Suppose you have a mixture of iron filings, sand, and sugar and you want to separate the three. Fill in the materials you expect to see at each step as you perform the actions shown to separate them. The materials you may expect to see are: iron filings, sand, sugar, and sugar water.
Answer:
Explanation:
mixture of iron filings, sand, and sugar
First Step - Iron Fillings
Use a magnet to separate the iron fillings from the mixture. Due to magnetic properties of the iron fillings, the magnets would attract the iron fillings and separate it from the mixture.
Second step - Sand
Place the sand and sugar mixture in water. The sugar would dissolve in water and the sand easily separated by filtration.
Third step - Sugar and Sugar water
Boil the sugar water to remove the water and place in the refrigerator for crystallization of the sugar.
Heat from the sun moves through space by the process of
es
A)
circulation.
B)
conduction
C)
convection.
D)
radiation
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of [tex]CH_4[/tex] is burned in excess oxygen gas
Given: [tex]CH _4 +2O_2\rightarrow CO_2+2H_2O[/tex] ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] weighs = 16 g
Thus we can say:
16 g of [tex]CH_4[/tex] on combustion releases heat = 802 kJ
Thus 24.8 g of [tex]CH_4[/tex] on combustion releases =[tex]\frac{802}{16}\times 24.8=1243.1kJ[/tex]
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
How many grams are there in 3.4 x 10^24 atoms of He?
Group of answer choices
2.07
5.7 g
0.57 g
20.7
Given :
Number of He atoms, [tex]n = 3.4\times 10^{24}[/tex] atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are [tex]6.022 \times 10^{23}[/tex] atoms in 4 g of He.
Let, number of gram He in [tex]3.4\times 10^{24}[/tex] atoms is x , so :
[tex]x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g[/tex]
Therefore, grams of He atoms is 22.58 g .
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g