Answer:
[tex]\boxed {\boxed {\sf 1290 \ g \ PI_3}}[/tex]
Explanation:
We want to convert from moles to grams, so we must use the molar mass.
1. Molar MassThe molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.
Phosphorus (P): 30.973762 g/molIodine (I): 126.9045 g/molNote that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.
I₃: 126.9045 * 3=380.7135 g/mol PI₃: 30.973762 + 380.7135 = 411.687262 g/mol 2. Convert Moles to GramsUse the molar mass as a ratio.
[tex]\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}[/tex]
We want to convert 3.14 moles to grams, so we multiply by that value.
[tex]3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \ mol \ PI_3}[/tex]
The units of moles of PI₃ cancel.
[tex]3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }[/tex]
[tex]1292.698 \ g\ PI_3[/tex]
3. RoundThe original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.
1292.698The 2 in the ones place tells us to leave the 9.
[tex]1290 \ g \ PI_3[/tex]
3.14 moles of phosphorous triiodide is approximately equal to 1290 grams of phosphorus triodide.
please mark all that apply!
Answer:
F G there you go the guy on top is right
Explanation:
F G
It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?
Answer:
5/8 M
Explanation:
NaOH + HCl ====> NaCl + H2O
in 25 mL of 0.5M acid, we have 1/80 Mol of HCl
it mean we must have 1/80 Mol of NaOH.
20 mL = 1/50 L
(1/80)Mol / (1/50)L = 5/8 M
EMERGENCY HELP ME OUT
Answer:
D, The volume will be multiplied by a factor of 4
Explanation:
First find the height
V = π(r^2)h
Plug in what we know
83 = π(3^2)h
83 = π(9)h
83 = (9π)h
9[tex]\pi[/tex] = 28.27
83/28.27 = (28.27)h/28.27
h = 2.94
Then find the volume of the new can by doubling the radius
3 x 2 = 6
r = 6
V = π(r^2)h
V = π(6^2)2.94
V = π(105.84)
V =332.51
For the first one, they rounded to the nearest whole #, so let's do the same.
V = 333
Then divide 333 by 83 to get 4
Therefore, the volume will be multiplied by a factor of 4
The 500 cubic centimeter of 0.250 M Na2SO4 solution,
added to an aqueous solution of 15.00 grams of barium
chloride, resulted in the formation of a white precipitate of
barium sulfate. How many moles and how many grams of
barium sulfate are formed, respectively?
Answer:
0.072 moles, 16.776g.
Explanation:
The reaction of Na2SO4 and BaCl2 occurs as follows:
Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2NaCl(aq)
To solve this question we must find the moles of each reactant. As the reaction is 1:1, the reactant with the low number of moles is limiting reactant. The moles of limiting reactant = Moles BaSO4. The mass can be obtained with the molar mass of BaSO4 -233.38g/mol-
Moles Na2SO4:
500cm³ = 0.500L * (0.250mol / L) = 0.125 moles
Moles BaCl2 -Molar mass: 208.23g/mol-
15.00g * (1mol / 208.23g) = 0.072 moles
The moles of BaSO4 are 0.072 moles and its mass is:
0.072 moles * (233.38g / mol) = 16.8g ≈ 16.776g
Which of the following phase changes describes what is
happening in the following endothermic process?
H20 (1) + heat --> H2O (g)
O melting
o freezing
o boiling
O condensing
Answer:
I think the answer is boiling
based on the graph below, which statement
Answer:
4. Atmospheric pressure decreases as altitude increases.
Explanation:
hope this helps and is right. p.s i really need brainliest :)
4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the
volume of the gas? Remember that R = 0.0821 L x atm/Kx mol AND that you must convert °C to K.
Fill in the variables chart:
Answer:
15.06 L
Explanation:
Using the ideal gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information provided in this question,
P = 3.50 atm
n = 1.9 moles
V = ?
T = 65°C = 65 + 273 = 338K
Using PV = nRT
V = nRT/P
V = (1.9 × 0.0821 × 338) ÷ (3.5)
V = 52.725 ÷ 3.5
V = 15.06 L
in order to balance the reaction, what number needs to go in front of F(2)?
Answer:
NA + F2 = NAF - Chemical Equation Balancer.
2 Na + F 2 → 2 NaF
Na is a reducing agent, F 2 is an oxidizing agent. ; Pale-yellow to greenish gas with a pungent, irritating odor.
Need help ASAP ( will give 50 points)
Select the correct answer. Which galaxies have light smoothly spread across the
galaxy? A. spiral galaxy B. irregular galaxy C. lenticular galaxy D. elliptical galaxy
Answer:
Your answer would be D, Hope this helps.
What is the correct name for the chemical formula N408?
Answer:
molar mass (molar weight)
Explanation:
Is this an alpha or beta decay?
Answer:
alpha decay
Explanation:
Polar bears are adapted to stay warm by growing thick fur. These organisms most likely live in a what
Answer:
They live in the open snow
Explanation:
How many moles of Chlorine gas are required to produce 5.35 moles of NaCl in this
reaction?
Answer:
2.675 moles of Chlorine gas are required
Explanation:
Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:
Cl2 + 2NaBr → 2NaCl + Br2
Where 1 mole of chlorine gas produce 2 moles of NaCl
Thus, to produce 5.35 moles of NaCl are required:
5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =
2.675 moles of Chlorine gas are requiredHow many atoms of Neon are in 65.0 L of Neon gas?
Answer:
65.0 g NH3 x
mol NH3
17.04 g NH3
x
6.02x1023 NH3 molecules
mol NH3
= 2.30x1024 NH3 molecules
(have uh good day)
Answer:
mole of Neon = 65L/22.4L
=2.901moles of Neon
1 mole of a substance contains 6.022x10^23atoms
So 2.901moles will contains
2.901 x 6.022x10^23atoms
=1.747 x 10^24atoms
6 a 100 sample of Au - 198 Au 198 be? Decays to 3.125 g in 13.5 days, what would the half-life of au198 be?
Answer:
Half-life = 2.7 days
Explanation:
The radioactive decay of an isotope follows the equation:
Ln[A] = -kt + ln[A]₀
Where [A] could be taken as the amount of A after t time, k is decay constant, [A]₀ initial amount of A.
Replacing to solve k:
Ln[3.125g] = -k*13.5days + ln[100g]
-3.465736 = -k*13.5days
k = 0.2567days⁻¹
Half-life is:
half-life = ln2 / k
Half-life = 2.7 days
What is SnO2 compound name
what is acid? Explain it
Answer:
An acid is a chemical that is posining or sometimes not
Explanation:
This is the best I could explain brainliest
Which half-reaction shows conservation of charge? * 5 points A) Cu + e– → Cu+ B) Cu2+ + 2e– → Cu C) Cu+ → Cu + e– D) Cu2+ → Cu + 2e–
Answer:
B) Cu2+ + 2e– → Cu.
Explanation:
Hello there!
In this case, in the regard of redox reactions, we must keep in mind that half-reactions show us how the flow of electrons when an element undergoes a change in its oxidation state, say increasing or decreasing. In such a way, if the element is oxidized, increase the oxidation state, we add electrons on the right side and the contrary if the element is reduced, decrease the oxidation state.
In such a way, we can see that the reaction B) Cu2+ + 2e– → Cu, shows how the Cu2+ cations are reduced by adding electrons to produce Cu and thus, conserve the charge.
Best regards!
A dead tree is not an important part of an ecosystem. T or F
A 400-gram sample of iron, initially at 21 0Cis heated to 65 0C. Determine the energy attained (in Joules) by the iron sample if the specific heat capacity of iron is 0.11 cal/g0C
Answer:
Q = 8100 J.
Explanation:
Hello there!
In this case, according to the given information, we can infer this is a question about calorimetry, and we can use the general heat equation to solve this one:
[tex]Q=mC(T_2-T_1)[/tex]
Thus, we plug in the given mass, specific heat and temperatures to obtain the energy involved in this heating process:
[tex]Q=400g*0.11\frac{cal}{g\°C} (65\°C-21\°C)\\\\Q=1936cal[/tex]
Which converted to Joules turns out to be:
[tex]Q=1936cal*\frac{4.184J}{1cal} \\\\Q=8100J[/tex]
Regards!
What is the percent by volume of 12.5 mL of ethanol in 250 mL of water?
3%
5%
4%
6%
10 points. Please help.
A balloon can hold 10 liters of a gas. If you blow up this balloon with 2 moles of oxygen gas at a pressure of 0.76 atmospheres, what is the temperature of the balloon? Pay attention to the unit of pressure used.
Answer:
The temperature of the balloon is 46.34 K.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
P= 0.76 atmV= 10 Ln= 2 molesR= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]T= ?Replacing:
0.76 atm* 10 L= 2 moles* 0.082 [tex]\frac{atm*L}{mol*K}[/tex] *T
Solving:
[tex]T=\frac{0.76 atm* 10 L}{2 moles* 0.082\frac{atm*L}{mol*K}}[/tex]
T= 46.34 K
The temperature of the balloon is 46.34 K.
How many significant figures are in the measurement 1.3000 meters
Answer:
5
Explanation:
mark me brainliest!
3. Which model has properties most similar to chlorine?
Model A
Model B
Model C
Model D
Answer:
bnsjsbbakakaisbsbwnsjznss
Explanation:
cnsjzjsnsnsjs ssnsnsnzksmnznnzna
a cell was taken from dolly the sheep and used to make a geneticly identical copy of her the copy lived to be 6 years old what is that called?
Explanation:
dolly was cloned I guess
What is the pOH of a solution of pH 3 acid? (Kw= 1.0 x 10-14)
Answer:
pOH = 11
Explanation:
The pH is an unit of concentration widely used in chemistry to find the quality of a solution.
To solve this question we must, as first, find the [H+] using the pH:
[H+] = 10^-pH
[H+] = 10^-3
Now, using kw:
kw = 1.0x10-14 = [H+] [OH-]
1.0x10-14 = [10^-3] [OH-]
[OH-] = 1.0x10-11
pOH = -log [OH-]
pOH = 11you can test carbon dioxide gas with
Answer:
you can test carbon dioxide gas with calcium hydroxide
hope this is what you're looking for
stay safe and have a nice day
✌◕ ◡ ◕✌
In a titration, a few drops of an indicator are added to a flask containing 35.0 milliiters of HNO3(aq) of unknown concentration. After 30.0 millliters of 0.15 M NaOH(aq) solution is slowly added o the flask, the indicator changes color, showing the acid is neutralized. Which choice is a correct numerical setup for calculating the concentration of the HNO3(aq) solution
Answer:
0.13M HNO3 is the concentration of the unknown
Explanation:
Nitric acid, HNO3, reacts with NaOH as follows:
HNO3 + NaOH → H2O + NaNO3
Where 1mol HNO3 reacts with 1mol NaOH
To find the concentration of HNO3 we must find, as first, the moles NaOH added = Moles HNO3 in the solution:
30mL * (1L / 1000mL) * (0.15mol / 1L) = 0.0045 moles HNO3
In 35.0mL = 0.035L:
0.0045 moles HNO3 / 0.035L =
0.13M HNO3 is the concentration of the unknown
what is oxidation of carbon compounds write the equation of these and name the oxidising agent used here
Answer:
It is equal
Explanation:
It is equal because there is the same amount of both and the measurment is correct.
When temperature drops, (for example from 20 degrees celsius to 10 degrees celsius)
a.) energy increases
b.) particles move slower
c.) particles collide more often
d.) pressure increases