Answer:
3.01×10²³ atoms of calcium
Explanation:
number of moles = number of atoms/Avogadro's constant
n = N/NA
N = n×NA = 0.500 mol×6.02×10²³ mol^-1
N = 3.01×10²³ atoms of calcium
What is the relative formula mass of a compound?
Answer:
To find the relative formula mass (M r) of a compound, you add together the relative atomic mass values (A r values) for all the atoms in its formula.
Explanation: Find the M r of carbon monoxide, CO. Find the M r of sodium oxide, Na 2O. The relative formula mass of a substance, shown in grams, is called one mole of that substance.
How much heat is released when 233 grams of water at room temperature (25C) is frozen into ice at -15C?
Answer: The amount of heat released when 233 grams of water at room temperature (25C) is frozen into ice at -15C is 17253.65 J.
Explanation:
As water converts into ice at [tex]0^{o}C[/tex]. So, the change in temperature is taking place from [tex]25^{o}C[/tex] to [tex]0^{o}C[/tex] and then from [tex]0^{o}C[/tex] to [tex]-15^{o}C[/tex].
So, amount of heat released by water is as follows.
[tex]q_{1} = m \times C \times (T_{2} - T_{1})\\= 233 g \times 4.18 J/g^{o}C \times (25 - 0)^{o}C\\= 24348.5 J[/tex]
m = mass of substance
C = specific heat of water = [tex]4.18 J/g^{o}C[/tex]
[tex]C'[/tex] = specific heat of ice = [tex]2.03 J/g^{o}C[/tex]
The amount of heat released by ice is as follows.
[tex]q_{2} = m \times C' \times (T'_{2} - T'_{1})\\= 233 g \times 2.03 J/g^{o}C \times (-15 - 0)^{o}C\\= -7094.85[/tex]
Now, total heat released during this change is as follows.
[tex]\Delta H = q_{1} + q_{2}\\= 24348.5 J + (-7094.85) J\\= 17253.65 J[/tex]
Thus, we can conclude that heat released when 233 grams of water at room temperature (25C) is frozen into ice at -15C is 17253.65 J.
Which statement best explains what causes the phase change from solid ice to liquid water?
a.Heat is released as ice turns into liquid water.
b.The mass increases when ice turns into liquid water.
c.Heat is absorbed as ice turns into liquid water.
d.The hydrogen bonds prevent the absorption of heat.
2
CuCl2 +4KI -> 2 Cul + 4 KCI + 12
Answer:
Explanation:
This is an example of a limiting reactant question, and is very common as a general chemistry problem.
We first see the balanced equation, that is:
2CuCl2+4KI→2CuI+4KCl+I2
We first need to find the limiting reactant
We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.
Copper(II) chloride has a molar mass of
134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist
0.56g134.45g/mol≈4.17⋅10−3 mol
Potassium iodide has a molar mass of
166 g/mol . So, in 0.64 g of potassium iodide, there exist
if it wrong i am sorry
answer asap
Food caught on fire on a restaurant's stove. How much thermal energy was present?
A. only a little compared to the total amount of energy
B. a lot of the energy was thermal
C. none of the energy was thermal
D. it was mostly potential energy, not thermal
If a gas occupies 2.3 liters at a pressure of 1.9 atm, what will be its volume at a
pressure of 3.8 atm?
Answer:
Option C (1.2 L) is the correct option.
Explanation:
The given values are:
Pressure,
[tex]P_1=1.9 \ atm[/tex]
[tex]P_2=3.8 \ atm[/tex]
Volume,
[tex]V_1=2.3 \ L[/tex]
[tex]V_2=?[/tex]
As we know,
The gas equation is:
⇒ [tex]PV=nRT[/tex]
At constant temperature,
⇒ [tex]P_1 V_1=P_2 V_2[/tex]
or,
⇒ [tex]V_2=\frac{P_1 V_1}{P_2}[/tex]
By substituting the values, we get
⇒ [tex]=\frac{1.9\times 2.3}{3.8}[/tex]
⇒ [tex]=\frac{4.37}{3.8}[/tex]
⇒ [tex]=1.15 \ L[/tex]
or,
⇒ [tex]=1.2 \ L[/tex]
Copper (II) Oxide (CuO) has atoms that form which type of bond?
Answer:
Copper(II) oxide is a metal oxide that has the formula CuO. It has an ionic structure. It contains a copper(2+). Cupric oxide, or copper (II) oxide, is an inorganic compound with the chemical formula CuO.
Explanation:
I hope that helps you.
Which is a possible excited state configuration for Nitrogen?
A. 1-5-2
B. 2-5
C. 1-6
D. 2-5-1
an evacuated cylinder has a volume of 50 liters. if 20 liters of nitrogen fas and 20 liters of oxygen gas are pumped into this evacuated cylinder, how much of the cylinder is filled with the two gasses?
The nitrogen gas and the oxygen gas will both occupy 50 liters.
Volume of a gasLet us recall form the kinetic theory of gases that a gas is in constant random motion. The gas does not have a specific volume but takes on the volume of the container since it will expand and fill the container.
The volume occupied by the two gases will be the same as the volume of the container. Hence, the nitrogen gas and the oxygen gas will both occupy 50 liters.
Learn more about volume of a gas: https://brainly.com/question/4519953
Answer:
B. The entire container because gases will expand to fill it.
Explanation:
I took to test, plus it directly says this in the lesson
A child receives a balloon filled with 47 L of helium from a vendor at an amusement park. The temperature outside is 320 K. What will the volume of the balloon be when the child brings it home to an air-conditioned house at 295 K? Assume that the pressure stays the same. Answer in units of L.
Answer:
43.3 L
Explanation:
Applying,
V/T = V'/T'................... Equation 1
Where V = Initial volume of the ball0on, T = Initial temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon.
make V' the subject of the equation
V' = VT'/T................ Equation 2
From the question,
Given: V = 47 L, T = 320 K, T' = 295 K
Substitute these values into equation 2
V' = (47×295)/320
V' = 43.3 L
What are the parts of the glowstick? What are the chemicals inside?
Please help I need on this please and thank you
Explanation:
amount of baking soda = 2.01 g
---> 2.01 g NaHCO3 × (1 mol NaHCO3/84.007 g NaHCO3)
= 0.024 mol NaHCO3
mass of the product = 1.28 g
Possible reactions:
NaHCO3(s) ---> NaOH(s) + CO2(g)
0.024 mol NaHCO3 × (1 mol NaOH/1 mol NaHCO3)
= 0.024 mol NaOH × (39.997 g NaOH/1.mol NaOH)
= 0.96 g NaOH
2NaHCO3(s) ---> Na2O(s) + 2CO2(g) + H2O(g)
0.024 mol NaHCO3 × (1 mol Na2O/2 mol NaHCO3)
= 0.012 mol Na2O × (61.9789 g Na2O)
= 0.73 g Na2O
2NaHCO3(s) ---> Na2CO3(s) + CO2(g) + H2O(g)
0.024 mol NaHCO3 × (1 mol Na2CO3/2 mol NaHCO3)
= 0.012 mol Na2CO3 × (105.9888 g Na2CO3/1 mol Na2CO3)
= 1.27 g Na2CO3
Conclusion:
Based on the mass of the product in the crucible and comparing it with the predicted product mass in different reactions, I conclude that Na2CO3 is the most likely product in the crucible.
How does the difference in air pressure masses affect wind speed? When low air pressure and high air pressure masses are far apart, air moves quickly from low to high pressure areas. When low air pressure and high air pressure masses are far apart, air moves quickly from high to low pressure areas. When low air pressure and high air pressure masses are close together, air moves quickly from high pressure to low pressure areas. When low air pressure and high air pressure masses are close together, air moves quickly from low to high pressure areas; this creates stronger wind speeds.
Answer:
it is from the currents the movements cause
Explanation:
Answer:The greater the difference in pressure, the faster the winds. When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure. When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.
Explanation:
(NEED HELP ASAP) Which statement best describes a key difference between a solar and lunar eclipse?
A.
During a lunar eclipse, the moon passes through Earth’s shadow; during a solar eclipse, the moon's shadow moves across Earth.
B.
During a lunar eclipse, the moon’s shadow falls on Earth’s surface; during a solar eclipse, the moon passes through Earth’s shadow.
C.
Solar eclipses happen once every ten years while lunar eclipses occur with every new moon.
D.
Solar eclipses occur with every new moon while lunar eclipses happen every five to six years.
Answer:
a
Explanation:
Gravity on Earth is 9.8 m/s2, and gravity on the Moon is 1.6 m/s2.
So, if the mass of an object on Earth is 40 kilograms, its mass on the Moon is
kilograms and its weight on the Moon is
newtons.
Reset Next
Answer: Mass is 40 kg, weight is 64 N
Explanation: Mass is same everywhere, weight G = mg, it depends on acceleration of gravity
79.4 grams of C3H8 are consumed with an excess of oxygen in the reaction 1 C3H8 + 5 O2 --> 3 CO2 + 4 H2O. How many moles of oxygen (O2) are consumed in this reaction?How many moles of carbon dioxide (CO2) are formed in this reaction? &
How many moles of water (H2O) are formed in this reaction?
Answer:
II would say there is co2 so i would say 30.4
Explanation:
Hope this helps
In which location would a free neutron from a decaying U-235 atom be most likely to cause another atom to split?
there you go. giving answers to most questions on the chem test (10th grade)
Answer:
The appropriate option would be B . Explanation: This is due to the reason enriched U has insignificant polluting influences. Along these lines, the U -235 particles focuses together and the possibilty of high energy neutron bombarding another Uranium -235 molecule in the region is high.
Explanation:
Answer:
thank u so much for the answers ! !! How do u get the answers???
Explanation:
[check out their questions for the answers guys chem final]
Can someone please help with this 4 mark question!
Answer:
6.941 u
Explanation:
Cu2O + C -> Cu + CO2 balanced equation
Answer:
2Cu2O + C --> 4Cu + CO2
Explanation
The Law of conservation of Mass states You can not destroy or create math in a chemical reaction, meaning you must have the same amount at the beginning and the end. This equation keeps the same amount of atoms on both sides.
Answer: Yes, it is a balanced equation.
Explanation:
https://chemequations.com/en/?s=Cu2O+%2B+C+%3D+Cu+%2B+CO2
This is where I got the answer so you know. Hope this helps :)
Pls hurry
Light is the fastest known entity in our universe.
O True
O False
Mark this and return
Save and Exit
Answer:
True
Explanation:
Answer:
true
Explanation:
source(s): trust me bro
Which of the following reactions is balanced?
Answer:
D
Explanation:
Because it has equal number of elements on each side of the arrow
What is the molarity of a sodium hydroxide solution if 25 mL of the solution is neutralized by 69.5 mL of 1.5 M HCl?
Answer:
4.17M
Explanation:
m1v1/m2v2=n1/n2
what is difference between asexual or sexual reproduction
Explanation:
asexual reproduction involves 1 parent and produces offspring that are genetically identical to each other and parent.
Sexual reproduction involves 2 parents and produces offspring that are genetically unique.
what is the proper formulanGaseous Butane (C4H10) that reacts with Gaseous Oxygen (O2) in a combustion reaction to form Carbon dioxide Gas and Gaseous Water (Dihydrogen monoxide).
Answer:
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Explanation:
The balanced equation for the reaction between butane and oxygen to produce carbon dioxide and water can be written as follow:
C₄H₁₀ + O₂ —> CO₂ + H₂O
Next, we shall balanced the equation. This is illustrated below:
C₄H₁₀ + O₂ —> CO₂ + H₂O
There are 4 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 4 before CO₂ as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + H₂O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + 5H₂O
There are 2 atoms of O on the left side and a total of 13 atoms on the right side. It can be balance by writing 13/2 before O₂ as shown below:
C₄H₁₀ + 13/2O₂ —> 4CO₂ + 5H₂O
Multiply through by 2 to express in whole number ratio.
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Thus, the equation is balanced.
A student has 475 mL of a 4.5 M HNO3 solution. He leaves the top of the container Monday morning the volume of solution is now 347 mL. What is the conventtration of the solution now
Answer:
6.1 M
Explanation:
Step 1: Calculate the moles of HNO₃ in the initial solution
A student has 475 mL (0.475 L) of a 4.5 M HNO₃ (4.5 mol HNO₃/ L) solution.
0.475 L × 4.5 mol HNO₃/ L = 2.1 mol HNO₃
He leaves the top of the container open, so water will evaporate, but the moles of HNO₃ will remain the same.
Step 2: Calculate the final concentration of the solution
2.1 moles of HNO₃ are in 347 mL (0.347 L) of solution.
[HNO₃] = 2.1 mol / 0.347 L = 6.1 M
1.
At constant pressure. 50 milliliters (mL) of a gas
at 20°C is heated to 30° C. The new volume of
the gas in milliliters (ml) is equal
Answer:
[tex]\boxed {\boxed {\sf V_2=75 \ mL}}[/tex]
Explanation:
Since the pressure is constant, the only variables we need to work with are temperature and volume. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Originally, the gas was 50 milliliters at 20 degrees celsius. Substitute these values into the left side of the equation.
[tex]\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{T_2}[/tex]
We don't know the volume of the new gas, but we know the temperature was changed to 30 degrees celsius.
[tex]\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{30 \textdegree C}[/tex]
Since we are solving for the new volume, we must isolate the variable. It is being divided by 30 °Cand the inverse of division is muliplication. Multiply both sides by 30 °C.
[tex]30 \textdegree C*\frac{50 \ mL}{20 \textdegree C}=\frac{ V_2}{30 \textdegree C}* 30 \textdegree C[/tex]
[tex]30 \textdegree C*\frac{50 \ mL}{20 \textdegree C}= V_2[/tex]
The units of degrees celsius cancel, so we are left with milliliters as the units.
[tex]30*\frac{50 \ mL}{20}= V_2[/tex]
[tex]\frac{1500 \ mL}{20}= V_2[/tex]
[tex]75 \ mL=V_2[/tex]
The new volume of the gas is 75 milliliters.
At the Sprite bottling plant where the temperature is at 235K, each bottle can hold 3.80 atm of pressurized carbon dioxide gas (to make the soda fizzy). At room temperature 298K what is the new pressure?
Answer:
P2 = 4.76 atm
Explanation:
Given:
T1 = 235K. P1 = 3.80 atm
T2 = 298K. P2 = ?
Here, we use Gay-Lussac's law:
P1/T1 = P2/T2
Solving for P2, we get
P2 = (T2/T1)P1
= (298K/238K)(3.80 atm)
= 4.76 atm
In the unbalanced chemical equation shown below, what is the coefficient of aluminum (AI) metal?
Al(s) + O2(g) → Al2O3(s)
Answer : A. 3
Explanation:
3Al(s) + 3O2(g) → 3Al2O3(s)
This is the right Answer :3
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Someone Please HELP Me
2C4H10(g) + 13O2(g) → 8CO2(g) + 10 H2O(g)
How many liters of O2 are required to produce 3.15g of carbon dioxide?
1: A50 L balloon is at 4 atm of pressure. What is the volume at 2 atm of pressure?
Answer:
100 L
Explanation:
Use Boyle's Law, p1v1 = p2v2.
p1 = 4 atm
v1 = 50L
p2 = 2 atm
v2 = ?
p1v1 = p2v2
(4 atm) (50L) = (2 atm) (v2)
v2 = (4 atm)(50L) / (2 atm) = 100 L