ = mean free path = 1.0 m
[tex]P= \dfrac{RT}{\sqrt{2} \pi \times d^2 \times N_A \times \lambda }[/tex]
[tex]P= \dfrac{8.314 \ J/mol.K \times 298 \ K}{\sqrt{2}\times (3.14) \times (364 \times 10^{-12} \ m) ^2 \times 6.023 \times 10^{23}/mol \times 1.0 \ m }[/tex]
P = 0.007 kg/m.s²
P = 0.007 Pa
[tex]P = 0.007 Pa \times \dfrac{0.007 \ torr}{1 \ Pa}[/tex]
P = 4.9 × 10⁻⁵ Pa
Which describes the correct procedure when converting a number from scientific notation to standard notation? A If the power of 10 is positive, move the decimal point to the left. BIf the power of 10 is positive, move the decimal point to the right. CIf the number being converted is greater than 10, move the decimal point to the left. DIf the number being converted is greater than 10, move the decimal point to the right.
Answer:
I think it's B
Explanation:
I think it is b because if the number is positive the zeroes will be on the left so you move the decimal to the right to get rid of the zeroes.
Calculate the pH of a buffer solution prepared by mixing 200 mL of 0.10 M NaF and 100 mL of 0.050 M HF.
Answer:
[tex]pH=3.74[/tex]
Explanation:
Hello,
In this case, by using the Henderson-Hasselbach equation one could compute the pH considering that the pKa of hydrofluoric acid, HF, is 3.14:
[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]
Whereas the concentration of the base and acid are computed by considering the mixing process with a total volume of 300 mL (0.3 L):
[tex]n_{HF}=0.1L*0.05mol/L=0.005molHF\\\\n_{NaF}=0.2L*0.1mol/L=0.02molNaF[/tex]
[tex][HF]=\frac{0.005molHF}{0.3L}=0.017M[/tex]
[tex][NaF]=\frac{0.02molHF}{0.3L}=0.067M[/tex]
Therefore, the pH turns out:
[tex]pH=3.14+log(\frac{0.067M}{0.017M} )\\\\pH=3.74[/tex]
Regards.
What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S
The question is incomplete; the complete question is;
What alkene would give the products below after reaction with O3, followed by reduction with (CH3)2S? Write the condensed structural formula (CH3)2C=O and CH3-CH2-CH=O
Answer:
2-methylpent-2-ene (C6H12)
Explanation:
Ozonolysis is a wonderful method for determining the location of double bonds in an alkene since the oxygenated carbons in the carbonyl compounds formed after ozonolysis are the ones that were initially joined by the double bonds in the original alkene.
Hence if an alkene yields (CH3)2C=O and CH3-CH2-CH=O, the original alkene must be C6H12, that is, 2-methylpent-2-ene