How long will it take a car, starting from rest, accelerating at 2 meters per second square to travel the same distance that another car traveling at a constant rate of 20m/s will travel?

Answer:

Its acceleration will increase.

Explanation:

For an object spinning around a central point, Its acceleration will increase if its distance from the centre is decreased.

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration. The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity

This is the acceleration of an object in a circle of radius r at a speed v. So, centripetal acceleration is greater at high speeds and in sharp curves smaller radii and for lager radii acceleration will be less.

acceleration, a = v²/r

For an object spinning around a central point, Its acceleration will increase if its distance from the centre is decreased.

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Answer:

Most importantly metals can pass an electric current without being affected and changed by the electricity. Electrical conductivity combined with ductility makes metals the most suitable materials for electrical transmission wires.

Answer:

V2 = (V1 - u) / (1 - V1 u / c^2)

V1 = speed of ship in observer frame = .99 c    to right

u = speed of frame 2 = -.99 c   to left relative to observer

V2 = speed of V1 relative to V2

V2 = (.99 - (-.99 ) / (1 - .99 (-.99)) c

V2 = 1.98 / (1 + .99^2) c = .99995 c

Answer:

A. 2.7 m/s

Explanation:

Answer:

[tex]\boxed {\boxed {\sf A. \ 2.7 \ m/s}}[/tex]

Explanation:

We want to find how fast a branch is falling after 0.28 seconds.

Essentially, we want to find its final velocity at exactly 0.28 seconds. We will use the following kinematic equation:

[tex]v_f= v_i+at[/tex]

The branch fell from the tree, so it initially started at rest or 0 meters per second. The branch is in free fall, so its acceleration is due to gravity, or 9.8 meters per second squared. It falls for 0.28 seconds.

Substitute the values into the formula.

[tex]v_f= 0 \ m/s + (9.8 \ m/s^2)(0.28 \ s)[/tex]

Multiply the numbers in parentheses.

[tex]v_f= 0 \ m/s +(9.8 \ m/s/s * 0.28 \ s )[/tex]

[tex]v_f= 0 \ m/s +2.744 \ m/s[/tex]

Add.

[tex]v_f= 2.744 \ m/s[/tex]

The original measurement of time has 2 significant figures, so our answer must have the same. For the number we found, that is the tenth place. The 4 in the hundredth place tells us to leave the 7.

[tex]v_f \approx 2.7 \ m/s[/tex]

The branch is moving at a velocity of approximately 2.7 meters per second.

Answer:

Pick c is the right one

Explanation:

5.0m/s

Hi there!

The formula for velocity given acceleration:

v = at

Plug in given values:

v = 6.4(7) = 44.8 m/s

A goal statement may involve how to develop physical skills in a given outdoor activity (e.g., soccer) in order to reach my maximum potential. It involves a statement of purpose.

A goal statement is a statement of purpose that describes long-term professional and/or motivational objectives.

A goal statement involves writing a statement about how to reach personal objectives, i.e., how to accomplish a career, job title, sports skills, educational training, etc.

An excellent statement of purpose should ideally be clear, specific, acceptable, time-bound and realistic.

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The distance traveled by the body in the given time is 1,250 m.

The given parameters;

The distance traveled by the body in the given time is calculated as follows;

[tex]s =ut + \frac{1}{2} at^2\\\\s = 0 \ + \ \frac{1}{2} (4)(25^2)\\\\s =1,250 \ m[/tex]

Thus, the distance traveled by the body in the given time is 1,250 m.

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The applied torque increases the angular speed by the application of an

angular acceleration.

Reasons:

The speed of the flywheel at the axis = 4 rev/s

The torque applied, T = 25 N·m

The time the torque is applied, t = 10 sec

Moment of inertia of the flywheel, I = 1.2 kg·m²

Required:

The speed at the end of the 10 seconds

Solution:

T = I·α

Where;

α = Angular acceleration

[tex]\displaystyle \alpha = \frac{T}{I}[/tex]

Therefore;

[tex]\displaystyle \alpha = \frac{24 \ N\cdot m}{1.2 \ kg \cdot m^2} = \mathbf{20\frac{5}{6} \ s^{-2}}[/tex]

The rotational speed, ω = ω₀ + α·t

Which gives;

[tex]\displaystyle \mathrm{The \ angular \ speed, } \ \omega = \frac{2 \cdot \pi \times 4 \ rad }{s} = \frac{8 \cdot \pi \ rad }{s}[/tex]

ω₀ = 8·π rad/s

Which gives;

[tex]\displaystyle \omega = \mathbf{8 \cdot \pi +2 \frac{5}{6} \times 10} = 233.47[/tex]

The speed of the wheel in revolution per second is therefore;

[tex]\displaystyle Speed \ in \ rev/s = \frac{8 \cdot \pi +2 \frac{5}{6} \times 10}{2\cdot \pi} \approx 37.16[/tex]

The speed after 10 seconds is approximately 37.16 rev/s.

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The modern atomic model is called the nuclear atomic model.

Therefore the correct answer is option C.

There are many types of atomic models proposed in past based on their individual assumptions and the experimentations

John Dalton's atomic model.

The Plum Pudding Model, developed by J.J. Thomson,

Rutherford's model provided an explanation for the presence of a nucleus inside the atom.

In accordance with the current atomic model, atoms have a nucleus made up of protons and neutrons and an ethereal gradient or cloud surrounding them that houses electrons;

The modern atomic model is called the nuclear atomic model.

Thus, the correct answer is option C.

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This temperature would be 170° F on the Fahrenheit scale. Hence, option (C) is correct.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances.

The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes.

the relation between Kelvin scale and Fahrenheit scale is given by:

(F - 32)/180 = (K - 273)/100

F - 32 = (350 - 273)(9/5)

F = 32 + (350 - 273)(9/5)

F = 170

Hence,  this temperature would be 170° F on the Fahrenheit scale.

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The force of friction needed to overcome to move the box is 29.4N

According to Newton's second law;

[tex]\sum F_x = ma_x\\[/tex]

Taking the sum of force along the plane;

[tex]F_m -F_f = ma\\F_m -F_f = 0\\F_m=F_f = \mu R[/tex]

This shows that the moving force is equal to the frictional force

Given that

[tex]\mu = 0.6\\R = mg = 49N[/tex]

Get the frictional force;

Since

[tex]F_f = \mu R\\F_f = 0.6 \times 49\\F_f = 29.4N[/tex]

Hence the force of friction needed to overcome to move the box is 29.4N

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The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

The given parameters;

The acceleration of the SRB and main engine is calculated as follows;

[tex]a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60 s} \\\\a = 52.16 \ m/s^2[/tex]

Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

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do your work in class you would know  kids

Its relative speed compared to Earth is 0.921

The speed of the object v = 2πr/T where r = radius of orbit and T = period of orbit.

Let v = speed of earth, r = radius of earth orbit = 1 AU and T = period of earth orbit.

So, v = 2πr/T

Also, v' = speed of NEO, r' = radius of NEO orbit = distance of NEO from sun = 1.18 AU and T' = period of NEO orbit.

So, v' = 2πr'/T'

v'/v = 2πr'/T' ÷ 2πr/T

v'/v = r'/r × T/T'

From Kepler's law, T² ∝ r³

So, T'²/T² = r'³/r³

(T'/T)² = (r'/r)³

T'/T =  √[(r'/r)]³

T/T' = √[(r'/r)]⁻³

So, substituting this into the equation, we have

v'/v = r'/r × T/T'

v'/v = r'/r × √[(r'/r)]⁻³

v'/v = √[(r'/r)]⁻¹

Since r' = 1.18 AU and r = 1 AU, r'/r = 1.18

So, v'/v = √[(r'/r)]⁻¹

v'/v = √[(1.18)]⁻¹

v'/v = [1.0863]⁻¹

v'/v = 0.921

So, its relative speed compared to Earth is 0.921

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Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between the objects.

now, several numbers change.

Fgravitynew = G*((1/4)*mass1*3*mass2)/(1/2 * D)² =

= G*((3/4)*mass1*mass2)/(D²/4) =

= (3/4)* (G*(mass1*mass2)/D²) *4 =

= 4*(3/4)* (G*(mass1*mass2)/D²) =

= 3* (G*(mass1*mass2)/D²) = 3* Fgravity

the new gravitational force will be 3×178 = 534 units.

11.4 m/s

Explanation:

The cord will break when the centripetal force exerted on it meets or exceeds the maximum tension [tex]T_{max}[/tex] that it can handle.

[tex]T_{max} = m\dfrac{v_{max}^2}{r}[/tex]

Solving for [tex]v_{max},[/tex] we get

[tex]v_{max}^2 = \dfrac{rT_{max}}{m}[/tex]

or

[tex]v_{max} = \sqrt{\dfrac{rT_{max}}{m}} =\sqrt{\dfrac{(1.3\:\text{m})(60\:\text{N})}{(0.6\:\text{kg})}}[/tex]

[tex]\:\:\:\:\:= 11.4\:\text{m/s}[/tex]

Answer: 20

Explanation:

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

We will start by completing the Boyle's Law stated

Boyle's Law states the volume and pressure of a gas are inversely proportional, provided that the temperature remains constant.

This means temperature is the constant of proportionality.

Now, we will name the three units of the constant of proportionality, that is, temperature. The units are

1. Degree Celsius (°C)

2. Degree Fahrenheit (°F)

3. Kelvin (K)

2. In the ideal gas equation (PV/nT=R), R represents the ideal gas constant.

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

Hence,

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

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Answer:

Explanation:

1)  average velocity is

v = (21 + 39)/2 = 30m m/s

d = vt 30(4.1) = 123 = 120 m

2)  d = ½gt²

d = ½(9.8)(4.1²)

d = 82.369 = 82 m

when rounding to the two significant digits of the question numerals.

Answer:

Explanation:

Normal force of the surface on the box will be

N = mg - Fsinθ

Ν = 10(9.8) - 600sin37

N = -263

As normal force cannot be less than zero, the applied force lifts the crate off the surface.

Now it's just a matter of finding the acceleration

In the horizontal direction, the acceleration is

a = F/m

a = (600cos37) / 10

a =  47.9181... m/s²

the crate weight is mg = 10(9.8) = 98 N.

In the vertical direction the acceleration is

a = ((600sin37 - 98) / 10)

a = 26.3089... m/s²

total acceleration is

a = √(47.9181² + 26.3089²)

a = 54.6653... m/s²

s = ½at²

t = √(2s/a)

t = √(2(1.0)/54.6653)

t = 0.19127...

t = 0.19 s

Answer:

Explanation:

550 ft•lb/s / hp•(1.82 hp) / 500 lb = 2.00 ft/s

Answer:

a) Impuise of force =F∗?(t) = area of F-T graph area= impulse =triangle + rectangle + triangle = 0.5*4*2 + 4*1 + 0.5*4*2 = 12 N-s (b) impulse = change in momentum \(= mExplanation:

Answer:

Explanation:

Conservation of momentum

115v + 133(0) = (115 + 133)1.35

v = 2.911304...

v= 2.91 m/s east

Answer:

The velocity east is 2.91

Explanation:

Fill in the box

2.91

Answer:

it says pdf only i dont knowwhat u want me to do

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According to above question ~

Let's find the charge (q) by using formula ~

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

Answer:

two of the same instrument playing notes at slightly different frequencies

Explanation:

The correct answer is two of the same instrument playing notes at slightly different frequencies.

Frequency is the number of occurrences of a periodic event per unit of time. In the context of sound waves, frequency refers to the number of complete cycles of a sound wave that occur in one second and is measured in units of Hertz (Hz).

In this question,

A beat frequency occurs when two sound waves with slightly different frequencies interfere with each other, resulting in a periodic variation in the amplitude of the resulting wave. The beat frequency is equal to the difference in frequency between the two original sound waves.

When two of the same instrument play notes at slightly different frequencies, the sound waves produced by each instrument will have slightly different frequencies due to differences in tuning or other factors. When the two sound waves interfere with each other, they will produce a beat frequency equal to the difference between their frequencies. This beat frequency will be audible as a periodic variation in the loudness or intensity of the sound.

In the other statements, There will not be any beat frequency because the sound waves being produced have either the same frequency or very different frequencies, which do not interfere with each other in a way that produces beats.

Therefore, The statement two of the same instrument playing notes at slightly different frequencies is correct.

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Answer:

A IS THE ANSWER

Explanation:

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