How many grams are in 10.0 mol of Chromium?

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

Answer:

36.23 %

Explanation:

Let's assume we have 1 mol of FeCl₂ · 4H₂O. In that case we would have:

Now we can calculate the percent by mass of water:

Answer:

a. Speed up, lose

Explanation:

#CARRYONLEARNING

Answer:

b. speed up, gain

Explanation:

Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

Answer:

0.00011 JK.

The process does NOT violate the second law of thermodynamics

Explanation:

The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.

=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.

The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.

The change in entropy of the cold container = 1/295 = 0.00339 J/K.

Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.

Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.

The process does NOT violate the second law of thermodynamics.

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

Answer:

sorry i dont know

Explanation:

Answer:

Pretty sure the answer is B

Answer:

neon gas

Explanation:

neon is a noble gas, meaning it has a full outer shell of elections. this means it is stable and is very unlikely to have a reaction with another substance.

Answer:

all i can help you with is one of them is Canada. If im

wrong i am sorry.

Explanation:Refer to the map of "The Major North American Land Biomes" to answer the question.

Answer:

is Canada and Texas

good luck and hope it helps

Cuz D is cyclo-thingy molecule and its a sugar

(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)

Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.

Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]

The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.

Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.

Therefore, option D. galactose is the monosaccharide.

Learn more about monosaccharides here:

https://brainly.com/question/5282729

Answer:

B

Explanation:

All elements on both sides of the equation have the same amount of moles

Answer:

Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.

Explanation:

Anabolic steroid is a drug that plays the role of testosterone.

Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.

Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.

Answer:

Parasites take nutrients from another organism's body.

Explanation:

Answer:

(a). (I). 0.816; 0.816

(ii). 0.917.

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Explanation:

So, without mincing words let's get straight into the solution to the question above.

(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;

P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).

P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).

The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.

The value of b = (1.2 + 1.2)/ 1.2 = 0.5.

Thus, putting the values into the equation (1) and (2) above gives;

NB: n = 3.

P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.

P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.

Using the (ii) carother's theory to Determine the critical extent of reaction gelation.

We have the following values for glycerol: k = 0.4, n = 3.

For ethylene glycol; k = 0.6, n = 2.

Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Answer:

Unlike other extinguishing agents - water, dry chemical, CO2, etc., a stable aqueous foam can extinguish a flammable or combustible liquid fire by the combined mechanisms of cooling, separating the flame/ignition source from the product surface, suppressing vapors and smothering. It can also secure for extended periods of time against reflash or reignition. Water, if used on a standard hydrocarbon fuel, is heavier than most of those liquids and if applied directly to the fuel surface, will sink to the bottom having little or no effect on extinguishment or vapor suppression. If the liquid fuel heats above 212ºF, the water may boil below the fuel surface throwing the fuel out of the contained area and spreading the fire. For this reason, foam is the primary fire-extinguishing agent for all potential hazards or areas where flammable liquids are transported, processed, stored or used as an energy source.

this is what I found, hope it helps

In contrast to other extinguishing agents such as water, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling, separating the flame source from the product surface, suppressing vapors, and smothering.

The term solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

It can also protect against ref lash or reignition for extended periods of time. Water is heavier than most liquids when used on a standard hydrocarbon fuel and will sink to the bottom if applied directly to the fuel surface, having little or no effect on extinguishment or vapor suppression.

If the liquid fuel heats above 212°F, water may boil beneath the fuel surface, releasing the fuel and spreading the fire.

Thus,  dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling.

To learn more about the solubility, follow the link;

https://brainly.com/question/22185953

#SPJ2

1. P = F/A; weight is a force (the force of gravity on an object), so divide the weight by the area given. P = 768 pounds/75.0 in² = 10.2 pounds/in².

2. Using the same equation from question 1, rearrange it to solve for A: A = F/P. We're given the force (the weight) and the pressure, so A = 125 pounds/3.25 pounds/in² = 38.5 in².

3. Again, using the same equation from question 1, rearrange it this time to solve for F: F = PA = (4.33 pounds/in²)(35.6 in²) = 154 pounds.

4. We can set up a proportion given that 14.7 PSI = 101 KPa. This ratio should hold for 23.6 PSI. In other words, 14.7/101 = 23.6/x; to solve for x, which would be your answer, we compute 23.6 PSI × 101 kPa ÷ 14.7 PSI = 162 kPa.

5. We are told that 1.00 atm = 760. mmHg, and we want to know how many atm are equal to 854 mmHg. As we did with question 4, we set up a proportion: 1/760. = x/854, and solve for x. 854 mmHg × 1.00 atm ÷ 760. mmHg = 1.12 atm.

6. The total pressure of the three gases in this container is just the sum of the partial pressures of each individual gas. Since our answer must be given in PSI, we should convert all our partial pressures that are not given in PSI into PSI for the sake of convenience. Fortunately, we only need to do that for one of the gases: oxygen, whose partial pressure is given as 324 mmHg. Given that 14.7 PSI = 760. mmHg, we can set up a proportion to find the partial pressure of oxygen gas in PSI: 14.7/760. = x/324; solving for x gives us 6.27 PSI oxygen. Now, we add up the partial pressures of all the gases: 11.2 PSI nitrogen + 6.27 PSI oxygen + 4.27 PSI carbon dioxide = 21.7 PSI, which is our total pressure.

Answer: Periodic Trends

Zeff increases because the positive charge of the nucleus increases while the outermost electrons stay the same distance from the nucleus (filling the same orbital). In other words, going across a period, the outermost electrons are more tightly held. This explains the trend in atomic radius.

It refers to how strongly an atom attracts electrons from other atoms. Electronegativity is a measure of an atom's ability to draw electrons towards itself, or the ability of the nucleus to hold electrons tightly

hope this helps have a great day❤️

Explanation:

Answer:

Answer:

2.14 g.

Explanation:

Hello!

In this case, since the mole ratio between nitrogen and oxygen is 2:5 respectively, we realize we first need the moles of nitrogen given it's atomic mass (14.01 g/mol):

[tex]n_N=0.750g*\frac{1mol}{14.01g}=0.0535molN[/tex]

Now, we calculate the moles of oxygen:

[tex]n_O=0.0535molO*\frac{5molO}{2molN}=0.134molO[/tex]

Then, we compute the moles of oxygen given its atomic mass (16.00 g/mol):

[tex]m_O=0.134molO*\frac{16.00gO}{1molO_2} \\\\m_O=2.14gO[/tex]

Best regards!

Answer:

Magnesium Sulfate

Explanation:

Answer:

magnesium sulfate

Explanation:

mg stands for magnesium and SO is sulfate

Answer:

170.68

Explanation:

PV=nRT or 22.4L for every mole of a gas at STP

Answer:

you have to shake the soda up

Answer:

4 g/cm³

Explanation:

Volume(V) = 60 cm³

mass (m) = 240 gm

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 240 / 60

= 4 g/cm³

Hope it will help

Answer:

That would be 4.17742995 * 10^13 :)

Explanation:

Answer:

A, B and D

Explanation:

Gas particles move randmly at high speed, colliding with each other

Answer:

[tex]C=0.152\frac{J}{g\°C}[/tex]

Explanation:

Hello!

In this case, when doing calorimetry problems, we need to use the following equation:

[tex]Q=mC(T_2-T_1)[/tex]

Whereas Q is the involved heat, m the mass, C the specific heat and T2 and T1 the final and initial temperatures respectively. Thus, since we need the specific heat, we proceed as follows:

[tex]C=\frac{Q}{m(T_2-T_1)}[/tex]

Thus, we plug in to obtain:

[tex]C=\frac{15,650J}{750g(250\°C-25\°C)} \\\\C=0.152\frac{J}{g\°C}[/tex]

Best regards!

Answer:

H-C-H

Explanation:

hydrogen plus carbon hdrocloide

Answer:

1 mol C₃H₈

Explanation:

Step 1: Write the balanced equation for the combustion of C₃H₈

C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.

Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced

We will use the established molar ratio.

3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈