how is sound produced by using stringed instrument​

Answers

Answer 1

sound vibrations

Explanation:

akechis pancakes

Answer 2

Answer:

By waves

Explanation:

when sound is being produced by string instruments it uses waves to help create that sound


Related Questions

A force of 100N moves a body on a horizontal frictionless surface when......

I. Friction force exerted on the body is less than 100N
II. Friction force exerted on the body is more than 100N
III. None of these
IV. Both of I and II

Answers

Answer:

I. Friction force exerted on the body is less than 100N

Explanation:

For  a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.

Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.

Therefore, for a body to move, Fm > Ff or Ff < Ff

Fm is the moving force

Ff is the force of friction

Given

Fm = 100N

For the 100N body to move the frictional force must be less than 100N

4. If the cooling of magma takes place slowly beneath Earth's surface, the rock is that is formed
is called
a. extrusive igneous rock
b. intrusive igneous rock
c. sedimentary rock
d. metamorphic rock

Answers

I agree with the answer above listen to them :)

PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.

Answers

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

[tex]Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J[/tex]

or

Q = 282,000 J

So, the required heat is 282,000 J .


What must exist for the engineering process to begin?
a. a problem
ь.a solution
c. research
d. scientific tools

Answers

Answer:

d

Explanation:

rzp-yyib-oiv

plèase jóin ón góógle mèèt

Answer:

a. a problem

Explanation:

The engineering process begins by defining a problem and completing background research on the problem.


Maurice is playing some of the arcades at the county fair. At one booth he throws a 1.2-kg ball forward with a velocity of 15 m/s and hits a 0.5-kg can
at rest. The ball continues forward at 9 m/s. What is the new velocity of the can, in m/s? (Round your answer to one decimal place if necessary.)

Answers

Answer:

9.6

Hope this helps.

(a) The roof of a large arena, with a weight of 290 kN, is lifted by 30 cm so that it can be centered. How much work is done on the roof by the forces making the lift? (b) In 1960 a Tampa, Florida, mother reportedly raised one end of a car that had fallen onto her son when a jack failed. If her panic lift effectively raised 4000 N (about 1/4 of the car's weight) by 5 cm, how much work did her force do on the car?

Answers

Answer:

87000 J ;

200 J

Explanation:

Workdone = mgh

Weight = mg = 290kN = 290 * 1000=290000 N

h = distance = 30 cm = 0.3 m

Workdone = 290000 * 0.3

Workdone = 87000 J

B.)

Workdone = Force * distance

Force = 4000 N

Distance, d = 5 cm = 0.05 m

Workdone by the woman, W = 4000N * 0.05m

W = 200Nm = 200 J

What is the increase in gravitational potential energy of an object of mass 9.00 kg when it is raised from the ground to a height of 2.41 m, in units of joules?

Answers

Answer:

23 asden

Explanation:

first clothes and shoes

write each of the following in scientific notation, correct to 2 decimal places.
a. 0.00000123 N
b. 417 000 000 kg
c. 246800 A
d. 0,00088 mm​

Answers

Answer:

The scientific notation for the each number is given below:

Explanation:

The scientific notation for the following numbers are:

a. For 0.00000123 N

1.23 × 10^-6

b. For 417 000 000 kg

4.17 × 10^8

c. For 246800 A

2.47 × 10^5

d. For 0.00088m

8.8 × 10^-4

The above represent scientific notations of each numbers

Explain why the sound waves always reach the observer after the light waves

Answers

Answer:

I think it's because the light waves travel faster than the sound waves.

The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.

What is the speed of light?

Light occurs in the electromagnetic spectrum. Recall that light can be transmitted through vaccuum unlike sound.

The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.

Learn more about speed of light:https://brainly.com/question/8832859

#SPJ2

Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1.

If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?

Answers

Answer:

3.2 m

Explanation:

From the question given above, the following data were obtained:

Coefficient of friction (μ) = 0.1

Initial velocity (u) = 0 m/s

Mass (m) = 6 Kg

Acceleration (a) = 0.4 m/s²

Time (t) = 4 s

Distance (s) =.?

The distance travelled can be obtained as illustrated below:

s = ut + ½at²

s = (0×4) + (½ × 0.4 × 4²)

s = 0 + (0.2 × 16)

s = 0 + 3.2

s = 3.2 m

Thus, the box will travel 3.2 m in 4 s.

Create a concept map that shows the relationships among the following: crest, trough, compression, rarefaction, wave length, wave frequency, amplitude, and wave
speed.

Answers

Uhm.. based on what? Can you please specify/add an image or some more text and elaborate?

A 1.6-kg ball is attached to the end of a 0.40-m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80-kg block initially at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3.0 m/s. What is the speed of the ball just after the collision?a. 1.5 m/sb. 1.3 m/sc. 2.1 m/sd. 1.1 m/se. 1.7 m/s

Answers

Answer:

a. 1.5 m/s

Explanation:

We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:

[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\[/tex]

where,

m₁ = mass of ball = 1.6 kg

m₂= mass of block = 0.8 kg

u₁ = initial speed of ball = 0 m/s

u₂ = initial speed of block = 0 m/s

v₁ = final speed of ball = ?

v₂ = final speed of block = 3 m/s

Therefore,

[tex](1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\[/tex]

v₁ = 1.5 m/s

Therefore, the correct option is:

a. 1.5 m/s

What year did Badminton become a full-medal Olympic sport?

Answers

Answer:

1992

Explanation:

Badminton made its debut as a demonstration sport at the 1972 Olympic Games in Munich. It was not until the 1992 Games in Barcelona that it was officially included on the Olympic programme, with men's and women's singles and doubles events.

An instrument that produces an electric current in the presence of
a radioactive substance is called a
a. particle accelerator.
b. Geiger counter.
c. cloud chamber.
d. bubble chamber.

Answers

Answer:

Option B, Geiger counter

Explanation:

studyhero A violin string has a length, from the bridge to the end of the fingerboard, of 50 cm. That section of the string has a mass of only 2 g. When the violinist plays an open string (the full length) a 440 Hz A-note is heard. Determine the length of the string needed to play a 528 Hz note without adjusting the tension in the string. This is accomplished by pressing on the fingerboard at the appropriate location.

Answers

Answer:

= 0.517 m

Explanation:

This is a resonance exercise where the ends of the string are fixed, therefore it has a node of them, the fundamental (longest) wavelength created has the form

                λ = 2L

wave speed is related to wavelength and frequency

               v = λ f

               v = 2L f

let's calculate

                v = 2 0.50 440

                v = 440 m / s

since they indicate that the tension of the string does not change and the linear density of the string is constant, the speed of the wave also remains constant

               f =[tex]\frac{v}{2L}[/tex]

let's find the length for the new resonance frequency

               L = [tex]\ \frac{v}{2f}[/tex]

let's calculate

               L = [tex]\frac{440}{2 \ 528}[/tex]

               L = 0.5166 m

Why do we use copper wiring?

Answers

Explanation:

The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals

What is optics???????

see my percentage of answering and thanks , it's crazy ​

Answers

Answer:

hi..bro

make pinky sis answer as brinlist ok

have a good day

Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer in vector form.)

Answers

Answer:

--------------------------------

Explanation:

Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (560 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 3.0 m away. Calculate the fringe separation between the third order and central fringe.

Answers

Answer:

 y = 4.666 10⁻² m

Explanation:

The constructive interference experiment for the double slit

         d sin sin θ = m λ

Let's use trigonometry to find a sine relationship.

         Tan θ = y / L

          tan θ = sin θ/ cos θ

in these experiments the angles are very small

           tan θ = sin θ

           sin θ = y / L

            [tex]d \frac{y}{L}[/tex] = m λ

              y = [tex]\frac{ m \lambda \ L}{d}[/tex]

we replace the values

              y = 3  560 10⁻⁹ 3.0 / 0.108 10⁻³

              y = 4.666 10⁻² m

Which of the following is an example of the transformation of gravitational potential energy into motion energy (kinetic energy)?

Answers

Answer:

c

Explanation:

because a drop of water is falling and that is gravitational potential energy into motion energy

A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?

Answers

Answer:

Explanation:

mass (m) = 65 kg

velocity (v) = 4.6 m/s

Kinetic energy (KE)

= 1/2 * m * v²

= 1/2 * 65 * 4.6²

=  687.7 J

hope it helps :)


C
D
7
The sun is the original source of
energy for many of our energy
resources
Which energy resource does not
originate from the sun? *
(1 Point)
.
A. Geothermal
B. Hydroelectric
C. Waves
D. Win

Answers

Answer:

geothermal

Explanation:

geothermal energy is the heat energy obtained from within the Earth. Hence not derived from Sun's energy.

Why do scientists perform multiple trials of the same experiment?

Answers

Answer:

it's a good idea to do multiple trials, that is, do the same experiment lots of times. When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time.

Explanation:

the last one which is to increase the likelihood of accurate experiment results

Explanation:

10. John does 176 J of work lifting himself a distance of 0.40 m. How
much force must John apply to accomplish this?
O 440 m
O 440 J
O 440 N
O 70.4 J

Answers

The answer is 440N

A pail in a water well is hoisted by means of a frictionless winch, which consists of a spool and a hand crank. When Jill turns the winch at her fastest water-fetching rate, she can lift the pail the 26.0 m to the top in 12.0 s. Calculate the average power supplied by Jill's muscles during the upward ascent. Assume the pail of water when full has a mass of 6.50 kg. W

Answers

Answer:

140.83 W

Explanation:

From the question given above, the following data were obtained:

Height (h) = 26 m

Time (t) = 12 s

Mass (m) = 6.50 Kg

Power (P) =?

Power is simply defined as the rate at which energy is used up. Mathematically, it is expressed as:

Power (P) = Energy (E) / Time (t)

But:

Energy (E) = mass (m) × acceleration due to gravity (g) × height (h)

E = mgh

P = E/t

P = mgh / t

With the above formula i.e

P = mgh / t

We can obtain the power supplied by Jill's muscles as follow:

Height (h) = 26 m

Time (t) = 12 s

Mass (m) = 6.50 Kg

Acceleration due to gravity (g) = 10 m/s²

Power (P) =?

P = mgh / t

P = 6.5 × 10 × 26 / 12

P = 140.83 W

Therefore, the power supplied by Jill's muscles is 140.83 W

A 50kg bicyclist on a 10kg bicycle speeds up from 5.0m/s to 10m/s. What was the total kinetic energy after accelerating?​

Answers

Answer:

Explanation:

Ek=1/2mv^2

m=50+10=60,v=10

Ek=1/2*60*100=3000J

please help me fast please help​

Answers

Answer:

the net energy Gained per hour equals 30Kcal/h

PLEASEEEE HELP ASAP
What are the two main divisions
of the peripheral nervous system?
A. Muscular Nervous System, Digestive Nervous
System
B. Circulatory Nervous System, Endocrine
Nervous System
C. Somatic Nervous System, Autonomic Nervous
System

Answers

It’s divided into two parts, the somatic nervous system and the autonomic nervous system.

hope this helps!! :)

Which water on earth is the largest,second to the largest,3rd to the largest,fourth to the largest and 5th to the largest?​

Answers

Answer:

Explanation:

There are a total of 5 differen classification for the types of bodies of water that exist on Earth. These 5 would be the following: Oceans, seas, lakes, rivers, and canals. Oceans are the biggest bodies of water on Earth. If we ranked them by their size the ranking would be the following...

Pacific Ocean - being 155,556,651 sq km. in size

Atlantic Ocean - being 76,761,938 sq km. in size

Indian Ocean - being 68,555,923 sq km. in size

Antarctic / Southern Ocean - being 20,327,001 sq km. in size

Arctic Ocean - being 14,055,930 sq km. in size

Describe the phenomenon of lightning?​

Answers


Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions in the atmosphere or ground temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy.
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