Mass of Copper(I) chromate( CuCrO₄) = 19.75 g
Further explanationThe mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
[tex]\tt \large{\boxed{\bold{mol=\dfrac{m(mass)}{MW(molecular~weight)}}}[/tex]
0.11 mole of Copper(I) chromate( CuCrO₄) ⇒ MW=179.54 g/mol, so mass :
[tex]\tt mass=mol\times MW\\\\mass=0.11\times 179.54\\\\mass=19.75~g[/tex]
Calculate the molecular mass of the following mass of the following chemical compound
C6H12O6
24 G/mol
180 gmol
155 g/mol
19 g/mol
Answer:
132g/mol
Explanation:
Given compound:
C₆H₁₂O₆
Molecular mass of the compound.
This is the sum of the atomic masses of the given elements in the compound;
C = 12
H = 12
O = 6
Molecular mass = 6(12) + 12(1) + 6(16) = 180g/mol
Record the mass of the object based on the reading from the triple-beam balance. The mass of the object is ____ grams.
Hello!
[tex]\large\boxed{167g}[/tex]
Looking at the balance, we see that:
The middle beam reads 100g.
The top beam reads 60g.
The bottom beam reads 7g.
Add all of the numbers together to get the total mass:
100 + 60 + 7 = 167g.
The mass of the object is 167 grams.
Explanation:
A triple beam balance is a mass measuring instrument used in labs to measure the mass of a substance. It unit in which it measures is grams. It consists of three beams which are: The middle beam has Increments of 100 grams The front beam has Increments from 0 grams to 10 grams The farther beam has Increments of 10 gramsGiven :
Readings of all the scales of three beams of the triple beam balance of an object.
To find :
The mass of object whose reading on triple beam balance is given.
Solution:
Middle beam reader at 100 grams
Front beam reader at 7 grams
Farther beam reader at 60 grams
The mass of object:
[tex]100 grams + 7 garms + 60 grams = 167 grams[/tex]
The mass of the object is 167 grams.
Learn more about triple beam balance here:
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