How many grams is 2.393 x 10^24 atoms of CI
70.45 g CI
140.9 ga
140.9 mole CI
70.45 mole CI

Answers

Answer 1

Answer:

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole of the compound, 2.393*10²⁴ atoms are contained in how many moles?

[tex]amount of moles=\frac{2.393*10^{24} *1 mole}{6.023*10^{23} }[/tex]

amount of moles= 3.973

If the molar mass of Cl is 35.453 [tex]\frac{g}{mole}[/tex], then the amount of mass that contains 3.973 moles can be calculated as:

3.973 moles*35.453 [tex]\frac{g}{mole}[/tex]= 140.85 grams ≅ 140.9 grams

There are 140.9 grams in 2.393*10²⁴ aotms of Cl.


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Answer:

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Explanation:

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Answer:

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Answers

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Answer:

Explanation:

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Answer:

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2

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Answer:

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Explanation:

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Answer:

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Answers

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Answers

Answer:

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Sorry I can’t help you with this question

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Answers

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Only awnser #5#6#7#8 please 20 points! And i will mark brainliest.

Answers

5. convection zone
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Explanation:

How many milliliters of a 3.28 M copper (II) nitrate Cu(NO3)2
solution are needed to provide a total of 146.59 g of Cu(NO3)2?
Use 187.56 g/mol as the molar mass of solute. Solve your answer
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Answers

Answer:

237.80mL

Explanation:

Molarity of a solution can be calculated using the formula;

Molarity = number of moles (n) ÷ volume (V)

However, we first need to calculate the number of moles of Cu(NO3)2 by using the formula:

moles = mass/molar mass

Molar mass of Cu(NO3)2 = 187.56 g/mol

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Answers

Answer:

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